[Tutor] Help with class.self variables
im trying to create a class user
so that
i can do
r=User(1)
r._user.keys()
['rating', 'last_name', 'pageviews', 'ip', 'number_polls', 'site',
'myrand', 'hotmail', 'number_activities', 'skype', 'id', 'city',
'rawpassword', 'number_useraudios', 'zip', 'number_votes',
'last_login', 'number_userpics', 'music', 'email', 'number_pages',
'username', 'number_posts', 'hash', 'number_comments',
'number_pictures', 'first_name', 'yahoo', 'groups', 'heroes',
'favoritestuff', 'number_usermessages_sent', 'vanity', 'interests',
'television', 'number_uservideos', 'created', 'dob', 'gender',
'number_friends', 'liketomeet', 'htmlcodes', 'aim', 'movies',
'password', 'books', 'profilepic', 'number_usermessages',
'email_subscribe', 'number_communities']
so i want this to become
r.rating
r.last_name
r.pageviews and so on
r.username
r.photos()
and so on
but
i want to set the keys of the user row as the
keys of User self
but i m not sure how to do it
for i in self._user.keys():
self[i]=self._user[i]
gives an error
Traceback (most recent call last):
File "stdin", line 1, in module
File "api.py", line 40, in __init__
self[i]=self._user[i]
AttributeError: instance has no attribute '__setitem__'
You can do something like
self.update(_user)
doesnt work either
Traceback (most recent call last):
File "stdin", line 1, in module
File "api.py", line 39, in __init__
self.update(self._user)
AttributeError: user instance has no attribute 'update'
Any thoughts on how to set this?
class User:
"""user object
"""
def __init__(self, id):
self._id = id
self._user=db.query('select * from users where
id=$id',vars=locals())
if not self._user:
self._validuser=False
self._username=''
self._firstname=''
self._lastname=''
self._dob=''
self._gender=''
self._sex=''
else:
self._user=self._user[0]
self._validuser=True
self._username=self._user.username
self._firstname=self._user.first_name
self._lastname=self._user.last_name
self._dob=self._user.dob
self._gender=self._user.gender
self._sex=self._user.gender
for i in self._user.keys():
self[i]=self._user[i]
def userrow(self):
return db.query('select * from users where
id=$self._id',vars=locals())[0]
def photos(self):
return db.query('select pic,id, username from userpics where
user_id=$self._id',vars=locals())
t
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[Tutor] James D Mcclatchey is out of the office.
I will be out of the office starting 05/14/2008 and will not return until 05/19/2008. I will respond to your message when I return. ***IMPORTANT NOTICE: This communication, including any attachment, contains information that may be confidential or privileged, and is intended solely for the entity or individual to whom it is addressed. If you are not the intended recipient, you should delete this message and are hereby notified that any disclosure, copying, or distribution of this message is strictly prohibited. Nothing in this email, including any attachment, is intended to be a legally binding signature.*** ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Help with class.self variables
On Wed, May 14, 2008 at 3:45 AM, Mark [EMAIL PROTECTED] wrote: i want to set the keys of the user row as the keys of User self but i m not sure how to do it for i in self._user.keys(): self[i]=self._user[i] Should be setattr(self, i, self._user[i]) You can do something like self.update(_user) Should be self.__dict__.update(self._user) You should probably consider an existing object-relation mapper such as SQLAlchemy, SQLObject or Django ORM rather than rolling your own. Kent ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] destroying a window once a movie has stoped playing
On Tue, May 13, 2008 at 9:07 PM, [EMAIL PROTECTED] wrote: def movieu(self): mov_name = video.mpg pygame.mixer.quit() screen = pygame.display.set_mode((320, 240)) video = pygame.movie.Movie(mov_name) screen = pygame.display.set_mode(video.get_size()) video.play() while video.get_busy(): for event in pygame.event.get(): if event.type == pygame.QUIT: break this is the peice of code i am using to run a movie in my scissors paper rock game so when rock beats scissors a movie will play. i can get the movie to play but i would like to no if i can make the window destroy once the movie has stoped This message is intended for the addressee named and may contain privileged information or confidential information or both. If you are not the intended recipient please delete it and notify the sender. ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor Hey Nick, You may have better luck asking pygame-specific questions on the pygame mailing list? Pygame maintains an active mailing list. You can email the list at [EMAIL PROTECTED] To get on or off the mailing list, send an email message to [EMAIL PROTECTED] with a simple command in the body. Some examples; (note, no subject is needed). If subscribing or unsubscribing, there's no need to enter any extra email address information. Just use the commands like they are below, the email address you mail from is the address mail will go to (or stop going to). (from: http://pygame.org/wiki/info) I think the Tutor list mainly helps with business type scripting such as accessing a database, opening, writing, reading, closing files, working with lists, dictionaries, tuples, and so forth? The pygame list is specific to pygame, and the gurus there can answer any pygame question you ask them! Happy Programming! -- b h a a l u u at g m a i l dot c o m Kid on Bus: What are you gonna do today, Napoleon? Napoleon Dynamite: Whatever I feel like I wanna do. Gosh! ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Else Clause In A Loop
