Re: [R] Multiple Conditional Tranformations
Gabor, Those are handy variations! Perhaps my brain in still in SAS mode on this. I'm expecting something like the code below that checks for male only once, checks for female only when not male (skipping NAs) and does all formulas under the appropriate conditions. The formulas I made up to keep the code short may not be as easily modified to let the logical 0/1 values fix them. if gender==m then do; Score1=... Score2= ... end; else if gender==f then do; Score1=... Score2= ... end; R may not have anything quite like that. R certainly has many other features that SAS lacks. Thanks, Bob = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc, News: http://listserv.utk.edu/archives/statnews.html = -Original Message- From: Gabor Grothendieck [mailto:[EMAIL PROTECTED] Sent: Saturday, November 25, 2006 12:39 AM To: Muenchen, Robert A (Bob) Cc: r-help@stat.math.ethz.ch Subject: Re: [R] Multiple Conditional Tranformations And here is a variation: transform(mydata, score1 = (2 + (gender == m)) * q1 + q2, score2 = score1 + 0.5 * q1 ) or transform( transform(mydata, score1 = (2 + (gender == m)) * q1 + q2), score2 = score1 + 0.5 * q1 ) On 11/25/06, Gabor Grothendieck [EMAIL PROTECTED] wrote: Try this: transform(mydata, score1 = (2 + (gender == m)) * q1 + q2, score2 = (2.5 + (gender == m)) * q1 + q2 ) On 11/24/06, Muenchen, Robert A (Bob) [EMAIL PROTECTED] wrote: Mark, I finally got that approach to work by spreading the logical condition everywhere. That gets the lengths to match. Still, I can't help but think there must be a way to specify the logic once per condition. Thanks, Bob mydata$score1-numeric(mydata$q1) #just initializing. mydata$score2-numeric(mydata$q1) mydata$score1-NA mydata$score2-NA mydata mydata$score1[mydata$gender == f]- 2*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score2[mydata$gender == f]-2.5*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score1[mydata$gender == m]-3*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata$score2[mydata$gender == m]-3.5*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc, News: http://listserv.utk.edu/archives/statnews.html = -Original Message- From: Leeds, Mark (IED) [mailto:[EMAIL PROTECTED] Sent: Friday, November 24, 2006 8:45 PM To: Muenchen, Robert A (Bob) Subject: RE: [R] Multiple Conditional Tranformations I'm not sure if I understand your question but I don't think you need iflelse statements. myscore-numeric(q1) ( because I'm not sure how to initialize a list so initialize a vector with q1 elements ) myscore-NA ( I think this should set all the values in myscore to NA ) myscore[mydata$gender == f]-2*mydata$q1 + mydata$q2 myscore[mydata$gender == m]-3*mydata$q1 + mydata$q2 the above should do what you do in the first part of your code but I don't know if that was your question ? also, it does it making myscore a vector because I didn't know how to initialize a list. Someone else may goive a better solution. I'm no expert. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Muenchen, Robert A (Bob) Sent: Friday, November 24, 2006 8:27 PM To: r-help@stat.math.ethz.ch Subject: [R] Multiple Conditional Tranformations Greetings, I'm learning R and I'm stuck on a basic concept: how to specify a logical condition once and then perform multiple transformations under that condition. The program below is simplified to demonstrate the goal. Its results are exactly what I want, but I would like to check the logical state of gender only once and create both (or any number of) scores at once. mystring- (id,group,gender,q1,q2,q3,q4 01,1,f,2,2,5,4 02,2,f,2,1,4,5 03,1,f,2,2,4,4 04,2,f,1,1,5,5 05,1,m,4,5,4, 06,2,m,5,4,5,5 07,1,m,3,3,4,5 08,2,m,5,5,5,4) mydata-read.table(textConnection(mystring),header=TRUE,sep=,,row.name s=id) mydata #Create score1 so that it differs for males and females: mydata$score1 - ifelse( mydata$gender==f , (mydata$score1 - (2*mydata$q1)+mydata
Re: [R] Multiple Conditional Tranformations
Firstly your outline does not check once, it checks twice. First it check for m and then it redundantly checks for f. On the other hand the two variations in my post do check once. Although substantially longer than the solutions in my prior posts, if you want the style shown in your post try this: mydata2 - cbind(mydata, score1 = 0, score2 = 0) is.m - mydata$gender == m mydata2[is.m, ] - transform(mydata[is.m, ], score1 = 3 * q1 + q2, score2 = 3.5 * q1 + q2 ) mydata2[!is.m,] - transform(mydata2[!is.m, ], score1 = 2 * q1 + q2, score2 = 2.5 * q1 + q2 ) On 11/25/06, Muenchen, Robert A (Bob) [EMAIL PROTECTED] wrote: Gabor, Those are handy variations! Perhaps my brain in still in SAS mode on this. I'm expecting something like the code below that checks for male only once, checks for female only when not male (skipping NAs) and does all formulas under the appropriate conditions. The formulas I made up to keep the code short may not be as easily modified to let the logical 0/1 values fix them. if gender==m then do; Score1=... Score2= ... end; else if gender==f then do; Score1=... Score2= ... end; R may not have anything quite like that. R certainly has many other features that SAS lacks. Thanks, Bob = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc, News: http://listserv.utk.edu/archives/statnews.html = -Original Message- From: Gabor Grothendieck [mailto:[EMAIL PROTECTED] Sent: Saturday, November 25, 2006 12:39 AM To: Muenchen, Robert A (Bob) Cc: r-help@stat.math.ethz.ch Subject: Re: [R] Multiple Conditional Tranformations And here is a variation: transform(mydata, score1 = (2 + (gender == m)) * q1 + q2, score2 = score1 + 0.5 * q1 ) or transform( transform(mydata, score1 = (2 + (gender == m)) * q1 + q2), score2 = score1 + 0.5 * q1 ) On 11/25/06, Gabor Grothendieck [EMAIL PROTECTED] wrote: Try this: transform(mydata, score1 = (2 + (gender == m)) * q1 + q2, score2 = (2.5 + (gender == m)) * q1 + q2 ) On 11/24/06, Muenchen, Robert A (Bob) [EMAIL PROTECTED] wrote: Mark, I finally got that approach to work by spreading the logical condition everywhere. That gets the lengths to match. Still, I can't help but think there must be a way to specify the logic once per condition. Thanks, Bob mydata$score1-numeric(mydata$q1) #just initializing. mydata$score2-numeric(mydata$q1) mydata$score1-NA mydata$score2-NA mydata mydata$score1[mydata$gender == f]- 