[sqlalchemy] Re: Dynamic where-statement with OR
On 11/7/06, DNeumann [EMAIL PROTECTED] wrote: Hello list, To build a dynamic where-statement in my script, i looked here for more info: http://www.sqlalchemy.org/docs/sqlconstruction.myt#sql_building statement = my_table.select() if id: statement.append_whereclause(my_table.c.id==id) if name: statement.append_whereclause(my_table.c.name==name) ... The where-statement is now generated with the AND-operator. now my question: Is it possible to get OR instead of AND? Or alternative Solutions? Another option that I use quite a lot is to use: query_args = [] if id: query_args.append(my_table.c.id==id) if name: query_args.append(my_table.c.name==name) statement = my_table.select(or_(*query_args)) You can build quite complex queries this way by nesting and_() and or_() in the list. Lee -- Lee McFadden blog: http://www.splee.co.uk work: http://fireflisystems.com --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups sqlalchemy group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~--~~~~--~~--~--~---
[sqlalchemy] Re: Dynamic or-Statement
build the OR clause separately: list = [] list.append(users.c.user_id==id) list.append(users.c.user_name==name) statement = user.select(or_(*list)) or statement.append_whereclause(or_(*list)) alternate method: critrerion = users.c.user_id==id criterion = criterion.or(users.c.user_name==name) crtierion = criterion.or(crit) ... statement = user.select(criterion) On Nov 8, 2006, at 3:33 AM, Dominik Neumann wrote: Hello list, i need to build a dynamic where-statement, linked by the OR-operator. In the docs there are only examples with AND. example (snippet from docs): statement = user.select() statement.append_whereclause(user.c.user_id == id) statement.append_whereclause(user.c.user_name == name) is it possible to get here the OR instead of the AND-operator? Best Regards, -dn --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups sqlalchemy group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~--~~~~--~~--~--~---
