On Sun, 28 Feb 2010 23:02:08 -0800 (PST), Sharpie <ch...@sharpsteen.net> wrote: > However, tonight I have been trying to solve an open channel flow > problem which requires me to find the roots of: > > y^3 - 1.39027132807289 * y^2 + 0.090610488164005 == 0 > > find_root() does return the correct answers-- but in this case both > positive roots are of interest so it would be nice to recover them > both at the same time.
Hi, How about this: sage: R.<y> = RR[] sage: f = y^3 - 1.39027132807289 * y^2 + 0.090610488164005 sage: f.roots() [(-0.236040904804615, 1), (0.286518993973450, 1), (1.33979323890405, 1)] Is this what you were hoping for? Best, Alex -- Alex Ghitza -- http://aghitza.org/ Lecturer in Mathematics -- The University of Melbourne -- Australia -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
