[Tutor] XML parsing when elements contain foreign characters
Howdy all,
Have you hear the news? Happy New Year!
Hope someone can help. I know this is a tutor list so please feel free to
send me somewhere else.
I'm trying to parse some XML and I'm struggling to reference elements that
contain foreign characters.
Code so far:
# -*- coding: utf-8 -*-
from xml.dom import minidom
xmldoc = minidom.parse('Export.xml')
products = xmldoc.getElementsByTagName('product')
print '%s Products' % len(products)
row_cnt = 0
titles = {}
stocklevel = {}
for product in products:
row_cnt+=1
title=product.getElementsByTagName('Titel')[0].firstChild.nodeValue
stock=product.getElementsByTagName('AntalPåLager')[0].firstChild.nodeValue
if title not in titles:
titles[title]=1
else:
titles[title]+=1
if stock not in stocklevel:
stocklevel[stock]=1
else:
stocklevel[stock]+=1
Traceback (most recent call last):
File C:\Python27\Testing Zizzi.py, line 16, in module
stock=product.getElementsByTagName('AntalPÃ¥Lager')[0].firstChild.nodeValue
IndexError: list index out of range
I've tried to encode the string before giving it to getElementsByTagName
but no joy.
Any ideas?
Many thanks!
Cheers,
Garry
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[Tutor] Question regarding xml.dom.minidom: How do you send an unsignedByte in an wsdl request
Howdy all, Hope this message finds everyone well - roll on the weekend! I'm trying some calls to an wsdl API I've subscribed to. But I'm struggling to know what they want when sending an unsignedByte in a request. I'm using xml.dom.minidom so to start with I have: from xml.dom.minidom import Document, parseString import httplib, urlparse And later on I create a doc with: doc=Document() And I have a using a little helper to add a text element: def add_text_element(doc, parent, name, value): element=doc.createElement(name) element.appendChild(doc.createTextNode(str(value))) parent.appendChild(element) Should I have a separate class for an unsignedByte? i.e. def add_byte_element What should it look like? This is what their API helpdesk have said: In this instance, the PriceFormat is defined as an unsignedByte. *xs:complexType name=GetOddsLadderRequest* *xs:attribute name=PriceFormat type=xs:unsignedByte / * */xs:complexType* Many thanks! Cheers, Garry ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] Dictionary Question
Howdy all, Hope this message finds everyone well. I have dictionary of keys and a string of values. i.e. 8 Fixtures: Swin1828 1844 1901 1916 1932 1948 2004 2019 2036 2052 2107 2122 HGrn1148 1204 1218 1232 1247 1304 1319 1333 1351 Newc1142 1157 1212 1227 1242 1258 1312 1327 1344 1403 Yarm1833 1849 1906 1922 1937 1953 2009 2024 2041 2057 2112 BVue1418 1437 1457 1517 1538 1558 1618 1637 1657 1717 1733 1747 1804 181 Hove1408 1427 1447 1507 1528 1548 1608 1627 1647 1707 1722 1738 1756 181 Romfd 1930 1946 2003 2019 2035 2053 2109 2125 2141 2157 2213 2230 Sund1839 1856 1911 1927 1943 1958 2014 2031 2047 2102 2117 I print that with the following: f = open(SummaryFile, 'a') header = %d Fixtures, %d Races:\n % len(FixtureDict.keys()) print header f.write(header) f.write(\n) for fixture, racetimes in FixtureDict.iteritems(): line = %s\t%s % (fixture, .join(racetimes)) print line f.write(line + \n) f.write(\n) f.close() What I'd like to is add the number of values to the Header line. So how would I get i.e. 8 Fixtures, 93 Races I tried header = %d Fixtures, %d Races:\n % (len(FixtureDict.keys()), len(FixtureDict.values())) But I get print header 8 Fixture, 8 Races Any ideas? Cheers, Garry ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Dictionary Question
On Wed, 22 Dec 2010 23:31:39 +1100, Steven D'Aprano wrote: In this case, you need to sum the number of races for all the fixtures: num_races = sum(len(racetimes) for racetimes in FixtureDict.values()) Many thanks Steven for your explanation and final golden nugget of code. On Wed, 22 Dec 2010 10:11:25 -0500, bob gailer wrote: Also note: len(dict.keys()) == len(dict.values()) == len(dict) Yup, thanks Bob. Cheers, G. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Help with a Dictionary