kinuthia muchane wrote: On Tue, 2008-05-13 at 11:09 -0400, Simón A. Ruiz wrote: When i is 3, then we'll only check (2 % 3 == 0) which is False, so the loop ends unbroken and runs the else clause letting us know that 3 is indeed a prime number. Shouldn't we be checking for (3%2 == 0) instead of (2%3 == 0)? Absolutely right. My mistake. Does this help at all? It was crystal clear! Thanks Simon (I didn't know how to put the accent mark over the 'o', though), the confusion is gone. ;) Awesome. Glad I could be of help. :-D Simón ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] basic lists and loops question
Jon Crump wrote:
Something basic about lists and loops that I'm not getting here. I've
got a long list of dictionaries that looks like this:
lst = [{'placename': u'Stow, Lincolnshire', 'long-name': u'Stow,
Lincolnshire.', 'end': datetime.date(1216, 9, 28), 'start':
datetime.date(1216, 9, 26)},
{'placename': u'Lincoln, Lincolnshire', 'long-name': u'Lincoln,
Lincolnshire.', 'end': datetime.date(1216, 9, 30), 'start':
datetime.date(1216, 9, 28)},
{'placename': u'Lincoln, Lincolnshire', 'long-name': u'Lincoln,
Lincolnshire.', 'end': datetime.date(1216, 10, 2), 'start':
datetime.date(1216, 10, 1)},
{'placename': u'Grimsby, Lincolnshire', 'long-name': u'Grimsby,
Lincolnshire.', 'end': datetime.date(1216, 10, 4), 'start':
datetime.date(1216, 10, 3)},
{'placename': u'Louth, Lincolnshire', 'long-name': u'Louth,
Lincolnshire.', 'end': datetime.date(1216, 10, 4), 'start':
datetime.date(1216, 10, 4)}
]
I have a function that searches through them to find pairs of
dictionaries that satisfy certain criteria. When the nested loops find
such a pair, I need to merge them. So far so good. This works:
def events(data):
evts = []
for x in lst:
for y in lst:
if (x['placename'] == y['placename']) and (x['end'].month + 1 ==
y['start'].month) and (y['start'] - x['end'] == datetime.timedelta(1)):
evts.append({'placename': x['placename'], 'long-name':
x['long-name'], 'start': x['start'], 'end': y['end']})
evts.append(x)
return evts
for x in events(lst):
print x
But then I need to delete the two original dictionaries that I merged.
If I do del x, I get an error local variable 'x' referenced before
assignment
Try lst.remove(x)
I've also tried decorating the processed dictionaries in the if loop
thus:
x['processed'] = True
y['processed'] = True
Then when I call events() I get back the merged dict and the decorated
dicts:
{'placename': u'Lincoln, Lincolnshire', 'end': datetime.date(1216, 10,
2), 'start': datetime.date(1216, 9, 28), 'long-name': u'Lincoln,
Lincolnshire.'}
{'placename': u'Lincoln, Lincolnshire', 'processed': True, 'end':
datetime.date(1216, 9, 30), 'start': datetime.date(1216, 9, 28),
'long-name': u'Lincoln, Lincolnshire.'}
{'placename': u'Lincoln, Lincolnshire', 'processed': True, 'end':
datetime.date(1216, 10, 2), 'start': datetime.date(1216, 10, 1),
'long-name': u'Lincoln, Lincolnshire.'}
But if I try to call events() thus:
for x in events(lst):
if x['processed'] == True:
print x
I get a KeyError.
Sounds like the key 'processed' is created by the assignment
x['processed'] = True. So those dictionaries that have not experienced
this assignment have no such key. You should instead use: if
'processed' in x:
Also if x['processed'] == True: can be expressed if x['processed']:
HTH
--
Bob Gailer
919-636-4239 Chapel Hill, NC
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Re: [Tutor] basic lists and loops question
On Wed, May 14, 2008 at 3:02 PM, Jon Crump [EMAIL PROTECTED] wrote:
Something basic about lists and loops that I'm not getting here.
I have a function that searches through them to find pairs of dictionaries
that satisfy certain criteria. When the nested loops find such a pair, I
need to merge them. So far so good. This works:
def events(data):
evts = []
for x in lst:
for y in lst:
if (x['placename'] == y['placename']) and (x['end'].month + 1 ==
y['start'].month) and (y['start'] - x['end'] == datetime.timedelta(1)):
evts.append({'placename': x['placename'], 'long-name':
x['long-name'], 'start': x['start'], 'end': y['end']})
evts.append(x)
return evts
for x in events(lst):
print x
But then I need to delete the two original dictionaries that I merged. If I
do del x, I get an error local variable 'x' referenced before assignment
Not sure why you got that error but it general it is not a good idea
to delete items from a container you are iterating; the results can be
unpredictable.
