Re: [R] generate random numbers subject to constraints

2008-03-27 Thread Charles C. Berry
On Thu, 27 Mar 2008, Robert A LaBudde wrote:

> At 05:06 PM 3/26/2008, Ted Harding wrote:
>> On 26-Mar-08 21:26:59, Ala' Jaouni wrote:
>>> X1,X2,X3,X4 should have independent distributions. They should be
>>> between 0 and 1 and all add up to 1. Is this still possible with
>>> Robert's method?
>>>
>>> Thanks
>>
>> I don't think so. A whileago you wrote
>> "The numbers should be uniformly distributed" (but in the
>> context of an example where you had 5 variable; now you
>> are back to 4 variables). Let's take the 4-case first.
>>
>> The two linear constraints confine the point (X1,X2,X3,X4)
>> to a triangular region within the 4-dimensional unit cube.
>> Say it has vertices A, B, C.
>> You could then start by generating points uniformly distributed
>> over a specific triangle in 2 dimentions, say the one with
>> vertices at A0=(0,0), B0=(0,1), C0=(1,0). This is easy.
>>
>> Then you need to find a linear transformation which will
>> map this triangle (A0,B0,C0) onto the triangle (A,B,C).
>> Then the points you have sampled in (A0,B0,C0) will map
>> into points which are uniformly distributed over the
>> triangle (A,B,C).
>>
>> More generally, you will be seeking to generate points
>> uniformly distributed over a simplex.
>>
>> For example, the case (your earlier post) of 5 points
>> with 2 linear constraints requires a tetrahedron with
>> vertices (A,B,C,D) in 5 dimensions whose coordinates you
>> will have to find. Then take an "easy" tetrahedron with
>> vertices (A0,B0,C0,D0) and sample uniformly within this.
>> Then find a linear mapping from (A0,B0,C0,D0) to (A,B,C,D)
>> and apply this to the sampled points.
>>
>> This raises a general question: Does anyone know of
>> an R function to sample uniformly in the interior
>> of a general (k-r)-dimensional simplex embedded in
>> k dimensions, with (k+1) given vertices?
>> 
>
> The method of "rejection":
>
> 1. Generate numbers randomly in the hypercube.
> 2. Test to see if the point falls within the prescribed area.
> 3. Accept the point if it does.
> 4. Repeat if it doesn't.
>
> Efficiency depends upon the ratio of volumes involved.

The ratio is zero.

The subspace of the solution has lower dimension than the space you are 
sampling from.

So you will repeat '4' forever. (Up to machine accuracy, of course.)

And as I pointed out in my response to Ala' Jaouni, the 'solution' may lie 
in the null space. When it does not it will be a point, a line segment, a 
piece of a plane, or a 3 dimensional simplex.

Chuck



>
>
> 
> Robert A. LaBudde, PhD, PAS, Dpl. ACAFS  e-mail: [EMAIL PROTECTED]
> Least Cost Formulations, Ltd.URL: http://lcfltd.com/
> 824 Timberlake Drive Tel: 757-467-0954
> Virginia Beach, VA 23464-3239Fax: 757-467-2947
>
> "Vere scire est per causas scire"
>
> __
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

Charles C. Berry(858) 534-2098
 Dept of Family/Preventive Medicine
E mailto:[EMAIL PROTECTED]  UC San Diego
http://famprevmed.ucsd.edu/faculty/cberry/  La Jolla, San Diego 92093-0901

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Re: [R] generate random numbers subject to constraints

2008-03-27 Thread Naji Nassar

Hi all


One suggestion, tranforme the x

00
u > or < ln()
(u1 & u2 are not independant)
Compute u3 given the above formula

Generate the x


Hope this help
Naji



Le 26/03/08 22:41, « Ala' Jaouni » <[EMAIL PROTECTED]> a écrit :

> X1,X2,X3,X4 should have independent distributions. They should be
> between 0 and 1 and all add up to 1. Is this still possible with
> Robert's method?
> 
> Thanks
> 
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

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Re: [R] generate random numbers subject to constraints

