[R] Urgent Help needed
Dear All: Urgent help is needed. I have a data set in matrix format of three columns: X, Y and index of four groups (1,2,3,4). What I need to do is the following; 1- How I can subtract the sample mean of each group indexed 1,2,3,4 from the corresponding data values of this group and create new columns say X-sample mean and Y-sample mean? I tried to use the tapply but I have some difficulties to restore the new data 2- How I can use the tapply if possible or any other R-function to find the correlation coefficient between the X and Y columns for each group indexed 1,2,3,4.? Could not use the tapply. I attached part of the data as txt file. Thank you so much for your attention to this matter, and I look forward to hear from you soon. Regards, Abou Data: x y index 15807.2412.54 15752.5133.54 12893.7601.53 8426.88 22.23 5706.24 333 3 3982.08 560 2 3642.62 670 2 295.68 124 1 215.40 104 1 195.40 204 1 4240.21 22.42 1222.72 45.92 1142.26 23.62 63.00 90.11 1216.00 82.42 2769.60 111 2 1790.46 34.72 26.10 26.10 1 19676.830.994 10920.60203 3 6144.00 46 3 4534.48 4534.48 3 4.0065 4 29500.0056 4 17100.0077 4 9000.00 435 3 6300.00 84 3 3962.88 334 2 5690.00 653 3 3736.00 233 2 2750.00 22 2 1316.00 345 2 4595.00 4595.00 3 5928.00 45 3 2645.70 0.002 2580.24 454 2 6547.34 6547.34 3 1615.68 5 2 194.06 55 1 184.80 6 1 82.94 44 1 16649.0056 4 4500.00 74 3 1600.00 744 2 = == AbouEl-Makarim Aboueissa, Ph.D. Assistant Professor of Statistics Department of Mathematics Statistics University of Southern Maine 96 Falmouth Street P.O. Box 9300 Portland, ME 04104-9300 Tel: (207) 228-8389 Email: [EMAIL PROTECTED] [EMAIL PROTECTED] Office: 301C Payson Smith x y index 15807.2412.54 15752.5133.54 12893.7601.53 8426.88 22.23 5706.24 333 3 3982.08 560 2 3642.62 670 2 295.68 124 1 215.40 104 1 195.40 204 1 4240.21 22.42 1222.72 45.92 1142.26 23.62 63.00 90.11 1216.00 82.42 2769.60 111 2 1790.46 34.72 26.10 26.10 1 19676.830.994 10920.60203 3 6144.00 46 3 4534.48 4534.48 3 4.0065 4 29500.0056 4 17100.0077 4 9000.00 435 3 6300.00 84 3 3962.88 334 2 5690.00 653 3 3736.00 233 2 2750.00 22 2 1316.00 345 2 4595.00 4595.00 3 5928.00 45 3 2645.70 0.002 2580.24 454 2 6547.34 6547.34 3 1615.68 5 2 194.06 55 1 184.80 6 1 82.94 44 1 16649.0056 4 4500.00 74 3 1600.00 744 2 __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Urgent Help needed
try this: t0 = read.table(datatest.txt, header=T) X.mean = ave(t0[,1], as.factor(t0[,3])) you do the rest of Y.mean and make them into a data.fame or whatever. HTH, Weiwei On 8/16/07, AbouEl-Makarim Aboueissa [EMAIL PROTECTED] wrote: Dear All: Urgent help is needed. I have a data set in matrix format of three columns: X, Y and index of four groups (1,2,3,4). What I need to do is the following; 1- How I can subtract the sample mean of each group indexed 1,2,3,4 from the corresponding data values of this group and create new columns say X-sample mean and Y-sample mean? I tried to use the tapply but I have some difficulties to restore the new data 2- How I can use the tapply if possible or any other R-function to find the correlation coefficient between the X and Y columns for each group indexed 1,2,3,4.? Could