Re: [Sikuli-driver] [Question #645284]: vnc & exit

2017-06-29 Thread David ENJOLRAS
Question #645284 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/645284

Status: Open => Solved

David ENJOLRAS confirmed that the question is solved:
vnc.stop()
is the solution !

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Re: [Sikuli-driver] [Question #645284]: vnc & exit

2017-06-29 Thread David ENJOLRAS
Question #645284 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/645284

Status: Needs information => Open

David ENJOLRAS gave more information on the question:
that's all I have.
maybe a blank line in the top of my script ?

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Re: [Sikuli-driver] [Question #645284]: vnc & exit

2017-06-28 Thread RaiMan
Question #645284 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/645284

Status: Open => Needs information

RaiMan requested more information:
vnc = vncStart("atemqesxhost21p", 5901)
vnc.stop
exit(0)

... are only 3 lines, but the error says:
 stopped with error in line 4

furthermore it must be:
vnc.stop()

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Re: [Sikuli-driver] [Question #645284]: vnc & exit

2017-06-28 Thread David ENJOLRAS
Question #645284 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/645284

Description changed to:
code:

vnc = vncStart("atemqesxhost21p", 5901)
vnc.stop
exit(0)

generate :
CConnection: Server supports RFB protocol version 3.8
CConnection: Using RFB protocol version 3.8

[error (28/06/17 08:10:18)] script [ BMR ] stopped with error in line 4
[error (28/06/17 08:10:18)] java.util.ConcurrentModificationException ( 
java.util.ConcurrentModificationException )

==> How to provide an exit code after after use vncStart ?
( given than exit(0) alone works well )

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