Re: [R] building a list in a loop
Does the following do what you want?
> d <- list() # empty list
> for(i in 1:8) if (i %% 2 == 0) {
newElement <- structure(list(i), names=LETTERS[i])
d <- c(d, newElement)
}
> str(d)
List of 4
$ B: int 2
$ D: int 4
$ F: int 6
$ H: int 8
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Fri, Jun 5, 2015 at 1:40 AM, carol white via R-help wrote:
> It might be an easy question but how to construct correctly a list in a
> loop?
>
> The following doesn't work
> before starting the loopd = NULL#in the loop, 1st iteration
> d = list(d,c(1,2,3)d[[1]]
> NULL
>
> [[2]]
> [1] 1 2 3#in the loop, 2nd iterationd=list(d,c(4,5,6)d
> [[1]]
> [[1]][[1]]
> NULL
>
> [[1]][[2]]
> [1] 1 2 3
>
>
> [[2]]
> [1] 4 5 6
> the goal is to have the result of d= list(c(1,2,3),c(4,5,6)) where the
> list components are not known out of the loop.
> d[[1]]
> [1] 1 2 3
>
> [[2]]
> [1] 4 5 6
> Moreover, how to name the components of the list in the loop while
> constructing as the names are not known out of the loop, either? note that
> the name of the component is stored in a variable in the loop
>
> d = NULL#name1 contains the name for c(1,2,3), how to give the name below?
> d = list(d,c(1,2,3)
> Thanks
>
> [[alternative HTML version deleted]]
>
> __
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] building a list in a loop
Your explanation of the problem is unclear and your use of HTML formatting corrupts your code examples. One issue is your reference to a loop while showing no loop nor input nor output. There is more than one construct for iterating in R. One problem you may be encountering is that you cannot change the vector over which you iterate in a for loop while you are in that loop. If that is your problem then you probably need to use something like a while loop. However your example is too abstract (and scrambled by HTML) for me to fix it. To make your problem clearer [1], you could give us a dput of a sample input data object with a few elements (rows, columns, whatever) and build each element of your output without resorting to a loop. We could then suggest ways to use a loop to accomplish the same thing. [1] http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example --- Jeff NewmillerThe . . Go Live... DCN:Basics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. On June 5, 2015 1:40:04 AM PDT, carol white via R-help wrote: >It might be an easy question but how to construct correctly a list in a >loop? > >The following doesn't work >before starting the loopd = NULL#in the loop, 1st iteration >d = list(d,c(1,2,3)d[[1]] >NULL > >[[2]] >[1] 1 2 3#in the loop, 2nd iterationd=list(d,c(4,5,6)d >[[1]] >[[1]][[1]] >NULL > >[[1]][[2]] >[1] 1 2 3 > > >[[2]] >[1] 4 5 6 >the goal is to have the result of d= list(c(1,2,3),c(4,5,6)) where the >list components are not known out of the loop. >d[[1]] >[1] 1 2 3 > >[[2]] >[1] 4 5 6 >Moreover, how to name the components of the list in the loop while >constructing as the names are not known out of the loop, either? note >that the name of the component is stored in a variable in the loop > >d = NULL#name1 contains the name for c(1,2,3), how to give the name >below? >d = list(d,c(1,2,3) >Thanks > > [[alternative HTML version deleted]] > >__ >R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] building a list in a loop
Hi
I do not understand. „i“ is variable and list elements are called by this
variable
#constructing list
> d<-as.list(sample(letters[1:5], 5, replace=F))
> names(d) <- letters[1:5]
> d
$a
[1] "c"
$b
[1] "a"
$c
[1] "e"
$d
[1] "b"
$e
[1] "d"
#variable el
> el<-"a"
#result
> d[[el]]<-"whatever I want to put under name a"
> d
$a
[1] "whatever I want to put under name a"
$b
[1] "a"
$c
[1] "e"
$d
[1] "b"
$e
[1] "d"
Cheers
Petr
From: carol white [mailto:wht_...@yahoo.com]
Sent: Friday, June 05, 2015 1:31 PM
To: PIKAL Petr
Cc: r-help@r-project.org
Subject: Re: [R] building a list in a loop
in this example can elements of the list be accessed by their name if their
name is the value of a variable?
el = "a"
can the first element d[[1]] be accessed by el instead of the list index like
d$a but via el?
