[sqlalchemy] Column type in select w/ if condition

2010-03-30 Thread Bryan
The underlying column returns a Decimal object when queried regularly,
and when summed as follows:

select([ mytable.c.hours ])
Decimal(1.0)
select([ func.sum(mytable.c.hours) ])
Decimal(1.0)

...but when I sum it w/ an if statement, it returns a float:

select([ func.sum(func.if_(True, mytable.c.hours, 0)) ])
1.0

How can I control the return type of that summed if column?

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Re: [sqlalchemy] Column type in select w/ if condition

2010-03-30 Thread Mariano Mara
Excerpts from Bryan's message of Tue Mar 30 11:27:57 -0300 2010:
 The underlying column returns a Decimal object when queried regularly,
 and when summed as follows:
 
 select([ mytable.c.hours ])
 Decimal(1.0)
 select([ func.sum(mytable.c.hours) ])
 Decimal(1.0)
 
 ...but when I sum it w/ an if statement, it returns a float:
 
 select([ func.sum(func.if_(True, mytable.c.hours, 0)) ])
 1.0
 
 How can I control the return type of that summed if column?
 

You could use cast [1] (example: casting to Float, untested):

from sqlalchemy.sql.expression import cast
from sqlalchemy.sa import Float
...
select([ cast(func.sum(func.if_(True, mytable.c.hours, 0)), Float)])

[1] 
http://www.sqlalchemy.org/docs/reference/sqlalchemy/expressions.html#sqlalchemy.sql.expression.cast

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