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UNCERTAINTY  PRINCIPLE

IS

UNTENABLE

 

By reanalysing the experiment of Heisenberg Gamma-Ray Microscope and one of ideal 
experiment from which uncertainty principle is derived , it is found that actually 
uncertainty principle can not be obtained from these two ideal experiments . And it is 
found that uncertainty principle is untenable.

 

Key words : 

uncertainty principle; experiment of Heisenberg Gamma-Ray Microscope; ideal experiment 

 

 

Ideal  Experiment  1      

Experiment  of  Heisenberg Gamma-Ray  Microscope

 

A free electron sits directly beneath the center of the microscope's lens (see the 
picture below or AIP page: http://www.aip.org/history/heisenberg/p08b.htm). The 
circular lens forms a cone of angle 2A from the electron. The electron is then 
illuminated from the left by gamma rays--high energy light which has the shortest 
wavelength. These yield the highest resolution, for according to a principle of wave 
optics, the microscope can resolve (that is, "see" or distinguish) objects to a size 
of dx, which is related to and to the wavelength L of the gamma ray, by the 
expression: 

dx = L/(2sinA)                                   (1)

However, in quantum mechanics, where a light wave can act like a particle, a gamma ray 
striking an electron gives it a kick. At the moment the light is diffracted by the 
electron into the microscope lens, the electron is thrust to the right. To be observed 
by the microscope, the gamma ray must be scattered into any angle within the cone of 
angle 2A. In quantum mechanics, the gamma ray carries momentum, as if it were a 
particle. The total momentum p is related to the wavelength by the formula

 p = h / L, where h is Planck's constant.               (2)

In the extreme case of diffraction of the gamma ray to the right edge of the lens, the 
total momentum in the x direction would be the sum of the electron's momentum P'x in 
the x direction and the gamma ray's momentum in the x direction: 

        P'x + (h sinA) / L', where L' is the wavelength of the deflected gamma ray.

In the other extreme, the observed gamma ray recoils backward, just hitting the left 
edge of the lens. In this case, the total momentum in the x direction is: 

      P''x - (h sinA) / L''.

The final x momentum in each case must equal the initial x momentum, since momentum is 
never lost (it is conserved). Therefore, the final x momenta are equal to each other: 

P'x + (h sinA) / L' = P''x - (h sinA) / L''              (3)

If A is small, then the wavelengths are approximately the same, 

L' ~ L" ~ L. So we have 

P''x - P'x = dPx ~ 2h sinA / L                     (4)

Since dx = L/(2 sinA), we obtain a reciprocal relationship between the minimum 
uncertainty in the measured position,dx, of the electron along the x axis and the 
uncertainty in its momentum, dPx, in the x direction: 

dPx ~ h / dx    or   dPx dx ~ h.               (5)

For more than minimum uncertainty, the "greater than" sign may added.

Except for the factor of 4pi and an equal sign, this is Heisenberg's uncertainty 
relation for the simultaneous measurement of the position and momentum of an object

    . 

Reanalysis

To be seen by the microscope, the gamma ray must be scattered into any angle within 
the cone of angle 2A.

The microscope can resolve (that is, "see" or distinguish) objects to a size of dx, 
which is related to and to the wavelength L of the gamma ray, by the expression:

dx = L/(2sinA)                                   (1)

It is the resolving limit of the microscope, and it is the uncertain quantity of the 
object's position.

Microscope can not see the object which the size is smaller than its resolving limit 
dx.

Therefore, to be seen by the microscope, the size of the electron must be larger than 
the resolving limit dx or equal to the resolving limit dx.

But if the size of the electron is larger than or equal to the resolving limit dx, 
electron will not be in the range dx. dx can not be deemed to be the uncertain 
quantity of the electron's position which can be seen by microscope, dx can be deemed 
to be the uncertain quantity of the electron's position which can not be seen by 
microscope only.

dx is the position's uncertain quantity of the electron which can not 

be seen by microscope

To be seen by the microscope, the gamma ray must be scattered into any angle within 
the cone of angle 2A, so we can measure the 

momentum of the electron.

dPx is the momentum's uncertain quantity of the electron which can be seen by 
microscope.

