[R] select row

2007-07-03 Thread Leonardo Lami
Hi all,
I have a little problem selecting some rows from a data.frame.
I'd like to select the rows where a determinated column take a
partivolar value.

For example:
tab
  id   x   y
124-2005 1621814 4834991
224-2005 1621856 4834907
324-2005 1621763 4834956
4   25-2006 1622330 4835189
5   25-2006 1622533 4834834
6   25-2006 1622535 4834909
7   25-2006 1622543 4834803
8   28-2005 1622798 4835043
9   28-2005 1622299 4835129

I'd like to select the row where id=25-2006

I searched on the search of the R site but I did'nt find anything of simple.
Can someone help me?

Thank you very much
Leonardo

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Re: [R] select row

2007-07-03 Thread Leonardo Lami
Thanks all of you for the help!
   
 Hi all,
 I have a little problem selecting some rows from a
 data.frame.
 I'd like to select the rows where a determinated
 column take a
 partivolar value.

 For example:
 tab
   id   x   y
 124-2005 1621814 4834991
 224-2005 1621856 4834907
 324-2005 1621763 4834956
 4   25-2006 1622330 4835189
 5   25-2006 1622533 4834834
 6   25-2006 1622535 4834909
 7   25-2006 1622543 4834803
 8   28-2005 1622798 4835043
 9   28-2005 1622299 4835129

 I'd like to select the row where id=25-2006

 I searched on the search of the R site but I did'nt
 find anything of simple.
 Can someone help me?

 Thank you very much
 Leonardo

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[R] gpclib problem

2007-06-15 Thread Leonardo Lami
Hi all,
I am trying to test the new adehabitat package but I have a problem with
a linked library, gpclib.

When I try do install it I have this output:

install.packages(gpclib, dependencies=TRUE,
repos=http://cran.cnr.berkeley.edu/;)
Avviso in install.packages(gpclib, dependencies = TRUE, repos =
http://cran.cnr.berkeley.edu/;) :
argument 'lib' is missing: using /usr/local/lib/R/site-library
dependency ''gpclib'' is not available

I have the same problem in other repository.


Leonardo

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Re: [R] gpclib library

2007-04-05 Thread Leonardo Lami

Hi
my OS is Linux Debian distribution, my R vers is 2.4.0 Patched
(2006-11-25 r39997)

I tried several repositories but the output is ever the same

Thank yor for your help

All the best
Leonardo


Prof Brian Ripley ha scritto:
 It's a _package_ that you are looking for (there is something else
 called a gpclib library, to do with GNU Pascal).

 You haven't told us your OS or R version, so we don't know what file
 you are looking for.  But try another mirror if one appears not to
 work (and using a US mirror with an email address in Italy seems odd).
 On Wed, 4 Apr 2007, Leonardo Lami wrote:

 Hi all,
 I'm tring to download the gpclib library but I don't find it in the old
 repository

 install.packages(c(gpclib), dependencies=TRUE,
 repos=http://cran.cnr.berkeley.edu/;)
 Avviso in install.packages(c(gpclib), dependencies = TRUE, repos =
 http://cran.cnr.berkeley.edu/;) :
 argument 'lib' is missing: using /usr/local/lib/R/site-library

 That's not what that message says: presumably you got some more output.



 May be my old library have some problem:

 library(gpclib)
 Errore in loadNamespace(package, c(which.lib.loc, lib.loc), keep.source
 = keep.source) :
in 'gpclib', metodi da esportare specificati, ma nessuno
 definito: show, get.bbox, plot, intersect, union, setdiff, [,
 append.poly, scale.poly, area.poly, get.pts, coerce
 Errore: caricamento pacchetto/namespace fallito per 'gpclib'

 Someone knows where I can find the library

 Thank you
 Leonardo

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[R] selection of character

2007-04-04 Thread Leonardo Lami
Hi all,

I have a simple question:
I have a character vector like this

 [1] 10_1 1_1  11_1 2_1  3_1  4_1  5_1  6_1  7_1  8_1
[11] 9_1  1_3  2_3  3_3  4_3  1_4  2_4  3_4  4_4  5_4
[21] 6_4  7_4  1_5  2_5  10_6 11_6 12_6 1_6  2_6  3_6
[31] 4_6  5_6  6_6  7_6  8_6  9_6  1_7  1_8  2_8  3_8
[41] 10_9 1_9  2_9  3_9  4_9  5_9  6_9  7_9  8_9  9_9
[43]  1_10 2_10

and I'd like to have a vector with only the value after the under scor,
like this:

 [1] 1 1  1 1  1  1  1  1  1  1
[11] 1  3  3  3  3  4  4  4  4  4
[21] 4  4  5  5  6 6 6 6  6  6
[31] 6  6  6  6  6  6  7  8  8  8
[41] 9 9  9  9  9  9  9  9  9  9
[43]  10 10

Is there a simple function to do this?