2*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score2[mydata$gender == f]-2.5*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score1[mydata$gender == m]-3*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata$score2[mydata$gender == m]-3.5*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc, News: http://listserv.utk.edu/archives/statnews.html = -Original Message- From: Leeds, Mark (IED) [mailto:[EMAIL PROTECTED] Sent: Friday, November 24, 2006 8:45 PM To: Muenchen, Robert A (Bob) Subject: RE: [R] Multiple Conditional Tranformations I'm not sure if I understand your question but I don't think you need iflelse statements. myscore-numeric(q1) ( because I'm not sure how to initialize a list so initialize a vector with q1 elements ) myscore-NA ( I think this should set all the values in myscore to NA ) myscore[mydata$gender == f]-2*mydata$q1 + mydata$q2 myscore[mydata$gender == m]-3*mydata$q1 + mydata$q2 the above should do what you do in the first part of your code but I don't know if that was your question ? also, it does it making myscore a vector because I didn't know how to initialize a list. Someone else may goive a better solution. I'm no expert. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Muenchen, Robert A (Bob) Sent: Friday, November 24, 2006 8:27 PM To: r-help@stat.math.ethz.ch Subject: [R] Multiple Conditional Tranformations Greetings, I'm learning R and I'm stuck on a basic concept: how
Re: [R] Multiple Conditional Tranformations
That's exactly what I'm looking for. Thanks so much for taking the time to do it that way. On the redundancy issue, I think SAS checks the else if condition only if the original if is false. The check for f when not m I put in only to exclude missing values for gender. Thanks!! Bob -Original Message- From: Gabor Grothendieck [mailto:[EMAIL PROTECTED] Sent: Saturday, November 25, 2006 7:37 AM To: Muenchen, Robert A (Bob) Cc: r-help@stat.math.ethz.ch Subject: Re: [R] Multiple Conditional Tranformations Firstly your outline does not check once, it checks twice. First it check for m and then it redundantly checks for f. On the other hand the two variations in my post do check once. Although substantially longer than the solutions in my prior posts, if you want the style shown in your post try this: mydata2 - cbind(mydata, score1 = 0, score2 = 0) is.m - mydata$gender == m mydata2[is.m, ] - transform(mydata[is.m, ], score1 = 3 * q1 + q2, score2 = 3.5 * q1 + q2 ) mydata2[!is.m,] - transform(mydata2[!is.m, ], score1 = 2 * q1 + q2, score2 = 2.5 * q1 + q2 ) On 11/25/06, Muenchen, Robert A (Bob) [EMAIL PROTECTED] wrote: Gabor, Those are handy variations! Perhaps my brain in still in SAS mode on this. I'm expecting something like the code below that checks for male only once, checks for female only when not male (skipping NAs) and does all formulas under the appropriate conditions. The formulas I made up to keep the code short may not be as easily modified to let the logical 0/1 values fix them. if gender==m then do; Score1=... Score2= ... end; else if gender==f then do; Score1=... Score2= ... end; R may not have anything quite like that. R certainly has many other features that SAS lacks. Thanks, Bob = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc, News: http://listserv.utk.edu/archives/statnews.html = -Original Message- From: Gabor Grothendieck [mailto:[EMAIL PROTECTED] Sent: Saturday, November 25, 2006 12:39 AM To: Muenchen, Robert A (Bob) Cc: r-help@stat.math.ethz.ch Subject: Re: [R] Multiple Conditional Tranformations And here is a variation: transform(mydata, score1 = (2 + (gender == m)) * q1 + q2, score2 = score1 + 0.5 * q1 ) or transform( transform(mydata, score1 = (2 + (gender == m)) * q1 + q2), score2 = score1 + 0.5 * q1 ) On 11/25/06, Gabor Grothendieck [EMAIL PROTECTED] wrote: Try this: transform(mydata, score1 = (2 + (gender == m)) * q1 + q2, score2 = (2.5 + (gender == m)) * q1 + q2 ) On 11/24/06, Muenchen, Robert A (Bob) [EMAIL PROTECTED] wrote: Mark, I finally got that approach to work by spreading the logical condition everywhere. That gets the lengths to match. Still, I can't help but think there must be a way to specify the logic once per condition. Thanks, Bob mydata$score1-numeric(mydata$q1) #just initializing. mydata$score2-numeric(mydata$q1) mydata$score1-NA mydata$score2-NA mydata mydata$score1[mydata$gender == f]- 2*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score2[mydata$gender == f]-2.5*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score1[mydata$gender == m]-3*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata$score2[mydata$gender == m]-3.5*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc, News: http://listserv.utk.edu/archives/statnews.html = -Original Message- From: Leeds, Mark (IED) [mailto:[EMAIL PROTECTED] Sent: Friday, November 24, 2006 8:45 PM To: Muenchen, Robert A (Bob) Subject: RE: [R] Multiple Conditional Tranformations I'm not sure if I understand your question but I don't think you need iflelse statements. myscore-numeric(q1) ( because I'm not sure how to initialize a list so initialize a vector with q1 elements ) myscore-NA ( I think this should set all the values in myscore to NA ) myscore[mydata$gender == f]-2*mydata$q1 + mydata$q2 myscore[mydata$gender == m]-3*mydata$q1 + mydata$q2 the above should do what you do in the first part of your code but I don't know
Re: [R] Multiple Conditional Tranformations
Here are some additional solutions. It appears that the SAS code is performing
the transformation row by row and for each row the code in your post is
specifying the transformation so if you want to do it that way we
could use 'by'
like this (where this time we have also added NA processing for the gender):
do.call(rbind, by(mydata, 1:nrow(mydata), function(x)
switch(as.character(x$gender),
m = transform(x, score1 = 3*q1+q2, score2 = 3.5*q1+q2),
f = transform(x, score1 = 2*q1+q2, score2 = 2.5*q1+q2),
NA)
))
# or this somewhat longer version:
do.call(rbind, by(mydata, 1:nrow(mydata), function(x) with(x, {
if (is.na(gender)) {
score1 - score2 - NA
} else if (gender == m) {
score1 = 3 * q1 + q2
score2 = 3.5 * q1 + q2
} else if (gender == f) {
score1 = 2 * q1 + q2
score2 = 2.5 * q1 + q2
}
cbind(x, score1, score2)
})))
On 11/25/06, Muehnchen, Robert A (Bob) [EMAIL PROTECTED] wrote:
That's exactly what I'm looking for. Thanks so much for taking the time
to do it that way.
