[R] Compiling R 2.4.0 in ubuntu/linux
I'm not sure if this is the place to post this question, but, I am having trouble compiling the source code. I do have a suitable C compiler and f2c but I get this error when I run ./configure configure: error: --with-readline=yes (default) and headers/libs are not available Any ideas? Thanks. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] whole object approach for nested loops
I have the following code that I am trying to execute using the whole
object approach and get rid of the for loop. I have looked at the
manual and seached the database for examples or similar questions with
no luck. The following example works without any problems.
for (j in 1:186)
{
entropy.cogp[1:3, j]<-alpha3[1:3]*c[j,2]
}
But when I try to remove the for loop and use
entropy.cogp[1:3, 1:186]<-alpha3[1:3]*c[1:186,2]
R tries to multiply the first member of alpha3 with the first member
of c[,2] and once c is exhausted, it multiplies the 187th member of
alpha3 with the first member of c[,2] and so on, resulting in an error
where it requires the size of alpha3 to be an exact multiple of the
size of c. This is clearly not what is intended by the for loop given
above. Is there a way to do this using a whole object approach to make
things run faster? Or is the for loop the only way of doing this?
Thanks...
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Re: [R] matrix logic
Uwe, FYI: I tried: "data3 <- ifelse(is.na(data1), data2, data1)" It seems to me that data3 is an array of length 100. I do NOT end up with a dataset of 5 columns and 20 rows. Uwe Ligges <[EMAIL PROTECTED]> wrote: Tom wrote: > On Tue, 10 Jan 2006 20:25:23 -0500, r user wrote: > > >>I have 2 dataframes, each with 5 columns and 20 rows. >>They are called data1 and data2.I wish to create a >>third dataframe called data3, also with 5 columns and >>20 rows. >> >>I want data3 to contains the values in data1 when the >>value in data1 is not NA. Otherwise it should contain >>the values in data2. >> >>I have tried afew methids, but they do not seem to >>work as intended.: >> >>data3<-ifelse(is.na(data1)=F,data1,data2) >> >>and >> >>data3[,]<-ifelse(is.na(data1[,])=F,data1[,],data2[,]) >> >>Please suggest the âbestâ way. "Better" way is to have the Syntax correct: data3 <- ifelse(is.na(data1), data2, data1) Please check the archives for almost millions of posts asking more or less this question...! > Not sure about the bast but... > > a<-c(1,2,3,NA,5) > b<-c(4,4,4,4,4) > > c<-a > c[which(is.na(a))]<-b[which(is.na(a))] Why do you want to know which()? na <- is.na(a) c[na] <- b[na] Uwe Ligges > > > > >>__ >>R-help@stat.math.ethz.ch mailing list >>https://stat.ethz.ch/mailman/listinfo/r-help >>PLEASE do read the posting guide! >>http://www.R-project.org/posting-guide.html >> > > > __ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html - Photo Books. You design it and well bind it! [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] transpose a matrix?
I have a data set in the following format: x<-data.frame(id=c(a,b,c),2005-01-15=c(100,225,425), 2005-02-23=c(1100,2325,4525)) > x id X2005.01.15 X2005.02.23 1 a 1001100 2 b 2252325 3 c 4254525 I want: id a b c X2005.01.15 100 225 425 X2005.02.23 1100 2325 4525 Any Suggestions? __ [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] given a mid-month date, get the month-end date
I have a vector of dates. I wish to find the month end date for each. Any suggestions? e.g. For 12/15/05, I want 12/31/05, For 10/15/1995, I want 10/31/1995, etc __ [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] creating a subset of a dataset using ifelse statement?