Thank you for your help
All the best

Leonardo

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[R] gpclib library

2007-04-04 Thread Leonardo Lami
Hi all,
I'm tring to download the gpclib library but I don't find it in the old
repository

install.packages(c(gpclib), dependencies=TRUE,
repos=http://cran.cnr.berkeley.edu/;)
Avviso in install.packages(c(gpclib), dependencies = TRUE, repos =
http://cran.cnr.berkeley.edu/;) :
 argument 'lib' is missing: using /usr/local/lib/R/site-library


May be my old library have some problem:

library(gpclib)
Errore in loadNamespace(package, c(which.lib.loc, lib.loc), keep.source
= keep.source) :
in 'gpclib', metodi da esportare specificati, ma nessuno
definito: show, get.bbox, plot, intersect, union, setdiff, [,
append.poly, scale.poly, area.poly, get.pts, coerce
Errore: caricamento pacchetto/namespace fallito per 'gpclib'

Someone knows where I can find the library

Thank you
Leonardo

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[R] data.frame to shape

2006-08-09 Thread Leonardo Lami
Hi all,
I have a simple question:
I have a data.frame like this:

   id   x   y
1  50 1647685 4815259
2  50 1647546 4815196
3  50 1647454 4815294
4  50 1647405 4815347
5  50 1647292 4815552
6 50 1647737 4815410
7 74 1647555 4815201
8 74 1647464 4815023
9 74 1646970 4815129
10 74 1646895 4815264
11 74 1646762 4815513

and I'd like to trasform it with the convert.to.shapefile function 
(shapefiles package) but to make this I must have a data.frame like this:

   id   x   y
1  50 1647685 4815259
2  50 1647546 4815196
3  50 1647454 4815294
4  50 1647405 4815347
5  50 1647292 4815552
6  50 1647737 4815410
7  50 1647685 4815259
8  74 1647555 4815201
9  74 1647464 4815023
10 74 1646970 4815129
11 74 1646895 4815264
12 74 1646762 4815513
13 74 1646762 4815513

with the first point of every id repeated to close the polygon.
There is a function to make this indipendently by the number of the id

Best regards
Leonardo

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email + jabber: [EMAIL PROTECTED]
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Re: [R] Fisher's discriminant functions

2005-10-05 Thread Leonardo Lami
Hi,
I have the same problem.
I found a solution but I think there is something of more simple and correct.

I take a group and I put 0 the values of the other group, after I use the 
function glm to abtain the  Fisher's discriminant function for this group.
I repeat the same for all the groups.

Some times ago i try to make the same query but without results.

Best wishes
Leonardo

Alle 22:22, giovedì 29 settembre 2005, Kjetil Holuerson ha scritto:
 This are in various packages, you could have a look at
 ade4 (on CRAN).

 Kjetil

 C NL wrote:
  Hi everyone,
 
I'm trying to solve a problem about how to get the
  Fisher's discriminant functions of a lda (linear
  discriminant analysis) object, I mean, the object
  obtained from doing lda(formula, data) function of
  the package MASS in R-project. This object gives me
  the canonical linear functions (n-1 coefficients
  matrix of n groups at least), and only with this
  information I could predict the group of an
  observation data using the predict function. But
  what I need is the Fisher's discriminant functions (n
  coefficients matrix of n groups) in order to classify
  my future data.
 
 The object predict gives me only the following
  attributes x, posterior and class, but none of
  them are the coefficients matrix of the Fisher's
  discriminant functions, and the reason why I'm not
  using the predict function for my predictions is
  because the time spent is very high for what I'm
  expecting, about 0.5 seconds while I can obtain this
  prediction with the Fisher's discriminant functions
  faster.
 
 So, I don't know if there's a package which I can
  use to obtain the mentioned coefficients matrix of the
  Fisher's discriminant functions.
 
 I anyone can help, I would appreciate it greatly.
 
  Thank you and regards.
 
 Carlos Niharra López
 
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[R] lda discriminant functions

2005-08-05 Thread Leonardo Lami
Hi list,
I'm looking about lda function.
I'd like to know how calcolate the value of the discriminant functions for the 
original datas.
I see that in the result object lda there is $scaling a matrix which 
transforms observations to discriminant functions, normalized so that within 
groups covariance matrix is spherical.