Thanks
On Friday, June 5, 2015 12:04 PM, PIKAL Petr
mailto:petr.pi...@precheza.cz>> wrote:
Hi
This I do not consider as a loop without index. AFAIK i is index and the loop
is executed twice. First with i equal to „a“ and second time with i equal to
„b“.
In that case you need to have some objects which are named “a” or “b” and you
can use it for selection or computing
d<-list(a=NULL, b=NULL)
for (i in c("a","b")) {
d[[i]]<-1:3
}
Cheers
Petr
From: carol white [mailto:wht_...@yahoo.com]
Sent: Friday, June 05, 2015 11:51 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop
for (i in c("a","b"))
best,
On Friday, June 5, 2015 11:36 AM, PIKAL Petr
mailto:petr.pi...@precheza.cz>> wrote:
Hi
Can you please specify how loop without index shall be constructed? It is
rather new topic for me.
Petr
From: carol white [mailto:wht_...@yahoo.com]
Sent: Friday, June 05, 2015 11:21 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop
also consider a loop without index (not like for (i ...) where index could be
used for the list construction)
Cheers,
On Friday, June 5, 2015 11:13 AM, PIKAL Petr
mailto:petr.pi...@precheza.cz>> wrote:
Hi
It is not clear what exactly do you want.
d<-list()
vec<-1:3
for (i in 1:2) {
vec<-vec+3*(i-1)
d[[i]]<-vec
#names(d)[i] <- paste("name",i)
}
You can add names in second loop or you can use names command in first loop.
Cheers
Petr
> -Original Message-
> From: R-help
> [mailto:r-help-boun...@r-project.org<mailto:r-help-boun...@r-project.org>] On
> Behalf Of carol
> white via R-help
> Sent: Friday, June 05, 2015 10:40 AM
> To: R-help Help
> Subject: [R] building a list in a loop
>
> It might be an easy question but how to construct correctly a list in a
> loop?
>
> The following doesn't work
> before starting the loopd = NULL#in the loop, 1st iteration
> d = list(d,c(1,2,3)d[[1]]
> NULL
>
> [[2]]
> [1] 1 2 3#in the loop, 2nd iterationd=list(d,c(4,5,6)d
> [[1]]
> [[1]][[1]]
> NULL
>
> [[1]][[2]]
> [1] 1 2 3
>
>
> [[2]]
> [1] 4 5 6
> the goal is to have the result of d= list(c(1,2,3),c(4,5,6)) where the
> list components are not known out of the loop.
> d[[1]]
> [1] 1 2 3
>
> [[2]]
> [1] 4 5 6
> Moreover, how to name the components of the list in the loop while
> constructing as the names are not known out of the loop, either? note
> that the name of the component is stored in a variable in the loop
>
> d = NULL#name1 contains the name for c(1,2,3), how to give the name
> below?
> d = list(d,c(1,2,3)
> Thanks
>
> [[alternative HTML version deleted]]
>
> __
> R-help@r-project.org<mailto:R-help@r-project.org> mailing list -- To
> UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-<http://www.r-project.org/posting->
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
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Re: [R] building a list in a loop
Here is the best solution that I found as the list is built in the embedded
functions withtout using loop index, list elements' names etc
d = list()d[[length(d)+1]] = 1:3d[[length(d)+1]] = 4:6
Many thanks for your help
On Friday, June 5, 2015 12:04 PM, PIKAL Petr
wrote:
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div.yiv1728143486WordSection1 {}#yiv1728143486 Hi This I do not consider as a
loop without index. AFAIK i is index and the loop is executed twice. First
with i equal to „a“ and second time with i equal to „b“. In that case you need
to have some objects which are named“a” or “b” and you can use it for
selection or computing d<-list(a=NULL, b=NULL)for (i in c("a","b"))
{d[[i]]<-1:3} CheersPetr From: carol white [mailto:wht_...@yahoo.com]
Sent: Friday, June 05, 2015 11:51 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop for (i in c("a","b")) best, On
Friday, June 5, 2015 11:36 AM, PIKAL Petr wrote: Hi
Can you please specify how loop without index shall be constructed? It is
rather new topic for me. Petr From: carol white [mailto:wht_...@yahoo.com]
Sent: Friday, June 05, 2015 11:21 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop also consider a loop without index
(not like for (i ...) where index could be used for the list construction)
Cheers, On Friday, June 5, 2015 11:13 AM, PIKAL Petr
wrote: Hi
It is not clear what exactly do you want.