Many thanks to Alan Gauld, Gerard Flanagan, Lie Ryan and spir for your replies. All systems are go! Cheers, Garry ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] Help with a Dictionary
Howdy all, I hope this message finds you all well. I have a list that I output in the following order: 2010-01-07 1103 Sund A7 450m 2010-01-07 Sheff A7 500m 2010-01-07 1119 Sund A6 450m 2010-01-07 1128 Sheff A6 500m 2010-01-07 1134 Sund A5 450m 2010-01-07 1142 Sheff A7 500m 2010-01-07 1148 Sund A5 450m 2010-01-07 1157 Sheff A6 500m 2010-01-07 1204 Sund A4 450m 2010-01-07 1212 Sheff A5 500m 2010-01-07 1218 Sund A4 450m 2010-01-07 1227 Sheff A3 500m 2010-01-07 1232 Sund A4 450m 2010-01-07 1242 Sheff A4 500m 2010-01-07 1247 Sund A4 450m 2010-01-07 1258 Sheff A3 500m 2010-01-07 1304 Sund A3 450m 2010-01-07 1312 Sheff A4 500m 2010-01-07 1319 Sund HC 640m 2010-01-07 1327 Sheff A5 500m 2010-01-07 1333 Sund A3 450m 2010-01-07 1344 Sheff A3 500m 2010-01-07 1351 Sund A2 450m 2010-01-07 1403 Sheff A2 500m 2010-01-07 1408 Romfd A7 400m 2010-01-07 1418 Crayfd S8 540m 2010-01-07 1427 Romfd A6 400m 2010-01-07 1437 Crayfd H3 380m ... etc. The above are RaceDate + RaceTime + Fixture + RaceDetails, and are output in RaceTime order. What I'd like to do, is output a transposed-like summary of just the Fixture + RaceTime. i.e. Sund 1103 1119 1134 1148 1204 1218 1232 1247 1304 1319 1333 1351 Sheff 1128 1142 1157 1212 1227 1242 1258 1312 1327 1344 1403 Romfd 1408 1427 ... Crayfd 1418 1437 ... Do I need to use a Dictionary? Many thanks! Cheers, Garry ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Help with a Dictionary
On Thu, Jan 7, 2010 at 15:26, Garry Bettle wrote: Howdy all, I hope this message finds you all well. I have a list that I output in the following order: 2010-01-07 1103 Sund A7 450m 2010-01-07 Sheff A7 500m 2010-01-07 1119 Sund A6 450m 2010-01-07 1128 Sheff A6 500m 2010-01-07 1134 Sund A5 450m 2010-01-07 1142 Sheff A7 500m 2010-01-07 1148 Sund A5 450m 2010-01-07 1157 Sheff A6 500m 2010-01-07 1204 Sund A4 450m 2010-01-07 1212 Sheff A5 500m 2010-01-07 1218 Sund A4 450m 2010-01-07 1227 Sheff A3 500m 2010-01-07 1232 Sund A4 450m 2010-01-07 1242 Sheff A4 500m 2010-01-07 1247 Sund A4 450m 2010-01-07 1258 Sheff A3 500m 2010-01-07 1304 Sund A3 450m 2010-01-07 1312 Sheff A4 500m 2010-01-07 1319 Sund HC 640m 2010-01-07 1327 Sheff A5 500m 2010-01-07 1333 Sund A3 450m 2010-01-07 1344 Sheff A3 500m 2010-01-07 1351 Sund A2 450m 2010-01-07 1403 Sheff A2 500m 2010-01-07 1408 Romfd A7 400m 2010-01-07 1418 Crayfd S8 540m 2010-01-07 1427 Romfd A6 400m 2010-01-07 1437 Crayfd H3 380m ... etc. The above are RaceDate + RaceTime + Fixture + RaceDetails, and are output in RaceTime order. What I'd like to do, is output a transposed-like summary of just the Fixture + RaceTime. i.e. Sund 1103 1119 1134 1148 1204 1218 1232 1247 1304 1319 1333 1351 Sheff 1128 1142 1157 1212 1227 1242 1258 1312 1327 1344 1403 Romfd 1408 1427 ... Crayfd 1418 1437 ... Do I need to use a Dictionary? Many thanks! Cheers, Garry This is what I've come up with. Sorry, python is something I touch on occasionally: must do more! As the races are output, I build a dictionary of key=FixtureName and value=RaceTimes: RaceTime = marketResp.market.displayTime.time() cRaceTime = RaceTime.strftime(%H%M) FixtureName = MarketSummary.marketName.strip() MarketName = marketResp.market.name if FixtureName not in FixtureList: FixtureList[FixtureName] = cRaceTime else: FixtureList[FixtureName]+= + cRaceTime And then, when I want the summary to be printed: for fixture in FixtureList: print fixture.ljust(6), FixtureList[fixture] It works, but have I done it the python way? Can't I unpack both the key and value from FixtureList? This doesn't work: for fixture, racetimes in FixtureList: print fixture, racetimes Traceback (most recent call last): File pyshell#3, line 1, in module for fixture, racetimes in FixtureList: ValueError: too many values to unpack Another thing I'd like to change is the ljust(). I believe it's depreciated later in 3.0+, so I should really find an alternative. Cheers, G. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] Trouble with a Recipe ...