not use the tapply. I attached part of the data as txt file. Thank you so much for your attention to this matter, and I look forward to hear from you soon. Regards, Abou Data: x y index 15807.2412.54 15752.5133.54 12893.7601.53 8426.88 22.23 5706.24 333 3 3982.08 560 2 3642.62 670 2 295.68 124 1 215.40 104 1 195.40 204 1 4240.21 22.42 1222.72 45.92 1142.26 23.62 63.00 90.11 1216.00 82.42 2769.60 111 2 1790.46 34.72 26.10 26.10 1 19676.830.994 10920.60203 3 6144.00 46 3 4534.48 4534.48 3 4.0065 4 29500.0056 4 17100.0077 4 9000.00 435 3 6300.00 84 3 3962.88 334 2 5690.00 653 3 3736.00 233 2 2750.00 22 2 1316.00 345 2 4595.00 4595.00 3 5928.00 45 3 2645.70 0.002 2580.24 454 2 6547.34 6547.34 3 1615.68 5 2 194.06 55 1 184.80 6 1 82.94 44 1 16649.0056 4 4500.00 74 3 1600.00 744 2 = == AbouEl-Makarim Aboueissa, Ph.D. Assistant Professor of Statistics Department of Mathematics Statistics University of Southern Maine 96 Falmouth Street P.O. Box 9300 Portland, ME 04104-9300 Tel: (207) 228-8389 Email: [EMAIL PROTECTED] [EMAIL PROTECTED] Office: 301C Payson Smith __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Weiwei Shi, Ph.D Research Scientist GeneGO, Inc. Did you always know? No, I did not. But I believed... ---Matrix III __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Urgent Help needed
For the 2nd item, perhaps: by(df[,1:2], df$index, FUN=cor) where df is your data.frame. -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O On 16/08/07, AbouEl-Makarim Aboueissa [EMAIL PROTECTED] wrote: Dear All: Urgent help is needed. I have a data set in matrix format of three columns: X, Y and index of four groups (1,2,3,4). What I need to do is the following; 1- How I can subtract the sample mean of each group indexed 1,2,3,4 from the corresponding data values of this group and create new columns say X-sample mean and Y-sample mean? I tried to use the tapply but I have some difficulties to restore the new data 2- How I can use the tapply if possible or any other R-function to find the correlation coefficient between the X and Y columns for each group indexed 1,2,3,4.? Could not use the tapply. I attached part of the data as txt file. Thank you so much for your attention to this matter, and I look forward to hear from you soon. Regards, Abou Data: x y index 15807.2412.54 15752.5133.54 12893.7601.53 8426.88 22.23 5706.24 333 3 3982.08 560 2 3642.62 670 2 295.68 124 1 215.40 104 1 195.40 204 1 4240.21 22.42 1222.72 45.92 1142.26 23.62 63.00 90.11 1216.00 82.42 2769.60 111 2 1790.46 34.72 26.10 26.10 1 19676.830.994 10920.60203 3 6144.00 46 3 4534.48 4534.48 3 4.0065 4 29500.0056 4 17100.0077 4 9000.00 435 3 6300.00 84 3 3962.88 334 2 5690.00 653 3 3736.00 233 2 2750.00 22 2 1316.00 345 2 4595.00 4595.00 3 5928.00 45 3 2645.70 0.002 2580.24 454 2 6547.34 6547.34 3 1615.68 5 2 194.06 55 1 184.80 6 1 82.94 44 1 16649.0056 4 4500.00 74 3 1600.00 744 2 = == AbouEl-Makarim Aboueissa, Ph.D. Assistant Professor of Statistics Department of Mathematics Statistics University of Southern Maine 96 Falmouth Street P.O. Box 9300 Portland, ME 04104-9300 Tel: (207) 228-8389 Email: [EMAIL PROTECTED] [EMAIL PROTECTED] Office: 301C Payson Smith __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Urgent Help needed
