[R] summary with names
Hi,
how can I tell 'summary' to print the name of the summarised
variable? This is probably an awkward newbie question but I
didn't find an answer in the Docus, the FAQ and maillist archive.
I want a summary for about 250 variables and realise it
the following way (I know, that I shouldn't use iterations
that way in R; but at the moment it's the easiest way for me):
for(i in fb.12.unt[varA1:varZ9]){print (summary(i, na.rm=t))}
It works fine, but I don't know which summary corresponds to
which variable, because the variable names are not printed.
Can somebody give me a hint?
TIA
Regards,
Christoph
--
Christoph Bier, Dipl.Oecotroph., Email: [EMAIL PROTECTED]
Universitaet Kassel, FG Oekologische Lebensmittelqualitaet und
Ernaehrungskultur \\ Postfach 12 52 \\ 37202 Witzenhausen
Tel.: +49 (0) 55 42 / 98 -17 21, Fax: -17 13
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Re: [R] summary with names
Christoph Bier wrote:
Hi,
how can I tell 'summary' to print the name of the summarised variable?
This is probably an awkward newbie question but I didn't find an answer
in the Docus, the FAQ and maillist archive.
I want a summary for about 250 variables and realise it the following
way (I know, that I shouldn't use iterations that way in R; but at the
moment it's the easiest way for me):
for(i in fb.12.unt[varA1:varZ9]){print (summary(i, na.rm=t))}
Given fb.12.unt is a list or data.frame,
lapply(fb.12.unt, summary, na.rm = TRUE)
or
sapply(fb.12.unt, summary, na.rm = TRUE)
might do what you want.
BTW: na.rm=t is wrong anyway ...
Uwe Ligges
It works fine, but I don't know which summary corresponds to which
variable, because the variable names are not printed. Can somebody give
me a hint?
TIA
Regards,
Christoph
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Re: [R] summary with names
Christoph Bier [EMAIL PROTECTED] wrote:
how can I tell 'summary' to print the name of the summarised
variable? This is probably an awkward newbie question but I
didn't find an answer in the Docus, the FAQ and maillist archive.
I want a summary for about 250 variables and realise it
the following way (I know, that I shouldn't use iterations
that way in R; but at the moment it's the easiest way for me):
for(i in fb.12.unt[varA1:varZ9]){print (summary(i, na.rm=t))}
It works fine, but I don't know which summary corresponds to
This surprises me.
which variable, because the variable names are not printed.
Can somebody give me a hint?
Can you give us an example of summary not giving variable names?
df-data.frame(var1=c(1,2,3),var2=c(4,5,6),factor1=c('a','a','b'))
summary(df)
var1 var2 factor1
Min. :1.0 Min. :4.0 a:2
1st Qu.:1.5 1st Qu.:4.5 b:1
Median :2.0 Median :5.0
Mean :2.0 Mean :5.0
3rd Qu.:2.5 3rd Qu.:5.5
Max. :3.0 Max. :6.0
summary(df[1:2])
var1 var2
Min. :1.0 Min. :4.0
1st Qu.:1.5 1st Qu.:4.5
Median :2.0 Median :5.0
Mean :2.0 Mean :5.0
3rd Qu.:2.5 3rd Qu.:5.5
Max. :3.0 Max. :6.0
--
Philippe
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Re: [R] summary with names
On Thu, 16 Oct 2003, Christoph Bier wrote:
Hi,
how can I tell 'summary' to print the name of the summarised
variable? This is probably an awkward newbie question but I
didn't find an answer in the Docus, the FAQ and maillist archive.
I want a summary for about 250 variables and realise it
the following way (I know, that I shouldn't use iterations
that way in R; but at the moment it's the easiest way for me):
for(i in fb.12.unt[varA1:varZ9]){print (summary(i, na.rm=t))}
It works fine, but I don't know which summary corresponds to
which variable, because the variable names are not printed.
Can somebody give me a hint?
In this context you will have to print the names yourself. summary()
doesn't know the names, it only knows the contents of i.
summary(a.data.frame) can print the names becuase the names are part of
the data frame.
