[R] RDCOMServer

2003-06-02 Thread Chunlou Yung
Hi there,

I downloaded RDCOMServer and the related packages from Omegahat. Tried their
R.Evaluator example. But failed to invoke any method from the client side.
When I looked at R.Evaluator from OLE View (some Microsoft development tool
for browsing all the OLEs), I got the following error message from
R.Evaluator:

CoGetClassObject failed
Class not registered
REGDB_E_CLASSNOTREG ($80040154)

RDCOMServer's isRegistered method said R.Evaluator was registered. So,
what's wrong?

Thanks.

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Re: [R] parse on left hand side of R assignment

2003-06-02 Thread Thomas Lumley
On Sat, 31 May 2003, Paul E. Johnson wrote:

 I keep finding myself in a situation where I want to calculate a
 variable name and then use it on the left hand side of an assignment.
 For example

 iteration - 1
 varName - paste(run,iteration,sep=)
 myList$parse(text=varName) - aColumn


In this particular case you can just use

myList[[varName]]-aColumn.

I don't think you can (easily) use assign, despite the suggestion -- it
doesn't dispatch assignment methods.

If you wanted to do something of this sort for which the above didn't work
you could also learn about substitute()
  eval(substitute(myList$newColumn-aColumn),
 list(newColumn=as.name(varName)))
as an alternative to parse().

-thomas

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[R] Help with Temporal series

2003-06-02 Thread Bernardo Rangel Tura


Good afternoon R-masters,  
  
I am with some doubts in the R, see the script below:

m-c(69.6,67.3,75.6,74.3,64.7,60,65.7,62.5,66.5)
d-c(11.6,15,17.8,18.3,11.2,11,4.6,5.8,7)
year-c(1994,1995,1996,1997,1998,1999,2000,2001,2002)
male-ts(m,start=c(1994))
death-ts(d,start=c(1994))
data-data.frame(year,death,male)
require(ts)
d100-HoltWinters(data$death,gamma=0)
m100-HoltWinters(data$male,gamma=0)
par(mfrow=c(3,1))
plot(d100,main=Death)
plot(m100,main=Male)
ccf(male,death)


I have 2 doubts:

1 - How to I should interpret the third graph?
2 - Has a hypothesis test to evaluate the cross-correlation it is significant in R?
Thanks in advance

Bernardo Rangel Tura, MD, MSc
National Institute of Cardiology Laranjeiras
Rio de Janeiro Brazil

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[R] persp colors

2003-06-02 Thread Timur Elzhov
Dear R experts!

I use image()  persp() functions for color plotting z(x,y)-type
graphics.  In image() colors correspond to z-values, that's what
I want.   OTOH, in persp() the col option means:

 col: the color(s) of the surface facets.  Transparent colours are
  ignored.  This is recycled to the (nx-1)(ny-1) facets.

but I'd like to persp()' colors behave like in image() function!

Could you help me to solve this problem?
Thank you very much.


--
WBR,
Timur.

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Re: [R] persp colors

2003-06-02 Thread Uwe Ligges
Timur Elzhov wrote:
Dear R experts!

I use image()  persp() functions for color plotting z(x,y)-type
graphics.  In image() colors correspond to z-values, that's what
I want.   OTOH, in persp() the col option means:
 col: the color(s) of the surface facets.  Transparent colours are
  ignored.  This is recycled to the (nx-1)(ny-1) facets.
but I'd like to persp()' colors behave like in image() function!

Could you help me to solve this problem?
Thank you very much.
--
WBR,
Timur.
That's not easy, because you have to redefine x, y and z values.

Simple example:

 x - y - 1:2
 z - matrix(1:4, 2)
 image(x, y, z)# OK, quite nice
but

 persp(x, y, z)

has only one facet. So the only way is to calculate the 9 values for x, 
y, and z to get the corners for the 4 facets in it.
That's easy for x and y, but can be impossible for z...

Uwe Ligges

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Re: [R] persp colors

2003-06-02 Thread Timur Elzhov
On Sun, Jun 01, 2003 at 06:53:55PM +0200, Uwe Ligges wrote:

 but I'd like to persp()' colors behave like in image() function!