On Thu, 2007-08-16 at 12:33 -0400, AbouEl-Makarim Aboueissa wrote: Dear All: Urgent help is needed. I have a data set in matrix format of three columns: X, Y and index of four groups (1,2,3,4). What I need to do is the following; 1- How I can subtract the sample mean of each group indexed 1,2,3,4 from the corresponding data values of this group and create new columns say X-sample mean and Y-sample mean? I tried to use the tapply but I have some difficulties to restore the new data 2- How I can use the “tapply” if possible or any other R-function to find the correlation coefficient between the X and Y columns for each group indexed 1,2,3,4.? Could not use the tapply. I attached part of the data as txt file. Thank you so much for your attention to this matter, and I look forward to hear from you soon. Regards, Abou Data: x y index 15807.24 12.54 15752.51 33.54 12893.76 01.53 8426.88 22.23 5706.24 333 3 3982.08 560 2 3642.62 670 2 295.68124 1 215.40104 1 195.40204 1 4240.21 22.42 1222.72 45.92 1142.26 23.62 63.00 90.11 1216.00 82.42 2769.60 111 2 1790.46 34.72 26.10 26.10 1 19676.83 0.994 10920.60 203 3 6144.00 46 3 4534.48 4534.48 3 4.00 65 4 29500.00 56 4 17100.00 77 4 9000.00 435 3 6300.00 84 3 3962.88 334 2 5690.00 653 3 3736.00 233 2 2750.00 22 2 1316.00 345 2 4595.00 4595.00 3 5928.00 45 3 2645.70 0.002 2580.24 454 2 6547.34 6547.34 3 1615.68 5 2 194.0655 1 184.806 1 82.94 44 1 16649.00 56 4 4500.00 74 3 1600.00 744 2 = I might be tempted to take the following approach: If your data is a matrix, coerce it to a data frame first. Let's call that 'DF'. str(DF) 'data.frame': 44 obs. of 3 variables: $ x: num 15807 15753 12894 8427 5706 ... $ y: num 12.5 33.5 1.5 22.2 333 560 670 124 104 204 ... $ index: int 4 4 3 3 3 2 2 1 1 1 ... Now use split() to break up the data frame into a list of 4 sub-dataframes, based upon the index value. We can use scale() within a lapply() loop to center the 'x' and 'y' columns for each sub-dataframe: DF.ctr - lapply(split(DF[, -3], DF$index), scale, scale = FALSE) str(DF.ctr) List of 4 $ 1: num [1:8, 1:2] 138.5 58.2 38.2 -94.2 -131.1 ... ..- attr(*, dimnames)=List of 2 .. ..$ : chr [1:8] 8 9 10 14 ... .. ..$ : chr [1:2] x y ..- attr(*, scaled:center)= Named num [1:2] 157.2 81.7 .. ..- attr(*, names)= chr [1:2] x y $ 2: num [1:16, 1:2] 1469 1129 1727 -1291 -1371 ... ..- attr(*, dimnames)=List of 2 .. ..$ : chr [1:16] 6 7 11 12 ... .. ..$ : chr [1:2] x y ..- attr(*, scaled:center)= Named num [1:2] 2513 230 .. ..- attr(*, names)= chr [1:2] x y $ 3: num [1:13, 1:2] 5879 1413 -1308 3906 -870 ... ..- attr(*, dimnames)=List of 2 .. ..$ : chr [1:13] 3 4 5 20 ... .. ..$ : chr [1:2] x y ..- attr(*, scaled:center)= Named num [1:2] 7014 1352 .. ..- attr(*, names)= chr [1:2] x y $ 4: num [1:7, 1:2] -6262 -6317 -2393 17931 7431 ... ..- attr(*, dimnames)=List of 2 .. ..$ : chr [1:7] 1 2 19 23 ... .. ..$ : chr [1:2] x y ..- attr(*, scaled:center)= Named num [1:2] 2206943 .. ..- attr(*, names)= chr [1:2] x y Now, create a new single DF comprised of the sub-dataframes from DF.ctr: DF.new - do.call(rbind, DF.ctr) Define colnames: colnames(DF.new) - c(x-mean, y-mean) str(DF.new) num [1:44, 1:2] 138.5 58.2 38.2 -94.2 -131.1 ... - attr(*, dimnames)=List of 2 ..