2008-03-27 Thread Robert A LaBudde
At 05:06 PM 3/26/2008, Ted Harding wrote:
>On 26-Mar-08 21:26:59, Ala' Jaouni wrote:
> > X1,X2,X3,X4 should have independent distributions. They should be
> > between 0 and 1 and all add up to 1. Is this still possible with
> > Robert's method?
> >
> > Thanks
>
>I don't think so. A whileago you wrote
>"The numbers should be uniformly distributed" (but in the
>context of an example where you had 5 variable; now you
>are back to 4 variables). Let's take the 4-case first.
>
>The two linear constraints confine the point (X1,X2,X3,X4)
>to a triangular region within the 4-dimensional unit cube.
>Say it has vertices A, B, C.
>You could then start by generating points uniformly distributed
>over a specific triangle in 2 dimentions, say the one with
>vertices at A0=(0,0), B0=(0,1), C0=(1,0). This is easy.
>
>Then you need to find a linear transformation which will
>map this triangle (A0,B0,C0) onto the triangle (A,B,C).
>Then the points you have sampled in (A0,B0,C0) will map
>into points which are uniformly distributed over the
>triangle (A,B,C).
>
>More generally, you will be seeking to generate points
>uniformly distributed over a simplex.
>
>For example, the case (your earlier post) of 5 points
>with 2 linear constraints requires a tetrahedron with
>vertices (A,B,C,D) in 5 dimensions whose coordinates you
>will have to find. Then take an "easy" tetrahedron with
>vertices (A0,B0,C0,D0) and sample uniformly within this.
>Then find a linear mapping from (A0,B0,C0,D0) to (A,B,C,D)
>and apply this to the sampled points.
>
>This raises a general question: Does anyone know of
>an R function to sample uniformly in the interior
>of a general (k-r)-dimensional simplex embedded in
>k dimensions, with (k+1) given vertices?
>

The method of "rejection":

1. Generate numbers randomly in the hypercube.
2. Test to see if the point falls within the prescribed area.
3. Accept the point if it does.
4. Repeat if it doesn't.

Efficiency depends upon the ratio of volumes involved.



Robert A. LaBudde, PhD, PAS, Dpl. ACAFS  e-mail: [EMAIL PROTECTED]
Least Cost Formulations, Ltd.URL: http://lcfltd.com/
824 Timberlake Drive Tel: 757-467-0954
Virginia Beach, VA 23464-3239Fax: 757-467-2947

"Vere scire est per causas scire"

__
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Re: [R] generate random numbers subject to constraints

2008-03-26 Thread Charles C. Berry
Ala' Jaouni  gmail.com> writes:

> 
> X1,X2,X3,X4 should have independent distributions. They should be
> between 0 and 1 and all add up to 1. Is this still possible with
> Robert's method?
> 

NO.

If they add to 1 they are not independent.

As Ted remarked, the constraints define two simplexes and the solution you seek
lies in their intersection.

However, depending on the choices of a, b, c, d, and n in a*X1+b*X2+c*X3+d*X4=n,
there may not be a solution that satisfies your constraints (no intersection
between the two simplexes - as when ahttps://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] generate random numbers subject to constraints

2008-03-26 Thread Ted Harding
OOPS! A mistake below. I should have written:

  This raises a general question: Does anyone know of
  an R function to sample uniformly in the interior
  of a general (k-r)-dimensional simplex embedded in
  k dimensions, with (k-r+1) given vertices?