d<-list()
vec<-1:3
for (i in 1:2) {
vec<-vec+3*(i-1)
d[[i]]<-vec
#names(d)[i] <- paste("name",i)
}
You can add names in second loop or you can use names command in first loop.
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of carol
> white via R-help
> Sent: Friday, June 05, 2015 10:40 AM
> To: R-help Help
> Subject: [R] building a list in a loop
>
> It might be an easy question but how to construct correctly a list in a
> loop?
>
> The following doesn't work
> before starting the loopd = NULL#in the loop, 1st iteration
> d = list(d,c(1,2,3)d[[1]]
> NULL
>
> [[2]]
> [1] 1 2 3#in the loop, 2nd iterationd=list(d,c(4,5,6)d
> [[1]]
> [[1]][[1]]
> NULL
>
> [[1]][[2]]
> [1] 1 2 3
>
>
> [[2]]
> [1] 4 5 6
> the goal is to have the result of d= list(c(1,2,3),c(4,5,6)) where the
> list components are not known out of the loop.
> d[[1]]
> [1] 1 2 3
>
> [[2]]
> [1] 4 5 6
> Moreover, how to name the components of the list in the loop while
> constructing as the names are not known out of the loop, either? note
> that the name of the component
Re: [R] building a list in a loop
in this example can elements of the list be accessed by their name if their
name is the value of a variable?el = "a"can the first element d[[1]] be
accessed by el instead of the list index like d$a but via el?
Thanks
On Friday, June 5, 2015 12:04 PM, PIKAL Petr
wrote:
#yiv1728143486 #yiv1728143486 _filtered #yiv1728143486
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div.yiv1728143486WordSection1 {}#yiv1728143486 Hi This I do not consider as a
loop without index. AFAIK i is index and the loop is executed twice. First
with i equal to „a“ and second time with i equal to „b“. In that case you need
to have some objects which are named“a” or “b” and you can use it for
selection or computing d<-list(a=NULL, b=NULL)for (i in c("a","b"))
{d[[i]]<-1:3} CheersPetr From: carol white [mailto:wht_...@yahoo.com]
Sent: Friday, June 05, 2015 11:51 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop for (i in c("a","b")) best, On
Friday, June 5, 2015 11:36 AM, PIKAL Petr wrote: Hi
Can you please specify how loop without index shall be constructed? It is
rather new topic for me. Petr From: carol white [mailto:wht_...@yahoo.com]
Sent: Friday, June 05, 2015 11:21 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop also consider a loop without index
(not like for (i ...) where index could be used for the list construction)
Cheers, On Friday, June 5, 2015 11:13 AM, PIKAL Petr
wrote: Hi
It is not clear what exactly do you want.
d<-list()
vec<-1:3
for (i in 1:2) {
vec<-vec+3*(i-1)
d[[i]]<-vec
#names(d)[i] <- paste("name",i)
}
You can add names in second loop or you can use names command in first loop.
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of carol
> white via R-help
> Sent: Friday, June 05, 2015 10:40 AM
> To: R-help Help
> Subject: [R] building a list in a loop
>
> It might be an easy question but how to construct correctly a list in a
> loop?
