Re: [Tutor] Help with OCR
Sriram Jaju ramjaju.m...@gmail.com wrote I'm new to python. I'm doing a project on OCR (Optical Character Recognition), I've heard a lot about Python so i want to know whether i can use python for OCR. That depends a lot on the environment. What OS will you be using? What are you doing exactly? Are you actually reading the characters optically or are you taking a feed from an OCR device? Are you processing a scanned image? If yes what are the tool require for that?. It depends on the above indformation. My another doubt is that, can i use python for programming microcontrollers Not normally, but if you can find a program that can program the microcontroller you might be able to drive it from Python. Or if the micro has an interface that can be driven from, for example, a serial port you may be able to do something. We can't give specific answers without a lot more specific information. -- Alan Gauld Author of the Learn to Program web site http://www.alan-g.me.uk/ ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Help with OCR
Shashwat Anand anand.shash...@gmail.com wrote My another doubt is that, can i use python for programming microcontrollers You bet. Really? How would he go about that? I've not seen (or even heard of) Python used in that role before. Alan G ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Help with OCR
I'm using windows7. I'm doing a robotic project in which a robot has to take instruction from images which are taken by camera. image consists of characters like 'START', 'STOP' etc. On Mon, Feb 7, 2011 at 2:25 PM, Alan Gauld alan.ga...@btinternet.comwrote: Sriram Jaju ramjaju.m...@gmail.com wrote I'm new to python. I'm doing a project on OCR (Optical Character Recognition), I've heard a lot about Python so i want to know whether i can use python for OCR. That depends a lot on the environment. What OS will you be using? What are you doing exactly? Are you actually reading the characters optically or are you taking a feed from an OCR device? Are you processing a scanned image? If yes what are the tool require for that?. It depends on the above indformation. My another doubt is that, can i use python for programming microcontrollers Not normally, but if you can find a program that can program the microcontroller you might be able to drive it from Python. Or if the micro has an interface that can be driven from, for example, a serial port you may be able to do something. We can't give specific answers without a lot more specific information. -- Alan Gauld Author of the Learn to Program web site http://www.alan-g.me.uk/ ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor -- Xcited 2 be AliveSriram ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] function help
ok...here's the function I've written so far. def padWithGaps(seq): for letter in seq: letter=- line=len(seq) dashline=line*letter return dashline def replace(someString,position,letter): first=someString[0:position] second=letter third=someString[position+1:len(someString)] newString=first+second+third return newString ##findScore(MPFVS,MS-V-) would return a score of 2 def findScore(first,second): count=0 for position in range(0,len(first)): if first[position]==second[position]: count=count+1 position=position+1 return count #shorter is a 3 amino acid sequence ##longer is any length sequence greater than 3 ###i=first amino acid; j=second amino acid; k=third amino acid def findAlignment(shorter,longer): for i in range(0,len(longer)-2): for j in range(1,len(longer)-1): for k in range(2,len(longer)): dashline=padWithGaps(longer) nextLine=replace(dashline,i,shorter[0]) nextNext=replace(nextLine,j,shorter[1]) alignment=replace(nextNext,k,shorter[2]) score=findScore(longer,alignment) don't know what to do here print longer print alignment print Score = + str(score) I don't know what to do at the end of my loop but what I'm trying to do in pseudocode is: if that alignment has the best score seen so far save the score and the alignment print the best score and the best alignment ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] nested loops
Alan Gauld wrote:- Wayne Werner waynejwer...@gmail.com wrote found = False highscore = 0 alignment = somealignment for x in something and not found: for y in somethingelse and not found: for z in evenmoresomething: if x+y+z highscore: highscore = x+y+z alignment = newalignment found = True break HTH, That's going to exit first time through, isn't it? -- Michael This mail was sent via Mail-SeCure System. This footnote confirms that this email message has been scanned by PineApp Mail-SeCure for the presence of malicious code, vandals computer viruses. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] function help
I'm not sure of the answer to your question, because i'm not sure I understand it. Perhaps you could rephrase it? But, there is some other stuff I noticed though: def padWithGaps(seq): for letter in seq: letter=- line=len(seq) dashline=line*letter return dashline This function is fairly inefficient. Let's say you pass the function a sequence three items long something like a_list = ['a','b','c']. Your telling Python to create a dashed line three dashes long three separate times. So, you do it for the 'a' part of the sequence, the 'b' and the 'c'. You can condense this to something like: def padWithGaps(seq): lent = len(seq) return lent*'-' And you really don't need to have a separate function for that, as you can just do it on the fly Another thing, whenever your taking a slice of a list and the first argument is 0, you can just omit that. For example, from my list a_list example above a_list[0:2] is equivalent to a_list[:2] As for the rest of them, what you could do is pass each function data that you would expect to be passed under normal operation (assuming this is possible of course) and instead of using return use print instead and see if the results are what you expect. What I mean is, let's say I pass the results from the padWithGaps (the results of which I call dashline to be consistent) to the next function: def replace(someString,position,letter): first=someString[0:position] second=letter third=someString[position+1:len(someString)] newString=first+second+third return newString So, I can do something like z = replace(dashline,0,'a') and then print z. What the results should be is a--. def findScore(first,second): count=0 for position in range(0,len(first)): if first[position]==second[position]: count=count+1 position=position+1 return count With this function here, there is a few things you can do to optimize and clean up clutter as well. I only point this out because it pays huge dividends in the long run (or it has for me at least). The first thing though is that you don't need to have the line position=position+1. Python will go to the next item in the list position whether you tell it to or not. So below is the same thing but without the position +=1 line: def findScore(first,second): count=0 for position in range(0,len(first)): if first[position]==second[position]: count=count+1 return count The other thing I would suggest is to use enumerate. Enumerate is your friend. And the last thing I would suggest is whenever you want to do something like a = a+1, you can just do a +=1. def findScore2(first,second): count=0 for i, position in enumerate(first): if position==second[i]: count+=1 return count enumerate returns both the next item in the list and the position of that item in the list (in this case, I called that variable i). So you will find that if you run findScore2 you will have the same results as findScore. Or at least you should ;) On Mon, Feb 7, 2011 at 11:45 AM, Ashley F aflint...