I am using R in a Microsoft Windows environment. I have a dataset called mp1b. I have a variable called h. h can take a value from -1 to 5. If h <1, I want to create a new dataset called mp2 that is the same as mp1b: mp2<-mp1b If h > 0, I want to set create a dataset mp2, where I limit the original dataset to those where mp1b$group = =h. similar to: mp2<-subset (mp1b, group= = h) I have tried this ifelse statement, but it does not seem to work as expected. mp2<-ifelse(h<1,mp1b,subset(mp1b,cluster_q==h)) Assistance is appreciated. - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] vector memory exhausted (limit reached?)" error message while loading saved workspace
I am running R 2.2.0 in a Windows XP environment. During my previous r session, I saved my workspace as 20051123b.Rdata. (On disk, it is ~1.25 gb.) I have launched R. (I have the following in my application shortcut <--max-mem-size=4000M>, and although it may not be necessary, I have also run the following line in R: . I have nothing loaded in the workspace. I am trying to load the saved workspace, which is ~1.25gb in size. I get the following message: vector memory exhausted (limit reached?)". I encounter this problem under both the official R 2.2.0, and the patched R 2.2.0. Is there anything I can do to load this workspace? It was working fine last time it was loaded in my R session. - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] running out of memory while running a VERY LARGE regression
I am running a VERY LARGE regression (many factors, many rows of data) using LM. I think I have my memory set as high as possible. ( I ran "memory.limit(size = 4000)") Is there anything I can do? ( FYI, I "think" I have removed all data I am not using, and I "think" I have only the data needed for the regression loaded.) Thanks. - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] percent rank by an index key?
A couple follow up questions:
1. Is there any way to modify this so that non-numeric values are ignored? (As
it is, length seems to "count" the NA values.)
2. In order fro the cbind function "x <- cbind(x, do.call("rbind", r))" to
work as intended, does the data need to be Ordered by State and Year?
e.g. "x <- x[order(x$State,x$Year), ]"
Here is some sample data, with non-numeric values included:
Year,State,Subject,Income
2000,TX,1,30776
2000,AL,1,81240
2000,TX,2,28035
2000,AL,2,35947
2000,TX,3,42010
2000,AL,3,48830
2000,TX,4,18040
2000,AL,4,77758
2000,TX,5,20771
2000,AL,5,59132
2000,TX,6,46370
2000,AL,6,45573
2000,TX,7,57256
2000,AL,7,83402
2000,TX,8,3780
2000,AL,8,90695
2000,TX,9,51745
2000,AL,9,4105
2000,TX,10,1154
2000,AL,10,96598
2001,TX,1,25767
2001,AL,1,37032
2001,TX,2,39848
2001,AL,2,69029
2001,TX,3,17142
2001,AL,3,92850
2001,TX,4,62939
2001,AL,4,82730
2001,TX,5,30708
2001,AL,5,25339
2001,TX,6,64710
2001,AL,6,44541
2001,TX,7,96699
2001,AL,7,9151
2001,TX,8,57793
2001,AL,8,20981
2001,TX,9,12523
2001,AL,9,36139
2001,TX,10,53553
2001,AL,10,3767
2002,TX,1,55232
2002,AL,1,54655
2002,TX,2,76255
2002,AL,2,53581
2002,TX,3,77030
2002,AL,3,34869
2002,TX,4,98956
2002,AL,4,60332
2002,TX,5,33052
2002,AL,5,12348
2002,TX,6,96057
2002,AL,6,24509
2002,TX,7,66177
2002,AL,7,45952
2002,TX,8,73331
2002,AL,8,35813
2002,TX,9,3014
2002,AL,9,57097
2002,TX,10,83657
2002,AL,10,91640
2003,TX,1,5638
2003,AL,1,17026
2003,TX,2,66902
2003,AL,2,71080
2003,TX,3,88195
2003,AL,3,95415
2003,TX,4,13028
2003,AL,4,49123
2003,TX,5,19867
2003,AL,5,22990
2003,TX,6,67639
2003,AL,6,69435
2003,TX,7,62469
2003,AL,7,59939
2003,TX,8,24874
2003,AL,8,44829
2003,TX,9,77180
2003,AL,9,68488
2003,TX,10,80686
2003,AL,10,72622
2004,TX,1,46854
2004,AL,1,62499
2004,TX,2,20461
2004,AL,2,53834
2004,TX,3,54909
2004,AL,3,69527
2004,TX,4,33066
2004,AL,4,78035
2004,TX,5,23569
2004,AL,5,59757
2004,TX,6,44514
2004,AL,6,41223
2004,TX,7,85665
2004,AL,7,91972
2004,TX,8,30073
2004,AL,8,90642
2004,TX,9,32741
2004,AL,9,97111
2004,TX,10,8093
2004,AL,10,20077
2005,TX,1,48377
2005,AL,1,88216
2005,TX,2,35752
2005,AL,2,74897
2005,TX,3,27772
2005,AL,3,88945
2005,TX,4,86512
2005,AL,4,88422
2005,TX,5,27488
2005,AL,5,21140
2005,TX,6,35777
2005,AL,6,32772
2005,TX,7,77477
2005,AL,7,98282
2005,TX,8,73346
2005,AL,8,38943
2005,TX,9,38947
2005,AL,9,70195
2005,TX,10,23890
2005,AL,10,84020
2000,TX,11,na
2005,AL,11,null
Sundar Dorai-Raj <[EMAIL PROTECTED]> wrote:
t c wrote:
> What is the easiest way to calculate a percent rank by an index key?