>
> The following doesn't work
> before starting the loopd = NULL#in the loop, 1st iteration
> d = list(d,c(1,2,3)d[[1]]
> NULL
>
> [[2]]
> [1] 1 2 3#in the loop, 2nd iterationd=list(d,c(4,5,6)d
> [[1]]
> [[1]][[1]]
> NULL
>
> [[1]][[2]]
> [1] 1 2 3
>
>
> [[2]]
> [1] 4 5 6
> the goal is to have the result of d= list(c(1,2,3),c(4,5,6)) where the
> list components are not known out of the loop.
> d[[1]]
> [1] 1 2 3
>
> [[2]]
> [1] 4 5 6
> Moreover, how to name the components of the list in the loop while
> constructing as the names are not known out of the loop, either? note
> that the name of the component is stored in a variable in the loop
>
> d = N
Re: [R] building a list in a loop
Hi
This I do not consider as a loop without index. AFAIK i is index and the loop
is executed twice. First with i equal to „a“ and second time with i equal to
„b“.
In that case you need to have some objects which are named “a” or “b” and you
can use it for selection or computing
d<-list(a=NULL, b=NULL)
for (i in c("a","b")) {
d[[i]]<-1:3
}
Cheers
Petr
From: carol white [mailto:wht_...@yahoo.com]
Sent: Friday, June 05, 2015 11:51 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop
for (i in c("a","b"))
best,
On Friday, June 5, 2015 11:36 AM, PIKAL Petr
mailto:petr.pi...@precheza.cz>> wrote:
Hi
Can you please specify how loop without index shall be constructed? It is
rather new topic for me.
Petr
From: carol white [mailto:wht_...@yahoo.com]
Sent: Friday, June 05, 2015 11:21 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop
also consider a loop without index (not like for (i ...) where index could be
used for the list construction)
Cheers,
On Friday, June 5, 2015 11:13 AM, PIKAL Petr
mailto:petr.pi...@precheza.cz>> wrote:
Hi
It is not clear what exactly do you want.
d<-list()
vec<-1:3
for (i in 1:2) {
vec<-vec+3*(i-1)
d[[i]]<-vec
#names(d)[i] <- paste("name",i)
}
You can add names in second loop or you can use names command in first loop.
Cheers
Petr
> -Original Message-
> From: R-help
> [mailto:r-help-boun...@r-project.org<mailto:r-help-boun...@r-project.org>] On
> Behalf Of carol
> white via R-help
> Sent: Friday, June 05, 2015 10:40 AM
> To: R-help Help
> Subject: [R] building a list in a loop
>
> It might be an easy question but how to construct correctly a list in a
> loop?
>
> The following doesn't work
> before starting the loopd = NULL#in the loop, 1st iteration
> d = list(d,c(1,2,3)d[[1]]
> NULL
>
> [[2]]
> [1] 1 2 3#in the loop, 2nd iterationd=list(d,c(4,5,6)d
> [[1]]
> [[1]][[1]]
> NULL
>
> [[1]][[2]]
> [1] 1 2 3
>
>
> [[2]]
> [1] 4 5 6
> the goal is to have the result of d= list(c(1,2,3),c(4,5,6)) where the
> list components are not known out of the loop.
> d[[1]]
> [1] 1 2 3
>
> [[2]]
> [1] 4 5 6
> Moreover, how to name the components of the list in the loop while
> constructing as the names are not known out of the loop, either? note
> that the name of the component is stored in a variable in the loop
>
> d = NULL#name1 contains the name for c(1,2,3), how to give the name
> below?
> d = list(d,c(1,2,3)
> Thanks
>
> [[alternative HTML version deleted]]
>
> __
> R-help@r-project.org<mailto:R-help@r-project.org> mailing list -- To
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-<http://www.r-project.org/posting->
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
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Re: [R] building a list in a loop
Hi
Can you please specify how loop without index shall be constructed? It is
rather new topic for me.
Petr
From: carol white [mailto:wht_...@yahoo.com]
Sent: Friday, June 05, 2015 11:21 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop
also consider a loop without index (not like for (i ...) where index could be
used for the list construction)
Cheers,
On Friday, June 5, 2015 11:13 AM, PIKAL Petr
mailto:petr.pi...@precheza.cz>> wrote:
Hi
It is not clear what exactly do you want.
d<-list()
vec<-1:3
for (i in 1:2) {
vec<-vec+3*(i-1)
d[[i]]<-vec
#names(d)[i] <- paste("name",i)
}
You can add names in second loop or you can use names command in first loop.