@yahoo.com wrote: ok...here's the function I've written so far. def padWithGaps(seq): for letter in seq: letter=- line=len(seq) dashline=line*letter return dashline def replace(someString,position,letter): first=someString[0:position] second=letter third=someString[position+1:len(someString)] newString=first+second+third return newString ##findScore(MPFVS,MS-V-) would return a score of 2 def findScore(first,second): count=0 for position in range(0,len(first)): if first[position]==second[position]: count=count+1 position=position+1 return count #shorter is a 3 amino acid sequence ##longer is any length sequence greater than 3 ###i=first amino acid; j=second amino acid; k=third amino acid def findAlignment(shorter,longer): for i in range(0,len(longer)-2): for j in range(1,len(longer)-1): for k in range(2,len(longer)): dashline=padWithGaps(longer) nextLine=replace(dashline,i,shorter[0]) nextNext=replace(nextLine,j,shorter[1]) alignment=replace(nextNext,k,shorter[2]) score=findScore(longer,alignment) don't know what to do here print longer print alignment print Score = + str(score) I don't know what to do at the end of my loop but what I'm trying to do in pseudocode is: if that alignment has the best score seen so far save the score and the alignment print the best score and the best alignment ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] JES Jython
Hi I have a problem in JES getting a solution to a function. Is there a way you guys can help? ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] JES Jython
On 2/7/2011 2:45 PM, Eun Koo wrote: Hi I have a problem in JES getting a solution to a function. Is there a way you guys can help? Maybe. You might say more about the problem. What is JES and how does it relate to Python? -- Bob Gailer 919-636-4239 Chapel Hill NC ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] JES Jython
Eun Koo, 07.02.2011 20:45: Hi I have a problem in JES getting a solution to a function. Is there a way you guys can help? If you can provide enough information for us to understand what your problem is, we may be able to help you. It's a matter of politeness to help us help you. The more work we have to put into figuring out what you want (or even what your words are supposed to mean), the less likely it is that someone will do that and help you out. Stefan ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] nested loops
Alan Gauld wrote: Wayne Werner waynejwer...@gmail.com wrote You probably want to add a sentinel to break out of the outer loops too: I don't think you want to break out of *any* of the loops. Otherwise you will skip testing combinations. In your example, the first time you set highscore and alignment, you break out of all three loops and only test the first triple x,y,z. found = False highscore = 0 alignment = somealignment for x in something and not found: for y in somethingelse and not found: for z in evenmoresomething: if x+y+z highscore: highscore = x+y+z alignment = newalignment found = True break That's the equivalent of a return in the innermost loop. If you're looking for the *first* matching highscore, that's fine, but not if you want the biggest. -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] JES Jython
Eun Koo wrote: Hi I have a problem in JES getting a solution to a function. Is there a way you guys can help? Probably not. This is a mailing list about learning the language Python, not specific to JES (whatever that is!) under Jython. If JES has a support forum dedicated to it, you should try there. Otherwise, try a Jython mailing list. You might try the main Python mailing list, python-l...@python.org, also available on Usenet as comp.lang.python. -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] function help
Ashley F wrote: ok...here's the function I've written so far. def padWithGaps(seq): for letter in seq: letter=- line=len(seq) dashline=line*letter return dashline I don't think that's a useful function. It seems to do a HUGE amount of work that just keeps getting thrown away. Let's say seq = GACT, this function will do the following: letter = G letter = - line = 4 # len of seq dashline = letter = A letter = - line = 4 dashline = letter = C letter = - line = 4 dashline = letter = T letter = - line = 4 dashline = It does everything four times. Now imagine that seq is a million characters long instead of four! This will do the job *much* faster: def padWithGaps(seq): return - * len(seq) *Much* faster, much easier to read. [...] I don't know what to do at the end of my loop but what I'm trying to do in pseudocode is: if that alignment has the best score seen so far save the score and the alignment print the best score and the best alignment You need to store the current best score and the current best alignment. Then each time around the innermost loop, you need to calculate the score and alignment (as you already do), and compare them to the best seen so far. If they are worse or equal, you don't need to do anything, just go on to the next loop as normal. But if they are better, then you need to update the best score and alignment, and print them. if score best_score: best_score = score best_alignment = alignment print 'best seen so far is', score, alignment Does that help? Try writing the code, and if you still can't get it working, ask again. -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] nested loops
Steven D'Aprano st...@pearwood.info wrote I don't think you want to break out of *any* of the loops. Otherwise you will skip testing combinations. In that case I misread the OP. I thought he specifically wanted to avoid testing all the options and exit when he reached his target. In your example, the first time you set highscore and alignment, you break out of all three loops Yep, thats what I thought was being asked for. It seems I mistook the intent. reading too quickly I suspect. Alan G ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Converting From Unicode to ASCII!!