What relates to dx is the electron which the size is smaller than the 

resolving limit .The electron is in the range dx, it can not be seen by the 
microscope, so its position is uncertain.

What relates to dPx is the electron which the size is larger than or equal to the 
resolving limit .The electron is not in the range dx, it can be seen by the 
microscope, so its position is certain.

Therefore, the electron which relate to dx and dPx respectively is not the same.

What we can see is the electron which the size is larger than or equal to the 
resolving limit dx and has certain position, dx = 0..

Quantum mechanics does not relate to the size of the object. but on the Experiment Of 
Heisenberg Gamma-Ray Microscope, the using of the microscope must relate to the size 
of the object, the size of the object which can be seen by the microscope must be 
larger than or equal to the resolving limit dx of the microscope, thus it does not 
exist alleged the uncertain quantity of the electron's position dx.

To be seen by the microscope, none but the size of the electron is larger than or 
equal to the resolving limit dx, the gamma ray which diffracted by the electron can be 
scattered into any angle within the cone of angle 2A, we can measure the momentum of 
the electron. 

What we can see is the electron which has certain position, dx = 0, so that none but 
dx = 0£¬we can measure the momentum of the electron.

In Quantum mechanics, the momentum of the electron can be measured accurately when we 
measure the momentum of the electron only, therefore, we can gained dPx = 0.

Therefore ,

dPx dx =0.                                     (6)

 

 

Ideal experiment 2

Experiment of single slit diffraction

 

Supposing a particle moves in Y direction originally and then passes a slit with width 
dx . So the uncertain quantity of the particle position in X direction is dx (see the 
picture below) , and interference occurs at the back slit . According to Wave Optics , 
the angle where No.1 min of interference pattern is , can be calculated by following 
formula :

sinA=L/2dx                                     (1)

and

L=h/p          where h is Planck¡¯s constant.       (2)

So uncertainty principle can be obtained 

dPx dx ~ h                                    (5)

 

Reanalysis

According to Newton first law , if the external force at the X direction does not 
affect particle ,the particle will keep the uniform straight line Motion State or 
Static State , and the motion at the Y direction unchangeable .Therefore , we can lead 
its position in the slit form its starting point .

The particle can have the certain position in the slit, and the uncertain quantity of 
the position dx =0 .

According to Newton first law , if the external force at the X direction does not 
affect particle,and the original motion at the Y direction is unchangeable , the 
momentum of the particle at the X direction will be Px=0 , and the uncertain quantity 
of the momentum will be dPx =0.

Get: 

dPx dx =0.                                     (6)

It has not any experiment to negate NEWTON FIRST LAW, in spite of quantum mechanics or 
classical mechanics, NEWTON FIRST LAW can be the same with the microcosmic world.

Under the above ideal experiment , it considered that slit¡¯s width is the uncertain 
quantity of the particle¡¯s position. But there is no reason for us to consider that 
the particle in the above experiment have position¡¯s uncertain quantity certainly, 
and no reason for us to consider that the slit¡¯s width is the uncertain quantity of 
the particle¡¯s position.

Therefore,  uncertainty principle 

dPx dx ~ h                                      (5)

which is derived from the above experiment is unreasonable .

 

Concluson

>From the above reanalysis , it is realized that the ideal experiment demonstration 
>for uncertainty principle is untenable .

uncertainty principle is untenable.                      .

 

Reference book :

1.   Max Jammer. (1974)  The philosophy of quantum mechanics  (John wiley & sons , Inc 
New York )   Page 65

2.  Max Jammer. (1974)  The philosophy of quantum mechanics  (John wiley & sons , Inc 
New York )   Page 67

http://www.aip.org/history/heisenberg/p08b.htm

 

Author  :   Gong BingXin

Address :   P.O.Box A111 YongFa XiaoQu XinHua HuaDu

         GuangZhou 510800 P.R.China

E-mail  :   [EMAIL PROTECTED]

Tel:        86¡ª20---86856616

  


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