Cheers
Petr
> -Original Message-
> From: R-help
> [mailto:r-help-boun...@r-project.org<mailto:r-help-boun...@r-project.org>] On
> Behalf Of carol
> white via R-help
> Sent: Friday, June 05, 2015 10:40 AM
> To: R-help Help
> Subject: [R] building a list in a loop
>
> It might be an easy question but how to construct correctly a list in a
> loop?
>
> The following doesn't work
> before starting the loopd = NULL#in the loop, 1st iteration
> d = list(d,c(1,2,3)d[[1]]
> NULL
>
> [[2]]
> [1] 1 2 3#in the loop, 2nd iterationd=list(d,c(4,5,6)d
> [[1]]
> [[1]][[1]]
> NULL
>
> [[1]][[2]]
> [1] 1 2 3
>
>
> [[2]]
> [1] 4 5 6
> the goal is to have the result of d= list(c(1,2,3),c(4,5,6)) where the
> list components are not known out of the loop.
> d[[1]]
> [1] 1 2 3
>
> [[2]]
> [1] 4 5 6
> Moreover, how to name the components of the list in the loop while
> constructing as the names are not known out of the loop, either? note
> that the name of the component is stored in a variable in the loop
>
> d = NULL#name1 contains the name for c(1,2,3), how to give the name
> below?
> d = list(d,c(1,2,3)
> Thanks
>
> [[alternative HTML version deleted]]
>
> __
> R-help@r-project.org<mailto:R-help@r-project.org> mailing list -- To
> UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-<http://www.r-project.org/posting->
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny
pouze jeho adresátům.
Jestliže jste obdržel(a) tento e-mail omylem, informujte laskavě neprodleně
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Nejste-li zamýšleným adresátem tohoto emailu, nejste oprávněni tento email
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Odesílatel e-mailu neodpovídá za eventuální škodu způsobenou modifikacemi či
zpožděním přenosu e-mailu.
V případě, že je tento e-mail součástí obchodního jednání:
- vyhrazuje si odesílatel právo ukončit kdykoliv jednání o uzavření smlouvy, a
to z jakéhokoliv důvodu i bez uvedení důvodu.
- a obsahuje-li nabídku, je adresát oprávněn nabídku bezodkladně přijmout;
Odesílatel tohoto e-mailu (nabídky) vylučuje přijetí nabídky ze strany příjemce
s dodatkem či odchylkou.
- trvá odesílatel na tom, že příslušná smlouva je uzavřena teprve výslovným
dosažením shody na všech jejích náležitostech.
- odesílatel tohoto emailu informuje, že není oprávněn uzavírat za společnost
žádné smlouvy s výjimkou případů, kdy k tomu byl písemně zmocněn nebo písemně
pověřen a takové pověření nebo plná moc byly adresátovi tohoto emailu případně
osobě, kterou adresát zastupuje, předloženy nebo jejich existence je adresátovi
či osobě jím zastoupené známá.
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Re: [R] building a list in a loop
Hi
I do not understand. My mind reading ambilities are limited.
Where do you get your vectors from?
Instead of
vec<-vec+3*(i-1)
you can use any computation to create any object.
d<-list()
n=2
for (i in 1:n) {
s<-sample(1:26, 10, replace=FALSE)
rn<-rnorm(10)
y<-rn*s*rnorm(1)+rnorm(1)
fit<-lm(y~s)
d[[i]]<-fit
names(d)[i] <- paste(letters[round(mean(s))],i, sep="")
}
So my opinion is that the code for populating list is pretty general.
Petr
From: carol white [mailto:wht_...@yahoo.com]
Sent: Friday, June 05, 2015 11:18 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop
vectors c(1,2,3) etc were an example. the general case should be considered if
it is a character vector with the unknown elements out of the loop. the same as
the name. your code can't be generalized.