On 26-Mar-08 22:06:54, Ted Harding wrote:
> On 26-Mar-08 21:26:59, Ala' Jaouni wrote:
>> X1,X2,X3,X4 should have independent distributions. They should be
>> between 0 and 1 and all add up to 1. Is this still possible with
>> Robert's method?
>> 
>> Thanks
> 
> I don't think so. A whileago you wrote
> "The numbers should be uniformly distributed" (but in the
> context of an example where you had 5 variable; now you
> are back to 4 variables). Let's take the 4-case first.
> 
> The two linear constraints confine the point (X1,X2,X3,X4)
> to a triangular region within the 4-dimensional unit cube.
> Say it has vertices A, B, C.
> You could then start by generating points uniformly distributed
> over a specific triangle in 2 dimentions, say the one with
> vertices at A0=(0,0), B0=(0,1), C0=(1,0). This is easy.
> 
> Then you need to find a linear transformation which will
> map this triangle (A0,B0,C0) onto the triangle (A,B,C).
> Then the points you have sampled in (A0,B0,C0) will map
> into points which are uniformly distributed over the
> triangle (A,B,C).
> 
> More generally, you will be seeking to generate points
> uniformly distributed over a simplex.
> 
> For example, the case (your earlier post) of 5 points
> with 2 linear constraints requires a tetrahedron with
> vertices (A,B,C,D) in 5 dimensions whose coordinates you
> will have to find. Then take an "easy" tetrahedron with
> vertices (A0,B0,C0,D0) and sample uniformly within this.
> Then find a linear mapping from (A0,B0,C0,D0) to (A,B,C,D)
> and apply this to the sampled points.
> 
> This raises a general question: Does anyone know of
> an R function to sample uniformly in the interior
> of a general (k-r)-dimensional simplex embedded in
> k dimensions, with (k+1) given vertices?
> 
> Best wishes to all,
> Ted.
> 
> 
>> On Wed, Mar 26, 2008 at 12:52 PM, Ted Harding
>> <[EMAIL PROTECTED]> wrote:
>>> On 26-Mar-08 20:13:50, Robert A LaBudde wrote:
>>>  > At 01:13 PM 3/26/2008, Ala' Jaouni wrote:
>>>  >>I am trying to generate a set of random numbers that fulfill
>>>  >>the following constraints:
>>>  >>
>>>  >>X1 + X2 + X3 + X4 = 1
>>>  >>
>>>  >>aX1 + bX2 + cX3 + dX4 = n
>>>  >>
>>>  >>where a, b, c, d, and n are known.
>>>  >>
>>>  >>Any function to do this?
>>>  >
>>>  > 1. Generate random variates for X1, X2, based upon whatever
>>>  > unspecified distribution you wish.
>>>  >
>>>  > 2. Solve the two equations for X3 and X4.
>>>
>>>  The trouble is that the original problem is not well
>>>  specified. Your suggestion, Robert, gives a solution
>>>  to one version of the problem -- enabling Ala' Jaouni
>>>  to say "I have generated 4 random numbers X1,X2,X3,X4
>>>  such that X1 and X2 have specified distributions,
>>>  and X1,X2,X3,X4 satisfy the two equations ... ".
>>>
>>>  However, suppose the real problem was: let X2,X2,X3,X4
>>>  have independent distributions F1,F2,F3,F4. Now sample
>>>  X1,X2,X3,X4 conditional on the two equations (i.e. from
>>>  the coditional density). That is a different problem.
>>>
>>>  As a slightly simpler example, suppose we have just X1,X2,X3
>>>  and they are independently uniform on (0,1). Now sample
>>>  from the conditional distribution, conditional on
>>>  X1 + X2 + X3 = 1.
>>>
>>>  The result is a random point uniformly distributed on the
>>>  planar triangle whose vertices are at (1,0,0),(0,1,0),(0,0,1).
>>>
>>>  Then none of X1,X2,X3 is uniformly distributed (in fact
>>>  the marginal density of each is 2*(1-x)).
>>>
>>>  However, your solution would work from either point of
>>>  view if the distributions were Normal.
>>>
>>>  If X1,X2,X3,X4 were neither Normally nor uniformly
>>>  distributed, then finding or simulating the conditional
>>>  distribution would in general be difficult.
>>>
>>>  Ala' Jaouni needs to tell us whether what he precisely
>>>  wants is as you stated the problem, Robert, or whether
>>>  he wants a conditional distribution for given distributions
>>>  if X1,X2,X3,X4, or whether he wants something else.
>>>
>>>  Best wishes to all,
>>>  Ted.
>>>
>>>  
>>>  E-Mail: (Ted Harding) <[EMAIL PROTECTED]>
>>>  Fax-to-email: +44 (0)870 094 0861
>>>  Date: 26-Mar-08   Time: 19:52:16
>>>  -- XFMail --
>>>
>> 
>> __
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
> 
> 
> E-Mail: (Ted Harding) <[EM

Re: [R] generate random numbers subject to constraints

2008-03-26 Thread Ted Harding
On 26-Mar-08 21:26:59, Ala' Jaouni wrote:
> X1,X2,X3,X4 should have independent distributions. They should be
> between 0 and 1 and all add up to 1. Is this still possible with
> Robert's method?
> 
> Thanks

I don't think so. A whileago you wrote
"The numbers should be uniformly distributed" (but in the
context of an example where you had 5 variable; now you
are back to 4 variables). Let's take the 4-case first.

The two linear constraints confine the point (X1,X2,X3,X4)
to a triangular region within the 4-dimensional unit cube.
Say it has vertices A, B, C.
You could then start by generating points uniformly distributed
over a specific triangle in 2 dimentions, say the one with
vertices at A0=(0,0), B0=(0,1), C0=(1,0). This is easy.