As people have already pointed out there are some other strange things
about the command.
-thomas
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Re: [R] summary with names
Philippe Glaziou schrieb: [...] Can you give us an example of summary not giving variable names? I could send you my data frame, but that's surely not what you want =). Your following example prints the value names on my machine, too. But my data frame does not. And the summary isn't printed among one another but abreast. Sorry, can't tell you why. But I will try to create a simple example. [example] Regards, Christoph -- Christoph Bier, Dipl.Oecotroph., Email: [EMAIL PROTECTED] Universitaet Kassel, FG Oekologische Lebensmittelqualitaet und Ernaehrungskultur \\ Postfach 12 52 \\ 37202 Witzenhausen Tel.: +49 (0) 55 42 / 98 -17 21, Fax: -17 13 __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] summary with names
Patrick Burns schrieb:
I think you mean na.rm=T by the way.
Yes, you're right!
Is
for(i in whatever) {cat(i, \n); print(summary(i, na.rm=TRUE))}
what you want?
No, it doesn't print the value names. I can't tell you why.
Philippe wonders, too. In his example the value names are
printed. But not with my data frame.
Regards,
Christoph
--
Christoph Bier, Dipl.Oecotroph., Email: [EMAIL PROTECTED]
Universitaet Kassel, FG Oekologische Lebensmittelqualitaet und
Ernaehrungskultur \\ Postfach 12 52 \\ 37202 Witzenhausen
Tel.: +49 (0) 55 42 / 98 -17 21, Fax: -17 13
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Re: [R] summary with names
Uwe Ligges schrieb:
Christoph Bier wrote:
Hi,
how can I tell 'summary' to print the name of the summarised variable?
This is probably an awkward newbie question but I didn't find an
answer in the Docus, the FAQ and maillist archive.
I want a summary for about 250 variables and realise it the
following way (I know, that I shouldn't use iterations that way in R;
but at the moment it's the easiest way for me):
for(i in fb.12.unt[varA1:varZ9]){print (summary(i, na.rm=t))}
Given fb.12.unt is a list or data.frame,
lapply(fb.12.unt, summary, na.rm = TRUE)
or
sapply(fb.12.unt, summary, na.rm = TRUE)
might do what you want.
Yes, it does :-)! Thanks a lot.
BTW: na.rm=t is wrong anyway ...
Sure, actually I used na.rm=T -- but not TRUE. My alleged
knowledge about this is based on a book about S and S-Plus.
I'm still waiting for An Introductory in R as I wrote in a
mail some days ago. I can not read Docus on a monitor, I need
paper in my hand =).
Best regards,
Christoph
--
Christoph Bier, Dipl.Oecotroph., Email: [EMAIL PROTECTED]
Universitaet Kassel, FG Oekologische Lebensmittelqualitaet und
Ernaehrungskultur \\ Postfach 12 52 \\ 37202 Witzenhausen
Tel.: +49 (0) 55 42 / 98 -17 21, Fax: -17 13
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[R] [Summary] Color names
Thanks to those who took time to respond. Based on the functions
that were pointed out to me I have the following:
# colors.hex and colors.name convert color names to hex and visa versa
# note that each color has a unique hex code but each hex code may have
# more than one color
colors.hex - function( x=colors() ) {
color.hex - function(x) do.call( rgb, as.list(col2rgb(x)/255) )
sapply( x, color.hex )
}
colors.name - function( x ) {
color.name - function( x ) colors()[ colors.hex() == x ]
lapply( x, color.name )
}
# For example,
colors.hex( red )
colors.hex( colors()[1:5] )
colors.name( #FF )
colors.name( rainbow(3) )
colors.name( rainbow(7) ) # note: only first element has a name
# LL partitions all color names into equivalence classes w same hex code
# LL2 is similar but only has equivalence classes with more than one name
LL - by( colors(), colors.hex(), as.vector )
LL2 - LL[ lapply( LL, length ) 1 ]
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