[sage-support] Re: question about solve() function
thank you! On Jan 9, 7:27 pm, William Stein wst...@gmail.com wrote: On Fri, Jan 9, 2009 at 3:49 AM, Sand Wraith omegat...@gmail.com wrote: Hi! Is it possible to get order of root of equation? For example equation: f(x)=(x+1)^2 and it's solution solve(f,x) will be [x == -1], but this is not perfect clear, because x==-1 have second order. This equation actually must have two same roots: [x == -1,x == -1]. Use the roots command: sage: f = (x + 1)^2 sage: f.roots() [(-1, 2)] The 2 is the multiplicity. William --~--~-~--~~~---~--~~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
[sage-support] Re: question about solve() function
On Fri, Jan 9, 2009 at 3:49 AM, Sand Wraith omegat...@gmail.com wrote: Hi! Is it possible to get order of root of equation? For example equation: f(x)=(x+1)^2 and it's solution solve(f,x) will be [x == -1], but this is not perfect clear, because x==-1 have second order. This equation actually must have two same roots: [x == -1,x == -1]. Use the roots command: sage: f = (x + 1)^2 sage: f.roots() [(-1, 2)] The 2 is the multiplicity. William --~--~-~--~~~---~--~~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~--~~~~--~~--~--~---
