Re: [Scons-dev] Proper way to get File path (undocumented rfile)
str(File) just calls f.path. There are also plenty of other attributes like
fullpath. Sometimes f.srcnode().path is useful. Most are documented, see
File and Directory Nodes in the man page. The ones that aren't (like rfile)
are intended for internal use but may occasionally still be useful. See
the API docs at
http://www.scons.org/doc/latest/HTML/scons-api/SCons.Node.FS.File-class.html
for gory details.
-- Gary
On Fri, Oct 2, 2015 at 10:07 AM, Jonathon Reinhart <
jonathon.reinh...@gmail.com> wrote:
> I, too have come across scenarios where rfile() was the only way to
> accomplish exactly what I needed. I believe the scenario was this:
>
> The arguments / command-line parameters to my external utility were so
> complex, SCons couldn't handle it himself. So I wrote my own
> variable-function-thing (like ${_concat}) in which I needed to expand the
> Nodes to their paths, just like SCons would when expanding $TARGETS to
> their paths. This is how I ended up finding rfile().
>
> It seems like it should be documented.
>
>
>
>
>
> On Fri, Oct 2, 2015 at 4:15 AM, anatoly techtonik
> wrote:
>
>> Hi,
>>
>> Currently the way to get filename from File node is to str() that File.
>> That's quite shady API, especially if used in function like:
>>
>> def convert(node):
>> return str(node).replace('\\', '/')
>>
>> I mean you have no idea what types of node are expected and why
>> there is slash escaping. The str(node) can return anything and
>> works on any types of nodes.
>>
>> So, there is undocumented method File.rfile() with the path.
>>
>> http://www.scons.org/doc/HTML/scons-api/SCons.Node.FS.File-class.html#rfile
>> Which contains os specific path and it is used for example in
>> https://github.com/wesnoth/wesnoth/pull/481/files
>>
>> The questions.
>> 1. Why it is called rfile?
>> 2. Should it be documented?
>> 3. What should be the proper API to get path info for File node?
>> 4. What is the proper API to convert paths to system-specific and to
>> canonical (forward slash) form?
>> --
>> anatoly t.
>>
>> ___
>> Scons-dev mailing list
>> Scons-dev@scons.org
>> https://pairlist2.pair.net/mailman/listinfo/scons-dev
>>
>>
>
>
> --
> Computers are incredibly fast, accurate and stupid. Human beings are
> incredibly slow, inaccurate and brilliant. Together they are powerful
> beyond imagination.
> A. Einstein
>
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>
--
Gary
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Re: [Scons-dev] Proper way to get File path (undocumented rfile)
I, too have come across scenarios where rfile() was the only way to
accomplish exactly what I needed. I believe the scenario was this:
The arguments / command-line parameters to my external utility were so
complex, SCons couldn't handle it himself. So I wrote my own
variable-function-thing (like ${_concat}) in which I needed to expand the
Nodes to their paths, just like SCons would when expanding $TARGETS to
their paths. This is how I ended up finding rfile().
It seems like it should be documented.
On Fri, Oct 2, 2015 at 4:15 AM, anatoly techtonik
wrote:
> Hi,
>
> Currently the way to get filename from File node is to str() that File.
> That's quite shady API, especially if used in function like:
>
> def convert(node):
> return str(node).replace('\\', '/')
>
> I mean you have no idea what types of node are expected and why
> there is slash escaping. The str(node) can return anything and
> works on any types of nodes.
>
> So, there is undocumented method File.rfile() with the path.
> http://www.scons.org/doc/HTML/scons-api/SCons.Node.FS.File-class.html#rfile
> Which contains os specific path and it is used for example in
> https://github.com/wesnoth/wesnoth/pull/481/files
>
> The questions.
> 1. Why it is called rfile?
> 2. Should it be documented?
> 3. What should be the proper API to get path info for File node?
> 4. What is the proper API to convert paths to system-specific and to
> canonical (forward slash) form?
> --
> anatoly t.
>
> ___
> Scons-dev mailing list
> Scons-dev@scons.org
> https://pairlist2.pair.net/mailman/listinfo/scons-dev
>
>
--
Computers are incredibly fast, accurate and stupid. Human beings are
incredibly slow, inaccurate and brilliant. Together they are powerful
beyond imagination.
A. Einstein
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[Scons-dev] Proper way to get File path (undocumented rfile)
Hi,
Currently the way to get filename from File node is to str() that File.
That's quite shady API, especially if used in function like:
def convert(node):
return str(node).replace('\\', '/')
I mean you have no idea what types of node are expected and why
there is slash escaping. The str(node) can return anything and
works on any types of nodes.
So, there is undocumented method File.rfile() with the path.
http://www.scons.org/doc/HTML/scons-api/SCons.Node.FS.File-class.html#rfile
Which contains os specific path and it is used for example in
https://github.com/wesnoth/wesnoth/pull/481/files
The questions.
1. Why it is called rfile?
2. Should it be documented?
3. What should be the proper API to get path info for File node?
4. What is the proper API to convert paths to system-specific and to
canonical (forward slash) form?
--
anatoly t.
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