Hi,
Hope this email finds everyone well - roll on the weekend.
I'm trying to run http://code.activestate.com/recipes/576824/
I'm in IDLE and I try:
email_it_via_gmail( {To: garry.bet...@gmail.com, Subject: Testing,
From: garry.bet...@gmail.com}, text=Testing)
but I get the following error:
Traceback (most recent call last):
File pyshell#17, line 1, in module
email_it_via_gmail( {To: garry.bet...@gmail.com, Subject:
Testing, From: garry.bet...@gmail.com}, text=Testing)
File C:\Documents and Settings\Garry\Desktop\recipe-576824-1.py,
line 50, in email_it_via_gmail
+ headers.get(Bcc, [])
TypeError: cannot concatenate 'str' and 'list' objects
Sorry, but I according to the recipe I don't need a Bcc.
Sorry, again, for such a simple question!
Cheers,
Garry
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Re: [Tutor] Trouble with a Recipe ...
Many, many thanks Vern.
For the life of me, I couldn't remember [] are for lists: I was trying with ().
Guess I picked a bad day to stop sniffing glue!
Cheers,
Garry
On Tue, Aug 25, 2009 at 15:55, Vern Cedervce...@canterburyschool.org wrote:
At the top in the docstring it says, 'To, Cc and Bcc values must be
*lists*'.
That means instead of To: garry.bet...@gmail.com, you need To:
[garry.bet...@gmail.com] i.e. a list containing the destination address.
That's so that you could send to, cc and bcc more than one address.
HTH,
Vern
Garry Bettle wrote:
Hi,
Hope this email finds everyone well - roll on the weekend.
I'm trying to run http://code.activestate.com/recipes/576824/
I'm in IDLE and I try:
email_it_via_gmail( {To: garry.bet...@gmail.com, Subject:
Testing, From: garry.bet...@gmail.com}, text=Testing)
but I get the following error:
Traceback (most recent call last):
File pyshell#17, line 1, in module
email_it_via_gmail( {To: garry.bet...@gmail.com, Subject:
Testing, From: garry.bet...@gmail.com}, text=Testing)
File C:\Documents and Settings\Garry\Desktop\recipe-576824-1.py,
line 50, in email_it_via_gmail
+ headers.get(Bcc, [])
TypeError: cannot concatenate 'str' and 'list' objects
Sorry, but I according to the recipe I don't need a Bcc.
Sorry, again, for such a simple question!
Cheers,
Garry
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--
This time for sure!
-Bullwinkle J. Moose
-
Vern Ceder, Director of Technology
Canterbury School, 3210 Smith Road, Ft Wayne, IN 46804
vce...@canterburyschool.org; 260-436-0746; FAX: 260-436-5137
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[Tutor] Normal Distribution
Sorry! Now with an appropriate subject line... G. Howdy all, Hope this email finds you all well - roll on the weekend. I've been tasked with replicating an Excel spreadsheet. The spreadsheet contains cells that use Excels' NORMDIST() function. I have all 3 variables required - value, mean and standard deviation - but does anyone already have equivalent python code for this function? Many thanks! Cheers, Garry PS: Excel Help: NORMDIST Returns the normal distribution for the specified mean and standard deviation. This function has a very wide range of applications in statistics, including hypothesis testing. Syntax NORMDIST(x,mean,standard_dev,cumulative) X is the value for which you want the distribution. Mean is the arithmetic mean of the distribution. Standard_dev is the standard deviation of the distribution. Cumulative is a logical value that determines the form of the function. If cumulative is TRUE, NORMDIST returns the cumulative distribution function; if FALSE, it returns the probability mass function. Remarks If mean or standard_dev is nonnumeric, NORMDIST returns the #VALUE! error value. If standard_dev ≤ 0, NORMDIST returns the #NUM! error value. If mean = 0, standard_dev = 1, and cumulative = TRUE, NORMDIST returns the standard normal distribution, NORMSDIST. When cumulative = TRUE, the formula is the integral from negative infinity to x of the given formula. ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
[Tutor] Quick question regarding Parsing a Delimited string
