Re: [R] Re: S4 method inheritance

2005-05-24 Thread Duncan Murdoch

Ross Boylan wrote:

On Mon, 2005-05-23 at 14:41 -0700, Ross Boylan wrote:




Finally, I'm a bit concerned that one article mentioned that S4
inheritance, in practice, is used mostly for data, not methods (Thomas
Lumley, R News 4(1), June 2004: p. 36).  Am I going down a road I
shouldn't travel?



Hmm, maybe I just found out.  If B is an S4 subclass of A (aka extends
A), how does B's method foo invoke A's foo?


Your question doesn't make sense in S4.  In S4, classes don't have 
methods, generics have methods.  There's no such thing as B's method 
or A's method.


You might get what you want with foo(as(bObject, A)) if bObject is an 
instance of class B.



The question assumes that A's foo was defined as an in place function,
so there's no (obvious) named object for it, i.e,
setMethod(A, signature(blah=numeric), function(x) something)


I don't know what you mean by in place function, but I hope my answer 
helps anyway.


Duncan Murdoch

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Re: [R] Re: S4 method inheritance

2005-05-24 Thread Robert Gentleman



Duncan Murdoch wrote:

Ross Boylan wrote:


On Mon, 2005-05-23 at 14:41 -0700, Ross Boylan wrote:




Finally, I'm a bit concerned that one article mentioned that S4
inheritance, in practice, is used mostly for data, not methods (Thomas
Lumley, R News 4(1), June 2004: p. 36).  Am I going down a road I
shouldn't travel?



Hmm, maybe I just found out.  If B is an S4 subclass of A (aka extends
A), how does B's method foo invoke A's foo?



Your question doesn't make sense in S4.  In S4, classes don't have 
methods, generics have methods.  There's no such thing as B's method 
or A's method.


You might get what you want with foo(as(bObject, A)) if bObject is an 
instance of class B.



The question assumes that A's foo was defined as an in place function,
so there's no (obvious) named object for it, i.e,
setMethod(A, signature(blah=numeric), function(x) something)




In general it may be best to think of a generic function as a 
dispatching mechanism. For S4 methods are associated with a specific 
generic function. A generic knows about all methods that are associated 
with it, and about no others. Thus in S4, the little tiff over who owns 
label goes away - they both do - different packages can define generic 
functions for label, or anything else they care to, and users can write 
methods for specific generic functions and associate them with a 
generic. [Note that in the S3 system there is no real mechanism for 
saying that foo.bar is a method for one generic named foo, and not for 
another - but the language does allow for multiple generics named foo - 
one of the very many reasons that S3 does not really do what you want it 
to, but many seem convinced otherwise].


The class hierarchy of the actual supplied arguments, is used to 
determine the dispatch order (a linearization of the available methods) 
once the generic is invoked. The most specific method is used first. It 
may intiate a call to callNextMethod (S4) or NextMethod (S3) to transfer 
control to the next most specific method - the manual pages provide more 
specific details.


As Duncan said - classes do not own methods in this paradigm. Generic 
functions do.


 HTH
   Robert



I don't know what you mean by in place function, but I hope my answer 
helps anyway.


Duncan Murdoch

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Re: [R] Re: S4 method inheritance

2005-05-24 Thread Thomas Lumley

On Mon, 23 May 2005, Ross Boylan wrote:


On Mon, 2005-05-23 at 14:41 -0700, Ross Boylan wrote:



Finally, I'm a bit concerned that one article mentioned that S4
inheritance, in practice, is used mostly for data, not methods (Thomas
Lumley, R News 4(1), June 2004: p. 36).  Am I going down a road I
shouldn't travel?


Hmm, maybe I just found out.  If B is an S4 subclass of A (aka extends
A), how does B's method foo invoke A's foo?



You may be looking for callNextMethod, or foo(as(object, A)).

