[Rcpp-devel] How to create list of list without known structure

2014-05-06 Thread Florian Burkart 
Hi,

I have been creating lists of lists with

return Rcpp::List::create(Rcpp::Named(vec) = someVector,
  Rcpp::Named(lst) = someList,
  Rcpp::Named(vec2) = someOtherVector);

or to follow Romain:

using namespace Rcpp ;
return List::create(
   _[vec]  = someVector,
   _[lst]  = someList,
   _[vec2] = someOtherVector
 ) ;

But how do I convert the following into a list of lists?

std::vectorstd::string m_column_headers;
std::vectorstd::vectorOptDouble  m_vectors_of_values;

Thank you,
Florian
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Re: [Rcpp-devel] How to create list of list without known structure

2014-05-06 Thread Dirk Eddelbuettel 

Hi Florian,

On 6 May 2014 at 09:35, Florian Burkart wrote:
| Hi,
| 
| I have been creating lists of lists with
| 
| return Rcpp::List::create(Rcpp::Named(vec) = someVector,
|                           Rcpp::Named(lst) = someList,
|                           Rcpp::Named(vec2) = someOtherVector);

Yes, it is a very common idiom as lists are the R structure used for nesting
object with varying types or sizes.
 
| or to follow Romain:
| 
| using namespace Rcpp ;
| return List::create(
|    _[vec]  = someVector,
|    _[lst]  = someList,
|    _[vec2] = someOtherVector
|  ) ;
| 
| But how do I convert the following into a list of lists?
| 
| std::vectorstd::string m_column_headers;
| std::vectorstd::vectorOptDouble  m_vectors_of_values;

You probably have to copy at some point.  You could also use Rcpp types as
the first (std::vectorstd::string) could be an Rcpp::CharacterVector (which
is a vector of strings, not single char); the second could be a
Rcpp::NumericMatrix.  There is some support for as and wrap() between
these, but there is no function doing magic of the 'here, just convert these
random two types I listed'.  It all depends.

Hope this helps, Dirk

-- 
Dirk Eddelbuettel | e...@debian.org | http://dirk.eddelbuettel.com
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Re: [Rcpp-devel] How to create list of list without known structure

2014-05-06 Thread Romain Francois 

Le 6 mai 2014 à 09:35, Florian Burkart florian.burk...@gmail.com a écrit :

 Hi,
 
 I have been creating lists of lists with 
 
 return Rcpp::List::create(Rcpp::Named(vec) = someVector,
   Rcpp::Named(lst) = someList,
   Rcpp::Named(vec2) = someOtherVector);
 
 or to follow Romain:
 
 using namespace Rcpp ;
 return List::create( 
_[vec]  = someVector, 
_[lst]  = someList, 
_[vec2] = someOtherVector
  ) ;
 
 But how do I convert the following into a list of lists?
 
 std::vectorstd::string m_column_headers;
 std::vectorstd::vectorOptDouble  m_vectors_of_values;

You probably just need to know about .names() =, i.e. something like this 
should do: 

List values = wrap(m_vectors_of_values) ;
values.names()  = m_column_headers ;

FWIW, in Rcpp11, you could use structure, e.g. :

List values = structure( m_vectors_of_values, _[names] = m_column_headers ) ;

Romain
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