Re: [R] synchronisation of time series data using interpolation
I saved the data sets as files and then tried to refer to those files. Therefore the instruction: z1-read.zoo(textConnection(/path/to/test1.txt) means that I wanted to replace the manual data entry for Lines1 with a file containing the data. It seems that your instructions only work when data is typed from the command terminal. I cannot use data stored in separated files. Command terminal output below: lines1-read.table(/path/to/test1.txt) lines2-read.table(/path/to/test2.txt) Warning message: incomplete final line found by readTableHeader on '/path/to/test2.txt' in: read.table(/path/to/test2.txt) This is test1 file: 01:00:00,500 01:00:15,600 01:00:30,750 01:00:45,720 01:01:00,700 01:01:15,725 01:01:30,640 01:01:45,710 This is test2 file: 01:00:12,20 01:01:01,55 01:01:55,22 Then I added a carriage return in test2 file and saved it: 01:00:12,20 01:01:01,55 01:01:55,22 Then I repeated the command terminal entry for lines2: lines2-read.table(/path/to/test2.txt) library(zoo) library(chron) z1-read.zoo(textConnection(lines1),header=FALSE,sep=,,FUN=times) Error in textConnection(lines1) : invalid 'text' argument __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] synchronisation of time series data using interpolation
You should be using read.zoo, not read.table. This read.zoo(textConnection(Lines1), ...) becomes read.zoo(test1.txt, ...) etc. See ?read.zoo and read the three vignettes in the zoo package. On Mon, Sep 28, 2009 at 8:13 AM, e-letter inp...@gmail.com wrote: I saved the data sets as files and then tried to refer to those files. Therefore the instruction: z1-read.zoo(textConnection(/path/to/test1.txt) means that I wanted to replace the manual data entry for Lines1 with a file containing the data. It seems that your instructions only work when data is typed from the command terminal. I cannot use data stored in separated files. Command terminal output below: lines1-read.table(/path/to/test1.txt) lines2-read.table(/path/to/test2.txt) Warning message: incomplete final line found by readTableHeader on '/path/to/test2.txt' in: read.table(/path/to/test2.txt) This is test1 file: 01:00:00,500 01:00:15,600 01:00:30,750 01:00:45,720 01:01:00,700 01:01:15,725 01:01:30,640 01:01:45,710 This is test2 file: 01:00:12,20 01:01:01,55 01:01:55,22 Then I added a carriage return in test2 file and saved it: 01:00:12,20 01:01:01,55 01:01:55,22 Then I repeated the command terminal entry for lines2: lines2-read.table(/path/to/test2.txt) library(zoo) library(chron) z1-read.zoo(textConnection(lines1),header=FALSE,sep=,,FUN=times) Error in textConnection(lines1) : invalid 'text' argument __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] synchronisation of time series data using interpolation
I created separate text files for the 2 data sets. I enter the following comands: library(zoo) library(chron) z1-read.zoo(textConnection(/path/to/test1.txt),header=FALSE,sep=,,FUN=times) z2-read.zoo(textConnection(/path/to/test2.txt),header=FALSE,sep=,,FUN=times) z3-window(na.approx(merge(z1,z2)),time(z1)) plot(z3$z1,z3$z2) Error in plot.window(xlim, ylim, log, asp, ...) : need finite 'xlim' values In addition: Warning messages: 1: no non-missing arguments to min; returning Inf in: min(x) 2: no non-missing arguments to max; returning -Inf in: max(x) 3: no non-missing arguments to min; returning Inf in: min(x) 4: no non-missing arguments to max; returning -Inf in: max(x) The resultant graph window was blank, so I entered the following command plot(z3$z1,z3$z2,xlim=c(0,100),ylim=c(0,100)) The graph window showed y axis (labelled 'z3$z1') and x axis (labelled 'Index'). I do not understand the instruction ...to use window to pick off... __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] synchronisation of time series data using interpolation