On the redundancy issue, I think SAS checks the else if condition only
if the original if is false. The check for f when not m I put in only
to exclude missing values for gender.
Thanks!!
Bob
-Original Message-
From: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
Sent: Saturday, November 25, 2006 7:37 AM
To: Muenchen, Robert A (Bob)
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] Multiple Conditional Tranformations
Firstly your outline does not check once, it checks twice. First it
check for m and then it redundantly checks for f. On the other
hand the two variations in my post do check once.
Although substantially longer than the solutions in my prior posts,
if you want the style shown in your post try this:
mydata2 - cbind(mydata, score1 = 0, score2 = 0)
is.m - mydata$gender == m
mydata2[is.m, ] - transform(mydata[is.m, ],
score1 = 3 * q1 + q2,
score2 = 3.5 * q1 + q2
)
mydata2[!is.m,] - transform(mydata2[!is.m, ],
score1 = 2 * q1 + q2,
score2 = 2.5 * q1 + q2
)
On 11/25/06, Muenchen, Robert A (Bob) [EMAIL PROTECTED] wrote:
Gabor,
Those are handy variations! Perhaps my brain in still in SAS mode on
this. I'm expecting something like the code below that checks for male
only once, checks for female only when not male (skipping NAs) and
does
all formulas under the appropriate conditions. The formulas I made up
to
keep the code short may not be as easily modified to let the logical
0/1 values fix them.
if gender==m then do;
Score1=...
Score2=
...
end;
else if gender==f then do;
Score1=...
Score2=
...
end;
R may not have anything quite like that. R certainly has many other
features that SAS lacks.
Thanks,
Bob
=
Bob Muenchen (pronounced Min'-chen), Manager
Statistical Consulting Center
U of TN Office of Information Technology
200 Stokely Management Center, Knoxville, TN 37996-0520
Voice: (865) 974-5230
FAX: (865) 974-4810
Email: [EMAIL PROTECTED]
Web: http://oit.utk.edu/scc,
News: http://listserv.utk.edu/archives/statnews.html
=
-Original Message-
From: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
Sent: Saturday, November 25, 2006 12:39 AM
To: Muenchen, Robert A (Bob)
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] Multiple Conditional Tranformations
And here is a variation:
transform(mydata,
score1 = (2 + (gender == m)) * q1 + q2,
score2 = score1 + 0.5 * q1
)
or
transform(
transform(mydata, score1 = (2 + (gender == m)) * q1 + q2),
score2 = score1 + 0.5 * q1
)
On 11/25/06, Gabor Grothendieck [EMAIL PROTECTED] wrote:
Try this:
transform(mydata,
score1 = (2 + (gender == m)) * q1 + q2,
score2 = (2.5 + (gender == m)) * q1 + q2
)
On 11/24/06, Muenchen, Robert A (Bob) [EMAIL PROTECTED] wrote:
Mark,
I finally got that approach to work by spreading the logical
condition
everywhere. That gets the lengths to match. Still, I can't help
but
think there must be a way to specify the logic once per condition.
Thanks,
Bob
mydata$score1-numeric(mydata$q1) #just initializing.
