i had the same problem - all i did was i fed FileOutputStream with a real
path, where i wanted files to be stored. ie.
FileOutputStream output = new
FileOutputStream("/and/directories/follow/file.name");
if anybody has more elegant solution, i'll be grateful.
regards,
vVolf
> -----Oryginalna wiadomooeæ-----
> Od: Alexander Batzios [mailto:[EMAIL PROTECTED]]
> Wys³ano: 14 marca 2001 06:12
> Do: [EMAIL PROTECTED]
> Temat: Set application's working path?
>
>
> Hello.
>
> I am using a JSP file to call a class, say myClass, which is
> a pure java
> application. From that class, I then need to call a method,
> say myMethod. The
> part of the JSP file that does the above is like:
>
> myClass mc = new myClass(parameters);
> mc.myMethod();
>
> Part of myMethod() functionality is reading/writting files.
> Well, the thing is
> that it only works in the /bin directory of tomcat (where the
> startup,shutdown
> scripts are). That is, it expects to find files there, and it
> creates files
> there. How can I change it's working path to a virtual path
> of the webserver?
> Or to where the JSP file that calls it lives?
>
> Any help will be greatly appreciated.
>
> Thanks,
> alex
>
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