[Trac] Re: How to get all the menus of a user through program?
On Thursday, January 16, 2020 at 11:29:21 AM UTC-8, RjOllos wrote:
>
>
>
> On Wednesday, January 15, 2020 at 10:34:32 PM UTC-8, Velu Narasimman wrote:
>>
>> Well, I am getting menu as a dictionary as shown below,
>>
>> {'mainnav': [{'active': False, 'name': 'project', 'label': > >}, {'active': False, 'name': 'added_common', 'label': }, {
>> 'active': False, 'name': 'admin', 'label': }, {'active':
>> False, 'name': 'reports', 'label': }, {'active': False,
>> 'name': 'metrics', 'label': }, {'active': False, 'name':
>> 'mytimesheet', 'label': }, {'active': True, 'name':
>> 'myprojects', 'label': }, {'active': False, 'name':
>> 'timesheetapproval', 'label': }], 'metanav': [{'active':
>> False, 'name': 'login', 'label': u'logged in as karthikeyan.nagaraja'}, {
>> 'active': False, 'name': 'logout', 'label': }, {'active':
>> False, 'name': 'prefs', 'label': }, {'active': False, 'name'
>> : 'about', 'label': }]}
>>
>> I get this, when I refresh the web page in my browser. These menus are
>> dynamic, differs among different users based on the permissions that they
>> have in system. But I wish to generate this without using a browser. So how
>> can I make a web request handling in program itself and the above menus?
>>
>
> Are you calling Chrome.get_navigation_items?
> https://trac.edgewall.org/browser/tags/trac-1.4/trac/web/chrome.py#L862
>
> You'll need to make a MockRequest. For examples, I believe this is done in
> a few plugins, but I don't recall which off-hand.
>
> I suppose you could use MockRequest from the test module:
> https://trac.edgewall.org/browser/tags/trac-1.4/trac/test.py#L151
>
> - Ryan
>
Or better might be to extract and modify this code to meet your needs:
https://trac.edgewall.org/browser/tags/trac-1.4/trac/web/chrome.py?marks=947-952#L947
With regard to the mock Request object, navigation contributors only check
permissions like "PERM in req.perm", so your mock could just return True
for that case.
- Ryan
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[Trac] Re: How to get all the menus of a user through program?
On Wednesday, January 15, 2020 at 10:34:32 PM UTC-8, Velu Narasimman wrote:
>
> Well, I am getting menu as a dictionary as shown below,
>
> {'mainnav': [{'active': False, 'name': 'project', 'label': },
> {'active': False, 'name': 'added_common', 'label': }, {
> 'active': False, 'name': 'admin', 'label': }, {'active':
> False, 'name': 'reports', 'label': }, {'active': False,
> 'name': 'metrics', 'label': }, {'active': False, 'name':
> 'mytimesheet', 'label': }, {'active': True, 'name':
> 'myprojects', 'label': }, {'active': False, 'name':
> 'timesheetapproval', 'label': }], 'metanav': [{'active':
> False, 'name': 'login', 'label': u'logged in as karthikeyan.nagaraja'}, {
> 'active': False, 'name': 'logout', 'label': }, {'active':
> False, 'name': 'prefs', 'label': }, {'active': False, 'name':
> 'about', 'label': }]}
>
> I get this, when I refresh the web page in my browser. These menus are
> dynamic, differs among different users based on the permissions that they
> have in system. But I wish to generate this without using a browser. So how
> can I make a web request handling in program itself and the above menus?
>
Are you calling Chrome.get_navigation_items?
https://trac.edgewall.org/browser/tags/trac-1.4/trac/web/chrome.py#L862
You'll need to make a MockRequest. For examples, I believe this is done in
a few plugins, but I don't recall which off-hand.
I suppose you could use MockRequest from the test module:
https://trac.edgewall.org/browser/tags/trac-1.4/trac/test.py#L151
- Ryan
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Re: [Trac] Re: How to get all the menus of a user through program?
well how to use this plugin? I am unable to view any documentation for
this. Please direct me and how can I get the menus with help of this
plugin? give me some thoughts.
