[sage-devel] Re: is_Integer() function semantics
On Fri, Apr 24, 2009 at 8:42 PM, Robert Bradshaw rober...@math.washington.edu wrote: On Apr 24, 2009, at 8:24 PM, Nick Alexander wrote: Another option is sage: 3/2 + 1/2 in ZZ True sage: 3/2 + 1/3 in ZZ False I just ran into the True in ZZ returns True thing again. How do I check to see if I passed an option or True? You can do x is True Also you could do isinstance(x, bool) and x but I like Robert's solution better. William --~--~-~--~~~---~--~~ To post to this group, send email to sage-devel@googlegroups.com To unsubscribe from this group, send email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
[sage-devel] Re: is_Integer() function semantics
How could you not notice? If I do is_Integer I get a big DeprecationWarning: Does your Sage not do that? The reason I did not notice it is that is_Integer() was in the body of a main loop and no warnings were printed. For example, [n for n in range(0,10) if is_Integer(n+1)] returns [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] However [n for n in range(0,10) if is_Integer(n)] returns null list [ ] In the first case the answer was correct and in the second case the answer was wrong. In both cases, please note no warning was printed. My sage version is 3.4 and using it on Mac OS X. I am using Robert's solution. It seems to work well. Thanks, Nirmal --~--~-~--~~~---~--~~ To post to this group, send email to sage-devel@googlegroups.com To unsubscribe from this group, send email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
[sage-devel] Re: is_Integer() function semantics
How could you not notice? If I do is_Integer I get a big DeprecationWarning: Does your Sage not do that? The reason I did not notice it is that is_Integer() was in the body of a main loop and no warnings were printed. For example, [n for n in range(0,10) if is_Integer(n+1)] returns [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] However [n for n in range(0,10) if is_Integer(n)] returns null list [ ] In the first case the answer was correct and in the second case the answer was wrong. In both cases, please note no warning was printed. My sage version is 3.4 and using it on Mac OS X. I am using Robert's solution. It seems to work well. Thanks, Nirmal --~--~-~--~~~---~--~~ To post to this group, send email to sage-devel@googlegroups.com To unsubscribe from this group, send email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
[sage-devel] Re: is_Integer() function semantics
[n for n in range(0,10) if is_Integer(n+1)]
snip
[n for n in range(0,10) if is_Integer(n)]
You are doing this from the command line, yes? The first is getting
preparsed, so that 1 is not a python int, it is a sage Integer:
sage: preparse('[n for n in range(0,10) if is_Integer(n+1)]')
'[n for n in range(Integer(0),Integer(10)) if is_Integer(n+Integer(1))]'
sage: preparse('[n for n in range(0,10) if is_Integer(n)]')
'[n for n in range(Integer(0),Integer(10)) if is_Integer(n)]'
As for the warnings not being printed, in the loop you are maybe not
considered to be in Python global scope? I cannot say.