 That's not easy, because you have to redefine x, y and z values.
 
 Simple example:
 
  x - y - 1:2
  z - matrix(1:4, 2)
  image(x, y, z)# OK, quite nice
 
 but
 
  persp(x, y, z)
 
 has only one facet. So the only way is to calculate the 9 values for x, 
 y, and z to get the corners for the 4 facets in it.
 That's easy for x and y, but can be impossible for z...

OK, thank you for answer!
But, I saw that other mathematic frameworks (CERN ROOT for instance)
can plot 3D surfaces with colors corresponding to z-value.
Is there way to do this in R (with another functions/packages)?
It's not necessary to use _one_ color per facet, yes?.. :)


--
WBR,
Timur.

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Re: [R] compositional data: percent values sum up to 1

2003-06-02 Thread Spencer Graves
What are you trying to do?  What I would do with this depends on many 
factors.

spencer graves

Christoph Lehmann wrote:
again, under another subject:
sorry, maybe an all too trivial question. But we have power data from J
frequency spectra and to have the same range for the data of all our
subjects, we just transformed them into % values, pseudo-code:
power[i,j]=power[i,j]/sum(power[i,1:J])

of course, now we have a perfect linear relationship in our x design-matrix,
since all power-values for each subject sum up to 1.
How shall we solve this problem: just eliminate one column of x, or
introduce a restriction which says exactly that our power data sum up to
1 for each subject?
Thanks a lot

Christoph
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[R] integrate

2003-06-02 Thread Rafael A. Irizarry
Im tryng to understand an error i get with integrate. this is 1.7.0 on
solaris 2.8.

##i am trying to approximate an integral of this function,
f-function(b) exp(-(b-mu)^2/(2*tau2))/(p-exp(b))*10^6

##with 
tau2 - .005;mu - 7.96;p - 2000
##from -inf to different upper limits. using
integrate(f,-Inf,log(p-exp(1)))
##i get the following error:
##Error in integrate(f, -Inf, log(p - exp(1))) : 
##  the integral is probably divergent

##whats confusing is that i only get this error when i use upper limit 
##in the range [log(p-2),log(p-1)]
##try this:
x - seq(1,10,.1)
y - sapply(x,function(i){
  x - try(integrate(f,-Inf,log(p-i)),silent=TRUE)
  if(class(x)==try-error) return(NA) else return(x$val)
})
x[is.na(y)]

##if i use stop=FALSE, the curve is interpolated nicely
plot(x,y)
y - sapply(x,function(i)
  x - integrate(f,-Inf,log(p-i),stop=FALSE)$val
)
lines(x,y)

##there doesnt appear to be anything strange about the function in 
##the 2-3 region.
x - seq(1,5,.1)
xx - log(p-x)
plot(x,f(xx))
abline(v=c(2,3))

##any ideas on why this is happening? 

##ps - same thing happens with:
##f - function(b) exp(-(b-mu)^2/(2*tau2) - log(p-exp(b)))*10^6
##it doesnt with
##f-function(b) exp(-(b-mu)^2/(2*tau2))/(p-exp(b))

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[R] Simulating a variable following an arbitrary distribution

2003-06-02 Thread Fernando Henrique Ferraz Pereira da Rosa
 Hi, I'd like to know if there's anything in R that could help me do
that. Let's suppose I have a density function of a random variable, for example
f(x) = (x^3)/4 0  x  2 and I would like to simulate it. For the common
distributions (exponencial, gamma, cauchy) there are the r-functions (rgamma,
rexp, runif, rcauchy, and so on).. But when the variable I want to simulate is
not one of those, how should I procede? I read some references on the subject
and saw that there are some algorithms that can do that, but I just wonder if
there is any implemented in R?