I've also tried decorating the processed dictionaries in the if loop thus:
x['processed'] = True
y['processed'] = True
Then when I call events() I get back the merged dict and the decorated
dicts:
{'placename': u'Lincoln, Lincolnshire', 'end': datetime.date(1216, 10, 2),
'start': datetime.date(1216, 9, 28), 'long-name': u'Lincoln, Lincolnshire.'}
{'placename': u'Lincoln, Lincolnshire', 'processed': True, 'end':
datetime.date(1216, 9, 30), 'start': datetime.date(1216, 9, 28),
'long-name': u'Lincoln, Lincolnshire.'}
{'placename': u'Lincoln, Lincolnshire', 'processed': True, 'end':
datetime.date(1216, 10, 2), 'start': datetime.date(1216, 10, 1),
'long-name': u'Lincoln, Lincolnshire.'}
But if I try to call events() thus:
for x in events(lst):
if x['processed'] == True:
print x
I get a KeyError.
The problem is that not every dict has the 'processed' key. Try
if x.get('processed') == True:
or just
if x.get('processed'):
x.get() will return None (instead of raising KeyError) if the key is
not present.
Kent
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Re: [Tutor] basic lists and loops question
Bob, and Kent, Many thanks! Sounds like the key 'processed' is created by the assignment x['processed'] = True. So those dictionaries that have not experienced this assignment have no such key. You should instead use: if 'processed' in x: Doh! Now that WAS obvious Try lst.remove(x) Now this was odd. My trusty guide Learning Python (Lutz Ascher) 2nd Ed. for python 2.3 says nothing about remove(). This must be 2.4 or 2.5 yes? this now has the desired effect (remains to be seen if it works for all instances): def events(data): evts = [] for x in data: for y in data: if (x['placename'] == y['placename']) and (x['end'].month + 1 == y['start'].month) and (y['start'] - x['end'] == datetime.timedelta(1)): x['end'] = y['end'] data.remove(x) evts.append(x) return evts I understand about removing elements from a container you're iterating. Is data.remove(x) problematic in this context? ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] basic lists and loops question
On Wed, May 14, 2008 at 6:03 PM, Jon Crump [EMAIL PROTECTED] wrote: def events(data): evts = [] for x in data: for y in data: if (x['placename'] == y['placename']) and (x['end'].month + 1 == y['start'].month) and (y['start'] - x['end'] == datetime.timedelta(1)): x['end'] = y['end'] data.remove(x) evts.append(x) return evts I understand about removing elements from a container you're iterating. Is data.remove(x) problematic in this context? Yes. It can cause the iteration to skip elements ofthe list. Better to post-process the list with a list comprehension: evts = [ evt for evt in evts if 'processed' not in evt ] Kent ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] basic lists and loops question
On Wed, May 14, 2008 at 9:06 PM, Kent Johnson [EMAIL PROTECTED] wrote: I understand about removing elements from a container you're iterating. Is data.remove(x) problematic in this context? Yes. It can cause the iteration to skip elements of the list. For example: In [1]: l=range(5) In [2]: for i in l: ...: print i ...: if i==2: ...: l.remove(i) ...: ...: 0 1 2 4 Notice how 3 is skipped. Don't do this! Kent ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] basic lists and loops question
Kent, On Wed, 14 May 2008, Kent Johnson wrote: I understand about removing elements from a container you're iterating. Is data.remove(x) problematic in this context? Yes. It can cause the iteration to skip elements ofthe list. Better to post-process the list with a list comprehension: evts = [ evt for evt in evts if 'processed' not in evt ] Thanks very much. This became clear when I applied the .remove(x) solution to the whole list: very strange results. Altering x in the y loop also had unforseen effects. I finally decorated every dictionary acted upon so I could check everything that was going on. the appended merged dict got a merged key and the two dictionaries that were merged each got a processed key, then I post processed the list to remove the 'processed' dictionaries **whew**. Thanks for clarifying AND saving me from error. Jon ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
[Tutor] looking for ways to get diff between two txt files
Hi, I would really appreciate if someone help to find a way to calculate delta (diff) between two similar text files. I have looked at difflib and found related script at this site http://www.java2s.com/Code/Python/Utility/Printfilediffsincontextunifiedorndiffformats.htm Is there a simple way to just get delta between two files? e.g. I have below two files and the delta between these two files is in diff_output.txt file1.txt hello world file2.txt hello world hello python diff_output.txt hello python -- Thanks, Kamal ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
