Re: [RE-wrenches] sizing a sub-panel used to combinemultipleinverter outputs

2011-03-30 Thread Jason Szumlanski
Another key is to remember that this discussion also applies to the
conductor between the main panel and subpanel. In a large PV system,
this could result in a pretty large wire between the two panels, and a
significant cost that is often overlooked. In some cases it makes sense
to locate the subpanel close to the main panel and run multiple sets of
smaller wires from the inverters to the subpanel.

 

And because the calculation is based on the first OC protection
connected to the inverters, adding a main breaker (theoretically 80A in
this example) in the subpanel doesn't change things. Even though this
wire would be theoretically protected by an 80A breaker at each end, you
can't size the wire for 160A / 1.2 = 133.3A. You have to size for
180A/1.2 = 150A. (not that it makes much of a difference in this
example, but it still must be considered)

 

At least that's how I understand it...

 

Jason Szumlanski

Fafco Solar 

 

 

From: re-wrenches-boun...@lists.re-wrenches.org
[mailto:re-wrenches-boun...@lists.re-wrenches.org] On Behalf Of Mark
Frye
Sent: Wednesday, March 30, 2011 1:33 AM
To: 'RE-wrenches'
Subject: Re: [RE-wrenches] sizing a sub-panel used to
combinemultipleinverter outputs

 

Opps!

 

My bad, I was thinking of a single phase system, not the three phase
system shown in the article.

 

For the three phase system Kent is correct in counting 180A of supply
per bar.

 

Mark Frye 
Berkeley Solar Electric Systems 
303 Redbud Way 
Nevada City,  CA 95959 
(530) 401-8024 
www.berkeleysolar.com http://www.berkeleysolar.com/   

 

 



From: re-wrenches-boun...@lists.re-wrenches.org
[mailto:re-wrenches-boun...@lists.re-wrenches.org] On Behalf Of Mark
Frye
Sent: Tuesday, March 29, 2011 10:17 PM
To: 'RE-wrenches'
Subject: Re: [RE-wrenches] sizing a sub-panel used to combine
multipleinverter outputs

I think Kent and I agree. For the case where the subpanel is not
dedicated a PV sub-panel he is calculating for 2 - 50A breakers and I
calculated for 3 - 50A breakers.


Mark Frye 
Berkeley Solar Electric Systems 
303 Redbud Way 
Nevada City,  CA 95959 
(530) 401-8024 
www.berkeleysolar.com http://www.berkeleysolar.com/   

 

 



From: re-wrenches-boun...@lists.re-wrenches.org
[mailto:re-wrenches-boun...@lists.re-wrenches.org] On Behalf Of Kent
Osterberg
Sent: Tuesday, March 29, 2011 9:26 PM
To: RE-wrenches
Subject: Re: [RE-wrenches] sizing a sub-panel used to combine multiple
inverter outputs

Per 705.12(D) the sub-panel could be any distribution equipment on the
premises. So the question becomes: is the sub-panel capable of supplying
branch circuits or feeder loads? If yes, then the sum of the breakers
(potentially) feeding the bus is 180 amps so a 150-amp rating is
required and the inverters would have to feed the opposite end of the
bus bars. If no, the code is not clear on the requirement, but obviously
the 80-amp breaker in the main panel limits the maximum current flowing
through the sub-panel. 

Kent Osterberg
Blue Mountain Solar



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Re: [RE-wrenches] sizing a sub-panel used to combinemultipleinverter outputs

2011-03-30 Thread Kent Osterberg




Jason,

Now you are opening up a can of worms. 

It's bad enough that 705.12(D) doesn't say anything about a panel that
can't (or shouldn't, or won't) have anything connected but interactive
inverters. But when that is the case, a bus rating of 100% of the
source circuits should apply. For PV systems a 125% factor will already
apply to each inverter circuit.

While it seems logical that the conductors are an extension of the bus
bar and should be treated the same way, 705.12(D) isn't about the
conductors - it's about the bus bars. The conductors are protected by
the breakers -- 80-amp breakers and wire with 80-amp ampacity. 

Getting into the example further, I see flaws in it. If the inverters
are 7500-watt 240-volt, the output current would be 7500/240 = 31.25
amps and 40-amp breakers would be adequate. Then there would have been
no issues, even going directly into the main panel. If the inverters
are 7500-watt 208-volt, the output current is 7500/208 = 36 amps and
the 50-amp breakers make sense. That means the bus bars and feeder
conductor have a continuous current of 72 amps. That means neither the
80-amp breaker nor 80-amp wire is sufficient because 72 x 1.25 = 90
amps. Now the example doesn't resolve the limitation of backfeeding at
the main. Opps!

