[R] Dataframe modification

2005-03-08 Thread Ramzi Feghali
Hello,
I have a problem and wish if anybody have a quick
solution or function or if this question was asked
before and you could give me the date to look in the
archives for the response.
My problem is that I have a dataframe D[663,40] with
only  one column with repeated values lines and a
factor with 4 levels.
I want to reorganize my dataframe, create a dataframe
D1[x,40*4] and put the repeated values in one line so
that all the factors will be in columns. For the
values with a missing level factor I want to keep
empty the concerning place.
For example if i a have this dataframe:

A   B   C   
32  a   14  
32  b   22  
55  a   44  
55  b   77  
55  c   55  
55  d   44  
83  c   77  
83  d   55  
83  e   44  
I want to transform it to have this one: 

32  a   14  b   22  
55  a   44  b   77  c   55  
83  c   77  d   55  e   
44


Thanks  best regards

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[R] Problem with installation under R 1.7.1 and unzip

2003-06-23 Thread Ramzi Feghali
Thanks a lot professor,
but no in fact it is like you've said c:\Program Files\R\rw1071\Rwork is my Working 
directory = C:\Program Files\R\rw1071\Rwork, i am in fact using the functions you've 
gave me to know what is happening with me because with R 1.6.2 i could install my 
packages with no problem like that, and i didn't change anything after uninstalling R 
1.6.2 and installing R 1.7.1 (except of course in the propreties of R 1.7.2 Shortcut)
 
zip.unpack(sma,dirperm)
[1] 1
attr(,extracted)
character(0)
Warning message: 
error 1 in extracting from zip file  

options(unzip)
$unzip
[1] internal
 
and this is what i got after the error message of packages installation
 
 traceback()
9: zip.unpack(pkg, tmpDir)
8: unpackPkg(foundpkgs[okp, 2], pkgnames[okp], lib, installWithVers)
7: install.packages(select.list(a[, 1], , TRUE), .libPaths()[1], 
   available = a, CRAN = getOption(BIOC))
6: eval(expr, envir, enclos)
5: eval(quote({
   a - CRAN.packages(CRAN = getOption(BIOC))
   install.packages(select.list(a[, 1], , TRUE), .libPaths()[1], 
   available = a, CRAN = getOption(BIOC))
   }), new.env())
4: eval(expr, envir, enclos)
3: eval(expr, p)
2: eval.parent(substitute(eval(quote(expr), envir)))
1: local({
   a - CRAN.packages(CRAN = getOption(BIOC))
   install.packages(select.list(a[, 1], , TRUE), .libPaths()[1], 
   available = a, CRAN = getOption(BIOC))
   })
 
thanks again
Ramzi



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Re: [R] Code for Support Vector Clustering Algorithm

2003-06-12 Thread Ramzi Feghali
No comment,
 
svm  package:e1071  R Documentation
Support Vector Machines
Description:
 `svm' is used to train a support vector machine. It can be used to
 carry out general regression and classification (of nu and
 epsilon-type), as well as density-estimation. A formula interface
 is provided.


David Meyer [EMAIL PROTECTED] wrote:
On 2003.06.12 09:15, Uwe Ligges wrote:
 Iouri Tipenko wrote:
 
 Dear R-Users,
 I'm a master student in Mathematics and Statistics at Carleton 
 University, Ottawa, Canada.
 I'm studying Clustering methods including different related 
 algorithms. One of them is Support Vector Clustering algorithm.
 I was wondering whether anybody implemented this algorithm and could 
 help me with the S-Plus or R computer code that I could use in my 
 simulations.
 I would really appreciate your help or any advise on where I can get 
 this code.
 
 There is an implementation of Support Vector Machines in package 
 e1071, which is available on CRAN.

...but it does not include Support Vector *clustering*.

David

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RE: [R] Basic question on applying a function to each row of a dataframe

2003-06-09 Thread Ramzi Feghali
Another another neat way is:
 
DF - data.frame(x=1:4, y=rep(1,4))
 foo - function(z,x,y)z[x]+z[y]
 apply(DF,1,foo,x=x,y=y)
1 2 3 4 
2 3 4 5 
 
or
 
 DF - data.frame(x=1:4, y=rep(1,4))
 foo - function(z)z-x+y
 foo(DF)
[1] 2 3 4 5


Liaw, Andy [EMAIL PROTECTED] wrote:
Another neat way is:

with(DF, foo(x, w))

HTH,
Andy

 -Original Message-
 From: peter leonard [mailto:[EMAIL PROTECTED]
 Sent: Sunday, June 08, 2003 4:35 PM
 To: [EMAIL PROTECTED]
 Subject: [R] Basic question on applying a function to each row of a
 dataframe
 
 
 Hi,
 
 I have a function foo(x,y) and a dataframe, DF, comprised of 
 two vectors, x 
  w, as follows :
 
 x w
 1 1 1
 2 2 1
 3 3 1
 4 4 1
 
 etc
 
 
 I would like to apply the function foo to each 'pair' within DF e.g 
 foo(1,1), foo(2,1), foo(3,1) etc
 
 I have tried
 
 apply(DF,foo)
 apply(DF[,],foo)
 apply(DF[DF$x,DF$w],foo)
 
 
 However, none of the above worked. Can anyone help ?
 
 Thanks in advance,
 Peter
 
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[R] Loops question

2003-06-09 Thread Ramzi Feghali


Hello Mr Ripley,
i was waiting you to ask and if you don't mind if there is a fast way in R to do these 
loops made with R and that takes a week because my matrix is with thousand of rows.
I got another method that is more fast and is utilised by many packages : interfacing 
with other languages, but it is only a question for information 
 

foo-function()
 {for (i in 1:(n-1)){
   for (k in (i+1):n){ 
   b_0
   for (j in 1:m){
if(bin[i,j]==TRUEbin[k,j]==TRUE) b_b+1}
 print (b)
 } 
 }
  }

Thanks a lot
Ramzi



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[R] Memory size of R

2003-04-14 Thread Ramzi Feghali
Hi all, anybody know how much can the memory size of R be settled?ThxRamzi 


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