Hello, I have 3 main tables and 3 association tables between them Main tables: Sites, Categories, Products Association Tables: Sites<->Categories, Categories<->Products, Sites<->ChosenProducts
Here is a link to diagram: https://dbdiagram.io/d/5f3a863d39081a20ae94d500 Here is my code: https://gist.github.com/DarkSuniuM/df1cfaeaf7a0745326653078febedc10 I need to join Site to Category and then Category to Product to get all products associated with a Site object. It's doable using the following statement: `session.query(Product).join(Categories.products).join(Categories.sites).filter(Site.id == 1).all()` I also am able to get chosein products by just getting the site and then using it's `chosen_products` attribute But I need to label or even create a temporary object for each object I need to be able to get the difference between available products (by categories for a site) and chosein products for a site I need to have a runtime(?) attribute on each result like "chosed" and have a boolean value for them based on their existence in chosen_products of website I need to be able list keywords for each product instead of having multiple objects of the same product cause of multiple categories I don't even know if the thing I wanna do is the right way to do it... So, 1. How can I join all these table together and be able to get the difference and intersect and full result? 2. How can I label them based on their existence in ChoseinProducts of a website 3. How can I have intersect of keywords between result (products) and site? (I guess this one should be done using AssociationProxy, but not sure how) Thanks in advance... -- SQLAlchemy - The Python SQL Toolkit and Object Relational Mapper http://www.sqlalchemy.org/ To post example code, please provide an MCVE: Minimal, Complete, and Verifiable Example. See http://stackoverflow.com/help/mcve for a full description. --- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sqlalchemy/d9f8d4a3-dd5f-43c2-9ea0-272771e8b7aan%40googlegroups.com.