$ : chr [1:44] 8 9 10 14 ... ..$ : chr [1:2] x-mean y-mean Now, use merge() to join DF and DF.new by the rownames: DF.final - merge(DF, DF.new, by = row.names) DF.final Row.namesx y index x-mean y-mean 1 1 15807.24 12.50 4 -6262.12857 -30.498571 2 10 195.40 204.00 138.22750 122.35 3 11 4240.21 22.40 2 1726.93188 -208.037500 4 12 1222.72 45.90 2 -1290.55812 -184.537500 5 13 1142.26 23.60 2 -1371.01812 -206.837500 6 1463.00 90.10 1 -94.17250 8.45 7 15 1216.00 82.40 2 -1297.27812 -148.037500 8 16 2769.60 111.00 2 256.32188 -119.437500 9 17 1790.46 34.70 2 -722.81812 -195.737500 101826.10 26.10 1 -131.07250 -55.55 1119 19676.830.99 4 -2392.53857 -42.008571 12 2 15752.51 33.50 4 -6316.85857-9.498571 1320 10920.60
Re: [R] Urgent Help needed
Thanks all. it works. Just one more thing: if you look to this out put, by(data1[,2:3], data1[,4], cor)[1] $`1` XY X 1.0000.4400451 Y 0.4400451 1.000 Q. How I can just pick the value of the correlation 0.4400451 from this output and call it sat corxy. Once again thank you all so much for your helps. Abou == AbouEl-Makarim Aboueissa, Ph.D. Assistant Professor of Statistics Department of Mathematics Statistics University of Southern Maine 96 Falmouth Street P.O. Box 9300 Portland, ME 04104-9300 Tel: (207) 228-8389 Email: [EMAIL PROTECTED] [EMAIL PROTECTED] Office: 301C Payson Smith Henrique Dallazuanna [EMAIL PROTECTED] 8/16/2007 2:05 PM For the 2nd item, perhaps: by(df[,1:2], df$index, FUN=cor) where df is your data.frame. -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O On 16/08/07, AbouEl-Makarim Aboueissa [EMAIL PROTECTED] wrote: Dear All: Urgent help is needed. I have a data set in matrix format of three columns: X, Y and index of four groups (1,2,3,4). What I need to do is the following; 1- How I can subtract the sample mean of each group indexed 1,2,3,4 from the corresponding data values of this group and create new columns say X-sample mean and Y-sample mean? I tried to use the tapply but I have some difficulties to restore the new data 2- How I can use the tapply if possible or any other R-function to find the correlation coefficient between the X and Y columns for each group indexed 1,2,3,4.? Could not use the tapply. I attached part of the data as txt file. Thank you so much for your attention to this matter, and I look forward to hear from you soon. Regards, Abou Data: x y index 15807.2412.54 15752.5133.54 12893.7601.53 8426.88 22.23 5706.24 333 3 3982.08 560 2 3642.62 670 2 295.68 124 1 215.40 104 1 195.40 204 1 4240.21 22.42 1222.72 45.92 1142.26 23.62 63.00 90.11 1216.00 82.42 2769.60 111 2 1790.46 34.72 26.10 26.10 1 19676.830.994 10920.60203 3 6144.00 46 3 4534.48 4534.48 3 4.0065 4 29500.0056 4 17100.0077 4 9000.00 435 3 6300.00 84 3 3962.88 334 2 5690.00 653 3 3736.00 233 2 2750.00 22 2 1316.00 345 2 4595.00 4595.00 3 5928.00 45 3 2645.70 0.002 2580.24 454 2 6547.34 6547.34 3 1615.68 5 2 194.06 55 1 184.80 6 1 82.94 44 1 16649.0056 4 4500.00 74 3 1600.00 744 2 = == AbouEl-Makarim Aboueissa, Ph.D. Assistant Professor of Statistics Department of Mathematics Statistics University of Southern Maine 96 Falmouth Street P.O. Box 9300 Portland, ME 04104-9300 Tel: (207) 228-8389 Email: [EMAIL PROTECTED] [EMAIL PROTECTED] Office: 301C Payson Smith __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Urgent Help needed