Nick
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[sage-devel] Re: is_Integer() function semantics
snip [n for n in range(0,10) if is_Integer(n)] You are doing this from the command line, yes? I am doing this in the notebook() -Nirmal --~--~-~--~~~---~--~~ To post to this group, send email to sage-devel@googlegroups.com To unsubscribe from this group, send email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
[sage-devel] Re: is_Integer() function semantics
Thanks for all the helpful suggestions. I did not realize that is_Integer() was deprecated. On Apr 22, 2:00 am, John Cremona john.crem...@gmail.com wrote: This is precisely why we deprecated all the is_*() functions for end-user use: -- | Sage Version 3.4.1.rc4, Release Date: 2009-04-19 | | Type notebook() for the GUI, and license() for information. | -- sage: is_Integer(3/2+1/2) /home/masgaj/.sage/temp/host_56_150/29373/_home_masgaj__sage_init_sage_0.py:1: DeprecationWarning: Using is_Integer from the top level is deprecated since it was designed to be used by developers rather than end users. It most likely does not do what you would expect it to do. If you really need to use it, import it from the module that it is defined in. # -*- coding: utf-8 -*- False sage: (3/2+1/2).is_integral() True The is_*() functions just test the type of an abject (in programming terms): sage: type(3/2+1/2) type 'sage.rings.rational.Rational' and the result of 3/2+1/2 is of type Rational. Mathematically, of course, the same number can be an integer and a rational (and a real and a complex and ...). John 2009/4/22 Robert Bradshaw rober...@math.washington.edu: On Apr 21, 2009, at 10:54 PM, Craig Citro wrote: In module sage.rings.integer is_Integer(3/2+1/2) returns False The expected output should be True as 3/2+1/2 = 2. I was planning to use this function to check if the result of division is a whole number. You could also use the is_integral method of rational numbers: sage: n = 3/2 + 1/2 sage: n.is_integral() True (This function also exists on Integers, so you could even use it in situations where you weren't sure if you had an honest Integer or an integer masquerading as a Rational.) Another option is sage: 3/2 + 1/2 in ZZ True sage: 3/2 + 1/3 in ZZ False - Robert --~--~-~--~~~---~--~~ To post to this group, send email to sage-devel@googlegroups.com To unsubscribe from this group, send email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
[sage-devel] Re: is_Integer() function semantics
On Fri, Apr 24, 2009 at 10:59 AM, nirmal nrsax...@gmail.com wrote: Thanks for all the helpful suggestions. I did not realize that is_Integer() was deprecated. How could you not notice? If I do is_Integer I get a big DeprecationWarning: sage: is_Integer(3) /Users/wstein/.sage/temp/D_69_91_158_76.dhcp4.washington.edu/15220/_Users_wstein__sage_init_sage_0.py:1: DeprecationWarning: Using is_Integer from the top level is deprecated since it was designed to be used by developers rather than end users. It most likely does not do what you would expect it to do. If you really need to use it, import it from the module that it is defined in. # -*- coding: utf-8 -*- True sage: Does your Sage not do that? William On Apr 22, 2:00 am, John Cremona john.crem...@gmail.com wrote: This is precisely why we deprecated all the is_*() functions for end-user use: -- | Sage Version 3.4.1.rc4, Release Date: 2009-04-19 | | Type notebook() for the GUI, and license() for information. | -- sage: is_Integer(3/2+1/2) /home/masgaj/.sage/temp/host_56_150/29373/_home_masgaj__sage_init_sage_0.py:1: DeprecationWarning: Using is_Integer from the top level is deprecated since it was designed to be used by developers rather than end users. It most likely does not do what you would expect it to do. If you really need to use it, import it from the module that it is defined in. # -*- coding: utf-8 -*- False sage: (3/2+1/2).is_integral() True The is_*() functions just test the type of an abject (in programming terms): sage: type(3/2+1/2) type 'sage.rings.rational.Rational' and the result of 3/2+1/2 is of type Rational. Mathematically, of course, the same number can be an integer and a rational (and a real and a complex and ...). John 2009/4/22 Robert Bradshaw rober...@math.washington.edu: On Apr 21, 2009, at 10:54 PM, Craig Citro wrote: In module sage.rings.integer is_Integer(3/2+1/2) returns False The expected output should be True as 3/2+1/2 = 2. I was planning to use this function to check if the result of division is a whole number. You could also use the is_integral method of rational numbers: sage: n = 3/2 + 1/2 sage: n.is_integral() True (This function also exists on Integers, so you could even use it in situations where you weren't sure if you had an honest Integer or an integer masquerading as a Rational.) Another option is sage: 3/2 + 1/2 in ZZ True sage: 3/2 + 1/3 in ZZ False - Robert -- William Stein Associate Professor of Mathematics University of Washington http://wstein.org --~--~-~--~~~---~--~~ To post to this group, send email to sage-devel@googlegroups.com To unsubscribe from this group, send email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
