Re: [Tutor] Having an Issue
On Fri, Mar 13, 2009 at 8:43 PM, Jared White wrote: > I dunno how this works but hopefully someone can help me > > I am trying to build a program in Python but for someone i can not get what > i am trying to build WORK > > by email you guys is there a way i can get some help some pointer on the > program i am trying to solve Yes, just send your questions to the list and we will try to help. It works best if you can - clearly describe what you are trying to do - show what you have tried so far - tell us what happens, including full error messages if any Kent ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
[Tutor] Having an Issue
I dunno how this works but hopefully someone can help me I am trying to build a program in Python but for someone i can not get what i am trying to build WORK by email you guys is there a way i can get some help some pointer on the program i am trying to solve Thanks ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] help
A hollow voice says PLUGH. Be sure your lantern is lit! -- Bob Gailer Chapel Hill NC 919-636-4239 ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] help
Sanhita Mallick wrote: help YOU ARE STANDING AT THE END OF A ROAD BEFORE A SMALL BRICK BUILDING . AROUND YOU IS A FOREST. A SMALL STREAM FLOWS OUT OF THE BUILDING AND DOWN A GULLY. Emile ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
[Tutor] help
help
--- On Sat, 3/14/09, tutor-requ...@python.org wrote:
> From: tutor-requ...@python.org
> Subject: Tutor Digest, Vol 61, Issue 50
> To: tutor@python.org
> Date: Saturday, March 14, 2009, 5:18 AM
> Send Tutor mailing list submissions to
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>
> Today's Topics:
>
>1. update list of dictionaries based on key (ski)
>2. Re: update list of dictionaries based on key (greg
> whittier)
>3. Re: update list of dictionaries based on key (ski)
>4. best gui for the job? (W W)
>5. Re: best gui for the job? (Lie Ryan)
>
>
> --
>
> Message: 1
> Date: Fri, 13 Mar 2009 16:09:58 +0100
> From: ski
> Subject: [Tutor] update list of dictionaries based on key
> To: python tutor
> Message-ID: <49ba7746.6090...@khine.net>
> Content-Type: text/plain; charset=ISO-8859-1; format=flowed
>
> Hello,
> Here is what I have so far:
>
> >>> mylist = [{'index': 0,
> 'title': 'Association of British Travel
> Agents', 'selected': False, 'edit_row':
> '?edit_affiliation=0',
> 'affiliation': 'ABTA',
> 'affiliation_no': u'G3903'},
> {'index': 1,
> 'title': 'Appointed Agents of IATA',
> 'selected': False, 'edit_row':
> '?edit_affiliation=1', 'affiliation':
> 'IATA', 'affiliation_no':
> u'none'}, {'index': 0, 'title':
> 'Association of Airline Cons.',
> 'selected': False, 'edit_row':
> '?edit_affiliation=0', 'affiliation':
> 'AAC', 'affiliation_no': u'sss'},
> {'index': 1, 'title': 'Association of
> British Travel Agents', 'selected': False,
> 'edit_row':
> '?edit_affiliation=1', 'affiliation':
> 'ABTA', 'affiliation_no': u'zser'}]
>
> >>> key = 'affiliation_no'
>
> >>> my_dup_keys = []
> >>> merged_list = []
>
> >>> mykeys = [item['affiliation'] for
> item in mylist]
>
> >>> for x in mykeys:
> if mykeys.count(x) >= 2:
> my_dup_keys.append(x)
>
> >>> for item in mylist:
> if item['affiliation'] in set(my_dup_keys):
> merged_list.append(item)
>
>
> >>> values = [d[key] for d in merged_list if
> d.has_key(key)]
> >>> for dict in merged_list:
> dict[key] = values
> mylist.append(dict)
>