Hi, try this: by(df[,1:2], df$index, FUN=function(x)cor(x[1],x[2])) -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O On 16/08/07, AbouEl-Makarim Aboueissa [EMAIL PROTECTED] wrote: Thanks all. it works. Just one more thing: if you look to this out put, by(data1[,2:3], data1[,4], cor)[1] $`1` XY X 1.0000.4400451 Y 0.4400451 1.000 Q. How I can just pick the value of the correlation 0.4400451 from this output and call it sat corxy. Once again thank you all so much for your helps. Abou == AbouEl-Makarim Aboueissa, Ph.D. Assistant Professor of Statistics Department of Mathematics Statistics University of Southern Maine 96 Falmouth Street P.O. Box 9300 Portland, ME 04104-9300 Tel: (207) 228-8389 Email: [EMAIL PROTECTED] [EMAIL PROTECTED] Office: 301C Payson Smith Henrique Dallazuanna [EMAIL PROTECTED] 8/16/2007 2:05 PM For the 2nd item, perhaps: by(df[,1:2], df$index, FUN=cor) where df is your data.frame. -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O On 16/08/07, AbouEl-Makarim Aboueissa [EMAIL PROTECTED] wrote: Dear All: Urgent help is needed. I have a data set in matrix format of three columns: X, Y and index of four groups (1,2,3,4). What I need to do is the following; 1- How I can subtract the sample mean of each group indexed 1,2,3,4 from the corresponding data values of this group and create new columns say X-sample mean and Y-sample mean? I tried to use the tapply but I have some difficulties to restore the new data 2- How I can use the tapply if possible or any other R-function to find the correlation coefficient between the X and Y columns for each group indexed 1,2,3,4.? Could not use the tapply. I attached part of the data as txt file. Thank you so much for your attention to this matter, and I look forward to hear from you soon. Regards, Abou Data: x y index 15807.2412.54 15752.5133.54 12893.7601.53 8426.88 22.23 5706.24 333 3 3982.08 560 2 3642.62 670 2 295.68 124 1 215.40 104 1 195.40 204 1 4240.21 22.42 1222.72 45.92 1142.26 23.62 63.00 90.11 1216.00 82.42 2769.60 111 2 1790.46 34.72 26.10 26.10 1 19676.830.994 10920.60203 3 6144.00 46 3 4534.48 4534.48 3 4.0065 4 29500.0056 4 17100.0077 4 9000.00 435 3 6300.00 84 3 3962.88 334 2 5690.00 653 3 3736.00 233 2 2750.00 22 2 1316.00 345 2 4595.00 4595.00 3 5928.00 45 3 2645.70 0.002 2580.24 454 2 6547.34 6547.34 3 1615.68 5 2 194.06 55 1 184.80 6 1 82.94 44 1 16649.0056 4 4500.00 74 3 1600.00 744 2 = == AbouEl-Makarim Aboueissa, Ph.D. Assistant Professor of Statistics Department of Mathematics Statistics University of Southern Maine 96 Falmouth Street P.O. Box 9300 Portland, ME 04104-9300 Tel: (207) 228-8389 Email: [EMAIL PROTECTED] [EMAIL PROTECTED] Office: 301C Payson Smith __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Urgent: How to obtain the Consistent Standard Errors after apply 2SLS through tsls() from sem or systemfit(2SLS) without this error message !!!!!!!!!!!!!
