[symfony-users] Re: Symfony 2 Online Conference
For those unfortunate enough to have missed the conference I tried to wrap it all up here: State of #Symfony 2 online conference - a killer feature revealed! - http://bit.ly/cU5KOi Cheers /Christian On Jun 23, 4:58 am, Eno symb...@gmail.com wrote: Anyone attending the online conference tomorrow? I didn't receieve any technical info on how to join the conference and my email asking for info bounced back (with an error message in French malheureusement!). Maybe someone at Sensio can help me? -- -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
[symfony-users] Re: backend module
Hi,
for 1) see
http://www.symfony-project.org/jobeet/1_4/Doctrine/en/12#chapter_12_templates_customization
you can copy out of your cache folder
/cache/APP/ENV/modules/MODULENAME/templates/_list_actions.php
to your module template folder and then remove the link
for 2) then just change the filter in the corresponding class by
replacing the widget
$this-widgetSchema['user_id'] = new
sfWidgetFormFilterInput(array('with_empty' = false))
Hope that helps
Susan
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[symfony-users] Re: fieldset
well, depends on your needs. can you share more details?
since $form prints you only list-elements, you can always decorate it
with a fieldset by yourself.
if you want it more advanced and automatically, you could create your
own decorator.
Have a look into this post:
http://www.thatsquality.com/articles/7-days-of-symfony-1-1-forms-widgets-and-validators-day7
this is still valid for symfony 1.4
for a checkbox list with different labels you could create something
like this:
$this-widgetSchema['member_type'] = new sfWidgetFormChoice(array(
'choices' = array(
'B' = 'Boss',
'U' = 'User'
),
'expanded' = true,
'renderer_options' = array('template' = 'strong%group%/
strong %options%')
));
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[symfony-users] Re: Day 1 - jobeet problem
Try with frontend_dev.php because index.php (the production controller) does not print out error messages. Also try to put there a phpinfo.php that prints out the phpinfo() so you can check if all your settings are allright. gabriel On Jun 22, 7:30 pm, Christian chri...@gmail.com wrote: Hi! my name is christian and i'm new with symfony framework. I found this step by step tutorial:http://www.symfony-project.org/jobeet/1_2/Propel/it/01 i have troubles during the apache configuration... this is my httpd.conf ___ __ # Be sure to only have this line once in your #configuration NameVirtualHost 127.0.0.1:8080 # This is the configuration for your project Listen 127.0.0.1:8080 VirtualHost 127.0.0.1:8080 DocumentRoot /home/chris/public_html/jobeet/web DirectoryIndex index.php Directory /home/chris/public_html/jobeet/web AllowOverride All Allow from All /Directory Alias /sf /home/chris/public_html/jobeet/web/lib/vendor/symfony/data/ web/sf Directory /home/chris/public_html/jobeet/web/lib/vendor/symfony/ data/web/sf AllowOverride All Allow from All /Directory /VirtualHost ___ where public_html is my apcahe DocumentRoot in whitch i have a lot of directory with different site, but when i put this link in my browser:http://localhost:8080/index.php(as the tutorial say) i can't see anything...only a blank page... can you help me please? thanks Chris -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
Re: [symfony-users] Symfony 2 Online Conference
On 6/23/10 4:58 AM, Eno wrote: Anyone attending the online conference tomorrow? I didn't receieve any technical info on how to join the conference and my email asking for info bounced back (with an error message in French malheureusement!). Maybe someone at Sensio can help me? I will take care of that. Fabien -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
[symfony-users] Re: Day 1 - jobeet problem
i opened it and this is the log: [Wed Jun 23 13:47:30 2010] [error] [client 127.0.0.1] PHP Warning: require_once(/home/chris/public_html/jobeet/web/config/ ProjectConfiguration.class.php): failed to open stream: No such file or directory in /home/chris/public_html/jobeet/web/index.php on line 4 [Wed Jun 23 13:47:30 2010] [error] [client 127.0.0.1] PHP Fatal error: require_once(): Failed opening required '/home/chris/ public_html/jobeet/web/config/ ProjectConfiguration.class.php' (include_path='.:/usr/share/php:/usr/ share/pear') in /home/chris/public_html/jobeet/web/index.php on line 4 [Wed Jun 23 13:47:30 2010] [error] [client 127.0.0.1] PHP Warning: require_once(/home/chris/public_html/jobeet/web/config/ ProjectConfiguration.class.php): failed to open stream: No such file or directory in /home/chris/public_html/jobeet/web/index.php on line 4 [Wed Jun 23 13:47:30 2010] [error] [client 127.0.0.1] PHP Fatal error: require_once(): Failed opening required '/home/chris/ public_html/jobeet/web/config/ ProjectConfiguration.class.php' (include_path='.:/usr/share/php:/usr/ share/pear') in /home/chris/public_html/jobeet/web/index.php on line 4 i fixed the link but when i restart apache the log answer is: [Wed Jun 23 13:50:52 2010] [error] [client 127.0.0.1] script '/home/ chris/public_html/jobeet/index.php' not found or unable to stat [Wed Jun 23 13:50:53 2010] [error] [client 127.0.0.1] File does not exist: /home/chris/public_html/jobeet/favicon.ico and localhost:8080/index.php is always blank... On 23 Giu, 03:13, Eno symb...@gmail.com wrote: On Tue, 22 Jun 2010, Christian wrote: where public_html is my apcahe DocumentRoot in whitch i have a lot of directory with different site, but when i put this link in my browser: http://localhost:8080/index.php(as the tutorial say) i can't see anything...only a blank page... can you help me please? Look at your Apache error log. -- -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
[symfony-users] Re: Route does not add a parameter when its defined as a default one.