Kent Osterberg
Blue Mountain Solar






Jason Szumlanski wrote:

  
  

  
  
  Another
key is to remember that this discussion also applies to the conductor
between the main panel and subpanel. In a large PV system, this could
result in a pretty large wire between the two panels, and a significant
cost that is often overlooked. In some cases it makes sense to locate
the subpanel close to the main panel and run multiple sets of smaller
wires from the inverters to the subpanel.
  
  And
because the calculation is based on the first OC protection connected
to the inverters, adding a main breaker (theoretically 80A in this
example) in the subpanel doesnt change things. Even though this wire
would be theoretically protected by an 80A breaker at each end, you
cant size the wire for 160A / 1.2 = 133.3A. You have to size for
180A/1.2 = 150A. (not that it makes much of a difference in this
example, but it still must be considered)
  
  At
least thats how I understand it
  
  
  Jason
Szumlanski
  Fafco
Solar
  
  
  
  
  
  
  From:
re-wrenches-boun...@lists.re-wrenches.org
[mailto:re-wrenches-boun...@lists.re-wrenches.org] On Behalf Of Mark
Frye
  Sent: Wednesday, March 30, 2011 1:33 AM
  To: 'RE-wrenches'
  Subject: Re: [RE-wrenches] sizing a sub-panel used to
combinemultipleinverter outputs
  
  
  
  Opps!
  
  My
bad, Iwas thinking of a singlephase system, not the three phase
system shown in the article.
  
  For
the three phase system Kent is correct in counting 180A of supply per
bar.
  
  Mark Frye
  
  Berkeley
Solar Electric Systems 
  303
Redbud Way 
  Nevada
City, CA 95959 
  (530)
401-8024 
  www.berkeleysolar.com 
  
  
  
  
  
  
  From:
re-wrenches-boun...@lists.re-wrenches.org
[mailto:re-wrenches-boun...@lists.re-wrenches.org] On Behalf Of Mark
Frye
  Sent: Tuesday, March 29, 2011 10:17 PM
  To: 'RE-wrenches'
  Subject: Re: [RE-wrenches] sizing a sub-panel used to combine
multipleinverter outputs
  I
think Kent and I agree. For the case where thesubpanel is not
dedicated a PV sub-panel he is calculating for 2 - 50A breakers and I
calculated for 3 - 50A breakers.
  
  Mark
Frye 
  Berkeley
Solar Electric Systems 
  303
Redbud Way 
  Nevada
City, CA 95959 
  (530)
401-8024 
  www.berkeleysolar.com 
  
  
  
  
  
  
  From:
re-wrenches-boun...@lists.re-wrenches.org
[mailto:re-wrenches-boun...@lists.re-wrenches.org] On Behalf Of Kent
Osterberg
  Sent: Tuesday, March 29, 2011 9:26 PM
  To: RE-wrenches
  Subject: Re: [RE-wrenches] sizing a sub-panel used to combine
multiple inverter outputs
  Per 705.12(D) the sub-panel could be any
distribution equipment on the premises. So the question becomes: is the
sub-panel capable of supplying branch circuits or feeder loads? If yes,
then the sum of the breakers (potentially) feeding the bus is 180 amps
so a 150-amp rating is required and the inverters would have to feed
the opposite end of the bus bars. If no, the code is not clear on the
requirement, but obviously the 80-amp breaker in the main panel limits
the maximum current flowing through the sub-panel. 
  
Kent Osterberg
Blue Mountain Solar
  
  
  
  

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Re: [RE-wrenches] sizing a sub-panel used to combinemultipleinverter outputs

2011-03-30 Thread Andrew Truitt
 I concur with Jason and Brian's interpretation of 690.64(B)(2).  I think
one of the intents of the code is to ensure that if there is a fault in a
busbar or conductor and the maximum amperage is being delivered to that
fault from all OCPDs supplying it (solar + utility), the busbar or conductor
should be able to handle the sum of those fault currents.  I have
encountered numerous jurisdictions that interpret it this way, and it is
hard to argue with them from a strictly code perspective.