Then you need to find a linear transformation which will
map this triangle (A0,B0,C0) onto the triangle (A,B,C).
Then the points you have sampled in (A0,B0,C0) will map
into points which are uniformly distributed over the
triangle (A,B,C).

More generally, you will be seeking to generate points
uniformly distributed over a simplex.

For example, the case (your earlier post) of 5 points
with 2 linear constraints requires a tetrahedron with
vertices (A,B,C,D) in 5 dimensions whose coordinates you
will have to find. Then take an "easy" tetrahedron with
vertices (A0,B0,C0,D0) and sample uniformly within this.
Then find a linear mapping from (A0,B0,C0,D0) to (A,B,C,D)
and apply this to the sampled points.

This raises a general question: Does anyone know of
an R function to sample uniformly in the interior
of a general (k-r)-dimensional simplex embedded in
k dimensions, with (k+1) given vertices?

Best wishes to all,
Ted.


> On Wed, Mar 26, 2008 at 12:52 PM, Ted Harding
> <[EMAIL PROTECTED]> wrote:
>> On 26-Mar-08 20:13:50, Robert A LaBudde wrote:
>>  > At 01:13 PM 3/26/2008, Ala' Jaouni wrote:
>>  >>I am trying to generate a set of random numbers that fulfill
>>  >>the following constraints:
>>  >>
>>  >>X1 + X2 + X3 + X4 = 1
>>  >>
>>  >>aX1 + bX2 + cX3 + dX4 = n
>>  >>
>>  >>where a, b, c, d, and n are known.
>>  >>
>>  >>Any function to do this?
>>  >
>>  > 1. Generate random variates for X1, X2, based upon whatever
>>  > unspecified distribution you wish.
>>  >
>>  > 2. Solve the two equations for X3 and X4.
>>
>>  The trouble is that the original problem is not well
>>  specified. Your suggestion, Robert, gives a solution
>>  to one version of the problem -- enabling Ala' Jaouni
>>  to say "I have generated 4 random numbers X1,X2,X3,X4
>>  such that X1 and X2 have specified distributions,
>>  and X1,X2,X3,X4 satisfy the two equations ... ".
>>
>>  However, suppose the real problem was: let X2,X2,X3,X4
>>  have independent distributions F1,F2,F3,F4. Now sample
>>  X1,X2,X3,X4 conditional on the two equations (i.e. from
>>  the coditional density). That is a different problem.
>>
>>  As a slightly simpler example, suppose we have just X1,X2,X3
>>  and they are independently uniform on (0,1). Now sample
>>  from the conditional distribution, conditional on
>>  X1 + X2 + X3 = 1.
>>
>>  The result is a random point uniformly distributed on the
>>  planar triangle whose vertices are at (1,0,0),(0,1,0),(0,0,1).
>>
>>  Then none of X1,X2,X3 is uniformly distributed (in fact
>>  the marginal density of each is 2*(1-x)).
>>
>>  However, your solution would work from either point of
>>  view if the distributions were Normal.
>>
>>  If X1,X2,X3,X4 were neither Normally nor uniformly
>>  distributed, then finding or simulating the conditional
>>  distribution would in general be difficult.
>>
>>  Ala' Jaouni needs to tell us whether what he precisely
>>  wants is as you stated the problem, Robert, or whether
>>  he wants a conditional distribution for given distributions
>>  if X1,X2,X3,X4, or whether he wants something else.
>>
>>  Best wishes to all,
>>  Ted.
>>
>>  
>>  E-Mail: (Ted Harding) <[EMAIL PROTECTED]>
>>  Fax-to-email: +44 (0)870 094 0861
>>  Date: 26-Mar-08   Time: 19:52:16
>>  -- XFMail --
>>
> 
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.


E-Mail: (Ted Harding) <[EMAIL PROTECTED]>
Fax-to-email: +44 (0)870 094 0861
Date: 26-Mar-08   Time: 22:06:38
-- XFMail --

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Re: [R] generate random numbers subject to constraints

2008-03-26 Thread Alberto Monteiro

Ala' Jaouni wrote:
>
> I am trying to generate a set of random numbers that fulfill the
> following constraints:
> 
> X1 + X2 + X3 + X4 = 1
> 
> aX1 + bX2 + cX3 + dX4 = n
> 
> where a, b, c, d, and n are known.
> 
> Any function to do this?
> 
You must give more information.

How are those numbers distributed? Are they normal? Positive?

If they can be anything, just generate X1, X2 and then compute X3, X4.

