Howdy,
Why not just do
RequestDispatcher rd =
getServletContext().getRequestDispatcher("/lookup.html");

I.e. don't have the explicit getContext("/example") call in the middle
as you're already in that context.

Yoav Shapira
Millennium ChemInformatics


>-----Original Message-----
>From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
>Sent: Wednesday, July 30, 2003 6:56 PM
>To: [EMAIL PROTECTED]
>Subject: How do I change servlet contexts???
>
>Tomcat: 4.1.24
>
>I have a war file whose base context is "/example".
>Within that context there is an HTTP servlet
>(GuestServlet) with a servlet mapping that captures
>everything under "/example/guest/*".  Within
>GuestServlet.class I create a RequestDispatcher to
>forward control to an HTML page (lookup.html) under
>the base context (/example).  The problem is when
>control is forwarded to /example/lookup.html it does
>not work.  The context remains unchanged at
>/example/guest and so it actually attempts to display
>/example/guest/lookup.html when I need
>/example/lookup.html.  I use the following code within
>GuestServlet.java to try and display lookup.html under
>the base context /example.  Will someone please tell
>me what I am doing wrong?
>
>public class GuestServlet extends HttpServlet {
>
>...
>
>  protected void doPost(HttpServletRequest request,
>HttpServletResponse response) throws ServletException,
>IOException {
>...
>    RequestDispatcher rd = null;
>    // Dispatch to next url
>    ServletContext cntxt =
>context.getContext("/example");
>    rd = cntxt.getRequestDispatcher("/lookup.html");
>    rd.forward(request, response);
>...
>  }
>...
>}
>
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