[sage-support] Re: How to do: is_Integer(sqrt(a^2+b^2))
On Sep 26, 12:06 am, Robert Bradshaw [EMAIL PROTECTED] wrote: SNIP Indeed! I like Mike Hansen's (or your) proposal to get rid of them all from the global namespace, and replace them only by is_lowercase_method_name functions that are all conceptually meaningful. Of course leave the type-checking is_Uppercase's around, but don't put them in all.py's. What do you guys think? +1 for sure. The patch is up at #4192 and will be merge shortly unless there is some last minute breakage. SNIP - Robert Cheers, Michael --~--~-~--~~~---~--~~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
[sage-support] Re: How to do: is_Integer(sqrt(a^2+b^2))
On Thu, Sep 25, 2008 at 5:33 PM, Quicksilver_Johny [EMAIL PROTECTED] wrote: If c=sqrt(a^2+b^2) How would I check if c is an integer in order to get a true/false value. I tried is_Integer(ZZ(c)), this returns true when c is an integer, but ZZ(c) returns an error when c is not an integer. Try using Python's try/except: try: ZZ(c) # c is an integer except TypeError: # c isn't an integer --~--~-~--~~~---~--~~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
[sage-support] Re: How to do: is_Integer(sqrt(a^2+b^2))
On Sep 25, 2008, at 5:43 PM, William Stein wrote: On Thu, Sep 25, 2008 at 5:33 PM, Quicksilver_Johny [EMAIL PROTECTED] wrote: If c=sqrt(a^2+b^2) How would I check if c is an integer in order to get a true/false value. I tried is_Integer(ZZ(c)), this returns true when c is an integer, but ZZ(c) returns an error when c is not an integer. Try using Python's try/except: try: ZZ(c) # c is an integer except TypeError: # c isn't an integer These is_* sure are causing a lot of confusion lately... Rational numbers also have an is_integral method, so you could also do c=sqrt(a^2+b^2) if c.is_integral(): # c is an integer - Robert --~--~-~--~~~---~--~~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
