RE: [R] which.pmin?

2005-01-24 Thread Huntsinger, Reid
That's what "ifelse" is for:

ifelse(fpr(b, k.floor) < fpr(b, k.ceiling), k.floor, k.ceiling)

Reid Huntsinger



-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Seung Jun
Sent: Friday, January 21, 2005 5:27 PM
To: R-help@stat.math.ethz.ch
Subject: [R] which.pmin?


I have two vectors (k.floor and k.ceiling) of integers of the same
length, and a function (fpr).

b <- 10:40
k.floor <- floor(log(2) * b)
k.ceiling <- ceiling(log(2) * b)
fpr.floor <- fpr(b, k.floor)
fpr.ceiling <- fpr(b, k.ceiling)

If R had a element-wise ternary function, I'd like to do something like 
this:

(fpr.floor < fpr.ceiling) ? k.floor : k.ceiling

That is, I'd like to go through the two vectors in parallel, picking
the one that returns the lower value of fpr. Failing to find such a
function, I wrote the following two lines:

ind <- sapply(data.frame(rbind(fpr.floor,fpr.ceiling)), which.min)
opt.k <- cbind(k.floor,k.ceiling)[1:length(ind)+length(ind)*(ind-1)]

opt.k is the vector I want, but I guess I abuse some functions here.
I'd like to ask the experts, What is the proper R-way to do this?

The API should be like "which.pmin(FUN, X, Y, ...)" that returns a
vector of the same length as X (and Y), provided that X, Y, ... have
the same length. Please fill the function body.

Seung

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Re: [R] which.pmin?

2005-01-21 Thread Rolf Turner

If I understand you correctly you could just do

ifelse(fpr.floor < fpr.ceiling, k.floor, k.ceiling)

cheers,

Rolf Turner
[EMAIL PROTECTED]

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Seung Jun wrote:

> I have two vectors (k.floor and k.ceiling) of integers of the same
> length, and a function (fpr).
> 
> b <- 10:40
> k.floor <- floor(log(2) * b)
> k.ceiling <- ceiling(log(2) * b)
> fpr.floor <- fpr(b, k.floor)
> fpr.ceiling <- fpr(b, k.ceiling)
> 
> If R had a element-wise ternary function, I'd like to do something like 
> this:
> 
> (fpr.floor < fpr.ceiling) ? k.floor : k.ceiling
> 
> That is, I'd like to go through the two vectors in parallel, picking
> the one that returns the lower value of fpr. Failing to find such a
> function, I wrote the following two lines:
> 
> ind <- sapply(data.frame(rbind(fpr.floor,fpr.ceiling)), which.min)
> opt.k <- cbind(k.floor,k.ceiling)[1:length(ind)+length(ind)*(ind-1)]
> 
> opt.k is the vector I want, but I guess I abuse some functions here.
> I'd like to ask the experts, What is the proper R-way to do this?
> 
> The API should be like "which.pmin(FUN, X, Y, ...)" that returns a
> vector of the same length as X (and Y), provided that X, Y, ... have
> the same length. Please fill the function body.

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Re: [R] which.pmin?

2005-01-21 Thread Marc Schwartz
On Fri, 2005-01-21 at 17:26 -0500, Seung Jun wrote:
> I have two vectors (k.floor and k.ceiling) of integers of the same
> length, and a function (fpr).
> 
> b <- 10:40
> k.floor <- floor(log(2) * b)
> k.ceiling <- ceiling(log(2) * b)
> fpr.floor <- fpr(b, k.floor)
> fpr.ceiling <- fpr(b, k.ceiling)
> 
> If R had a element-wise ternary function, I'd like to do something like 
> this:
> 
> (fpr.floor < fpr.ceiling) ? k.floor : k.ceiling
> 
> That is, I'd like to go through the two vectors in parallel, picking
> the one that returns the lower value of fpr. Failing to find such a
> function, I wrote the following two lines:
> 
> ind <- sapply(data.frame(rbind(fpr.floor,fpr.ceiling)), which.min)
> opt.k <- cbind(k.floor,k.ceiling)[1:length(ind)+length(ind)*(ind-1)]
> 
> opt.k is the vector I want, but I guess I abuse some functions here.
> I'd like to ask the experts, What is the proper R-way to do this?
> 
> The API should be like "which.pmin(FUN, X, Y, ...)" that returns a
> vector of the same length as X (and Y), provided that X, Y, ... have
> the same length. Please fill the function body.

I believe that ifelse() is what you seek. Try:

  ifelse(fpr.floor < fpr.ceiling, k.floor, k.ceiling)

See ?ifelse for more information.

HTH,

Marc Schwartz

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Re: [R] which.pmin?

2005-01-21 Thread Thomas Lumley
On Fri, 21 Jan 2005, Seung Jun wrote:
If R had a element-wise ternary function, I'd like to do something like this:
  (fpr.floor < fpr.ceiling) ? k.floor : k.ceiling
R does:  ifelse()
-thomas
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