The comment about inheritance in my R News article has nothing to do with 
S3 vs S4.  It is just that extensions of data structures typically happen 
by specialisation (for which inheritance is appropriate) whereas models 
are typically extended by generalisation (for which inheritance isn't 
appropriate).


The only relevance to the S3 vs S4 discussion is that it provides an 
explanation for the lack of appreciation of S4. Since most statisticians 
don't use inheritance when programming they don't see the benefit in a 
system that gets inheritance right.


-thomas

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Re: [R] Re: S4 method inheritance

2005-05-24 Thread Ross Boylan
On Tue, May 24, 2005 at 07:07:07AM -0400, Duncan Murdoch wrote:
 Ross Boylan wrote:
 On Mon, 2005-05-23 at 14:41 -0700, Ross Boylan wrote:
 
 
 
 Finally, I'm a bit concerned that one article mentioned that S4
 inheritance, in practice, is used mostly for data, not methods (Thomas
 Lumley, R News 4(1), June 2004: p. 36).  Am I going down a road I
 shouldn't travel?
 
 
 Hmm, maybe I just found out.  If B is an S4 subclass of A (aka extends
 A), how does B's method foo invoke A's foo?
 
 Your question doesn't make sense in S4.  In S4, classes don't have 
 methods, generics have methods.  There's no such thing as B's method 
 or A's method.
Oops, I keep taking the references to objects too literally.  Thanks.
 
 You might get what you want with foo(as(bObject, A)) if bObject is an 
 instance of class B.
 
 The question assumes that A's foo was defined as an in place function,
 so there's no (obvious) named object for it, i.e,
 setMethod(A, signature(blah=numeric), function(x) something)
There's my confusion: the first argument should be the name of the
generic, not the class.
 
 I don't know what you mean by in place function, but I hope my answer 
 helps anyway.

Just for clarification, in place function was in contrast to a
function defined elsewhere with an explicit name, e.g.,
   fforA-function(x) something
   setMethod(foo, signature(blah=numeric), fforA)
In that case I could just refer to fforA directly. (Trying to avoid
the S3ish f.A).

Is sounds as if the use of as() or callNextMethod() will get me what I
want.  And the docs seem clear that callNextMethod() returns control
(and a value) to the calling function.

Thanks to everyone for their help.

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Re: [R] Re: S4 method inheritance

2005-05-24 Thread Ross Boylan
On Tue, May 24, 2005 at 06:27:56AM -0700, Robert Gentleman wrote:
 
 
 Duncan Murdoch wrote:
 Ross Boylan wrote:
 
 On Mon, 2005-05-23 at 14:41 -0700, Ross Boylan wrote:
 
 
 
 Finally, I'm a bit concerned that one article mentioned that S4
 inheritance, in practice, is used mostly for data, not methods (Thomas
 Lumley, R News 4(1), June 2004: p. 36).  Am I going down a road I
 shouldn't travel?
 
 
 Hmm, maybe I just found out.  If B is an S4 subclass of A (aka extends
 A), how does B's method foo invoke A's foo?
 
 
 Your question doesn't make sense in S4.  In S4, classes don't have 
 methods, generics have methods.  There's no such thing as B's method 
 or A's method.
 
 You might get what you want with foo(as(bObject, A)) if bObject is an 
 instance of class B.
 
 The question assumes that A's foo was defined as an in place function,
 so there's no (obvious) named object for it, i.e,
 setMethod(A, signature(blah=numeric), function(x) something)
 
 
 In general it may be best to think of a generic function as a 
 dispatching mechanism. For S4 methods are associated with a specific 
 generic function. 
specific generic is a reference to the ability to define generics
 within the context of a particular package?
 A generic knows about all methods that are associated 
 with it, and about no others. 
Presumably setMethod does the association.  Is the where argument
intended to identify which generic method to pick?  The fact that
there is not a package argument to setMethod, as there is to
setGeneric, is a little confusing to me.