Thank you,

--

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Re: [R] Simulating a variable following an arbitrary distribution

2003-06-02 Thread Edgar Acuna
Hi,
Use the Inverse transformation method. See any basic Cbook in simulation
for instance Sheldon Ross's book.
Regards,
Edgar

On Mon, 2 Jun 2003, Fernando Henrique Ferraz Pereira da Rosa wrote:

  Hi, I'd like to know if there's anything in R that could help me do
 that. Let's suppose I have a density function of a random variable, for example
 f(x) = (x^3)/4 0  x  2 and I would like to simulate it. For the common
 distributions (exponencial, gamma, cauchy) there are the r-functions (rgamma,
 rexp, runif, rcauchy, and so on).. But when the variable I want to simulate is
 not one of those, how should I procede? I read some references on the subject
 and saw that there are some algorithms that can do that, but I just wonder if
 there is any implemented in R?

 Thank you,

 --

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Re: [R] Simulating a variable following an arbitrary distribution

2003-06-02 Thread Spencer Graves
	  Your specific example is a scaled beta.  Therefore, 2*rbeta(1000, 4, 
1) will generate 1000 random numbers according to that distribution. 
You can get the same distribution from 2*qbeta(runif(1000), 4, 1).
	  We can generalize this last example to any case of interest.  Example:

df4 - function(x)(x^3)/4
pf4 - function(q)(q^4)/16
qf4 - function(p)(16*p)^0.25
rf4 - function(n)qf4(runif(n))
Then rf4(1000) will produce 1000 pseudo-random deviates following this 
distribution.

hth.  spencer graves

Edgar Acuna wrote:
Hi,
Use the Inverse transformation method. See any basic Cbook in simulation
for instance Sheldon Ross's book.
Regards,
Edgar
On Mon, 2 Jun 2003, Fernando Henrique Ferraz Pereira da Rosa wrote:


Hi, I'd like to know if there's anything in R that could help me do
that. Let's suppose I have a density function of a random variable, for example
f(x) = (x^3)/4 0  x  2 and I would like to simulate it. For the common
distributions (exponencial, gamma, cauchy) there are the r-functions (rgamma,
rexp, runif, rcauchy, and so on).. But when the variable I want to simulate is
not one of those, how should I procede? I read some references on the subject
and saw that there are some algorithms that can do that, but I just wonder if
there is any implemented in R?
Thank you,

--

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[R] Re: Re: Submited (004756-3463) #DF/010989#

2003-06-02 Thread support
This is an automated response.  SkillSoft Support has
received your message and this issue has been assigned
ticket number :  DF/010989

Please ensure that  #DF/010989#  appears in the subject
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[R] extending subsets over another variable..

2003-06-02 Thread John Christie
Hi,
	I've been trying to learn and use R for data analysis, and so far it 
has be OK.  It is very slow with the aov command.  But, other than that 
things are generally OK.	Anyway, todays problem is one that I have 
looked in quite a few places to try to solve but to know avail.  I hope 
the list can help.
	I have my data organized in the appropriate way (i.e. a data point on 
each row and columns for each variable).  I want to divide my subjects 
up by a median.  However, I don't want the overall subject median but a 
subset, and then to split the entire subjects data on that subset.  I 
don't see a way to do that at all.  Any help would be appreciated.

to make things clearer, here is an example of how to split subject by 
median

ss-split(s, ave(s$x, s$subj)  median(ave(s$x,s$subj)))

what I need to do is split by subject when s is further split by a sub 
factor.

TIA
John Christie
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[R] want to write a package for R

2003-06-02 Thread
 hello,everyone!
 I have studied in univ. for two years.and my teacher have put out 
some stat. model .and i want to write it to a R package, and take 
it to my future paper.any advise? i learned something about SAS/stat.
and i have read the tutorial of R.
 now i can interactive with R,and
write R file.but i didn't have a contour of how to write a package.
R extension said package is consisted of DESCRIPTION,INDEX,subdirectories
,bundles.should i write all the file?
 thank you.

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Re: [R] compositional data: percent values sum up to 1

2003-06-02 Thread Christoph Lehmann
I want to do a logistic regression analysis, and to compare with, a
discriminant analysis. The mentioned power maps are my exogenous data,
the dependent variable (not mentioned so far) is a diagnosis
(ill/healthy)

thanks for the interest and the help

Christoph

On Sun, 2003-06-01 at 21:01, Spencer Graves wrote:
 What are you trying to do?  What I would do with this depends on many 
 factors.
 
 spencer graves
 
 Christoph Lehmann wrote:
  again, under another subject:
  sorry, maybe an all too trivial question. But we have power data from J
  frequency spectra and to have the same range for the data of all our
  subjects, we just transformed them into % values, pseudo-code:
  
  power[i,j]=power[i,j]/sum(power[i,1:J])
  
  of course, now we have a perfect linear relationship in our x design-matrix,
  since all power-values for each subject sum up to 1.
  