> >>> print mylist
> [{'index': 0, 'title': 'Association of
> British Travel Agents',
> 'selected': False, 'edit_row':
> '?edit_affiliation=0', 'affiliation':
> 'ABTA', 'affiliation_no':
> [u'G3903', u'zser']}, {'index': 1,
> 'title':
> 'Appointed Agents of IATA', 'selected':
> False, 'edit_row':
> '?edit_affiliation=1', 'affiliation':
> 'IATA', 'affiliation_no':
> u'none'}, {'index': 0, 'title':
> 'Association of Airline Cons.',
> 'selected': False, 'edit_row':
> '?edit_affiliation=0', 'affiliation':
> 'AAC', 'affiliation_no': u'sss'},
> {'index': 1, 'title': 'Association of
> British Travel Agents', 'selected': False,
> 'edit_row':
> '?edit_affiliation=1', 'affiliation':
> 'ABTA', 'affiliation_no':
> [u'G3903', u'zser']}, {'index': 0,
> 'title': 'Association of British
> Travel Agents', 'selected': False,
> 'edit_row': '?edit_affiliation=0',
> 'affiliation': 'ABTA',
> 'affiliation_no': [u'G3903',
> u'zser']}, {'index':
> 1, 'title': 'Association of British Travel
> Agents', 'selected': False,
> 'edit_row': '?edit_affiliation=1',
> 'affiliation': 'ABTA',
> 'affiliation_no': [u'G3903',
> u'zser']}]
>
>
> This sort of works but I want to return a list that updates
> 'mylist' not
> append to it, so I will get:
>
> [{'index': 0, 'title': 'Association of
> British Travel Agents',
> 'selected': False, 'edit_row':
> '?edit_affiliation=0', 'affiliation':
> 'ABTA', 'affiliation_no':
> [u'G3903', u'zser']}, {'index': 1,
> 'title':
> 'Appointed Agents of IATA', 'selected':
> False, 'edit_row':
> '?edit_affiliation=1', 'affiliation':
> 'IATA', 'affiliation_no':
> u'none'}, {'index': 0, 'title':
> 'Association of Airline Cons.',
> 'selected': False, 'edit_row':
> '?edit_affiliation=0', 'affiliation':
> 'AAC', 'affiliation_no': u'sss'}]
>
>
> Thanks
>
> Norman
>
>
>
> --
>
> Message: 2
> Date: Fri, 13 Mar 2009 11:43:19 -0400
> From: greg whittier
> Subject: Re: [Tutor] update list of dictionaries based on
> key
> To: python tutor
> Message-ID:
>
> Content-Type: text/plain; charset=ISO-8859-1
>
> On Fri, Mar 13, 2009 at 11:09 AM, ski
> wrote:
> > Hello,
> > Here is what I have so far:
> >
> mylist = [{'index': 0,
> 'title': 'Association of British Travel
> Agents',
> 'selected': False,
> 'edit_row': '?edit_affiliation=0',
> 'affiliation': 'ABTA',
> 'affiliation_no':
> u'G3903'}, {'i
Re: [Tutor] best gui for the job?
On Fri, Mar 13, 2009 at 1:18 PM, Lie Ryan wrote: > W W wrote: > > What do you mean "good enough resolution"? I suppose I really meant quality - the shapes I drew with PIL were severely aliased, but maybe I didn't do it right. -Wayne -- To be considered stupid and to be told so is more painful than being called gluttonous, mendacious, violent, lascivious, lazy, cowardly: every weakness, every vice, has found its defenders, its rhetoric, its ennoblement and exaltation, but stupidity hasn’t. - Primo Levi ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] best gui for the job?
W W wrote: Hi, What is the best gui to implement a simple paint-esque program in? I already built a really simple one in Tkinter - but Tkinter lacks a save functionality. I considered using the PIL to draw in the background, but it didn't seem to have a good enough resolution. I thought about pyGTK because I have some familiarity with that, but I can't find any examples of saving a drawingarea. What do you mean "good enough resolution"? ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
[Tutor] best gui for the job?