Alberto Monteiro

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Re: [R] generate random numbers subject to constraints

2008-03-26 Thread Ala' Jaouni
X1,X2,X3,X4 should have independent distributions. They should be
between 0 and 1 and all add up to 1. Is this still possible with
Robert's method?

Thanks

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Re: [R] generate random numbers subject to constraints

2008-03-26 Thread Ala' Jaouni
X1,X2,X3,X4 should have independent distributions. They should be
between 0 and 1 and all add up to 1. Is this still possible with
Robert's method?

Thanks

On Wed, Mar 26, 2008 at 12:52 PM, Ted Harding
<[EMAIL PROTECTED]> wrote:
> On 26-Mar-08 20:13:50, Robert A LaBudde wrote:
>  > At 01:13 PM 3/26/2008, Ala' Jaouni wrote:
>  >>I am trying to generate a set of random numbers that fulfill
>  >>the following constraints:
>  >>
>  >>X1 + X2 + X3 + X4 = 1
>  >>
>  >>aX1 + bX2 + cX3 + dX4 = n
>  >>
>  >>where a, b, c, d, and n are known.
>  >>
>  >>Any function to do this?
>  >
>  > 1. Generate random variates for X1, X2, based upon whatever
>  > unspecified distribution you wish.
>  >
>  > 2. Solve the two equations for X3 and X4.
>
>  The trouble is that the original problem is not well
>  specified. Your suggestion, Robert, gives a solution
>  to one version of the problem -- enabling Ala' Jaouni
>  to say "I have generated 4 random numbers X1,X2,X3,X4
>  such that X1 and X2 have specified distributions,
>  and X1,X2,X3,X4 satisfy the two equations ... ".
>
>  However, suppose the real problem was: let X2,X2,X3,X4
>  have independent distributions F1,F2,F3,F4. Now sample
>  X1,X2,X3,X4 conditional on the two equations (i.e. from
>  the coditional density). That is a different problem.
>
>  As a slightly simpler example, suppose we have just X1,X2,X3
>  and they are independently uniform on (0,1). Now sample
>  from the conditional distribution, conditional on
>  X1 + X2 + X3 = 1.
>
>  The result is a random point uniformly distributed on the
>  planar triangle whose vertices are at (1,0,0),(0,1,0),(0,0,1).
>
>  Then none of X1,X2,X3 is uniformly distributed (in fact
>  the marginal density of each is 2*(1-x)).
>
>  However, your solution would work from either point of
>  view if the distributions were Normal.
>
>  If X1,X2,X3,X4 were neither Normally nor uniformly
>  distributed, then finding or simulating the conditional
>  distribution would in general be difficult.
>
>  Ala' Jaouni needs to tell us whether what he precisely
>  wants is as you stated the problem, Robert, or whether
>  he wants a conditional distribution for given distributions
>  if X1,X2,X3,X4, or whether he wants something else.
>
>  Best wishes to all,
>  Ted.
>
>  
>  E-Mail: (Ted Harding) <[EMAIL PROTECTED]>
>  Fax-to-email: +44 (0)870 094 0861
>  Date: 26-Mar-08   Time: 19:52:16
>  -- XFMail --
>

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Re: [R] generate random numbers subject to constraints

2008-03-26 Thread Ted Harding
On 26-Mar-08 20:13:50, Robert A LaBudde wrote:
> At 01:13 PM 3/26/2008, Ala' Jaouni wrote:
>>I am trying to generate a set of random numbers that fulfill
>>the following constraints:
>>
>>X1 + X2 + X3 + X4 = 1
>>
>>aX1 + bX2 + cX3 + dX4 = n
>>
>>where a, b, c, d, and n are known.
>>
>>Any function to do this?
> 
> 1. Generate random variates for X1, X2, based upon whatever 
> unspecified distribution you wish.
> 
> 2. Solve the two equations for X3 and X4.

The trouble is that the original problem is not well
specified. Your suggestion, Robert, gives a solution
to one version of the problem -- enabling Ala' Jaouni
to say "I have generated 4 random numbers X1,X2,X3,X4
such that X1 and X2 have specified distributions,
and X1,X2,X3,X4 satisfy the two equations ... ".

However, suppose the real problem was: let X2,X2,X3,X4
have independent distributions F1,F2,F3,F4. Now sample
X1,X2,X3,X4 conditional on the two equations (i.e. from
the coditional density). That is a different problem.