On Mon, Feb 7, 2011 at 10:15 PM, Nevins Duret dur...@bellsouth.net wrote: Hello all, Don’t know if I’ll be bashed on this forum for doing this, but I will assure you I have the best intentions and simply want to apply a real world problem and how to go about solving it using python3.1. Here is my predicament. A good friend of mine locked herself out of her computer and forgot her password. I pretty much scoured the internet as a resource only to hit a brick wall. I tried using ophcrack version 2.3.1 in order to obtain the password and felt completely at home being that it was Linux, but then towards the end it failed and the output of this file which seems to contain the Users and passwords The linux forums might be better. Or you could use: http://www.google.com/search?client=ubuntuchannel=fsq=linux+lost+password+brute+forceie=utf-8oe=utf-8 but in Unicode format: Administrator:500::31d6cfe0d16ae931b73c59d7e0c089c 0::: Guest:501::31d6cfe0d16ae931b73c59d7e0c089c0::: SUPPORT_388945a0:1002::881037e0b6909b04b6900f7c806 dca6e::: HelpAssistant:1004:b209ce7e3ff7aea1131906e9f5df481 9:d83f663c50bcd5815ccb94f9e38a9a4b::: Beverly:1005:6395b1acd69aaad3b435b51404ee:992a c78ffb08204c592c6e47b916f85d::: And it didn’t complete as a result of this error message: Tables found: /mnt/hdc/tables/xp_free_small Found one partition that contains hashes: /mnt/hda1/WINDOWS/system32/config Starting Ophcrack QIconvCodec::convertFromUnicode: using ASCII for conversion, iconv_open failed QIconvCodec::convertToUnicode: using ASCII for conversion, iconv_open failed /home/tux/launch.sh: line 100: 1044 Killed ABLES_INLINE -w $FOUND/ -n $numcpu -o /tmp/ophcrack.txt $opts Press a key to exit:: Now , I remember reading somewhere that Python is very good for converting Unicode data into ASCII and admittedly know nothing about this: Is there a work around in Python where I can simply import the file like and convert it to readable string using A for loop. Any help on this would be greatly appreciated. So far, I’m reading up on this topic at this url: http://docs.python.org/howto/unicode.html Best Regards, Nevins Duret ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor -- The lawyer in me says argue...even if you're wrong. The scientist in me... says shut up, listen, and then argue. But the lawyer won on appeal, so now I have to argue due to a court order. Furthermore, if you could be a scientific celebrity, would you want einstein sitting around with you on saturday morning, while you're sitting in your undies, watching Underdog?...Or better yet, would Einstein want you to violate his Underdog time? Can you imagine Einstein sitting around in his underware? Thinking about the relativity between his pubic nardsac, and his Fruit of the Looms, while knocking a few Dorito's crumbs off his inner brilliant white thighs, and hailing E = mc**2, and licking the orangy, delicious, Doritoey crust that layered his genetically rippled fingertips? But then again, J. Edgar Hoover would want his pantyhose intertwined within the equation. However, I digress, momentarily. But Einstein gave freely, for humanity, not for gain, other than personal freedom. An equation that benefited all, and yet gain is a personal product. Also, if you can answer it, is gravity anymore than interplanetary static cling? ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Converting From Unicode to ASCII!!
And I forgot, that you don't have to install another version, but just boot from the live disk, and mount the partition. But from looking, you should be able to recover with linux utilities. Look here: http://aplawrence.com/Linux/lostlinuxpassword.htmlhttp://aplawrence.com/Linux/lostlinuxpassword.html ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