These are just example routes, there are no routes with the same name.
Why should order of route matter when I use it's name in the url
helper (e.g. link_for(5 '@blog?page=5'))?
For Route 3 this should output http://localhost/blog/page/5, but the
output is http://localhost/blog.
On Jun 23, 4:38 am, Eno symb...@gmail.com wrote:
Remember the orderf of routes *does* matter, so you should have most
specific route to least specific routes, e.g. using a wildcard will
match all routes that start /blog so probably that route should be last.
On Tue, 22 Jun 2010, Ivo Az. wrote:
Here's examples:
Link
?php echo link_to($page, '@blog?page='.$page) ?
Route 1
blog:
url: /blog/*
param: { module: blog, action: list }
Output:http://localhost/blog/page/2
Route 2
blog:
url: /blog/:page
param: { module: blog, action: list, page: 1 }
Output:http://localhost/blog/2
Route 3
blog:
url: /blog/*
param: { module: blog, action: list, page: 1 }
Output:http://localhost/blog
Why in 3rd case the url does not contain the page parameter as in
first example?
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[symfony-users] Re: Day 1 - jobeet problem
same thing with frontend_dev.php... On 23 Giu, 08:55, pghoratiu pghora...@gmail.com wrote: Try with frontend_dev.php because index.php (the production controller) does not print out error messages. Also try to put there a phpinfo.php that prints out the phpinfo() so you can check if all your settings are allright. gabriel On Jun 22, 7:30 pm, Christian chri...@gmail.com wrote: Hi! my name is christian and i'm new with symfony framework. I found this step by step tutorial:http://www.symfony-project.org/jobeet/1_2/Propel/it/01 i have troubles during the apache configuration... this is my httpd.conf ___ __ # Be sure to only have this line once in your #configuration NameVirtualHost 127.0.0.1:8080 # This is the configuration for your project Listen 127.0.0.1:8080 VirtualHost 127.0.0.1:8080 DocumentRoot /home/chris/public_html/jobeet/web DirectoryIndex index.php Directory /home/chris/public_html/jobeet/web AllowOverride All Allow from All /Directory Alias /sf /home/chris/public_html/jobeet/web/lib/vendor/symfony/data/ web/sf Directory /home/chris/public_html/jobeet/web/lib/vendor/symfony/ data/web/sf AllowOverride All Allow from All /Directory /VirtualHost ___ where public_html is my apcahe DocumentRoot in whitch i have a lot of directory with different site, but when i put this link in my browser:http://localhost:8080/index.php(asthe tutorial say) i can't see anything...only a blank page... can you help me please? thanks Chris -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
Re: [symfony-users] Abridged summary of symfony-users@googlegroups.com - 44 Messages in 23 Topics
Beste, Tot en met 27 juni ben ik niet aanwezig op kantoor. U kunt voor dringende zaken contact opnemen met Wout Withagen: w...@freshheads.com of 013 5448761. Met vriendelijke groet, Joost Farla joost.fa...@freshheads.com - - freshheads grafisch ontwerp en internet applicaties Dunantstraat 1c | 5017 KC Tilburg | Nederland tel. +31 (0)13 5448761 | fax. +31 (0)13 5448762 i...@freshheads.com | www.freshheads.com -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
[symfony-users] Re: How to pass PHP values to addJavascript() (or something else) ?