Hi, I am trying to obtain the heteroskedasticity consitent standard errors (HCSE) after apply 2SLS. I obtain 2SLS through tsls from package sem or systemfit: tsls library (sem) Reg2SLS -tsls(LnP~Sc+Ag+Ag2+Var+R+D,~I2+Ag+Ag2+Var+R+D) summary (Reg2SLS) systemfit library (systemfit) RS - LnP~Sc+Ag+Ag2+Var+R+D Inst - ~I2+Ag+Ag2+Var+R+D labels -list(RS) system -list(RS) Reg2SLS - systemfit(2SLS, system, labels, Inst, saveMemory=TRUE) summary (Reg2SLS) If I try to obtain the HCSE with robcov I obtain the following error message in both cases: Error in rep.default(1, p) : rep() incorrect type for second argument If I tried to apply vcovHAC or vcovHC in the systemfit output of 2SLS I receive the following messages of errors respectively: Error in estfun(x) : no applicable method for estfun (for vcovHAC) Error in terms.default(object) : no terms component (for vcovHC) If somebody can help me to solve this problem I will thank you a lot. Best regards Guillermo [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Urgent: How to obtain the Consistent Standard Errors after apply 2SLS through tsls() from sem or systemfit(2SLS) without this error message !!!!!!!!!!!!!
Hi, I am trying to obtain the heteroskedasticity consitent standard errors (HCSE) after apply 2SLS. I obtain 2SLS through tsls from package sem or systemfit: tsls library (sem) Reg2SLS -tsls(LnP~Sc+Ag+Ag2+Var+R+D,~I2+Ag+Ag2+Var+R+D) summary (Reg2SLS) systemfit library (systemfit) RS - LnP~Sc+Ag+Ag2+Var+R+D Inst - ~I2+Ag+Ag2+Var+R+D labels -list(RS) system -list(RS) Reg2SLS - systemfit(2SLS, system, labels, Inst, saveMemory=TRUE) summary (Reg2SLS) If I try to obtain the HCSE with robcov I obtain the following error message in both cases: Error in rep.default(1, p) : rep() incorrect type for second argument If I tried to apply vcovHAC or vcovHC in the systemfit output of 2SLS I receive the following messages of errors respectively: Error in estfun(x) : no applicable method for estfun (for vcovHAC) Error in terms.default(object) : no terms component (for vcovHC) If somebody can help me to solve this problem I will thank you a lot. Best regards Guillermo [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] urgent
Hello R Users, I have two sets of values x - c(7, 7 , 8, 9, 15, 17, 18) y - c(7, 8, 9, 15, 17, 19, 20, 20, 25, 23, 22) I am able to create multi histogram using multhist(). But not able to control the 'xlim'. ie the xaxis is showing 7.5, 13, 18, 23 1st on what basis it is calculated 2nd I want it to be like 7 8 9 15 17 and so on Can any one help me With Regards Subhabrata Pal [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] urgent
1) R-help mailing list is run entirely by volunteers, so requests such
as urgent may sound rude
2) Use an informative subject line please !
3) Please state which package multhist comes from.
4) Please show your call to multhist.
5) multhist does _histograms_ by aggregating points within certain
intervals. In your case, you simply want a plot of your raw data. You
can use barplot directly via
multi.barplot - function( mylist, ... ){
u - unique( unlist( mylist ) )
tb - t(sapply( mylist, function(v) table(factor(v, levels=u)) ) )
barplot( tb, beside=TRUE, ... )
return(tb)
}
x - c(7, 7 , 8, 9, 15, 17, 18)
y - c(7, 8, 9, 15, 17, 19, 20, 20, 25, 23, 22)
z - c(8, 9, 9, 9, 31)
multi.barplot( list(x, y, z), col=1:3 )
legend( topright, legend=c(one, two, three), fill=1:3 )
Regards, Adai
On Tue, 2005-12-06 at 15:32 +0530, Subhabrata wrote:
Hello R Users,
I have two sets of values
x - c(7, 7 , 8, 9, 15, 17, 18)
y - c(7, 8, 9, 15, 17, 19, 20, 20, 25, 23, 22)
I am able to create multi histogram using
multhist(). But not able to control the 'xlim'.
