[sage-support] Drawing Circle using simple equation of circle

2012-05-07 Thread Priyanka Kapoor 
I plotted circle using parametric equation, using circle() function.
But i want to plot x^2+y^2=4
I tried this:
var('x,y')
b=[x^2+y^2==4]
c=plot(b,(x,-2,2),(y,-2,2),color='blue')
c.save('ram.png')

I am getting the following error
TypeError: float() argument must be a string or a number

Can anyone help me. I am new to sage that's why unable to solve errors



-- 
Priyanka Kapoor
http://kapoorpriyanka.in
Linux User Group, Ludhiana

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Re: [sage-support] Drawing Circle using simple equation of circle

2012-05-07 Thread Hakan Granath 
You might want to use implicit_plot instead:

var('x,y')
b = x^2+y^2==4
c = implicit_plot(b,(x,-2,2),(y,-2,2),color='blue')
c.save('ram.png')

/Håkan

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Re: [sage-support] Drawing Circle using simple equation of circle

2012-05-07 Thread Priyanka Kapoor 
 You might want to use implicit_plot instead:

 var('x,y')
 b = x^2+y^2==4
 c = implicit_plot(b,(x,-2,2),(y,-2,2),color='blue')
 c.save('ram.png')

It gives the following error
TypeError: 'tuple' object is not callable



-- 
Priyanka Kapoor
http://kapoorpriyanka.in
Linux User Group, Ludhiana

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Re: [sage-support] Drawing Circle using simple equation of circle

2012-05-07 Thread Hakan Granath 
On Mon, May 7, 2012 at 1:24 PM, Priyanka Kapoor
anjalicool.kapoor...@gmail.com wrote:
 You might want to use implicit_plot instead:

 var('x,y')
 b = x^2+y^2==4
 c = implicit_plot(b,(x,-2,2),(y,-2,2),color='blue')
 c.save('ram.png')

 It gives the following error
 TypeError: 'tuple' object is not callable

Please note that I wrote

b = x^2+y^2==4

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Re: [sage-support] Drawing Circle using simple equation of circle

2012-05-07 Thread Priyanka Kapoor 
 Please note that I wrote

 b = x^2+y^2==4

I got a plot.thank you.  Sir , can't we draw it using plot() function.


-- 
Priyanka Kapoor
http://kapoorpriyanka.in
Linux User Group, Ludhiana

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