Is this what you want?
x - scan(textConnection(1979.00
+
+ 1979.020833
+
+ 1979.041667
+
+ 1979.062500), what=0)
Read 4 items
# get the year and then determine the number of seconds in the year so you can
# use the decimal part of the year
x.year - floor(x)
# fraction of the year
x.frac - x - x.year
# number of seconds in each year
x.sec.yr - unclass(ISOdate(x.year+1,1,1,0,0,0)) -
unclass(ISOdate(x.year,1,1,0,0,0))
# now get the actual time
x.actual - ISOdate(x.year,1,1,0,0,0) + x.frac * x.sec.yr
x.actual
[1] 1979-01-01 00:00:00 GMT 1979-01-08 14:29:49 GMT 1979-01-16
05:00:10 GMT
[4] 1979-01-23 19:30:00 GMT
On 8/7/07, Yogesh Tiwari [EMAIL PROTECTED] wrote:
Hello R Users,
How to convert decimal date to date as .mm.dd.hr.min.sec
For example, I have decimal date in one column , and want to convert and
write it in equivalent date(.mm.dd.hr.min.sec) in another next six
columns.
1979.00
1979.020833
1979.041667
1979.062500
Is it possible in R ?
Kindly help,
Regards,
Yogesh
--
Dr. Yogesh K. Tiwari,
Scientist,
Indian Institute of Tropical Meteorology,
Homi Bhabha Road,
Pashan,
Pune-411008
INDIA
Phone: 0091-99 2273 9513 (Cell)
: 0091-20-258 93 600 (O) (Ext.250)
Fax: 0091-20-258 93 825
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