ie the xaxis is showing 7.5, 13, 18, 23
1st on what basis it is calculated
2nd I want it to be like 7 8 9 15 17 and so on
Can any one help me
With Regards
Subhabrata Pal
[[alternative HTML version deleted]]
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Re: [R] urgent
I don't have an answer to your query, but I do have three suggestions: 1. Use a sensible subject line. This may be urgent to you, but I doubt that it is to anyone else. 2. Do indicate what package contains multhist(). I have no idea (nor do I know what a 'multi histogram' is). 3. Don't send HTML mail. People are very willing to help, but you do have to make it easy to do so. Peter Ehlers Subhabrata wrote: Hello R Users, I have two sets of values x - c(7, 7 , 8, 9, 15, 17, 18) y - c(7, 8, 9, 15, 17, 19, 20, 20, 25, 23, 22) I am able to create multi histogram using multhist(). But not able to control the 'xlim'. ie the xaxis is showing 7.5, 13, 18, 23 1st on what basis it is calculated 2nd I want it to be like 7 8 9 15 17 and so on Can any one help me With Regards Subhabrata Pal [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] urgent request
Hi guys, I want to do weighted conditional logistic regression, but clogit do not accept weights. Would you tell me whether there are any ways to do this? Thanks a lot in advance, Spring __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] urgent
Hello, My name is Mrs. Jennifer Wilson i am a dying woman who have decided to donate what i have to you/ church.I am 59 years old and i was diagnosed for cancer for about 2 years ago,immediately after the death of my husband, who has left me everything he worked for. I have been touched by God to donate from what i have inherited from my late husband to the you for the god work of God,rather than allow my relatives to use my husband hard earned funds ungodly.Please pray,that the good Lord forgive me my sins.I have asked God to forgive me and i beleive he has because He is a merciful God. I will be going in for an operation in less than one hour. I decided to WILL/donate the sum of $1,500,000 (One million five hundred thousand dollars) to you for the good work of the lord, and also to help the motherless and less privilege and also for the assistance of the widows according to (JAMES 1:27). At the moment i cannot take any telephone calls right now due to the fact that my relatives are around me and my health status.I have adjusted my WILL and my lawyer is aware i have changed my will you and he will arrange the transfer of the funds from my account to you. I wish you all the best and may the good Lord bless you abundantly, and please use the funds well and always extend the good work to others. Contact my lawyer with this specified email [EMAIL PROTECTED] and tell him that i have WILLED ($1,500,000.00) to you and i have also notified him that i am WILLING that amount to you for a specific and good work.I know i dont know you but i have been directed to do this.Thanks and God bless. NB: I will appreciate your utmost confidentiality in this matter until the task is accomplished as I don't want anything that will Jeopardize my last wish. And Also I will be contacting with you by email as I don't want my relation or anybody to know because they are always around me. Regards, Jennifer Wilson __ [EMAIL PROTECTED] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Spam {Re: [R] urgent}
I'm sorry for this spam that astonishingly came through to the
mailing list.
It seems these guys have been exercising against known spam
filters and achieved more than in the past.
Also, recent versions of our spamfilter have been tuned such as
to rather produce a few false negatives {spam not detected}
with hardly ever any false positive {non-spam not delivered to recipient},
which makes a lot of sense.
We (I and local e-mail administrators) do keep an eye on this,
me spending a little time for manual tuning, but we do not
want to allocate too much time for this.
PLEASE do not reply to this e-mail (at least not to R-help!).
It is *not* relevant to R and not worth the time (also since too
many people think they know what they are talking about :-).
If you want, reply to me privately.
Martin Maechler, ETH Zurich
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[R] Urgent Help on Cumulant computation on two R.V's
Hey Now I am going to check the independence of random variables using cumulant function. So if R has such package or functions to calculate the sample cumulant of a random vector? Thanks a lot. Fred __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