[sage-devel] Re: is_Integer() function semantics
Another option is sage: 3/2 + 1/2 in ZZ True sage: 3/2 + 1/3 in ZZ False I just ran into the True in ZZ returns True thing again. How do I check to see if I passed an option or True? Nick --~--~-~--~~~---~--~~ To post to this group, send email to sage-devel@googlegroups.com To unsubscribe from this group, send email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
[sage-devel] Re: is_Integer() function semantics
On Apr 24, 2009, at 8:24 PM, Nick Alexander wrote: Another option is sage: 3/2 + 1/2 in ZZ True sage: 3/2 + 1/3 in ZZ False I just ran into the True in ZZ returns True thing again. How do I check to see if I passed an option or True? You can do x is True - Robert --~--~-~--~~~---~--~~ To post to this group, send email to sage-devel@googlegroups.com To unsubscribe from this group, send email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
[sage-devel] Re: is_Integer() function semantics
On Apr 21, 2009, at 10:54 PM, Craig Citro wrote: In module sage.rings.integer is_Integer(3/2+1/2) returns False The expected output should be True as 3/2+1/2 = 2. I was planning to use this function to check if the result of division is a whole number. You could also use the is_integral method of rational numbers: sage: n = 3/2 + 1/2 sage: n.is_integral() True (This function also exists on Integers, so you could even use it in situations where you weren't sure if you had an honest Integer or an integer masquerading as a Rational.) Another option is sage: 3/2 + 1/2 in ZZ True sage: 3/2 + 1/3 in ZZ False - Robert --~--~-~--~~~---~--~~ To post to this group, send email to sage-devel@googlegroups.com To unsubscribe from this group, send email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
[sage-devel] Re: is_Integer() function semantics
This is precisely why we deprecated all the is_*() functions for end-user use: -- | Sage Version 3.4.1.rc4, Release Date: 2009-04-19 | | Type notebook() for the GUI, and license() for information.| -- sage: is_Integer(3/2+1/2) /home/masgaj/.sage/temp/host_56_150/29373/_home_masgaj__sage_init_sage_0.py:1: DeprecationWarning: Using is_Integer from the top level is deprecated since it was designed to be used by developers rather than end users. It most likely does not do what you would expect it to do. If you really need to use it, import it from the module that it is defined in. # -*- coding: utf-8 -*- False sage: (3/2+1/2).is_integral() True The is_*() functions just test the type of an abject (in programming terms): sage: type(3/2+1/2) type 'sage.rings.rational.Rational' and the result of 3/2+1/2 is of type Rational. Mathematically, of course, the same number can be an integer and a rational (and a real and a complex and ...). John 2009/4/22 Robert Bradshaw rober...@math.washington.edu: On Apr 21, 2009, at 10:54 PM, Craig Citro wrote: In module sage.rings.integer is_Integer(3/2+1/2) returns False The expected output should be True as 3/2+1/2 = 2. I was planning to use this function to check if the result of division is a whole number. You could also use the is_integral method of rational numbers: sage: n = 3/2 + 1/2 sage: n.is_integral() True (This function also exists on Integers, so you could even use it in situations where you weren't sure if you had an honest Integer or an integer masquerading as a Rational.) Another option is sage: 3/2 + 1/2 in ZZ True sage: 3/2 + 1/3 in ZZ False - Robert --~--~-~--~~~---~--~~ To post to this group, send email to sage-devel@googlegroups.com To unsubscribe from this group, send email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
[sage-devel] Re: is_Integer() function semantics
In module sage.rings.integer is_Integer(3/2+1/2) returns False The expected output should be True as 3/2+1/2 = 2. I was planning to use this function to check if the result of division is a whole number. You could also use the is_integral method of rational numbers: sage: n = 3/2 + 1/2 sage: n.is_integral() True (This function also exists on Integers, so you could even use it in situations where you weren't sure if you had an honest Integer or an integer masquerading as a Rational.) -cc --~--~-~--~~~---~--~~ To post to this group, send email to sage-devel@googlegroups.com To unsubscribe from this group, send email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