Hi, What is the best gui to implement a simple paint-esque program in? I already built a really simple one in Tkinter - but Tkinter lacks a save functionality. I considered using the PIL to draw in the background, but it didn't seem to have a good enough resolution. I thought about pyGTK because I have some familiarity with that, but I can't find any examples of saving a drawingarea. Also, to clarify what I mean by "best" - I want it to be fairly simple to implement (my non-saving sketch in a single color/size is about 100 lines), yet extensible - I'd like the ability to further enhance my program down the road. Changing the opacity, and the possibility to work with layers is a plus. If anyone has tips or knows of any tutorials (I haven't really been able to find anything suitable), please let me know. Thanks for any suggestions, Wayne -- To be considered stupid and to be told so is more painful than being called gluttonous, mendacious, violent, lascivious, lazy, cowardly: every weakness, every vice, has found its defenders, its rhetoric, its ennoblement and exaltation, but stupidity hasn’t. - Primo Levi ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] update list of dictionaries based on key
greg whittier wrote:
On Fri, Mar 13, 2009 at 11:09 AM, ski wrote:
Hello,
Here is what I have so far:
mylist = [{'index': 0, 'title': 'Association of British Travel Agents',
'selected': False, 'edit_row': '?edit_affiliation=0', 'affiliation': 'ABTA',
'affiliation_no': u'G3903'}, {'index': 1, 'title': 'Appointed Agents of
IATA', 'selected': False, 'edit_row': '?edit_affiliation=1', 'affiliation':
'IATA', 'affiliation_no': u'none'}, {'index': 0, 'title': 'Association of
Airline Cons.', 'selected': False, 'edit_row': '?edit_affiliation=0',
'affiliation': 'AAC', 'affiliation_no': u'sss'}, {'index': 1, 'title':
'Association of British Travel Agents', 'selected': False, 'edit_row':
'?edit_affiliation=1', 'affiliation': 'ABTA', 'affiliation_no': u'zser'}]
key = 'affiliation_no'
my_dup_keys = []
merged_list = []
mykeys = [item['affiliation'] for item in mylist]
for x in mykeys:
if mykeys.count(x) >= 2:
my_dup_keys.append(x)
for item in mylist:
if item['affiliation'] in set(my_dup_keys):
merged_list.append(item)
values = [d[key] for d in merged_list if d.has_key(key)]
for dict in merged_list:
dict[key] = values
mylist.append(dict)
print mylist
[{'index': 0, 'title': 'Association of British Travel Agents', 'selected':
False, 'edit_row': '?edit_affiliation=0', 'affiliation': 'ABTA',
'affiliation_no': [u'G3903', u'zser']}, {'index': 1, 'title': 'Appointed
Agents of IATA', 'selected': False, 'edit_row': '?edit_affiliation=1',
'affiliation': 'IATA', 'affiliation_no': u'none'}, {'index': 0, 'title':
'Association of Airline Cons.', 'selected': False, 'edit_row':
'?edit_affiliation=0', 'affiliation': 'AAC', 'affiliation_no': u'sss'},
{'index': 1, 'title': 'Association of British Travel Agents', 'selected':
False, 'edit_row': '?edit_affiliation=1', 'affiliation': 'ABTA',
'affiliation_no': [u'G3903', u'zser']}, {'index': 0, 'title': 'Association
of British Travel Agents', 'selected': False, 'edit_row':
'?edit_affiliation=0', 'affiliation': 'ABTA', 'affiliation_no': [u'G3903',
u'zser']}, {'index': 1, 'title': 'Association of British Travel Agents',
'selected': False, 'edit_row': '?edit_affiliation=1', 'affiliation': 'ABTA',
'affiliation_no': [u'G3903', u'zser']}]
This sort of works but I want to return a list that updates 'mylist' not
append to it, so I will get:
[{'index': 0, 'title': 'Association of British Travel Agents', 'selected':
False, 'edit_row': '?edit_affiliation=0', 'affiliation': 'ABTA',
'affiliation_no': [u'G3903', u'zser']}, {'index': 1, 'title': 'Appointed
Agents of IATA', 'selected': False, 'edit_row': '?edit_affiliation=1',
'affiliation': 'IATA', 'affiliation_no': u'none'}, {'index': 0, 'title':
'Association of Airline Cons.', 'selected': False, 'edit_row':
'?edit_affiliation=0', 'affiliation': 'AAC', 'affiliation_no': u'sss'}]
It's a little hard to figure what you're getting at. This looks like
a table represented by a list of dictionaries that you'd like to group
by "affiliation."
i have objects in my database, called addresses, each address has a
metadata called affiliation.
also each address is a member of a company.
in my company class, i wanted to get all the addresses affiliations and
only list the unique values.
affiliation_nos = {}
for row in mylist:
affiliation_nos.set_default(row['affiliation'],[]).append(row['affliation_no'])
will give you a list of affiliation_no's for each affiliation and if
you want a list of dicts, you could do
mynewlist = [dict(affiliation=affiliation, affiliation_nos =
affiliation_nos[affiliation]) for affiliation in
affiliation_nos.keys()]
I don't know what to do about all the other fields though. In your
example input list you have two dictionaries with affiliation =
'ABTA'. In your output you kept the one with index=0 and threw away
index=1. (same for 'edit_row') How do you determine which to keep?
