Re: [R] overlapping pattern match (errata 2.0)
Another way to find all the multiple occurances of a character in a string is to use 'rle': x.s - 'aaabbcdeeeggiijjysbbddeffghjjjsdk' x - unlist(strsplit(x.s, NULL)) x [1] a a a b b c d e e e f f f f g g i i j [20] j y s b b d d e f f g h j j j s d k k [39] k k k rle(x) Run Length Encoding lengths: int [1:21] 3 2 1 1 3 4 2 2 2 1 ... values : chr [1:21] a b c d e f g i j y s b d e f g ... When the lengths are 1, the corresponding 'values' are the repeated characters. FMGCFMGC [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent by: cc: [EMAIL PROTECTED] [EMAIL PROTECTED]Subject: Re: [R] overlapping pattern match (errata 2.0) ath.ethz.ch 03/28/03 17:36 well! excuse me again but... your.string - aaacdf nc1 - nchar(your.string)-1 x - unlist(strsplit(your.string, NULL)) CORRECT x2 - c() for (i in 1:nc1) x2 - c(x2, paste(x[i], x[i+1], sep=)) ERRATA 2 cat(ocurrences of aa in your.string: , length(grep(aa, x2)), sep=, fill=TRUE) Fran PD: sorry again __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help -- NOTICE: The information contained in this electronic mail transmission is intended by Convergys Corporation for the use of the named individual or entity to which it is directed and may contain information that is privileged or otherwise confidential. If you have received this electronic mail transmission in error, please delete it from your system without copying or forwarding it, and notify the sender of the error by reply email or by telephone (collect), so that the sender's address records can be corrected. __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] overlapping pattern match
Here's a way. string - aaacdf pattern - aa nstring - nchar(string) npattern - nchar(pattern) stringlist - substring(string, 1:(nstring-npattern+1), npattern:nstring) sum(stringlist==pattern) Also, have a look at: pmatch, charmatch, grep, sub, gsub, regexpr, chartr. I couldn't find a simple function to do what you want. Hope this helps. Jerome On March 27, 2003 05:34 pm, Yiping Fan wrote: Content-Length: 360 Status: R X-Status: N Hi, all, I have a string like aaacdf, I want to find how many aa in the string. Obviously, It is 2 in this case. it is easy to do in Perl, but how to do such overlapping match in R or Splus. Thanks! Y.Fan __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] overlapping pattern match
try with this: your.string - aaacdf nc1 - nchar(your.string)-1 x - unlist(strsplit(cadena, NULL)) x2 - c() for (i in 1:nc1) x2 - c(x2, paste(x2[i], x2[i+1], sep=)) cat(ocurrences of aa in your.string:, length(grep(aa, x2)), sep=, fill=TRUE) Hope it helps! Fran --- original message --- Hi, all, I have a string like aaacdf, I want to find how many aa in the string. Obviously, It is 2 in this case. it is easy to do in Perl, but how to do such overlapping match in R or Splus. Thanks! Y.Fan __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help
[R] overlapping pattern match
Hi, all, I have a string like aaacdf, I want to find how many aa in the string. Obviously, It is 2 in this case. it is easy to do in Perl, but how to do such overlapping match in R or Splus. Thanks! Y.Fan __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help
