Re: [R] retrieve name of an object?
I am not sure what you mean by a hack? Can you elaborate further, give details on the problem you are trying to solve. Does this work as a lesser hack: tail(as.character(quote(mtcars$cyl)),1) [1] cyl tail(as.character(quote(cyl)),1) [1] cyl On Wed, Aug 4, 2010 at 7:47 AM, Liviu Andronic landronim...@gmail.com wrote: Dear all Is there an easier way to retrieve the name of an object? For example, tmp - 1:10 as.character(quote(tmp)) [1] tmp as.character(quote(mtcars$cyl)) [1] $ mtcars cyl as.character(quote(mtcars$cyl))[3] [1] cyl The last call more than anything seems a hack. Is there a better way? Thank you Liviu __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve? __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] retrieve name of an object?
Tryu this: deparse(substitute(mtcars)) On Wed, Aug 4, 2010 at 8:47 AM, Liviu Andronic landronim...@gmail.comwrote: Dear all Is there an easier way to retrieve the name of an object? For example, tmp - 1:10 as.character(quote(tmp)) [1] tmp as.character(quote(mtcars$cyl)) [1] $ mtcars cyl as.character(quote(mtcars$cyl))[3] [1] cyl The last call more than anything seems a hack. Is there a better way? Thank you Liviu __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] retrieve name of an object?
On 04/08/2010 7:47 AM, Liviu Andronic wrote: Dear all Is there an easier way to retrieve the name of an object? For example, tmp - 1:10 as.character(quote(tmp)) [1] tmp as.character(quote(mtcars$cyl)) [1] $ mtcars cyl as.character(quote(mtcars$cyl))[3] [1] cyl The last call more than anything seems a hack. Is there a better way? I don't understand what you want. cyl is not the name of an object; it's the name of a component of the mtcars object. If you know that, you can simply use names(mtcars) to get all the names, and names(mtcars)[2] to get cyl. Perhaps you thought the result of the expression mtcars$cyl was an object whose name was cyl? It's not. Unless you assign it to something, it's an anonymous object. As other have pointed out, in a function you can use substitute(arg) to retrieve the expression passed as arg, and deparse(substitute(arg)) to turn it into a string that's suitable for using as a label. But that's not the name of the object. The name of the object in that case is arg. Duncan Murdoch __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] retrieve name of an object?
Dear Duncan
On Wed, 04 Aug 2010 08:33:49 -0400
Duncan Murdoch murdoch.dun...@gmail.com wrote:
As other have pointed out, in a function you can use substitute(arg)
to retrieve the expression passed as arg, and
deparse(substitute(arg)) to turn it into a string that's suitable for
using as a label. But that's not the name of the object. The name
of the object in that case is arg.
Thank you for the explanation. I was indeed trying to retrieve the
expression passed as an argument in a function, to use it as a label.
Sofar the best I can manage is this:
my.fun - function(x) {
print(deparse(substitute(x)))
print(paste(substitute(x)[3]))
}
my.fun(mtcars$cyl)
[1] mtcars$cyl
[1] cyl
Thanks all for their suggestions
Liviu
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