[sage-support] Re: random questions

2008-04-29 Thread Hector Villafuerte

On Fri, Mar 28, 2008 at 9:05 AM, kcrisman [EMAIL PROTECTED] wrote:
[...]
  Or I could make an init.sage file and put it in, right?  It could be
  useful to put a sample of the sort of commands which live in that kind
  of file on the Wiki FAQ, or even a blank file with suggestions
  commented out in the actual distribution.

+1

For now, here's mine. This allows me to reach python extensions
installed with apt-get.

[EMAIL PROTECTED]:~/.sage$ cat init.sage
import sys
sys.path += ['/usr/local/lib/python2.5/site-packages',
'/usr/lib/python2.5/site-packages',
'/var/lib/python-support/python2.5']

Best,
-- 
 Hector

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[sage-support] Re: random questions

2008-03-28 Thread kcrisman


 Your best is to use Sage's actual polynomial objects instead of
 symbolic expressions (if you're just interested in polynomial
 expressions).

 sage: R.y = ZZ[]
 sage: a = y^5 - y - 12
 sage: a.roots(RR)
 [(1.68758384186451, 1)]
 sage: a.roots(CC)

 [(1.68758384186451, 1),
  (0.472524075221555 + 1.59046294160722*I, 1),
  (0.472524075221555 - 1.59046294160722*I, 1),
  (-1.31631599615381 + 0.922151856490895*I, 1),
  (-1.31631599615381 - 0.922151856490895*I, 1)]

 If you want to use symbolic expressions, you can use the .find_root() method.

 sage: a = x^5 - x - 12
 sage: a.find_root(0,2)
 1.6875838418645157

Ah, I knew there had to be a method!  As usual, I'm looking for the
easiest interface, and this is very nice.


 Sage on startup predefines i in the same way it predefines x. (This is
 in sage.all_cmdline and sage.all_notebook.) Here's what's going on:

 sage: j = I()
 sage: abs(1+j)
 sqrt(2)

Hmm.  So

sage: z=1+i

nonetheless is interpreted as symbolic until further notice?  That's
useful to know.


   A followup would be to ask if any of those functions have functional
   notation; there are lots of functions for CC, but they mostly seem to
   use object notation.

 What methods did you have in mind?

Just the usual - everything!  :)  But upon further experimentation I
find that I must have been not trying the right things yesterday,
because arg works functionally, and the behavior that log(i) returns
log(I) is consistent with log(2) returning log(2), symbolically, as
above.  Sorry for asking that - I must have been too tired last night
to try everything.


   3.  I remember that at some point implicit coefficient multiplication
   was implemented, e.g.

 Implicit multiplication is turned off by default.  You can turn it on:

 sage: implicit_multiplication(True)
 sage: 2x
 2*x

 --Mike

Or I could make an init.sage file and put it in, right?  It could be
useful to put a sample of the sort of commands which live in that kind
of file on the Wiki FAQ, or even a blank file with suggestions
commented out in the actual distribution.

Thanks!
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[sage-support] Re: random questions

2008-03-27 Thread Mike Hansen

Hello,

  1.  The solve wrapper of maxima does some nice stuff symbolically, but
  of course it can't handle everything, like

  sage: solve(x^5-x-12,x)
  [0 == x^5 - x - 12]

  which makes sense!  But I poked around a little for a numerical
  approximation of solutions command and didn't find it.  This probably
  means I just didn't look in the right places - any ideas?  I
  understand Mathematica calls this sort of thing nsolve, but I really
  don't know.

Your best is to use Sage's actual polynomial objects instead of
symbolic expressions (if you're just interested in polynomial
expressions).

sage: R.y = ZZ[]
sage: a = y^5 - y - 12
sage: a.roots(RR)
[(1.68758384186451, 1)]
sage: a.roots(CC)

[(1.68758384186451, 1),
 (0.472524075221555 + 1.59046294160722*I, 1),
 (0.472524075221555 - 1.59046294160722*I, 1),
 (-1.31631599615381 + 0.922151856490895*I, 1),
 (-1.31631599615381 - 0.922151856490895*I, 1)]

If you want to use symbolic expressions, you can use the .find_root() method.

sage: a = x^5 - x - 12
sage: a.find_root(0,2)
1.6875838418645157


  2.  How far does Sage recognize complex numbers a priori?  For
  instance,

  sage: abs(1+i)
  sqrt(2)

  but pretty much anything else doesn't seem to recognize it, as indeed

Sage on startup predefines i in the same way it predefines x. (This is
in sage.all_cmdline and sage.all_notebook.) Here's what's going on:

sage: j = I()
sage: abs(1+j)
sqrt(2)


  A followup would be to ask if any of those functions have functional
  notation; there are lots of functions for CC, but they mostly seem to
  use object notation.

What methods did you have in mind?


  3.  I remember that at some point implicit coefficient multiplication
  was implemented, e.g.

Implicit multiplication is turned off by default.  You can turn it on:

sage: implicit_multiplication(True)
sage: 2x
2*x

--Mike

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