On Friday, June 5, 2015 11:13 AM, PIKAL Petr
mailto:petr.pi...@precheza.cz>> wrote:
Hi
It is not clear what exactly do you want.
d<-list()
vec<-1:3
for (i in 1:2) {
vec<-vec+3*(i-1)
d[[i]]<-vec
#names(d)[i] <- paste("name",i)
}
You can add names in second loop or you can use names command in first loop.
Cheers
Petr
> -Original Message-
> From: R-help
> [mailto:r-help-boun...@r-project.org<mailto:r-help-boun...@r-project.org>] On
> Behalf Of carol
> white via R-help
> Sent: Friday, June 05, 2015 10:40 AM
> To: R-help Help
> Subject: [R] building a list in a loop
>
> It might be an easy question but how to construct correctly a list in a
> loop?
>
> The following doesn't work
> before starting the loopd = NULL#in the loop, 1st iteration
> d = list(d,c(1,2,3)d[[1]]
> NULL
>
> [[2]]
> [1] 1 2 3#in the loop, 2nd iterationd=list(d,c(4,5,6)d
> [[1]]
> [[1]][[1]]
> NULL
>
> [[1]][[2]]
> [1] 1 2 3
>
>
> [[2]]
> [1] 4 5 6
> the goal is to have the result of d= list(c(1,2,3),c(4,5,6)) where the
> list components are not known out of the loop.
> d[[1]]
> [1] 1 2 3
>
> [[2]]
> [1] 4 5 6
> Moreover, how to name the components of the list in the loop while
> constructing as the names are not known out of the loop, either? note
> that the name of the component is stored in a variable in the loop
>
> d = NULL#name1 contains the name for c(1,2,3), how to give the name
> below?
> d = list(d,c(1,2,3)
> Thanks
>
> [[alternative HTML version deleted]]
>
> __
> R-help@r-project.org<mailto:R-help@r-project.org> mailing list -- To
> UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-<http://www.r-project.org/posting->
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny
pouze jeho adresátům.
Jestliže jste obdržel(a) tento e-mail omylem, informujte laskavě neprodleně
jeho odesílatele. Obsah tohoto emailu i s přílohami a jeho kopie vymažte ze
svého systému.
Nejste-li zamýšleným adresátem tohoto emailu, nejste oprávněni tento email
jakkoliv užívat, rozšiřovat, kopírovat či zveřejňovat.
Odesílatel e-mailu neodpovídá za eventuální škodu způsobenou modifikacemi či
zpožděním přenosu e-mailu.
V případě, že je tento e-mail součástí obchodního jednání:
- vyhrazuje si odesílatel právo ukončit kdykoliv jednání o uzavření smlouvy, a
to z jakéhokoliv důvodu i bez uvedení důvodu.
- a obsahuje-li nabídku, je adresát oprávněn nabídku bezodkladně přijmout;
Odesílatel tohoto e-mailu (nabídky) vylučuje přijetí nabídky ze strany příjemce
s dodatkem či odchylkou.
- trvá odesílatel na tom, že příslušná smlouva je uzavřena teprve výslovným
dosažením shody na všech jejích náležitostech.
- odesílatel tohoto emailu informuje, že není oprávněn uzavírat za společnost
žádné smlouvy s výjimkou případů, kdy k tomu byl písemně zmocněn nebo písemně
pověřen a takové pověření nebo plná moc byly adresátovi tohoto emailu případně
osobě, kterou adresát zastupuje, předloženy nebo jejich existence je adresátovi
či osobě jím zastoupené známá.
This e-mail and any documents attached to it may be confidential and are
intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its sender.
Delete the contents of this e-mail with all attachments and its copies from
your system.
If you are not the intended recipient of this e-mail, you are not authorized to
use, disseminate, copy or disclose this e-mail in any manner.
The sender of this e-mail shall not be liable for any possible damage caused by
modifications of the e-mail or by delay with transfer of the email.
In case that this e-mail forms part of business dealings:
- the sender reserves the right to end negotiations about