Hi, I've been programming for over 20 yrs, but only the last few in python and then only in dribs and drabs. I'm having a difficult time parsing a delimited string. e.g. 100657641~GBP~ACTIVE~0~1~~true~5.0~1247065352508~: 3818854~0~24104.08~4.5~~22.1~false|4.4~241.67~L~1~4.3~936.0~L~2~4.2~210.54~L~3~|4.5~19.16~B~1~4.6~214.27~B~2~4.7~802.13~B~3~: 3991404~1~19974.18~4.7~~21.7~false|4.6~133.01~L~1~4.5~124.83~L~2~4.4~319.33~L~3~|4.7~86.61~B~1~4.8~247.9~B~2~4.9~142.0~B~3~: 4031423~2~15503.56~6.6~~15.1~false|6.6~53.21~L~1~6.4~19.23~L~2~6.2~53.28~L~3~|6.8~41.23~B~1~7.0~145.04~B~2~7.2~37.23~B~3~ That is just a selection of the full string - and I've broken it up for this email. It's delimited by : and then by ~ and finally, in some cases, | (a pipe). If the string is called m, I thought I could create a list with m.split(:). I would like to then first of all find in this list the entry beginning with e.g. 3991404. I thought I could pop each item in the list and compare that seems pretty long winded. When the ItemFound is now = '3991404~1~19974.18~4.7~~21.7~false|4.6~133.01~L~1~4.5~124.83~L~2~4.4~319.33~L~3~|4.7~86.61~B~1~4.8~247.9~B~2~4.9~142.0~B~3~:' I would like to return the 3rd item delimited with ~, which in this case, is 4.7 Can anyone help? Many thanks! Cheers, Garry ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Quick question regarding Parsing a Delimited string
On Wed, Jul 8, 2009 at 21:37, Kent Johnsonken...@tds.net wrote: On Wed, Jul 8, 2009 at 1:22 PM, Rich Lovelyroadier...@googlemail.com wrote: If you really want to speed up the search, you could turn the list of lists into a dict, using the first value in each sublist as a key: dct = dict((i[0], i[1:]) for i in lst) Then you can access it using the normal dictionary interface. dct[3991404][3] I'm suspicious of this claim if there is only one lookup needed. You iterate the whole list and incur the overhead of constructing a dict. If there will be multiple lookups it may well be a win but as always there is no substitute for measurement if you want to know what is faster. Kent Hi Kent, No, I think the dict will be fine: I have to find every one that is in my original list. Many thanks to both you and Rich for all the help. I'll let you know how I get on. Cheers, Garry ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] python parser
On Mon, 22 Dec 2008 09:39:37 -0800, johnf wrote: Well I'm attempting to convert VFP and MsSQL (stored procedures and triggers) to Python and Postgres (functions and triggers). Actually, python is very close to VFP and I would convert very well. MsSQL is another question. Hi John, I hope this message finds you well. You might be interested in the following: http://dabodev.com/ Dabo is a 3-tier, cross-platform application development framework, written in Python atop the wxPython GUI toolkit. And while Dabo is designed to create database-centric apps, that is not a requirement. Lots of people are using Dabo for the GUI tools to create apps that have no need to connect to a database at all. NB: The VFP-angle is well and truely catered for: Background Dabo's authors, Ed Leafe and Paul McNett, have strong backgrounds in database application development using the awesome and underrated Microsoft Visual FoxPro development environment. While Visual FoxPro shines at developing data-centric applications, it has one limitation that cannot be ignored: it only runs on Microsoft Windows, and Ed and Paul both have clients that want their applications to run on Linux and Macintosh. We are sure we are not alone in this regard: it is a multi-platform world with more diverse needs than one vendor can fulfill. Ed and Paul got to talking one day: Paul had been researching various multiplatform GUI toolkits for about 18 months, and Ed has lots of experience developing the Visual FoxPro Codebook framework. We decided to work together to make a framework for developing robust data-centric applications for multi-platform deployment. We've come up with a design that is simple, flexible, and robust, and we've begun developing our own client applications using the Dabo framework. G. ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
[Tutor] Pycron - Does anyone have experience with this?
Howdy all, Hope this finds everyone well - roll on the weekend. I've been using pycron for months now with no trouble at all. It's a great scheduling program. I'm now trying to schedule a file copy from a network share. However, Pycron chokes, as it requires the share to fully qualified. Instead of: s:\subdir1\subdir2\file.ext it wants: \\servername\share\subdir1\subdir2\file.ext But no matter how I try to do the file copy - batch file, WSH and Win32API calls - it still refuses to run. It seems a shame to have to look for another scheduling solution. Can anyone help? Many thanks! Cheers, Garry ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