  How shall we solve this problem: just eliminate one column of x, or
  introduce a restriction which says exactly that our power data sum up to
  1 for each subject?
  
  Thanks a lot
  
  Christoph
 
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-- 
Christoph Lehmann [EMAIL PROTECTED]

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Re: [R] want to write a package for R

2003-06-02 Thread Ott Toomet
Hello,

You should start creating a separate directory for your package
(e.g. foo).  As a minimum you need three things:

1) your R functions (as .R files in directory foo/R)

2) documentation of your functions in .Rd format (look writing R
   extensions and function prompt(), they must reside in foo/man directory)

3) The DESCRIPTION file (in the foo directory).  Everything else is
   made by R.

Now run R CMD build foo in the directory above (where the subdir foo
is lying).

It was pretty easy to do on linux, with windows you probably need
necessary tools as perl.  Otherwise, it should be similar.

Bundles are just collections of different packages, probably not for
you right now.

Perhaps it helps.

Ott

 | Date: Sun, 1 Jun 2003 16:02:13 +0800 (CST)
 | From: Ìì²Å [EMAIL PROTECTED]

 |  hello,everyone!
 |  I have studied in univ. for two years.and my teacher have put out 
 | some stat. model .and i want to write it to a R package, and take 
 | it to my future paper.any advise? i learned something about SAS/stat.
 | and i have read the tutorial of R.
 |  now i can interactive with R,and
 | write R file.but i didn't have a contour of how to write a package.
 | R extension said package is consisted of DESCRIPTION,INDEX,subdirectories
 | ,bundles.should i write all the file?
 |  thank you.

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[R] Help - Curvature measures of nonlinearity

2003-06-02 Thread Ivone Figueiredo
Dear colleagues,

Von Bertalanffy model is commonly adjust to data on fish length (TL) and age (AGE) 
TL= Linf*(1-exp(-K*(AGE-t0)). Linf, K and t0 are parameters of the model.
One main goal of the growth study is the comparison of growth parameter estimates 
between sexes of the same species, or estimates from different populations. 
The realibility statistical tests normally applied are highly dependent on the 
nonlinearity of the model used.

Are there any developed routines in R ? to:
1) calculate the maximum intrinsic curvature
2) maximum parameter affecting curvature 
3) plot the two dimensional cross sections of confidence regions (for different alpha 
values) of the model parameters

Regards,
Ivone Figueiredo 
[[alternate HTML version deleted]]

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[R] Rounding problem R vs Excel

2003-06-02 Thread Mike White
For numbers ending in 5 Excel always rounds up and I want to reproduce this in R 
rather than use the round function.
I have tried:

x-as.integer(x*100+0.5)/100

and

x-floor(x*100+0.5)/100

However, some values of x cause problems e.g

x-floor(4.145*100+0.5)/100
4.14

I have tried breaking it down into steps and force the results to 10 significant 
figures in the following function, which seems to work

roundoff-function(x){
a-signif(x*100+0.5,digits=10)
roundoff-floor(a)/100
roundoff
}

Is there a more sensible way of do this for all numbers?

Thanks
Mike

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Re: [R] want to write a package for R

2003-06-02 Thread Uwe Ligges
 wrote:


Hello ??,


  hello,everyone!
  I have studied in univ. for two years.and my teacher have put out 
 some stat. model .and i want to write it to a R package, and take 
 it to my future paper.any advise? i learned something about SAS/stat.

SAS/stat, hmmm, not very interesting given you are going to write an *R*
package.


 and i have read the tutorial of R.
  now i can interactive with R,and
 write R file.but i didn't have a contour of how to write a package.
 R extension said package is consisted of DESCRIPTION,INDEX,subdirectories
 ,bundles.should i write all the file?