 Thus in S4, the little tiff over who owns 
 label goes away - they both do - different packages can define
 generic 
They is two different packages?  Or is this a reference to my
original confusion about class vs generic ownership of a method?

 functions for label, or anything else they care to, and users can write 
 methods for specific generic functions and associate them with a 
 generic.
...
  HTH
Robert

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Re: [R] Re: S4 method inheritance

2005-05-24 Thread Robert Gentleman



Ross Boylan wrote:

On Tue, May 24, 2005 at 06:27:56AM -0700, Robert Gentleman wrote:



Duncan Murdoch wrote:


Ross Boylan wrote:



On Mon, 2005-05-23 at 14:41 -0700, Ross Boylan wrote:





Finally, I'm a bit concerned that one article mentioned that S4
inheritance, in practice, is used mostly for data, not methods (Thomas
Lumley, R News 4(1), June 2004: p. 36).  Am I going down a road I
shouldn't travel?



Hmm, maybe I just found out.  If B is an S4 subclass of A (aka extends
A), how does B's method foo invoke A's foo?



Your question doesn't make sense in S4.  In S4, classes don't have 
methods, generics have methods.  There's no such thing as B's method 
or A's method.


You might get what you want with foo(as(bObject, A)) if bObject is an 
instance of class B.




The question assumes that A's foo was defined as an in place function,
so there's no (obvious) named object for it, i.e,
setMethod(A, signature(blah=numeric), function(x) something)


In general it may be best to think of a generic function as a 
dispatching mechanism. For S4 methods are associated with a specific 
generic function. 


specific generic is a reference to the ability to define generics
 within the context of a particular package?



Well, more that you can identify one (either explicitly by its package 
[ie. fully-qualified name], or implicitly by the fact that it is first 
on the search path - the former being prefered). But the notion is that 
there is one and you have asked that your method be made available to 
that one generic function for dispatch. This is in contrast to S3 - 
where no such functionality exists - that I know of; under S3 any method 
is a method for all generic functions of the correct name and the 
programmer has no (easy) control. Under S4 methods are not really 
ordinary functions, should not be called directly and are invoked only 
via calls to the generic (you can of course break all of those rules).




A generic knows about all methods that are associated 
with it, and about no others. 


Presumably setMethod does the association.  Is the where argument
intended to identify which generic method to pick?  The fact that
there is not a package argument to setMethod, as there is to
setGeneric, is a little confusing to me.




 I believe that is the documented behavior. Yes the where argument 
should allow you complete specificity. I will leave it to the auther to 
clarify differences between the where and package arguments in the call 
to setGeneric (or you, if you care to explore the code).


Thus in S4, the little tiff over who owns 
label goes away - they both do - different packages can define
generic 


They is two different packages?  Or is this a reference to my
original confusion about class vs generic ownership of a method?



 It is the two packages. The S langauge allows for the same symbol to 
be bound to different values in different namespaces (in R that is 
becoming explicit, in SPlus it is less so, but still generally true). I 
can think of no good reason to treat generic functions, or any other 
first class object, differently.


HTH,
 Robert



functions for label, or anything else they care to, and users can write 
methods for specific generic

 functions and associate them with a

generic.


...


HTH
  Robert





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[R] Re: S4 method inheritance

2005-05-23 Thread Ross Boylan
On Mon, 2005-05-23 at 14:41 -0700, Ross Boylan wrote:


 Finally, I'm a bit concerned that one article mentioned that S4
 inheritance, in practice, is used mostly for data, not methods (Thomas
 Lumley, R News 4(1), June 2004: p. 36).  Am I going down a road I
 shouldn't travel?
 
Hmm, maybe I just found out.  If B is an S4 subclass of A (aka extends
A), how does B's method foo invoke A's foo?

The question assumes that A's foo was defined as an in place function,
so there's no (obvious) named object for it, i.e,
setMethod(A, signature(blah=numeric), function(x) something)

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