Your files do not have data appropriate to your commands. Since you did not provide the data (see last line of every message to r-help) there is not much more that can be said. On Sat, Sep 26, 2009 at 4:24 AM, e-letter inp...@gmail.com wrote: I created separate text files for the 2 data sets. I enter the following comands: library(zoo) library(chron) z1-read.zoo(textConnection(/path/to/test1.txt),header=FALSE,sep=,,FUN=times) z2-read.zoo(textConnection(/path/to/test2.txt),header=FALSE,sep=,,FUN=times) z3-window(na.approx(merge(z1,z2)),time(z1)) plot(z3$z1,z3$z2) Error in plot.window(xlim, ylim, log, asp, ...) : need finite 'xlim' values In addition: Warning messages: 1: no non-missing arguments to min; returning Inf in: min(x) 2: no non-missing arguments to max; returning -Inf in: max(x) 3: no non-missing arguments to min; returning Inf in: min(x) 4: no non-missing arguments to max; returning -Inf in: max(x) The resultant graph window was blank, so I entered the following command plot(z3$z1,z3$z2,xlim=c(0,100),ylim=c(0,100)) The graph window showed y axis (labelled 'z3$z1') and x axis (labelled 'Index'). I do not understand the instruction ...to use window to pick off... __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] synchronisation of time series data using interpolation
Test1 file contained data set 1, test2 contained data set 2 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] synchronisation of time series data using interpolation
On Sat, Sep 26, 2009 at 9:08 AM, e-letter inp...@gmail.com wrote: Test1 file contained data set 1, test2 contained data set 2 Its not clear to me what you are referring to. The data in your initial post do not exhibit this problem and there is no data in any of your subsequent posts in this thread. Here is what happens when I run it with your data -- no errors: Lines1 - time,datum + 01:00:00,500 + 01:00:15,600 + 01:00:30,750 + 01:00:45,720 + 01:01:00,700 + 01:01:15,725 + 01:01:30,640 + 01:01:45,710 Lines2 - time,datum + 01:00:12,20 + 01:01:01,55 + 01:01:55,22 library(zoo) library(chron) z1 - read.zoo(textConnection(Lines1), header = TRUE, sep = ,, FUN = times) z2 - read.zoo(textConnection(Lines2), header = TRUE, sep = ,, FUN = times) z3 - window(na.approx(merge(z1, z2)), time(z1)) plot(z3$z1, z3$z2) __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] synchronisation of time series data using interpolation
Create the series as zoo series from the data, and then merge them and fill in NAs with interpolated values using na.approx. Finally use window to pick off the times that were in z1 and plot. See the three vignettes that come with zoo and for time and dates see the article in R News 4/1 and its references. Lines1 - time,datum 01:00:00,500 01:00:15,600 01:00:30,750 01:00:45,720 01:01:00,700 01:01:15,725 01:01:30,640 01:01:45,710 Lines2 - time,datum 01:00:12,20 01:01:01,55 01:01:55,22 library(zoo) library(chron) z1 - read.zoo(textConnection(Lines1), header = TRUE, sep = ,, FUN = times) z2 - read.zoo(textConnection(Lines2), header = TRUE, sep = ,, FUN = times) z3 - window(na.approx(merge(z1, z2)), time(z1)) plot(z3$z1, z3$z2) On Fri, Sep 25, 2009 at 1:41 AM, e-letter inp...@gmail.com wrote: Readers, I have data with different time stamps that I wish to plot (for example): data set 1 time(hh:mm:ss),datum 01:00:00,500 01:00:15,600 01:00:30,750 01:00:45,720 01:01:00,700 01:01:15,725 01:01:30,640 01:01:45,710 data set 2 time,datum 01:00:12,20 01:01:01,55 01:01:55,22 The time interval in data set 1 does not change, but the time interval in data set 2 does change, such that for a specific total time range (e.g. 60 minutes) there will be more data in data set 1 than in data set 2. I thought I could solve this problem using interpolation, to create a new data set using data from data set 2, interpolated to the time stamps in data set 1: data set 3 time,datum 01:00:00,18 01:00:15,23 01:00:30,30 01:00:45,41 01:01:00,53 01:01:15,46 01:01:30,38 01:01:45,29 Therefore I would then be able to plot the data in data set 1 against the interpolated data in data set 3, because there would be equal quantities of data in both data sets. I've looked at the interp function in the help manual, but I don't understand if this function can perform the task I want. Any advice please? Yours, rhelp at conference.jabber.org r 251 (27-06-07) mandriva 2008 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