Great, you already found the Writing R Extensions manual. Indeed, just
do what's descibed in there.

Uwe Ligges

PS: Please configure you mailtool to send plain text messages.

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[R] authorized characters and symbols

2003-06-02 Thread vincent . stoliaroff
Hi R lovers

Obviously I cannot use the underscore _  character to name an object in R
Is there a special reason for that ?

I want to use it to rename a function
maybe the problem is due to the nature of the object I work on

thanks for any comments on that very little and not very bothering trouble





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Re: [R] authorized characters and symbols

2003-06-02 Thread Prof Brian Ripley
On Mon, 2 Jun 2003 [EMAIL PROTECTED] wrote:

 Obviously I cannot use the underscore _  character to name an object 
 in R

Actually, you can but it is more trouble than it is worth as you will 
always have to quote the name, and often explicitly get it:

 my_pi - pi
 get(my_pi)
[1] 3.141593

 Is there a special reason for that ?

Yes, it is allowed for assignment, but not for much longer.  Once
it is removed for assignment (1.8.0) it will be allowed as part of a name
after a decent interval.

 I want to use it to rename a function
 maybe the problem is due to the nature of the object I work on
 
 thanks for any comments on that very little and not very bothering trouble

-- 
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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[R] (no subject)

2003-06-02 Thread Alicia Lopez
I would be gratefulf if anybody can help me with this problem.  I have not
a experience with R 
language, actually this is my first job with it :

I have write some instructions for acomplish a simulation, and I have 36
conditions 
with 1000 iterations each one . The program runs without problems, but in
the 19 nth 
condition  gives and  error message (after running   some iterations of
this condition)   
is:

Error in var(x, na.rm = na.rm) : missing observations in cov/cor

Somebody would give me any clue about the origin of this error?
There is any probability  that the origin of the problem is  the scarcitie
of resources?
(  I don´t understand how is possible a programming error).

Any help will be welcome.




---
ALICIA LÓPEZ JÁUREGUI
 

   DEPARTAMENTO DE PSICOLOGIA SOCIAL Y METODOLOGIA
   FACULTAD DE PSICOLOGIA 
   Avda. de Tolosa, 70
   20018 DONOSTIA (SPAIN)

 TEL.: 943 / 018340   
 E-MAIL: [EMAIL PROTECTED]

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[R] Re: R-help Digest, Vol 3,Issue 29: RE: Ordinal Data - regression trees prop. odds

2003-06-02 Thread Andreas Christmann
   1. RE: Ordinal data - Regression Trees   Proportional Odds
  (Liaw, Andy)


AFAIK there's no implementation (or description) of tree algorithm that
handles ordinal response.  
Regression trees with an ordinal response variable can be computed with 
SPSS Answer Tree 3.0.

Andreas Christmann
-
Andreas Christmann
University of Dortmund
Department of Statistics
44221 Dortmund
Germany
-
Phone: +231 / 755 3180
Email: [EMAIL PROTECTED]
WWW: 
http://www.statistik.uni-dortmund.de/de/content/einrichtungen/lehrstuehle/datenanalyse.html

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[R] RE: Ordinal data - Regression Trees Proportional Odds

2003-06-02 Thread Andreas Christmann
 1. RE: Ordinal data - Regression Trees   Proportional Odds
  (Liaw, Andy)
 AFAIK there's no implementation (or description) of tree algorithm
 that handles ordinal response.

Regression trees with an ordinal response variable can be computed with 
SPSS Answer Tree 3.0.

Andreas Christmann
--
-
Andreas Christmann
University of Dortmund
Department of Statistics
44221 Dortmund
Germany
-
Phone: +231 / 755 3180
Email: [EMAIL PROTECTED]
WWW: 
http://www.statistik.uni-dortmund.de/de/content/einrichtungen/lehrstuehle/datenanalyse.html

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[R] Virus Warning

2003-06-02 Thread administrator

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[R] Virus Warning

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[R] Undeliverable: Re: Submited (004756-3463)

2003-06-02 Thread System Administrator
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2003-06-02 Thread Mail Delivery System
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