As a slightly simpler example, suppose we have just X1,X2,X3
and they are independently uniform on (0,1). Now sample
from the conditional distribution, conditional on
X1 + X2 + X3 = 1.

The result is a random point uniformly distributed on the
planar triangle whose vertices are at (1,0,0),(0,1,0),(0,0,1).

Then none of X1,X2,X3 is uniformly distributed (in fact
the marginal density of each is 2*(1-x)).

However, your solution would work from either point of
view if the distributions were Normal.

If X1,X2,X3,X4 were neither Normally nor uniformly
distributed, then finding or simulating the conditional
distribution would in general be difficult.

Ala' Jaouni needs to tell us whether what he precisely
wants is as you stated the problem, Robert, or whether
he wants a conditional distribution for given distributions
if X1,X2,X3,X4, or whether he wants something else.

Best wishes to all,
Ted.


E-Mail: (Ted Harding) <[EMAIL PROTECTED]>
Fax-to-email: +44 (0)870 094 0861
Date: 26-Mar-08   Time: 19:52:16
-- XFMail --

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Re: [R] generate random numbers subject to constraints

2008-03-26 Thread Paul Smith
On Wed, Mar 26, 2008 at 7:27 PM, Ala' Jaouni <[EMAIL PROTECTED]> wrote:
>  I failed to mention that the X values have to be positive and between 0 and 
> 1.

Use Robert's method, and to do his step 1, use runif (?runif) to get
random numbers from the uniform distribution between 0 and 1.

Paul

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Re: [R] generate random numbers subject to constraints

2008-03-26 Thread Giovanni Petris

You have 4 random variables that satisfy 2 linear constraints, so you
are trying to generate a point in a (4-2) = 2 dimensional linear
(affine, in fact) subspace of R^4. 

If you don't have any further requirement for the distribution of the
random points you want to generate, there are infinitely many ways of
doing it. 

It would be a good idea if you could explain in some more detail what
you want to do, so that we can give you relevant suggestions. 

Best,
Giovanni

> Date: Wed, 26 Mar 2008 11:28:28 -0700
> From: "Ala' Jaouni" <[EMAIL PROTECTED]>
> Sender: [EMAIL PROTECTED]
> Precedence: list
> 
> I am trying to generate a set of random numbers that fulfill the
> following constraints:
> 
> X1 + X2 + X3 + X4 = 1
> 
> aX1 + bX2 + cX3 + dX4 = n
> 
> where a, b, c, d, and n are known.
> 
> Any function to do this?
> 
> Thanks,
> -Ala'
> 
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> R-help@r-project.org mailing list
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> and provide commented, minimal, self-contained, reproducible code.
> 
> 

-- 

Giovanni Petris  
Department of Mathematical Sciences
University of Arkansas - Fayetteville, AR 72701
Ph: (479) 575-6324, 575-8630 (fax)
http://definetti.uark.edu/~gpetris/

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Re: [R] generate random numbers subject to constraints

2008-03-26 Thread Ala' Jaouni
Hi,
I failed to mention that the X values have to be positive and between 0 and 1.

e.g.

0.1812*X1 + 0.1871*X2 + 0.1847*X3 + 0.2745*X4 + 0.1304*X5 = 0.2

so one possible combination of X values can be:
0.319, 0.201, 0.084, 0.26, 0.136

another possible combination:
0.151, 0.253, 0.197, 0.256, 0.143

The numbers should be uniformly distributed.

I might have misused the word random but I only need a subset of all
possible solutions.

-Ala'

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Re: [R] generate random numbers subject to constraints

2008-03-26 Thread Robert A LaBudde
At 01:13 PM 3/26/2008, Ala' Jaouni wrote:
>I am trying to generate a set of random numbers that fulfill the following
>constraints:
>
>X1 + X2 + X3 + X4 = 1
>
>aX1 + bX2 + cX3 + dX4 = n
>
>where a, b, c, d, and n are known.
>
>Any function to do this?

1. Generate random variates for X1, X2, based upon whatever 
unspecified distribution you wish.

2. Solve the two equations for X3 and X4.


Robert A. LaBudde, PhD, PAS, Dpl. ACAFS  e-mail: [EMAIL PROTECTED]
Least Cost Formulations, Ltd.URL: http://lcfltd.com/
824 Timberlake Drive Tel: 757-467-0954
Virginia Beach, VA 23464-3239Fax: 757-467-2947

"Vere scire est per causas scire"

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