mydata$score2-numeric(mydata$q1)
mydata$score1-NA
mydata$score2-NA
mydata
mydata$score1[mydata$gender == f]-
2*mydata$q1[mydata$gender==f] +
mydata$q2[mydata$gender==f]
mydata$score2[mydata$gender ==
f]-2.5*mydata$q1[mydata$gender==f] +
mydata$q2[mydata$gender==f]
mydata$score1[mydata$gender ==
m]-3*mydata$q1[mydata$gender==m]
+
mydata$q2[mydata$gender==m]
mydata$score2[mydata$gender ==
m]-3.5*mydata$q1[mydata$gender==m] +
mydata$q2[mydata$gender==m]
mydata
Re: [R] Multiple Conditional Tranformations
Here is a correction:
do.call(rbind, by(mydata, 1:nrow(mydata), function(x)
switch(as.character(x$gender),
m = transform(x, score1 = 3*q1+q2, score2 = 3.5*q1+q2),
f = transform(x, score1 = 2*q1+q2, score2 = 2.5*q1+q2),
transform(x, score1 = NA, score2 = NA))
))
On 11/25/06, Gabor Grothendieck [EMAIL PROTECTED] wrote:
Here are some additional solutions. It appears that the SAS code is
performing
the transformation row by row and for each row the code in your post is
specifying the transformation so if you want to do it that way we
could use 'by'
like this (where this time we have also added NA processing for the gender):
do.call(rbind, by(mydata, 1:nrow(mydata), function(x)
switch(as.character(x$gender),
m = transform(x, score1 = 3*q1+q2, score2 = 3.5*q1+q2),
f = transform(x, score1 = 2*q1+q2, score2 = 2.5*q1+q2),
NA)
))
# or this somewhat longer version:
do.call(rbind, by(mydata, 1:nrow(mydata), function(x) with(x, {
if (is.na(gender)) {
score1 - score2 - NA
} else if (gender == m) {
score1 = 3 * q1 + q2
score2 = 3.5 * q1 + q2
} else if (gender == f) {
score1 = 2 * q1 + q2
score2 = 2.5 * q1 + q2
}
cbind(x, score1, score2)
})))
On 11/25/06, Muehnchen, Robert A (Bob) [EMAIL PROTECTED] wrote:
That's exactly what I'm looking for. Thanks so much for taking the time
to do it that way.
On the redundancy issue, I think SAS checks the else if condition only
if the original if is false. The check for f when not m I put in only
to exclude missing values for gender.
Thanks!!
Bob
-Original Message-
From: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
Sent: Saturday, November 25, 2006 7:37 AM
To: Muenchen, Robert A (Bob)
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] Multiple Conditional Tranformations
Firstly your outline does not check once, it checks twice. First it
check for m and then it redundantly checks for f. On the other
hand the two variations in my post do check once.
Although substantially longer than the solutions in my prior posts,
if you want the style shown in your post try this:
mydata2 - cbind(mydata, score1 = 0, score2 = 0)
is.m - mydata$gender == m
mydata2[is.m, ] - transform(mydata[is.m, ],
score1 = 3 * q1 + q2,
score2 = 3.5 * q1 + q2
)
mydata2[!is.m,] - transform(mydata2[!is.m, ],
score1 = 2 * q1 + q2,
score2 = 2.5 * q1 + q2
)
On 11/25/06, Muenchen, Robert A (Bob) [EMAIL PROTECTED] wrote:
Gabor,
Those are handy variations! Perhaps my brain in still in SAS mode on
this. I'm expecting something like the code below that checks for male
only once, checks for female only when not male (skipping NAs) and
does
all formulas under the appropriate conditions. The formulas I made up
to
keep the code short may not be as easily modified to let the logical
0/1 values fix them.
if gender==m then do;
Score1=...
Score2=
...
end;
else if gender==f then do;
Score1=...
Score2=
...
end;
R may not have anything quite like that. R certainly has many other
features that SAS lacks.
Thanks,
Bob
=
Bob Muenchen (pronounced Min'-chen), Manager
Statistical Consulting Center
U of TN Office of Information Technology
200 Stokely Management Center, Knoxville, TN 37996-0520
Voice: (865) 974-5230
FAX: (865) 974-4810
Email: [EMAIL PROTECTED]
Web: http://oit.utk.edu/scc,
News: http://listserv.utk.edu/archives/statnews.html
=
-Original Message-
From: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
Sent: Saturday, November 25, 2006 12:39 AM
To: Muenchen, Robert A (Bob)
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] Multiple Conditional Tranformations
And here is a variation:
transform(mydata,
score1 = (2 + (gender == m)) * q1 + q2,
score2 = score1 + 0.5 * q1
)
or
transform(
transform(mydata, score1 = (2 + (gender == m)) * q1 + q2),
score2 = score1 + 0.5 * q1
)
On 11/25/06, Gabor Grothendieck [EMAIL PROTECTED] wrote:
Try this:
transform(mydata,
score1 = (2 + (gender == m)) * q1 + q2,
score2 = (2.5 + (gender == m)) * q1 + q2
)
On 11/24/06, Muenchen, Robert A (Bob) [EMAIL PROTECTED] wrote:
Mark,
I finally got that approach to work by spreading the logical
condition
everywhere. That gets the lengths to match. Still, I can't help
but
think there must be a way to specify the logic once per condition.
Thanks,
Bob
mydata$score1-numeric(mydata$q1) #just initializing.
mydata$score2-numeric(mydata$q1)
mydata$score1-NA
mydata$score2-NA
mydata
mydata$score1[mydata$gender == f
Re: [R] Multiple Conditional Tranformations
I have a program that is similar to your longer version, but I could
never get the syntax quite right. This will be a big help in
understanding how by works with functions.
Thanks,
Bob
-Original Message-
From: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
Sent: Saturday, November 25, 2006 11:11 AM
To: Muenchen, Robert A (Bob)
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] Multiple Conditional Tranformations
Here is a correction:
do.call(rbind, by(mydata, 1:nrow(mydata), function(x)
switch(as.character(x$gender),
m = transform(x, score1 = 3*q1+q2, score2 = 3.5*q1+q2),
f = transform(x, score1 = 2*q1+q2, score2 = 2.5*q1+q2),
transform(x, score1 = NA, score2 = NA))
))
On 11/25/06, Gabor Grothendieck [EMAIL PROTECTED] wrote:
Here are some additional solutions. It appears that the SAS code is
performing
the transformation row by row and for each row the code in your post
is
specifying the transformation so if you want to do it that way we
could use 'by'
like this (where this time we have also added NA processing for the
gender):
do.call(rbind, by(mydata, 1:nrow(mydata), function(x)
switch(as.character(x$gender),
m = transform(x, score1 = 3*q1+q2, score2 = 3.5*q1+q2),
f = transform(x, score1 = 2*q1+q2, score2 = 2.5*q1+q2),
NA)
))
# or this somewhat longer version:
do.call(rbind, by(mydata, 1:nrow(mydata), function(x) with(x, {
if (is.na(gender)) {
score1 - score2 - NA
} else if (gender == m) {
score1 = 3 * q1 + q2
score2 = 3.5 * q1 + q2
} else if (gender == f) {
score1 = 2 * q1 + q2
score2 = 2.5 * q1 + q2
}
cbind(x, score1, score2)
})))
On 11/25/06, Muehnchen, Robert A (Bob) [EMAIL PROTECTED] wrote:
That's exactly what I'm looking for. Thanks so much for taking the
time
to do it that way.