I'd like to have the value of the discriminant function not normalized.

Best regards
Leonardo

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[R] lda function

2005-08-03 Thread Leonardo Lami
Hello,
I'm tring to make a linear discriminant analysis eith lda (MASS).
In the value of the resulting object is there information about the value of 
the centroids of the discriminated group for the discriminant functions?

Thank you in advance for your help!
Leonardo
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[R] predictive classification groups functions

2005-07-29 Thread Leonardo Lami
Hi all,
I have a little question about linear discriminant analysis in R.
I have a dataframe with datas groupped by 4 cluster.
I'd like to know if there is a command that give 4 predictive classification 
groups functions (one for every cluster group).

Thanks of all
Leonardo

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[R] tapply and NA value

2005-03-25 Thread Leonardo Lami
Hi,
I'm writing for a little help.
I have a dataframe with same NA value and I'd like to obtain the means of the 
value of a coloumn grouped by the levels of a factor coloumn of the datframe.
I'm using the function tapply but I see that if only a NA value is present 
the result is NA.
There is an option to have the correct result or I must use an other function?

Thanks of all
Leonardo
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Re: [R] tapply and NA value

2005-03-25 Thread Leonardo Lami
Thanks very much!
Best of all,
Leonardo


Alle 10:52, venerdì 25 marzo 2005, Dimitris Rizopoulos ha scritto:
 you should look at the 'na.rm=FALSE' argument of '?mean()', i.e.,

 x - rnorm(100); x[sample(100, 10)] - NA
 f - sample(letters[1:5], 100, TRUE)
 ###
 tapply(x, f, mean)
 tapply(x, f, mean, na.rm=TRUE)


 I hope it helps.

 Best,
 Dimitris

 
 Dimitris Rizopoulos
 Ph.D. Student
 Biostatistical Centre
 School of Public Health
 Catholic University of Leuven

 Address: Kapucijnenvoer 35, Leuven, Belgium
 Tel: +32/16/336899
 Fax: +32/16/337015
 Web: http://www.med.kuleuven.ac.be/biostat/
  http://www.student.kuleuven.ac.be/~m0390867/dimitris.htm


 - Original Message -
 From: Leonardo Lami [EMAIL PROTECTED]
 To: r-help@stat.math.ethz.ch
 Sent: Friday, March 25, 2005 10:35 AM
 Subject: [R] tapply and NA value

  Hi,
  I'm writing for a little help.
  I have a dataframe with same NA value and I'd like to obtain the
  means of the
  value of a coloumn grouped by the levels of a factor coloumn of the
  datframe.
  I'm using the function tapply but I see that if only a NA value is
  present
  the result is NA.
  There is an option to have the correct result or I must use an other
  function?
 
  Thanks of all
  Leonardo
  --
  Leonardo Lami
  [EMAIL PROTECTED]www.faunalia.it
  Via Colombo 3 - 51010 Massa e Cozzile (PT), Italy   Tel:
  (+39)349-1310164
  GPG key @: hkp://wwwkeys.pgp.net http://www.pgp.net/wwwkeys.html
  https://www.biglumber.com
 
  __
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-- 
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[EMAIL PROTECTED]www.faunalia.it
Via Colombo 3 - 51010 Massa e Cozzile (PT), Italy   Tel: (+39)349-1310164
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[R] bar charts

2004-12-10 Thread Leonardo Lami
Hi,
I'd like plot a bar graphic of a array.
I'd like to have the values of the single columns as juxtaposed bars (like in 
barplot with beside=TRUE) and I'd like to have the values of the single 
columns expressed  like percentage of the sum of the coloumn.
In this way all the bars are composed by the sum of the percentage of the 
values of a coloumn (with different colors) and all they have 100% value. 

Thanks
Leonardo Lami

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[R] Bar chart

2004-12-10 Thread Leonardo Lami
Hi,
I'd like plot a bar graphic of a array.
I'd like to have the values of the single columns as juxtaposed bars (like in 
barplot with beside=TRUE) and I'd like to have the values of the single 
columns expressed  like percentage of the sum of the coloumn.
In this way all the bars are composed by the sum of the percentage of the 
values of a coloumn (with different colors) and all they have 100% value. 

Thanks
Leonardo Lami

-- 
Leonardo Lami
[EMAIL PROTECTED]www.faunalia.it
Via Colombo 3 - 51010 Massa e Cozzile (PT), Italy   Tel: (+39)349-1310164
GPG key @: hkp://wwwkeys.pgp.net http://www.pgp.net/wwwkeys.html
https://www.biglumber.com

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