I want to keep it based on the 'affiliation' key.
In essence, from my original 'mylist' I want to keep all the list items
as they are, but just update the list items that have more than one
'affiliation' by updating only the 'affiliation_no' to contain both entries.
Perhaps there is a simpler way to do this ;)
I will change my code so that mylist does not contain the 'index' and
'edit_row' keys. Perhaps then it will be easier to update the dictionary?
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Re: [Tutor] update list of dictionaries based on key
On Fri, Mar 13, 2009 at 11:09 AM, ski wrote:
> Hello,
> Here is what I have so far:
>
mylist = [{'index': 0, 'title': 'Association of British Travel Agents',
'selected': False, 'edit_row': '?edit_affiliation=0', 'affiliation':
'ABTA',
'affiliation_no': u'G3903'}, {'index': 1, 'title': 'Appointed Agents of
IATA', 'selected': False, 'edit_row': '?edit_affiliation=1', 'affiliation':
'IATA', 'affiliation_no': u'none'}, {'index': 0, 'title': 'Association of
Airline Cons.', 'selected': False, 'edit_row': '?edit_affiliation=0',
'affiliation': 'AAC', 'affiliation_no': u'sss'}, {'index': 1, 'title':
'Association of British Travel Agents', 'selected': False, 'edit_row':
'?edit_affiliation=1', 'affiliation': 'ABTA', 'affiliation_no': u'zser'}]
>
key = 'affiliation_no'
>
my_dup_keys = []
merged_list = []
>
mykeys = [item['affiliation'] for item in mylist]
>
for x in mykeys:
> if mykeys.count(x) >= 2:
> my_dup_keys.append(x)
>
for item in mylist:
> if item['affiliation'] in set(my_dup_keys):
> merged_list.append(item)
>
>
values = [d[key] for d in merged_list if d.has_key(key)]
for dict in merged_list:
> dict[key] = values
> mylist.append(dict)
>
print mylist
> [{'index': 0, 'title': 'Association of British Travel Agents', 'selected':
> False, 'edit_row': '?edit_affiliation=0', 'affiliation': 'ABTA',
> 'affiliation_no': [u'G3903', u'zser']}, {'index': 1, 'title': 'Appointed
> Agents of IATA', 'selected': False, 'edit_row': '?edit_affiliation=1',
> 'affiliation': 'IATA', 'affiliation_no': u'none'}, {'index': 0, 'title':
> 'Association of Airline Cons.', 'selected': False, 'edit_row':
> '?edit_affiliation=0', 'affiliation': 'AAC', 'affiliation_no': u'sss'},
> {'index': 1, 'title': 'Association of British Travel Agents', 'selected':
> False, 'edit_row': '?edit_affiliation=1', 'affiliation': 'ABTA',
> 'affiliation_no': [u'G3903', u'zser']}, {'index': 0, 'title': 'Association
> of British Travel Agents', 'selected': False, 'edit_row':
> '?edit_affiliation=0', 'affiliation': 'ABTA', 'affiliation_no': [u'G3903',
> u'zser']}, {'index': 1, 'title': 'Association of British Travel Agents',
> 'selected': False, 'edit_row': '?edit_affiliation=1', 'affiliation': 'ABTA',
> 'affiliation_no': [u'G3903', u'zser']}]
>
>
> This sort of works but I want to return a list that updates 'mylist' not
> append to it, so I will get:
>
> [{'index': 0, 'title': 'Association of British Travel Agents', 'selected':
> False, 'edit_row': '?edit_affiliation=0', 'affiliation': 'ABTA',
> 'affiliation_no': [u'G3903', u'zser']}, {'index': 1, 'title': 'Appointed
> Agents of IATA', 'selected': False, 'edit_row': '?edit_affiliation=1',
> 'affiliation': 'IATA', 'affiliation_no': u'none'}, {'index': 0, 'title':
> 'Association of Airline Cons.', 'selected': False, 'edit_row':
> '?edit_affiliation=0', 'affiliation': 'AAC', 'affiliation_no': u'sss'}]
>
It's a little hard to figure what you're getting at. This looks like
a table represented by a list of dictionaries that you'd like to group
by "affiliation."
