[R] Page's trend test?
Hello Is there an R implementation of the "Page's trend test" as described in http://en.wikipedia.org/wiki/Page%27s_trend_test or something equivalent? Thanks for your help, Vaclav __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] xyplot inside a for loop problem
Hello everyone Could someone please explain me why are xyplot() calls inside a for loop unsuccessful? Calling plot() is OK but xyplot() just opens the graphics window and that is all. No error, no warning :-( The same xyplot() outside for loop works fine. - library(lattice) # OK: plot(1,2,type='p',main='standalone plot') # OK: for (name in 1) plot(1,2,type='p',main='plot in for') # OK: xyplot(1~2,type='p',main='standalone xyplot') # This does not plot anything: for (name in 1) xyplot(1~2,type='p',main='xyplot in for') - Thank you very much for your help Vaclav __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] how to fix a factor
On Fri, 19 Mar 2004, Giampiero Salvi wrote: > Hi all, > I created a data frame with three factors, plus the response that > looks like this: > > x1x2 x3 y > a 1 1 0.3 > a 2 1 0.1 > b 1 1 0.4 > c 4 3 0.1 > ... > > I would like to analise the effect of two of them, keeping the third fixed > (I already know the effect of the last). The reason why I don't create several > data frames for each value of the thirs factor is simply convenience (I'd like > to be able to decide which factor I want to rule out) > > for example I'd like to write something like > > boxplot(y ~ x1 + x2, x3 == 1) > > which of course doesn't work, otherwise I wouldn't write :-) > > Is this possible and how? ?boxplot The subset parameter of boxplot might be what you are looking for. Vaclav __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] Draw abbreviated key (lattice, xyplot)
Deepayan,
> Both auto.key and simpleKey are convenience tools to make key drawing
> easy in 'typical' cases. For more flexibility, define the key as a list
> (the structure is described under 'key' in ?xyplot). You may want to
> look at ?Rows as well, in conjunction with trellis.par.get().
> See ?splom and ?cloud for examples.
>
> You are not very explicit in your description, but perhaps your only
> problem with your second solution is that the first 5 levels are in
> alphabetical order (but you haven't said what order you want them to be
> in). This is an artifact of R's factor() function, where the levels are
> by default
>
> factor(x, levels = sort(unique.default(x), na.last = TRUE), ...
>
> So your problem may be solved simply by redefining your country variable
> appropriately:
>
> yourdata$country <-
> factor(as.character(yourdata$country),
>levels = c('USA', 'Germany', < ... >))
>
> (the as.character() is probably redundant)
Thank you very much - this solves my problem. Putting the countries of
interest first has two benefits
a) different colors are assigned to them
b) including just first n of them in the key using simpleKey is easy
As I am more used a little different notation to construct the levels in
the order I want.
t<-transform(t,country=factor(country,
levels=unique(c(subset(country,year==1997),unique(country)
where
subset(country,year==1997) are the countries I want to be first
unique(country) after that ensures that I include all the countries and
no NAs are introduced
This is how I plot the abbreviated key then
attach(t)
xyplot(papers~year, groups=country, type='l',
key=simpleKey(levels(country)[1:10],columns=2,lines=T,points=F))
Thanks again,
Vaclav
> Hope that helps,
>
> Deepayan
>
> On Thursday 18 March 2004 09:42, Vaclav Petricek wrote:
> > Hello
> >
> > I have been experimenting with xyplot, reading the help and googling
> > but I am still unable to draw an abbreviated key.
> >
> > I would like to display key for a few particular countries.
> >
> > My dataset looks like this
> >
> >year paperscountry papers.total
> > 1 1988403USA 551
> > 2 1988 31 United Kingdom 551
> > 3 1988 24 Canada 551
> > 4 1988 20Netherlands 551
> > 5 1988 19 Israel 551
> > 6 1988 16Germany 551
> > 7 1988 13 France 551
> > 8 1988 10 Italy 551
> > 9 1988 8Switzerland 551
> > 10 1988 5 Japan 551
> > 11 1988 5Denmark 551
> > 12 1988 3 Spain 551
> > 13 1988 3 Russia 551
> > 14 1988 2 Sweden 551
> > 15 1988 2 Poland 551
> > 16 1988 2Finland 551
> > 17 1988 2 Brasil 551
> > 18 1988 2 Australia 551
> > 19 1988 1 Thailand 551
> > 20 1988 1 Norway 551
> > 21 1988 1 Mexico 551
> > 22 1988 1Ireland 551
> > 23 1988 1 Greece 551
> > 24 1989649USA 926
> > 25 1989 53 United Kingdom 926
> > 26 1989 43 France 926
> > 27 1989 37 Canada 926
> > 28 1989 36Germany 926
> > 29 1989 28Netherlands 926
> > 30 1989 19 Sweden 926
> > [...]
> >
> > I use xyplot to show how many papers
> >
> > > xyplot(papers~year,groups=country,type='l',auto.key=T)
> >
> > produces an extremely long key
> >
> > > xyplot(papers~year,groups=country,type='l',key=simpleKey(levels(as.
> > >factor(country))[1:5]))
> >
> > shows *alphabetically* first five countries in the key
> >
> > > xyplot(papers~year,groups=country,type='l',key=simpleKey(c('USA','G
> > >ermany')))
> >
> > displays correct countries but the colors obviously do not match.