On 22 Giu, 10:03, François franc...@robichet.com wrote: I'd like to pass values to my JS script when I call it. So I look the API for the addJavascript() method, herre is it : You shouldn't pass variables from php to javascript. Javascript should be always unobtrusive, so the only point of contact between your html (and php) and your javascript should be the DOM. Just insert your php variables somewhere in your page (e.g. in a hidden field of a form), then retrieve them with javascript (with jQuery, it's really simple) cheers Massimiliano -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
[symfony-users] Re: Get record id and set it into form
i used mergeForm() i used id_table_a as foreign key. so if i change it to table_a_id symfony would act as you described ? On 21 juin, 12:48, glmasw glen.swinfi...@gmail.com wrote: When you say 'merged two forms' did you use the embedForm() or mergeForm() or did you do this manually? Assuming that the table_a_id is the foreign key for the record in table b, Symfony will deal with this for you if you use merged or embedded forms - see Doing More With Symfony - Advanced Forms:http://www.symfony-project.org/more-with-symfony/1_4/en/06-Advanced-F... On Jun 21, 8:00 am, Tom Ptacnik to...@tomor.cz wrote: I think that the solution might be owerwriting the doSave method .. or some method where the saving of the object is done. You need to save the foreign object first - to obtain the id from the database, then save the main object. On 19 čvn, 12:24, titiyoyo terence.pi...@gmail.com wrote: Hi there, i'm new to symfony and am bumping into a problem here. I merged two forms from 2 different models and need to get a foreign key from table A to put in this table B form. Basically, i have to - create a record in table A and get this record's id - create a record in table B an set it's table_a_id to the value i just got - fill out the rest of the info that will be put in table B My question is : how can i get the needed id ? -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
[symfony-users] I18n in form filter
Is it possible to use fields from the i18n object table in the form filter? So can I embed the UserI18nFormFilter class in my UserFormFilter? The normal embedI18n function from the sfForm class doesn't work... -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
Re: [symfony-users] change label in ahDoctrineEasyEmbeddedRelationsPlugin
I'll have to take a look at that — please ping me again in a little while (this
evening or tomorrow morning).
Daniel
Sent from my iPad
On Jun 23, 2010, at 10:29 AM, slau susan@gmx.de wrote:
Hi everybody,
I am using ahDoctrineEasyEmbeddedRelationsPlugin to embed pictureForms
within a let's say galleryForm. Each picture has a field title, which I use
also as return value for the __toString() method.
in my galleryForm the related photos are listed. But each photo form is
labeled again with the object-name. See screen.gif , title=wom appears on the
left side as form name again.
How can I turn off or at least replace the label with something else?
My widget looks right now like that:
$this-embedRelations(array(
'Photos' = array(
'considerNewFormEmptyFields'= array('title', 'file'),
'noNewForm' = false, // false - show new form
'newFormLabel' = 'Add new photo',
'newFormClass' = 'JCropPhotoForm',
'newFormClassArgs' = array(array('article_id' =
$this-getOption('id'))),
'displayEmptyRelations' = true,
'formClass' = 'JCropPhotoForm',
'formClassArgs' =
array(array('ah_add_delete_checkbox' = true )),
'newFormAfterExistingRelations' = true, //moves new photo form after
the existing photo lists
'formFormatter' = null,
'multipleNewForms' = true, // needs to be true if
newFormsInitialCount 1
'newFormsInitialCount' = 1, // number of new forms, if
multipleNewForms is true
'newFormsContainerForm' = '',// pass BaseForm object here
or we will create ahNewRelationsContainerForm
'newRelationButtonLabel'= '+ add photo', // seems not to
work, but the button shows up only, when multipleNewForms is true
'newRelationAddByCloning' = true,
'newRelationUseJSFramework' = 'jQuery'
)
));
Susan
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screen.gif
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Re: [symfony-users] ahDoctrineEasyEmbeddedRelationsPlugin bug when sfWidgetFormInputFile used?
Yes, this is — regrettably — a known and documented shortcoming of this plugin. I'll have to spend some time getting this to work. :( Daniel Sent from my iPad On Jun 23, 2010, at 5:21 PM, slau susan@gmx.de wrote: Hi, bug or feature or developer mistake? I try to use ahDoctrineEasyEmbeddedRelationsPlugin for a gallery with multiple pictures. So this is a 1:n relation. The form works fine as long my embed pictureForm has just standard input-fields. as soon I change the file field to sfWidgetFormInputFile the empty form for possible new uploads will be saved as well. did someone else had that problem? susan -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
[symfony-users] Updating the database with embedded form values
Hi all,
i've got a question regarding where to put the code that actually
saves the values in an embedded form.
