Re: [R] error message: .Random.seed is not an integer vector but of type 'list'
Jim Bouldin wrote: I'm trying to run this simple random sample procedure and keep getting the error message shown. I don't understand this; I've designated x as a numeric vector, so what is going on here? Thanks. x = as.vector(c(1:12));x [1] 1 2 3 4 5 6 7 8 9 10 11 12 mode(x) [1] numeric sample(x, 3) Error in sample(x, 3) : .Random.seed is not an integer vector but of type 'list' Something has changed/corrupted an object called .Random.seed that is required by the Random Number Generator. Just say rm(.Random.seed) and try again. Uwe Ligges Jim Bouldin, PhD Research Ecologist Department of Plant Sciences, UC Davis Davis CA, 95616 530-554-1740 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] error message: .Random.seed is not an integer vector but of type 'list'
Thank you. However, when I tried that, I got this message: Warning message: In rm(.Random.seed) : variable .Random.seed was not found Jim Bouldin wrote: I'm trying to run this simple random sample procedure and keep getting the error message shown. I don't understand this; I've designated x as a numeric vector, so what is going on here? Thanks. x = as.vector(c(1:12));x [1] 1 2 3 4 5 6 7 8 9 10 11 12 mode(x) [1] numeric sample(x, 3) Error in sample(x, 3) : .Random.seed is not an integer vector but of type 'list' Something has changed/corrupted an object called .Random.seed that is required by the Random Number Generator. Just say rm(.Random.seed) and try again. Uwe Ligges Jim Bouldin, PhD Research Ecologist Department of Plant Sciences, UC Davis Davis CA, 95616 530-554-1740 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] error message: .Random.seed is not an integer vector but of type 'list'
Jim Bouldin wrote: Thank you. However, when I tried that, I got this message: Warning message: In rm(.Random.seed) : variable .Random.seed was not found In that case, have you attached some package that has its own .Random.seed? Try to find where the current .random.seed comes from R complains about. Uwe Ligges Jim Bouldin wrote: I'm trying to run this simple random sample procedure and keep getting the error message shown. I don't understand this; I've designated x as a numeric vector, so what is going on here? Thanks. x = as.vector(c(1:12));x [1] 1 2 3 4 5 6 7 8 9 10 11 12 mode(x) [1] numeric sample(x, 3) Error in sample(x, 3) : .Random.seed is not an integer vector but of type 'list' Something has changed/corrupted an object called .Random.seed that is required by the Random Number Generator. Just say rm(.Random.seed) and try again. Uwe Ligges Jim Bouldin, PhD Research Ecologist Department of Plant Sciences, UC Davis Davis CA, 95616 530-554-1740 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] error message: .Random.seed is not an integer vector but of type 'list'
Jim Bouldin wrote: Thank you. However, when I tried that, I got this message: Warning message: In rm(.Random.seed) : variable .Random.seed was not found In that case, have you attached some package that has its own .Random.seed? Try to find where the current .random.seed comes from R complains about. Uwe Ligges No, there are no attached packages, just the ones that load automatically. The R commander has some type of RNG but it is not loaded. Completely stumped. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] error message: .Random.seed is not an integer vector but
On 23-Jul-09 15:30:05, Jim Bouldin wrote: I'm trying to run this simple random sample procedure and keep getting the error message shown. I don't understand this; I've Thanks. x = as.vector(c(1:12));x [1] 1 2 3 4 5 6 7 8 9 10 11 12 mode(x) [1] numeric sample(x, 3) Error in sample(x, 3) : .Random.seed is not an integer vector but of type 'list' Jim Bouldin, PhD I think this error is not arising from the code you have given above. I get: x=as.vector(c(1:12)) sample(x,3) # [1] 8 12 2 which is fine. '.Random.seed' should be an integer vector to start with. See '?set.seed'. Therefore it should not be a list. Try entering .Random.seed and see what you get -- when I do it it is a vector of 626 assorted integers. Also try: is.vector(.Random.seed) and, if that is not TRUE, try str(.Random.seed) typeof(.Random.seed) If .Random.seed turns out to be a list, then something has gone seriously wrong somewhere. It may be that somwehere in your code there is a command that meddles with .Random.seed (or perhaps it was saved, in .Rdata, from a previous session where something went wrong). Or, worst scenario, your R installation is broken ... And, while I'm at it, your x=as.vector(c(1:12)) is overkill! Simply x - (1:12) ; sample(x,3) should be enough, or even sample((1:12),3) since (1:12) is a vector (of integers). Hoping this helps, Ted. E-Mail: (Ted Harding) ted.hard...@manchester.ac.uk Fax-to-email: +44 (0)870 094 0861 Date: 23-Jul-09 Time: 17:13:55 -- XFMail -- __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] error message: .Random.seed is not an integer vector but
