I doubt this has ever worked:
In fact, my message was not clear. I test if type(a*b) ==
sage.algebras.free_algebra_element.FreeAlgebraElement
With older versions, type(a*b) ==
sage.algebras.free_algebra_element.FreeAlgebraElement
which is not the case anymore.
But your advice is good, thanks !
Matthieu
De : Nicolas M. Thiery nicolas.thi...@u-psud.fr
À : sage-combinat-devel@googlegroups.com
Envoyé le : Mercredi 10 avril 2013 15h33
Objet : Re: [sage-combinat-devel] Free Algebra Element
Bonjour Matthieu,
On Wed, Apr 10, 2013 at 02:15:20PM +0100, Matthieu Deneufchatel wrote:
Do I miss something or is there a bug :
sage: R.a,b=FreeAlgebra(QQ,2)
sage: a*b
a*b
sage: type(a*b)
class
'sage.algebras.free_algebra_element.FreeAlgebra_generic_with_category.element_class'
sage:
type(a*b)==sage.algebras.free_algebra_element.FreeAlgebra_generic_with_category.element_class
---
AttributeError Traceback (most recent call
last)
/home/deneufchatel/ipython console in module()
AttributeError: 'module' object has no attribute
'FreeAlgebra_generic_with_category'
The same code used to give something consistent with older versions of
Sage (4.8 ?).
I doubt this has ever worked: the class
FreeAlgebra_generic_with_category is generated on the fly to add
generic code from the categories to the code of FreeAlgebra and
FreeAlgebraElement. For details, see:
http://www.sagemath.org/doc/reference/categories/sage/categories/category.html
On the other hand you can do something like:
sage: type(a*b) == R.element_class
Cheers,
Nicolas
--
Nicolas M. Thiéry Isil nthi...@users.sf.net
http://Nicolas.Thiery.name/
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