Re: [Tutor] Creating an Invalid Message for user
Hello Saba, and welcome,
Saba, unfortunately your email is almost unreadable to me. To me, your
code looks like this:
On Fri, Apr 18, 2014 at 10:19:52PM +0100, Saba Usmani wrote:
> print "Welcome to the binary and decimal converter"loop = Truewhile
> loop: bord = raw_input("Enter b for binary or d decimal or exit to
> exit") if bord == "b": d = 0 b = 0 factor = 1; b = raw_input ("Enter
> Binary Number:") b=b.lstrip("0") b = int(b) while(b > 0): if((int(b) %
> 10) == 1): d += factor b /= 10 factor = factor * 2 print "The Decimal
> Number is: ", d elif bord == "d": x=0 n=int(input('Enter Decimal
> Number: ')) x=n k=[] # array while (n>0): a=int(float(n%2))
> k.append(a) n=(n-a)/2 k.append(0) string="" for j in k[::-1]:
> string=string+str(j) print('The binary Number for %d is %s'%(x,
> string)) elif bord == "exit" : print "Goodbye" loop = False
A complete mess! Unfortunately, I have neither the time nor the
inclination to spend a lot of effort trying to unmangle the code to see
what you intended it to be.
As a programmer, you will often be dealing with text formats, and with
text it is very important that your email program (Outlook, it seems)
doesn't mess up the layout. Especially with Python. Unfortunately,
if your email program is configured to send so-called "Rich Text"
(actually HTML, exactly the same format that web pages use) a
side-effect is that it may mess up the layout as above.
I recommend that, when posting to technical forums like this tutor
mailing list, you turn off "Rich Text" posting so we can see the code
the way it is meant to be seen. If you help us to see your code the way
it should be seen, we can help you with your code.
Regards,
--
Steven
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Re: [Tutor] Creating an Invalid Message for user
On 18/04/14 22:19, Saba Usmani wrote:
I am meant to design code for a program that converts from binary number
to decimal and vice versa.
First, you know that python includes functions for doing that already
right? So you are just doing this as a learning exercise?
while loop:
bord = raw_input("Enter b for binary or d decimal or exit to exit")
if bord == "b":
d = 0
b = 0
factor = 1;
b = raw_input ("Enter Binary Number:")
b=b.lstrip("0")
Before converting to an int check each character is in the numeric range
you need. For binary thats like
for ch in inputstring:
if ch not in "01":
# process invalid input
For decimal its
for ch in inputstring:
if ch not in "0123456789":
# process bad input.
You could put that in a function and pass in the
numbers as a parameter...
If you accept floats as input then it gets a whole
lot more complicated. but you are converting to int
so I assume its ints you expect.
HTH
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.flickr.com/photos/alangauldphotos
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[Tutor] Creating an Invalid Message for user
Hi,
I am meant to design code for a program that converts from binary number to
decimal and vice versa.
This is what i have so far:
print "Welcome to the binary and decimal converter"loop = Truewhile loop:
bord = raw_input("Enter b for binary or d decimal or exit to exit")if bord
== "b":d = 0b = 0factor = 1;b = raw_input
("Enter Binary Number:")b=b.lstrip("0")b = int(b)
while(b > 0):if((int(b) % 10) == 1):d += factor
b /= 10factor = factor * 2print "The Decimal Number
is: ", d elif bord == "d":x=0n=int(input('Enter
Decimal Number: '))x=nk=[] # arraywhile (n>0):
a=int(float(n%2))k.append(a)n=(n-a)/2
k.append(0)string=""for j in k[::-1]:
string=string+str(j)print('The binary Number for %d is %s'%(x, string))
elif bord == "exit" :print "Goodbye"loop = False
- This code does not recognize invalid inputs e.g in the binary to decimal
conversion, so if I enter e.g 10021, not a binary number, it will not inform
me,the user, that the input is invalid. The same problem occurs with the
decimal to binary conversion - if i enter e.g 123&&gf I am not told to try
again with a valid input - how do I implement this in the code above
ThanksSaba___
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