affiliation_nos = {}
for row in mylist:
affiliation_nos.set_default(row['affiliation'],[]).append(row['affliation_no'])
will give you a list of affiliation_no's for each affiliation and if
you want a list of dicts, you could do
mynewlist = [dict(affiliation=affiliation, affiliation_nos =
affiliation_nos[affiliation]) for affiliation in
affiliation_nos.keys()]
I don't know what to do about all the other fields though. In your
example input list you have two dictionaries with affiliation =
'ABTA'. In your output you kept the one with index=0 and threw away
index=1. (same for 'edit_row') How do you determine which to keep?
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[Tutor] update list of dictionaries based on key
Hello,
Here is what I have so far:
>>> mylist = [{'index': 0, 'title': 'Association of British Travel
Agents', 'selected': False, 'edit_row': '?edit_affiliation=0',
'affiliation': 'ABTA', 'affiliation_no': u'G3903'}, {'index': 1,
'title': 'Appointed Agents of IATA', 'selected': False, 'edit_row':
'?edit_affiliation=1', 'affiliation': 'IATA', 'affiliation_no':
u'none'}, {'index': 0, 'title': 'Association of Airline Cons.',
'selected': False, 'edit_row': '?edit_affiliation=0', 'affiliation':
'AAC', 'affiliation_no': u'sss'}, {'index': 1, 'title': 'Association of
British Travel Agents', 'selected': False, 'edit_row':
'?edit_affiliation=1', 'affiliation': 'ABTA', 'affiliation_no': u'zser'}]
>>> key = 'affiliation_no'
>>> my_dup_keys = []
>>> merged_list = []
>>> mykeys = [item['affiliation'] for item in mylist]
>>> for x in mykeys:
if mykeys.count(x) >= 2:
my_dup_keys.append(x)
>>> for item in mylist:
if item['affiliation'] in set(my_dup_keys):
merged_list.append(item)
>>> values = [d[key] for d in merged_list if d.has_key(key)]
>>> for dict in merged_list:
dict[key] = values
mylist.append(dict)
>>> print mylist
[{'index': 0, 'title': 'Association of British Travel Agents',
'selected': False, 'edit_row': '?edit_affiliation=0', 'affiliation':
'ABTA', 'affiliation_no': [u'G3903', u'zser']}, {'index': 1, 'title':
'Appointed Agents of IATA', 'selected': False, 'edit_row':
'?edit_affiliation=1', 'affiliation': 'IATA', 'affiliation_no':
u'none'}, {'index': 0, 'title': 'Association of Airline Cons.',
'selected': False, 'edit_row': '?edit_affiliation=0', 'affiliation':
'AAC', 'affiliation_no': u'sss'}, {'index': 1, 'title': 'Association of
British Travel Agents', 'selected': False, 'edit_row':
'?edit_affiliation=1', 'affiliation': 'ABTA', 'affiliation_no':
[u'G3903', u'zser']}, {'index': 0, 'title': 'Association of British
Travel Agents', 'selected': False, 'edit_row': '?edit_affiliation=0',
'affiliation': 'ABTA', 'affiliation_no': [u'G3903', u'zser']}, {'index':
1, 'title': 'Association of British Travel Agents', 'selected': False,
'edit_row': '?edit_affiliation=1', 'affiliation': 'ABTA',
'affiliation_no': [u'G3903', u'zser']}]
This sort of works but I want to return a list that updates 'mylist' not
append to it, so I will get:
[{'index': 0, 'title': 'Association of British Travel Agents',
'selected': False, 'edit_row': '?edit_affiliation=0', 'affiliation':
'ABTA', 'affiliation_no': [u'G3903', u'zser']}, {'index': 1, 'title':
'Appointed Agents of IATA', 'selected': False, 'edit_row':
'?edit_affiliation=1', 'affiliation': 'IATA', 'affiliation_no':
u'none'}, {'index': 0, 'title': 'Association of Airline Cons.',
'selected': False, 'edit_row': '?edit_affiliation=0', 'affiliation':
'AAC', 'affiliation_no': u'sss'}]
Thanks
Norman
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