>
>
>
> Foe example, I have a dataset with 3 fields:
>
>
>
> Year, State, Income ,
>
>
>
> I wish to calculate the rank, by year, by state.
>
> I also wish to calculate the percent rank, where I define percent rank as
> rank/n.
>
>
>
> (n is the number of numeric data points within each date-state grouping.)
>
>
>
>
>
> This is what I am currently doing:
>
>
>
> 1. I create a group by field by using the paste function to combine date
> and state into a field called date_state. I then use the rank function to
> calculate the rank by date, by state.
>
>
>
> 2. I then add a field called one that I set to 1 if the value in income is
> numeric and to 0 if it is not.
>
>
>
> 3. I then take an aggregate sum of one. This gives me a count (n) for each
> date-state grouping.
>
>
>
>
>
> 4. I next use merge to add this count to the table.
>
>
>
> 5. Finally, I calculate the percent rank.
>
>
>
> Pr<-rank/n
>
>
>
> The merge takes quite a bit of time to process.
>
>
>
> Is there an easier/more efficient way to calculate the percent rank?
>
How about using ?by:
set.seed(100)
# fake data set, replace with your own
# "Subject" is just a dummy to produce replicates
x <- expand.grid(Year = 2000:2005,
State = c("TX", "AL"),
Subject = 1:10)
x$Income <- floor(runif(NROW(x)) * 10)
r <- by(x$Income, x[c("Year", "State")],
function(x) {
r <- rank(x)
n <- length(x)
cbind(Rank = r, PRank = r/n)
})
x <- cbind(x, do.call("rbind", r))
HTH,
--sundar
Sundar Dorai-Raj <[EMAIL PROTECTED]> wrote:
t c wrote:
> What is the easiest way to calculate a percent rank by an index key?
>
>
>
> Foe example, I have a dataset with 3 fields:
>
>
>
> Year, State, Income ,
>
>
>
> I wish to calculate the rank, by year, by state.
>
> I also wish to calculate the percent rank, where I define percent rank as
> rank/n.
>
>
>
> (n is the number of nume
[R] percent rank by an index key?
What is the easiest way to calculate a percent rank by an index key? Foe example, I have a dataset with 3 fields: Year,State, Income , I wish to calculate the rank, by year, by state. I also wish to calculate the percent rank, where I define percent rank as rank/n. (n is the number of numeric data points within each date-state grouping.) This is what I am currently doing: 1. I create a group by field by using the paste function to combine date and state into a field called date_state. I then use the rank function to calculate the rank by date, by state. 2. I then add a field called one that I set to 1 if the value in income is numeric and to 0 if it is not. 3. I then take an aggregate sum of one. This gives me a count (n) for each date-state grouping. 4. I next use merge to add this count to the table. 5. Finally, I calculate the percent rank. Pr<-rank/n The merge takes quite a bit of time to process. Is there an easier/more efficient way to calculate the percent rank? - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] getting last 2 charcters of a string, other "text" functions?