On Thursday, January 16, 2020 at 3:33:36 PM UTC+5:30, hasienda wrote:
>
> Am 16. Januar 2020 07:34:32 MEZ schrieb Velu Narasimman <
> velava...@gmail.com >:
>>
>> Well, I am getting menu as a dictionary as shown below,
>>
>> {'mainnav': [{'active': False, 'name': 'project', 'label': > >}, {'active': False, 'name': 'added_common', 'label': }, {
>> 'active': False, 'name': 'admin', 'label': }, {'active':
>> False, 'name': 'reports', 'label': }, {'active': False,
>> 'name': 'metrics', 'label': }, {'active': False, 'name':
>> 'mytimesheet', 'label': }, {'active': True, 'name':
>> 'myprojects', 'label': }, {'active': False, 'name':
>> 'timesheetapproval', 'label': }], 'metanav': [{'active':
>> False, 'name': 'login', 'label': u'logged in as karthikeyan.nagaraja'}, {
>> 'active': False, 'name': 'logout', 'label': }, {'active':
>> False, 'name': 'prefs', 'label': }, {'active': False, 'name'
>> : 'about', 'label': }]}
>>
>> I get this, when I refresh the web page in my browser. These menus are
>> dynamic, differs among different users based on the permissions that they
>> have in system. But I wish to generate this without using a browser. So how
>> can I make a web request handling in program itself and the above menus?
>>
>>
>>
>> On Thursday, January 16, 2020 at 10:24:17 AM UTC+5:30, Velu Narasimman
>> wrote:
>>>
>>> Hi,
>>>
>>> I am using MenusPlugin
>>> for displaying submenus. I need to get all the menus that are about to be
>>> displayed for a user even before he logs into the site. Is it possible? If
>>> yes, how shall I do it in a back-end program? Please share me your ideas.
>>>
>>> Thanks in advance.
>>>
>>
> So you know about XML-RPC-Plugin [1]?
>
> IMHO this is the most standardized non-browser access to enabled Trac
> sites.
>
> [1] https://trac-hacks.org/wiki/XmlRpcPlugin
>
> Mit freundlichem Gruß
>
> Steffen Hoffmann
>
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Re: [Trac] Re: How to get all the menus of a user through program?
Am 16. Januar 2020 07:34:32 MEZ schrieb Velu Narasimman
:
>Well, I am getting menu as a dictionary as shown below,
>
>{'mainnav': [{'active': False, 'name': 'project', 'label': "a">}, {
>'active': False, 'name': 'added_common', 'label': },
>{'active':
>False, 'name': 'admin', 'label': }, {'active': False,
>'name':
>'reports', 'label': }, {'active': False, 'name':
>'metrics',
>'label': }, {'active': False, 'name': 'mytimesheet',
>'label': <
>Element "a">}, {'active': True, 'name': 'myprojects', 'label': "a"
>>}, {'active': False, 'name': 'timesheetapproval', 'label': "a">}],
>'metanav': [{'active': False, 'name': 'login', 'label': u'logged in as
>karthikeyan.nagaraja'}, {'active': False, 'name': 'logout', 'label': <
>Element "a">}, {'active': False, 'name': 'prefs', 'label': "a">}, {
>'active': False, 'name': 'about', 'label': }]}
>
>I get this, when I refresh the web page in my browser. These menus are
>dynamic, differs among different users based on the permissions that
>they
>have in system. But I wish to generate this without using a browser. So
>how
>can I make a web request handling in program itself and the above
>menus?
>
>
>
>On Thursday, January 16, 2020 at 10:24:17 AM UTC+5:30, Velu Narasimman
>wrote:
>>
>> Hi,
>>
>> I am using MenusPlugin
>for
>> displaying submenus. I need to get all the menus that are about to be
>
>> displayed for a user even before he logs into the site. Is it
>possible? If
>> yes, how shall I do it in a back-end program? Please share me your
>ideas.
>>
>> Thanks in advance.
>>
>
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So you know about XML-RPC-Plugin [1]?
IMHO this is the most standardized non-browser access to enabled Trac sites.
[1] https://trac-hacks.org/wiki/XmlRpcPlugin
Mit freundlichem Gruß
Steffen Hoffmann
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