My scenario: I have a business object and a business_category object
as well as a business_business_category object which ties
business_categories to a business in a many to many relationship.
I have created a custom form (businessCategoriesSelectionForm) which
basically does:
--
$categories = Doctrine::getTable('business_category')-findAll();
foreach ($categories as $category) {
$this-setWidget($category-getSlug(), new
sfWidgetFormInputCheckbox());
$this-setValidator($category-getSlug(), new
sfValidatorBoolean());
}
--
to build a list of checkboxes. In the businessForm I then embed this
form:
--
// Embed the categories form
$businessCategoriesSelectionForm = new
businessCategoriesSelectionForm();
$this-embedForm('businessCategoriesSelectionForm',
$businessCategoriesSelectionForm);
--
Everything is good so far; when I am using the admin-generator
backend, I then see the custom form I build appear; with the
checkboxes appearing as they should etc.
So now, my question is: where do I write the code which will delete/
create business_business_category objects to ensure that the business
is linked to which ever categories have been selected in the
checkboxes?
I am used to doing it in the controller, whenever these kinds of
things are done via the front end (ie not using the admin-generator
system). Is this the best way to be doing it?
If so, where does this sort of code go? What method would I use in /
apps/backend/modules/business/actions/actions.class.php? Some sort of
preFoo() method?
I've gotten the impression from the docs that this sort of thing
should actually be done on the form itself; using the updateObject()
method or something. Is that the best place for it? And if so, would I
put it on the businessForm updateObject() or the
businessCategoriesSelectionForm form?
In the past, it's always seemed better to put this kind of stuff in
the controller itself, instead of the form; because to me the form is
more about setting up and validating form's, not so much about
actually updating the database (via the Model layer of course).
Am I way off track here?
And where should that update code go?
thanks a lot!
Brett
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[symfony-users] Re: Updating the database with embedded form values
Additionally to this; I have tried using the doUpdateObject() method;
I figure I can put the update code in there. However, the method isn't
getting called.
In my /lib/form/doctrine/businessForm.class.php, as a method of the
businessForm class, I have:
protected function doUpateObject($values) {
echo 'why doesnt this work?';
exit('in doUpateObject');
parent::doUpdateObject($values);
}
However when I use the backend admin generator, and save a business;
this method doesn't get called -- the exit() doesn't get triggered.
What am I missing here?
thanks
On Jun 24, 11:33 am, bretth brett...@gmail.com wrote:
Hi all,
i've got a question regarding where to put the code that actually
saves the values in an embedded form.
My scenario: I have a business object and a business_category object
as well as a business_business_category object which ties
business_categories to a business in a many to many relationship.
I have created a custom form (businessCategoriesSelectionForm) which
basically does:
--
$categories = Doctrine::getTable('business_category')-findAll();
foreach ($categories as $category) {
$this-setWidget($category-getSlug(), new
sfWidgetFormInputCheckbox());
$this-setValidator($category-getSlug(), new
sfValidatorBoolean());
}
--
to build a list of checkboxes. In the businessForm I then embed this
form:
--
// Embed the categories form
$businessCategoriesSelectionForm = new
businessCategoriesSelectionForm();
$this-embedForm('businessCategoriesSelectionForm',
$businessCategoriesSelectionForm);
--
Everything is good so far; when I am using the admin-generator
backend, I then see the custom form I build appear; with the
checkboxes appearing as they should etc.
So now, my question is: where do I write the code which will delete/
create business_business_category objects to ensure that the business
is linked to which ever categories have been selected in the
checkboxes?
I am used to doing it in the controller, whenever these kinds of
things are done via the front end (ie not using the admin-generator
system). Is this the best way to be doing it?
If so, where does this sort of code go? What method would I use in /
apps/backend/modules/business/actions/actions.class.php? Some sort of
preFoo() method?
I've gotten the impression from the docs that this sort of thing
should actually be done on the form itself; using the updateObject()
method or something. Is that the best place for it? And if so, would I
put it on the businessForm updateObject() or the
businessCategoriesSelectionForm form?
In the past, it's always seemed better to put this kind of stuff in
the controller itself, instead of the form; because to me the form is
more about setting up and validating form's, not so much about
actually updating the database (via the Model layer of course).
Am I way off track here?
And where should that update code go?
thanks a lot!
Brett
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