I wish to obtain the right-most n characters of a character string? What is the appropriate function? - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] getting an aggregate count, and adding it to a dataset as a new column
I have the data below in a dataset called test3. What is the easiest way to get a count, by date, of all numerical values of var1, and to then add this count to the test3 dataset as a new column? What I have: date,var1,cat 1/1/2005,5,a 1/1/2005,12,a 1/1/2005,44,b 2/1/2005,1,b 2/1/2005,8,a 2/1/2005,32,z 2/1/2005,44,a 3/1/2005,5,z 3/1/2005,7,e 3/1/2005,95,s 3/1/2005,95,s 1/1/2005,NA,NA 1/1/2005,4,NA 1/1/2005,5,NA 3/1/2005,NA,NA 4/1/2005,NA,a what I want: date,var1,cat,n 1/1/2005,5,a,5 1/1/2005,12,a,5 1/1/2005,44,b,5 2/1/2005,1,b,4 2/1/2005,8,a,4 2/1/2005,32,z,4 2/1/2005,44,a,4 3/1/2005,5,z,4 3/1/2005,7,e,4 3/1/2005,95,s,4 3/1/2005,95,s,4 1/1/2005,NA,NA,5 1/1/2005,4,NA,5 1/1/2005,5,NA,5 3/1/2005,NA,NA,4 4/1/2005,NA,a,0 - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] Correlation, by date, of two variables?
I have a dataset with three variables: date, var1, var2 How can I calculate the correlation, by date, between var1 and var2? e.g. datevar1var2 1/1/200154 1/1/200185 1/1/200197 2/1/200172 2/1/200121 2/1/200146 3/1/200135 3/1/200143 3/1/200169 3/1/20017-1 the results I want: 1/1/2001 0.891042111 2/1/2001 0.075093926 3/1/2001 -0.263117406 - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] R training/"tutor"
Can anyone recommend a place to post/look for someone to help me with R? I'm looking for a consultant/trainer/tutor that knows R well, and can help me over the phone or via email. Thanks. - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] functions available for use with aggregate?
What are the functions available for use with aggregate? Where can a reference to them be found? - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] adding 1 month to a date
Thanks. How do I use this to calculate a new variable (e.g."data$next_month")
from an existing variable (e.g."Data$date_").
I tried : ,
but get the following error message: "Error in seq.Date(as.Date(data$date),
len = 2, by = "1 month") : 'from' must be of length 1"
Thanks.
Gabor Grothendieck <[EMAIL PROTECTED]> wrote:
Try this:
seq(as.Date("2005-01-15"), len = 2, by = "month")[2]
or here is another approach:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/61570.html
On 10/11/05, t c wrote:
>
> Within an R dataset, I have a date field called "date_". (The dates are in
> the format "-MM-DD", e.g. "1995-12-01".)
>
>
>
> How can I add or subtract "1 month" from this date, to get "1996-01-01" or "
> "1995-11-01".
>
>
>
>
>
> -
>
> [[alternative HTML version deleted]]
>
>
>
> __
> R-help@stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
>
>
-
-
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PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] adding 1 month to a date
Thanks. How do I se thsi to calculate a new variable (e.g."data$next_month")
from an existing variable (e.g."Data$date_").
I tried : ,
but get the following error message: "Error in seq.Date(as.Date(data$date),
len = 2, by = "1 month") : 'from' must be of length 1"
Thanks.
Gabor Grothendieck <[EMAIL PROTECTED]> wrote:
Try this:
seq(as.Date("2005-01-15"), len = 2, by = "month")[2]
or here is another approach:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/61570.html
On 10/11/05, t c wrote:
>
> Within an R dataset, I have a date field called "date_". (The dates are in
> the format "-MM-DD", e.g. "1995-12-01".)
>
>
>
> How can I add or subtract "1 month" from this date, to get "1996-01-01" or "
> "1995-11-01".
>
>
>
>
>
> -
>
> [[alternative HTML version deleted]]
>
>
>
> __
> R-help@stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
>
>
-
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PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] adding 1 month to a date
Within an R dataset, I have a date field called date_. (The dates are in the format -MM-DD, e.g. 1995-12-01.) How can I add or subtract 1 month from this date, to get 1996-01-01 or 1995-11-01. - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