On the redundancy issue, I think SAS checks the else if condition
only
if the original if is false. The check for f when not m I put in
only
to exclude missing values for gender.
Thanks!!
Bob
-Original Message-
From: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
Sent: Saturday, November 25, 2006 7:37 AM
To: Muenchen, Robert A (Bob)
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] Multiple Conditional Tranformations
Firstly your outline does not check once, it checks twice. First it
check for m and then it redundantly checks for f. On the other
hand the two variations in my post do check once.
Although substantially longer than the solutions in my prior posts,
if you want the style shown in your post try this:
mydata2 - cbind(mydata, score1 = 0, score2 = 0)
is.m - mydata$gender == m
mydata2[is.m, ] - transform(mydata[is.m, ],
score1 = 3 * q1 + q2,
score2 = 3.5 * q1 + q2
)
mydata2[!is.m,] - transform(mydata2[!is.m, ],
score1 = 2 * q1 + q2,
score2 = 2.5 * q1 + q2
)
On 11/25/06, Muenchen, Robert A (Bob) [EMAIL PROTECTED] wrote:
Gabor,
Those are handy variations! Perhaps my brain in still in SAS mode
on
this. I'm expecting something like the code below that checks for
male
only once, checks for female only when not male (skipping NAs) and
does
all formulas under the appropriate conditions. The formulas I made
up
to
keep the code short may not be as easily modified to let the
logical
0/1 values fix them.
if gender==m then do;
Score1=...
Score2=
...
end;
else if gender==f then do;
Score1=...
Score2=
...
end;
R may not have anything quite like that. R certainly has many
other
features that SAS lacks.
Thanks,
Bob
=
Bob Muenchen (pronounced Min'-chen), Manager
Statistical Consulting Center
U of TN Office of Information Technology
200 Stokely Management Center, Knoxville, TN 37996-0520
Voice: (865) 974-5230
FAX: (865) 974-4810
Email: [EMAIL PROTECTED]
Web: http://oit.utk.edu/scc,
News: http://listserv.utk.edu/archives/statnews.html
=
-Original Message-
From: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
Sent: Saturday, November 25, 2006 12:39 AM
To: Muenchen, Robert A (Bob)
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] Multiple Conditional Tranformations
And here is a variation:
transform(mydata,
score1 = (2 + (gender == m)) * q1 + q2,
score2 = score1 + 0.5 * q1
)
or
transform(
transform(mydata, score1 = (2 + (gender == m)) * q1 + q2),
score2 = score1 + 0.5 * q1
)
On 11/25/06, Gabor Grothendieck [EMAIL PROTECTED] wrote:
Try this:
transform(mydata,
score1 = (2 + (gender == m)) * q1 + q2,
score2 = (2.5 + (gender == m)) * q1 + q2
)
On 11/24/06, Muenchen, Robert A (Bob) [EMAIL PROTECTED] wrote:
Mark,
I finally got that approach
Re: [R] Multiple Conditional Tranformations
Mark, Here's what I get when I try that approach. Thanks, Bob mydata$score1-numeric(mydata$q1) #just initializing. mydata$score2-numeric(mydata$q1) mydata$score1-NA mydata$score2-NA mydata group gender q1 q2 q3 q4 score1 score2 1 1 f 2 2 5 4 NA NA 2 2 f 2 1 4 5 NA NA 3 1 f 2 2 4 4 NA NA 4 2 f 1 1 5 5 NA NA 5 1 m 4 5 4 NA NA NA 6 2 m 5 4 5 5 NA NA 7 1 m 3 3 4 5 NA NA 8 2 m 5 5 5 4 NA NA mydata$score1[mydata$gender == f]-2*mydata$q1 + mydata$q2 Warning message: number of items to replace is not a multiple of replacement length mydata$score2[mydata$gender == f]-2.5*mydata$q1 + mydata$q2 Warning message: number of items to replace is not a multiple of replacement length mydata$score1[mydata$gender == m]-3*mydata$q1 + mydata$q2 Warning message: number of items to replace is not a multiple of replacement length mydata$score2[mydata$gender == m]-3.5*mydata$q1 + mydata$q2 Warning message: number of items to replace is not a multiple of replacement length -Original Message- From: Leeds, Mark (IED) [mailto:[EMAIL PROTECTED] Sent: Friday, November 24, 2006 8:45 PM To: Muenchen, Robert A (Bob) Subject: RE: [R] Multiple Conditional Tranformations I'm not sure if I understand your question but I don't think you need iflelse statements. myscore-numeric(q1) ( because I'm not sure how to initialize a list so initialize a vector with q1 elements ) myscore-NA ( I think this should set all the values in myscore to NA ) myscore[mydata$gender == f]-2*mydata$q1 + mydata$q2 myscore[mydata$gender == m]-3*mydata$q1 + mydata$q2 the above should do what you do in the first part of your code but I don't know if that was your question ? also, it does it making myscore a vector because I didn't know how to initialize a list. Someone else may goive a better solution. I'm no expert. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Muenchen, Robert A (Bob) Sent: Friday, November 24, 2006 8:27 PM To: r-help@stat.math.ethz.ch Subject: [R] Multiple Conditional Tranformations Greetings, I'm learning R and I'm stuck on a basic concept: how to specify a logical condition once and then perform multiple transformations under that condition. The program below is simplified to demonstrate the goal. Its results are exactly what I want, but I would like to check the logical state of gender only once and create both (or any number of) scores at once. mystring- (id,group,gender,q1,q2,q3,q4 01,1,f,2,2,5,4 02,2,f,2,1,4,5 03,1,f,2,2,4,4 04,2,f,1,1,5,5 05,1,m,4,5,4, 06,2,m,5,4,5,5 07,1,m,3,3,4,5 08,2,m,5,5,5,4) mydata-read.table(textConnection(mystring),header=TRUE,sep=,,row.name s=id) mydata #Create score1 so that it differs for males and females: mydata$score1 - ifelse( mydata$gender==f , (mydata$score1 - (2*mydata$q1)+mydata$q2), ifelse( mydata$gender==m, (mydata$score1 - (3*mydata$q1)+mydata$q2), NA ) ) mydata #Create score2 so that it too differs for males and females: mydata$score2 - ifelse( mydata$gender==f , (mydata$score2 - (2.5*mydata$q1)+mydata$q2), ifelse( mydata$gender==m, (mydata$score2 - (3.5*mydata$q1)+mydata$q2), NA ) ) mydata Thanks! Bob = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc http://oit.utk.edu/scc , News: http://listserv.utk.edu/archives/statnews.html http://listserv.utk.edu/archives/statnews.html = [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. This is not an offer (or solicitation of an offer) to buy/sell the securities/instruments mentioned or an official confirmation. Morgan Stanley may deal as principal in or own or act as market maker for securities/instruments mentioned or may advise the issuers. This is not research and is not from MS Research but it may refer to a research analyst/research report. Unless indicated, these views are the author's and may differ from those of Morgan Stanley research or others in the Firm. We do not represent this is accurate or complete and we may not update this. Past performance is not indicative of future returns. For additional information, research reports and important disclosures, contact me or see
Re: [R] Multiple Conditional Tranformations
Mark, I finally got that approach to work by spreading the logical condition everywhere. That gets the lengths to match. Still, I can't help but think there must be a way to specify the logic once per condition. Thanks, Bob mydata$score1-numeric(mydata$q1) #just initializing. mydata$score2-numeric(mydata$q1) mydata$score1-NA mydata$score2-NA mydata mydata$score1[mydata$gender == f]- 2*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score2[mydata$gender == f]-2.5*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score1[mydata$gender == m]-3*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata$score2[mydata$gender == m]-3.5*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc, News: http://listserv.utk.edu/archives/statnews.html = -Original Message- From: Leeds, Mark (IED) [mailto:[EMAIL PROTECTED] Sent: Friday, November 24, 2006 8:45 PM To: Muenchen, Robert A (Bob) Subject: RE: [R] Multiple Conditional Tranformations I'm not sure if I understand your question but I don't think you need iflelse statements. myscore-numeric(q1) ( because I'm not sure how to initialize a list so initialize a vector with q1 elements ) myscore-NA ( I think this should set all the values in myscore to NA ) myscore[mydata$gender == f]-2*mydata$q1 + mydata$q2 myscore[mydata$gender == m]-3*mydata$q1 + mydata$q2 the above should do what you do in the first part of your code but I don't know if that was your question ? also, it does it making myscore a vector because I didn't know how to initialize a list. Someone else may goive a better solution. I'm no expert. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Muenchen, Robert A (Bob) Sent: Friday, November 24, 2006 8:27 PM To: r-help@stat.math.ethz.ch Subject: [R] Multiple Conditional Tranformations Greetings, I'm learning R and I'm stuck on a basic concept: how to specify a logical condition once and then perform multiple transformations under that condition. The program below is simplified to demonstrate the goal. Its results are exactly what I want, but I would like to check the logical state of gender only once and create both (or any number of) scores at once. mystring- (id,group,gender,q1,q2,q3,q4 01,1,f,2,2,5,4 02,2,f,2,1,4,5 03,1,f,2,2,4,4 04,2,f,1,1,5,5 05,1,m,4,5,4, 06,2,m,5,4,5,5 07,1,m,3,3,4,5 08,2,m,5,5,5,4) mydata-read.table(textConnection(mystring),header=TRUE,sep=,,row.name s=id) mydata #Create score1 so that it differs for males and females: mydata$score1 - ifelse( mydata$gender==f , (mydata$score1 - (2*mydata$q1)+mydata$q2), ifelse( mydata$gender==m, (mydata$score1 - (3*mydata$q1)+mydata$q2), NA ) ) mydata #Create score2 so that it too differs for males and females: mydata$score2 - ifelse( mydata$gender==f , (mydata$score2 - (2.5*mydata$q1)+mydata$q2), ifelse( mydata$gender==m, (mydata$score2 - (3.5*mydata$q1)+mydata$q2), NA ) ) mydata Thanks! Bob = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc http://oit.utk.edu/scc , News: http://listserv.utk.edu/archives/statnews.html http://listserv.utk.edu/archives/statnews.html = [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. This is not an offer (or solicitation of an offer) to buy/sell the securities/instruments mentioned or an official confirmation. Morgan Stanley may deal as principal in or own or act as market maker for securities/instruments mentioned or may advise the issuers. This is not research and is not from MS Research but it may refer to a research analyst/research report. Unless indicated, these views are the author's and may differ from those of Morgan Stanley research or others in the Firm. We do not represent this is accurate or complete and we may not update this. Past performance is not indicative of future returns. For additional information, research
Re: [R] Multiple Conditional Tranformations