However, Jason Fisher once pointed out to me that if the fault occurs in a
feeder between the main service panel and a subpanel (solar accumulation
panel or otherwise) it is impossible for any part of that conductor to carry
more current than allowed by the largest OCPD feeding the conductor.  Its
the same principle behind the 690.64(B)(7) requirement to locate the solar
interconnection breaker at the opposite end of the busbar from the incoming
feeders.  This argument obviously doesn't apply to accumulation panel
busbars where you have more than 2 OCPDs supplying current, but I think it
is a valid argument for basing your feeder conductor sizing on the largest
OCPD protecting that conductor.



For a brighter energy future,

Andrew Truitt
Principal
Truitt Renewable Energy Consulting
NABCEP Certified PV Installer™ (ID# 032407-66)
(202) 486-7507
http://www.linkedin.com/pub/andrew-truitt/8/622/713

[image: 24 copy.jpg]

Don't get me wrong: I love nuclear energy! It's just that I prefer fusion
to fission. And it just so happens that there's an enormous fusion reactor
safely banked a few million miles from us. It delivers more than we could
ever use in just about 8 minutes. And it's wireless!

~William McDonough







On Wed, Mar 30, 2011 at 10:12 AM, Kent Osterberg k...@coveoregon.comwrote:

 Jason,

 Now you are opening up a can of worms.

 It's bad enough that 705.12(D) doesn't say anything about a panel that
 can't (or shouldn't, or won't) have anything connected but interactive
 inverters. But when that is the case, a bus rating of 100% of the source
 circuits should apply. For PV systems a 125% factor will already apply to
 each inverter circuit.

 While it seems logical that the conductors are an extension of the bus bar
 and should be treated the same way, 705.12(D) isn't about the conductors -
 it's about the bus bars. The conductors are protected by the breakers --
 80-amp breakers and wire with 80-amp ampacity.

 Getting into the example further, I see flaws in it. If the inverters are
 7500-watt 240-volt, the output current would be 7500/240 = 31.25 amps and
 40-amp breakers would be adequate. Then there would have been no issues,
 even going directly into the main panel. If the inverters are 7500-watt
 208-volt, the output current is 7500/208 = 36 amps and the 50-amp breakers
 make sense. That means the bus bars and feeder conductor have a continuous
 current of 72 amps.  That means neither the 80-amp breaker nor 80-amp wire
 is sufficient because 72 x 1.25 = 90 amps. Now the example doesn't resolve
 the limitation of backfeeding at the main. Opps!


 Kent Osterberg
 Blue Mountain Solar






 Jason Szumlanski wrote:

   Another key is to remember that this discussion also applies to the
 conductor between the main panel and subpanel. In a large PV system, this
 could result in a pretty large wire between the two panels, and a
 significant cost that is often overlooked. In some cases it makes sense to
 locate the subpanel close to the main panel and run multiple sets of smaller
 wires from the inverters to the subpanel.



 And because the calculation is based on the first OC protection connected
 to the inverters, adding a main breaker (theoretically 80A in this example)
 in the subpanel doesn’t change things. Even though this wire would be
 theoretically protected by an 80A breaker at each end, you can’t size the
 wire for 160A / 1.2 = 133.3A. You have to size for 180A/1.2 = 150A. (not
 that it makes much of a difference in this example, but it still must be
 considered)



 At least that’s how I understand it…



 Jason Szumlanski

 Fafco Solar





 *From:* re-wrenches-boun...@lists.re-wrenches.org [
 mailto:re-wrenches-boun...@lists.re-wrenches.orgre-wrenches-boun...@lists.re-wrenches.org]
 *On Behalf Of *Mark Frye
 *Sent:* Wednesday, March 30, 2011 1:33 AM
 *To:* 'RE-wrenches'
 *Subject:* Re: [RE-wrenches] sizing a sub-panel used to
 combinemultipleinverter outputs



 Opps!



 My bad, I was thinking of a single phase system, not the three phase system
 shown in the article.



 For the three phase system Kent is correct in counting 180A of supply per
 bar.



 Mark Frye
 Berkeley Solar Electric Systems
 303 Redbud Way
 Nevada City,  CA 95959
 (530) 401-8024
 www.berkeleysolar.com




  --

 *From:* re-wrenches-boun...@lists.re-wrenches.org [
 mailto:re-wrenches-boun...@lists.re-wrenches.orgre-wrenches-boun...@lists.re-wrenches.org]
 *On Behalf Of *Mark Frye
 *Sent:* Tuesday