On 23-Jul-09 16:08:17, Jim Bouldin wrote: Jim Bouldin wrote: Thank you. However, when I tried that, I got this message: Warning message: In rm(.Random.seed) : variable .Random.seed was not found In that case, have you attached some package that has its own .Random.seed? Try to find where the current .random.seed comes from R complains about. Uwe Ligges No, there are no attached packages, just the ones that load automatically. The R commander has some type of RNG but it is not loaded. Completely stumped. Follow-up to my previous reply (just posted). Having read the other responses and your reactions, try the following: rm(.Random.seed) set.seed(54321) ## (Or your favourite magic number) [*] x = as.vector(c(1:12)) ## To reproduce your original code ... ! sample(x,3) [*] When you did rm(.Random.seed) as suggested by Uwe, the variable .Random.seed was lost, so you have to create it again. If, after the above, you still get the problem, then something is very seriously wrong. Ted. E-Mail: (Ted Harding) ted.hard...@manchester.ac.uk Fax-to-email: +44 (0)870 094 0861 Date: 23-Jul-09 Time: 17:23:09 -- XFMail -- __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] error message: .Random.seed is not an integer vector but
Thanks much Ted. I actually had just tried what you suggest here before you posted, and resolved the problem. Thanks also for the other tips. I wrote x = as.vector(c(1:12)) because I thought that the mode of x might be the problem, the error message pointing to .Random.seed notwithstanding. On a related note, I did a brief test a couple weeks back where I ran a million random samples of 3 from the vector 1:12 and compared the mean against the known mean. It was off by 1 percent, which indicated that the RNG was biased more than I'd have thought. Comments? Jim Follow-up to my previous reply (just posted). Having read the other responses and your reactions, try the following: rm(.Random.seed) set.seed(54321) ## (Or your favourite magic number) [*] x = as.vector(c(1:12)) ## To reproduce your original code ... ! sample(x,3) [*] When you did rm(.Random.seed) as suggested by Uwe, the variable .Random.seed was lost, so you have to create it again. If, after the above, you still get the problem, then something is very seriously wrong. Ted. E-Mail: (Ted Harding) ted.hard...@manchester.ac.uk Fax-to-email: +44 (0)870 094 0861 Date: 23-Jul-09 Time: 17:23:09 -- XFMail -- Jim Bouldin, PhD Research Ecologist Department of Plant Sciences, UC Davis Davis CA, 95616 530-554-1740 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] error message: .Random.seed is not an integer vector but
-Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Jim Bouldin Sent: Thursday, July 23, 2009 9:49 AM To: ted.hard...@manchester.ac.uk; ted.hard...@manchester.ac.uk; r-h...@r- project.org Subject: Re: [R] error message: .Random.seed is not an integer vector but Thanks much Ted. I actually had just tried what you suggest here before you posted, and resolved the problem. Thanks also for the other tips. I wrote x = as.vector(c(1:12)) because I thought that the mode of x might be the problem, the error message pointing to .Random.seed notwithstanding. On a related note, I did a brief test a couple weeks back where I ran a million random samples of 3 from the vector 1:12 and compared the mean against the known mean. It was off by 1 percent, which indicated that the RNG was biased more than I'd have thought. Comments? Jim snip It would be necessary to see the code for your 'brief test' before anyone could meaningfully comment on your results. But your results for a single test could have been a valid random result. Dan Daniel J. Nordlund Washington State Department of Social and Health Services Planning, Performance, and Accountability Research and Data Analysis Division Olympia, WA 98504-5204 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