> >
> > Could you please point me in the right direction?
> >
> > Vaclav
> >
> > __
> > [EMAIL PROTECTED] mailing list
> > https://www.stat.math.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide!
> > http://www.R-project.org/posting-guide.html
>
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[R] Draw abbreviated key (lattice, xyplot)
Hello
I have been experimenting with xyplot, reading the help and googling but
I am still unable to draw an abbreviated key.
I would like to display key for a few particular countries.
My dataset looks like this
year paperscountry papers.total
1 1988403USA 551
2 1988 31 United Kingdom 551
3 1988 24 Canada 551
4 1988 20Netherlands 551
5 1988 19 Israel 551
6 1988 16Germany 551
7 1988 13 France 551
8 1988 10 Italy 551
9 1988 8Switzerland 551
10 1988 5 Japan 551
11 1988 5Denmark 551
12 1988 3 Spain 551
13 1988 3 Russia 551
14 1988 2 Sweden 551
15 1988 2 Poland 551
16 1988 2Finland 551
17 1988 2 Brasil 551
18 1988 2 Australia 551
19 1988 1 Thailand 551
20 1988 1 Norway 551
21 1988 1 Mexico 551
22 1988 1Ireland 551
23 1988 1 Greece 551
24 1989649USA 926
25 1989 53 United Kingdom 926
26 1989 43 France 926
27 1989 37 Canada 926
28 1989 36Germany 926
29 1989 28Netherlands 926
30 1989 19 Sweden 926
[...]
I use xyplot to show how many papers
> xyplot(papers~year,groups=country,type='l',auto.key=T)
produces an extremely long key
> xyplot(papers~year,groups=country,type='l',key=simpleKey(levels(as.factor(country))[1:5]))
shows *alphabetically* first five countries in the key
> xyplot(papers~year,groups=country,type='l',key=simpleKey(c('USA','Germany')))
displays correct countries but the colors obviously do not match.
Could you please point me in the right direction?
Vaclav
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[R] reshape direction=wide
Hello
I am reshaping a data.frame bids --> reshaped as shown below.
I thought this should be possible with a single invocation of
reshape, but the only way I came up with is reshaping subsets for each
keyword and then joining them together. Does anyone have an idea how to
solve this in a more elegant way? Efficiency is a concern as the datasets
are very large.
Is there a way to specify multiple v.names?
bids
batch keyword rankid bid
1 312221627 Broadband1 401173481 2.64
2 312221627 Broadband2 236096320 2.63
3 312221627 Broadband3 367411639 2.62
4 312221627 Broadband4 188906982 2.61
5 312221627 Broadband5 227691359 2.01
205 312221627 Outsourcing1 406300683 3.68
206 312221627 Outsourcing2 12862485 3.65
207 312221627 Outsourcing3 237944232 3.65
208 312221627 Outsourcing4 95867634 3.64
reshaped
batch keyword bid.1 bid.2 bid.3 bid.4 bid.5 id.1 id.2 id.3
id.4 id.5
1 312221608 Broadband 2.63 2.62 2.62 2.61 2.01 236096320 401173481 367411639
188906982 227691359
2 312221617 Broadband 2.64 2.63 2.62 2.61 2.01 401173481 236096320 367411639
188906982 227691359
3 312221627 Broadband 2.64 2.63 2.62 2.61 2.01 401173481 236096320 367411639
188906982 227691359
4 312221639 Broadband 2.65 2.64 2.63 2.62 2.01 188906982 401173481 236096320
367411639 227691359
5 312221649 Broadband 2.65 2.64 2.63 2.62 2.01 188906982 401173481 236096320
367411639 227691359
6 312221659 Broadband 2.65 2.64 2.63 2.62 2.01 188906982 401173481 236096320
367411639 227691359
7 312221708 Broadband 2.65 2.64 2.63 2.62 2.01 188906982 401173481 236096320
367411639 227691359
8 312221719 Broadband 2.65 2.64 2.63 2.62 2.01 188906982 401173481 236096320
367411639 227691359
9 312221729 Broadband 2.65 2.64 2.63 2.62 2.01 188906982 401173481 236096320
367411639 227691359
10 312221739 Broadband 2.65 2.64 2.63 2.62 2.01 188906982 401173481 236096320
367411639 227691359
keywords <- levels(bids[,'keyword'])
reshaped <<- NULL
for (key in keywords)
{
keywordbid <- bids[bids[,'keyword']==key,]
keywordbid[,'id'] = NULL
keywordbid <- reshape(keywordbid, v.names='bid',
timevar='rank',direction='wide',idvar='batch')
keywordid <- bids[bids[,'keyword']==key,]
keywordid[,'bid'] = NULL
keywordid <- reshape(keywordid, v.names='id',
timevar='rank',direction='wide',idvar='batch')
if(is.null(reshaped))
{
reshaped <<- merge(keywordbid, keywordid)
} else {
reshaped <<- rbind(reshaped, merge(keywordbid, keywordid))
}
rm(keywordbid, keywordid)
}
Thank you very much for any comments,
--
Vaclav Petricek
http://kocour.ms.mff.cuni.cz/~petricek
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