Good idea. I'm still getting used to how flexible R is on substitutions like that! -Bob -Original Message- From: Leeds, Mark (IED) [mailto:[EMAIL PROTECTED] Sent: Friday, November 24, 2006 10:20 PM To: Muenchen, Robert A (Bob) Subject: RE: [R] Multiple Conditional Tranformations You could set temp-which(my$gender[my$gender == f]) and then temp will have the female indices and Then you could just put temp everywhere instead of the statement but I think that's the best you can do. Definitely, someone will reply and there may be a shorter way that I am unaware of. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Muenchen, Robert A (Bob) Sent: Friday, November 24, 2006 10:09 PM To: r-help@stat.math.ethz.ch Subject: Re: [R] Multiple Conditional Tranformations Mark, I finally got that approach to work by spreading the logical condition everywhere. That gets the lengths to match. Still, I can't help but think there must be a way to specify the logic once per condition. Thanks, Bob mydata$score1-numeric(mydata$q1) #just initializing. mydata$score2-numeric(mydata$q1) mydata$score1-NA mydata$score2-NA mydata mydata$score1[mydata$gender == f]- 2*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score2[mydata$gender == f]-2.5*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score1[mydata$gender == m]-3*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata$score2[mydata$gender == m]-3.5*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc, News: http://listserv.utk.edu/archives/statnews.html = -Original Message- From: Leeds, Mark (IED) [mailto:[EMAIL PROTECTED] Sent: Friday, November 24, 2006 8:45 PM To: Muenchen, Robert A (Bob) Subject: RE: [R] Multiple Conditional Tranformations I'm not sure if I understand your question but I don't think you need iflelse statements. myscore-numeric(q1) ( because I'm not sure how to initialize a list so initialize a vector with q1 elements ) myscore-NA ( I think this should set all the values in myscore to NA ) myscore[mydata$gender == f]-2*mydata$q1 + mydata$q2 myscore[mydata$gender == m]-3*mydata$q1 + mydata$q2 the above should do what you do in the first part of your code but I don't know if that was your question ? also, it does it making myscore a vector because I didn't know how to initialize a list. Someone else may goive a better solution. I'm no expert. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Muenchen, Robert A (Bob) Sent: Friday, November 24, 2006 8:27 PM To: r-help@stat.math.ethz.ch Subject: [R] Multiple Conditional Tranformations Greetings, I'm learning R and I'm stuck on a basic concept: how to specify a logical condition once and then perform multiple transformations under that condition. The program below is simplified to demonstrate the goal. Its results are exactly what I want, but I would like to check the logical state of gender only once and create both (or any number of) scores at once. mystring- (id,group,gender,q1,q2,q3,q4 01,1,f,2,2,5,4 02,2,f,2,1,4,5 03,1,f,2,2,4,4 04,2,f,1,1,5,5 05,1,m,4,5,4, 06,2,m,5,4,5,5 07,1,m,3,3,4,5 08,2,m,5,5,5,4) mydata-read.table(textConnection(mystring),header=TRUE,sep=,,row.name s=id) mydata #Create score1 so that it differs for males and females: mydata$score1 - ifelse( mydata$gender==f , (mydata$score1 - (2*mydata$q1)+mydata$q2), ifelse( mydata$gender==m, (mydata$score1 - (3*mydata$q1)+mydata$q2), NA ) ) mydata #Create score2 so that it too differs for males and females: mydata$score2 - ifelse( mydata$gender==f , (mydata$score2 - (2.5*mydata$q1)+mydata$q2), ifelse( mydata$gender==m, (mydata$score2 - (3.5*mydata$q1)+mydata$q2), NA ) ) mydata Thanks! Bob = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc http://oit.utk.edu/scc , News: http://listserv.utk.edu/archives/statnews.html http://listserv.utk.edu/archives/statnews.html = [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R
Re: [R] Multiple Conditional Tranformations
Try this: transform(mydata, score1 = (2 + (gender == m)) * q1 + q2, score2 = (2.5 + (gender == m)) * q1 + q2 ) On 11/24/06, Muenchen, Robert A (Bob) [EMAIL PROTECTED] wrote: Mark, I finally got that approach to work by spreading the logical condition everywhere. That gets the lengths to match. Still, I can't help but think there must be a way to specify the logic once per condition. Thanks, Bob mydata$score1-numeric(mydata$q1) #just initializing. mydata$score2-numeric(mydata$q1) mydata$score1-NA mydata$score2-NA mydata mydata$score1[mydata$gender == f]- 2*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score2[mydata$gender == f]-2.5*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score1[mydata$gender == m]-3*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata$score2[mydata$gender == m]-3.5*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc, News: http://listserv.utk.edu/archives/statnews.html = -Original Message- From: Leeds, Mark (IED) [mailto:[EMAIL PROTECTED] Sent: Friday, November 24, 2006 8:45 PM To: Muenchen, Robert A (Bob) Subject: RE: [R] Multiple Conditional Tranformations I'm not sure if I understand your question but I don't think you need iflelse statements. myscore-numeric(q1) ( because I'm not sure how to initialize a list so initialize a vector with q1 elements ) myscore-NA ( I think this should set all the values in myscore to NA ) myscore[mydata$gender == f]-2*mydata$q1 + mydata$q2 myscore[mydata$gender == m]-3*mydata$q1 + mydata$q2 the above should do what you do in the first part of your code but I don't know if that was your question ? also, it does it making myscore a vector because I didn't know how to initialize a list. Someone else may goive a better solution. I'm no expert. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Muenchen, Robert A (Bob) Sent: Friday, November 24, 2006 8:27 PM To: r-help@stat.math.ethz.ch Subject: [R] Multiple Conditional Tranformations Greetings, I'm learning R and I'm stuck on a basic concept: how to specify a logical condition once and then perform multiple transformations under that condition. The program below is simplified to demonstrate the goal. Its results are exactly what I want, but I would like to check the logical state of gender only once and create both (or any number of) scores at once. mystring- (id,group,gender,q1,q2,q3,q4 01,1,f,2,2,5,4 02,2,f,2,1,4,5 03,1,f,2,2,4,4 04,2,f,1,1,5,5 05,1,m,4,5,4, 06,2,m,5,4,5,5 07,1,m,3,3,4,5 08,2,m,5,5,5,4) mydata-read.table(textConnection(mystring),header=TRUE,sep=,,row.name s=id) mydata #Create score1 so that it differs for males and females: mydata$score1 - ifelse( mydata$gender==f , (mydata$score1 - (2*mydata$q1)+mydata$q2), ifelse( mydata$gender==m, (mydata$score1 - (3*mydata$q1)+mydata$q2), NA ) ) mydata #Create score2 so that it too differs for males and females: mydata$score2 - ifelse( mydata$gender==f , (mydata$score2 - (2.5*mydata$q1)+mydata$q2), ifelse( mydata$gender==m, (mydata$score2 - (3.5*mydata$q1)+mydata$q2), NA ) ) mydata Thanks! Bob = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc http://oit.utk.edu/scc , News: http://listserv.utk.edu/archives/statnews.html http://listserv.utk.edu/archives/statnews.html = [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. This is not an offer (or solicitation of an offer) to buy/sell the securities/instruments mentioned or an official confirmation. Morgan Stanley may deal as principal in or own or act as market maker for securities/instruments mentioned or may advise the issuers. This is not research and is not from MS Research but it may refer to a research analyst/research report. Unless indicated
Re: [R] Multiple Conditional Tranformations
And here is a variation: transform(mydata, score1 = (2 + (gender == m)) * q1 + q2, score2 = score1 + 0.5 * q1 ) or transform( transform(mydata, score1 = (2 + (gender == m)) * q1 + q2), score2 = score1 + 0.5 * q1 ) On 11/25/06, Gabor Grothendieck [EMAIL PROTECTED] wrote: Try this: transform(mydata, score1 = (2 + (gender == m)) * q1 + q2, score2 = (2.5 + (gender == m)) * q1 + q2 ) On 11/24/06, Muenchen, Robert A (Bob) [EMAIL PROTECTED] wrote: Mark, I finally got that approach to work by spreading the logical condition everywhere. That gets the lengths to match. Still, I can't help but think there must be a way to specify the logic once per condition. Thanks, Bob mydata$score1-numeric(mydata$q1) #just initializing. mydata$score2-numeric(mydata$q1) mydata$score1-NA mydata$score2-NA mydata mydata$score1[mydata$gender == f]- 2*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score2[mydata$gender == f]-2.5*mydata$q1[mydata$gender==f] + mydata$q2[mydata$gender==f] mydata$score1[mydata$gender == m]-3*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata$score2[mydata$gender == m]-3.5*mydata$q1[mydata$gender==m] + mydata$q2[mydata$gender==m] mydata = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc, News: http://listserv.utk.edu/archives/statnews.html = -Original Message- From: Leeds, Mark (IED) [mailto:[EMAIL PROTECTED] Sent: Friday, November 24, 2006 8:45 PM To: Muenchen, Robert A (Bob) Subject: RE: [R] Multiple Conditional Tranformations I'm not sure if I understand your question but I don't think you need iflelse statements. myscore-numeric(q1) ( because I'm not sure how to initialize a list so initialize a vector with q1 elements ) myscore-NA ( I think this should set all the values in myscore to NA ) myscore[mydata$gender == f]-2*mydata$q1 + mydata$q2 myscore[mydata$gender == m]-3*mydata$q1 + mydata$q2 the above should do what you do in the first part of your code but I don't know if that was your question ? also, it does it making myscore a vector because I didn't know how to initialize a list. Someone else may goive a better solution. I'm no expert. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Muenchen, Robert A (Bob) Sent: Friday, November 24, 2006 8:27 PM To: r-help@stat.math.ethz.ch Subject: [R] Multiple Conditional Tranformations Greetings, I'm learning R and I'm stuck on a basic concept: how to specify a logical condition once and then perform multiple transformations under that condition. The program below is simplified to demonstrate the goal. Its results are exactly what I want, but I would like to check the logical state of gender only once and create both (or any number of) scores at once. mystring- (id,group,gender,q1,q2,q3,q4 01,1,f,2,2,5,4 02,2,f,2,1,4,5 03,1,f,2,2,4,4 04,2,f,1,1,5,5 05,1,m,4,5,4, 06,2,m,5,4,5,5 07,1,m,3,3,4,5 08,2,m,5,5,5,4) mydata-read.table(textConnection(mystring),header=TRUE,sep=,,row.name s=id) mydata #Create score1 so that it differs for males and females: mydata$score1 - ifelse( mydata$gender==f , (mydata$score1 - (2*mydata$q1)+mydata$q2), ifelse( mydata$gender==m, (mydata$score1 - (3*mydata$q1)+mydata$q2), NA ) ) mydata #Create score2 so that it too differs for males and females: mydata$score2 - ifelse( mydata$gender==f , (mydata$score2 - (2.5*mydata$q1)+mydata$q2), ifelse( mydata$gender==m, (mydata$score2 - (3.5*mydata$q1)+mydata$q2), NA ) ) mydata Thanks! Bob = Bob Muenchen (pronounced Min'-chen), Manager Statistical Consulting Center U of TN Office of Information Technology 200 Stokely Management Center, Knoxville, TN 37996-0520 Voice: (865) 974-5230 FAX: (865) 974-4810 Email: [EMAIL PROTECTED] Web: http://oit.utk.edu/scc http://oit.utk.edu/scc , News: http://listserv.utk.edu/archives/statnews.html http://listserv.utk.edu/archives/statnews.html = [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible
