Re: [Tutor] General question rgrd. usage of libraries

[Palm Tree]

Hum i also suggest you get more experience with python

think of a project and learn while doing it. thus you'll get motivation
while at the same time doing something useful which you could reuse in the
future.

else,

me for bs4 i googled what i needed. I also put an increasing variable to
ease web scraping tasks. like

var =0
...
print(var, element)

also, i suggest you decode to unicode as you'll get crazy hex stuffs if you
don't

.decode("utf-8")

i scrape websites written in french, so i always need unicode.

else the

.text is very helpful

like 'p' gives you the element

but

'p.text' gives you the content

To find suitable libraries i suggest you become good at doing the desired
task by hand as far as possible, so you'll know your job well. Then you
identify boring, impossible or tiring tasks. Then you google like .. python
module  or just python how to  and see how they did it
or what module they used to do it.

Hope it helps,

Abdur-Rahmaan Janhangeer,
Mauritius

On 6 May 2017 00:56, "Jim"  wrote:

> On 05/05/2017 08:45 AM, Rafael Knuth wrote:
>
>> Hi there,
>>
>> I just recently learned how to build a basic web scraper with Python
>> 3.5 (I am learning Python for data analytics purposes). Being new to
>> coding, I have a question:
>>
>> How do I know which libraries I need to perform a certain task?
>> For example, in case of this web scraper (which I built with help of a
>> tutorial on YouTube) I need to have urrlib and Beautiful Soup
>>
>> import urllib
>> import urllib.request
>> from bs4 import BeautifulSoup
>>
>> theurl = "https://twitter.com/rafaelknuth;
>> thepage = urllib.request.urlopen(theurl)
>> soup = BeautifulSoup(thepage, "html.parser")
>>
>> print(soup.title.text)
>>
>> i = 1
>> for tweets in soup.findAll("div",{"class":"content"}):
>> print(i)
>> print(tweets.find("p").text)
>> i = i + 1
>>
>> Is there a way I can figure out which libraries I need when drafting my
>> code?
>> Can you share your experiences? Right now, if I wanted for example to
>> populate a Google Sheet with my scraped web content - how would I know
>> which libraries I would need to actually make this happen? I am trying
>> wondering if there is a process to figure out what I exactly need
>> library-wise.
>>
>>
>>
> There is a Python API to google sheets but when I had a look, it seemed
> fairly complex. I haven't tried it yet but depending on what you need to do
> this library may be what you need:
>   https://pypi.python.org/pypi/gspread.
>
> Regards,  Jim
>
>
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[Tutor] selenium, automated testing and python

[Palm Tree]

Sorry i'm a bit new to automated testing.

I have explored python wide and deep but can someone just tell me why as a
coder i need automated testing?

i have tried some googling but the explanations are a bit crazy.

thanks.
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Re: [Tutor] Tkinter layout question

[Palm Tree]

for entering digits on the canva i think better create a sort of sudoku
generator and display it on the canva in a create_text object.

On 20 Apr 2017 05:24, "Phil"  wrote:

> I'm looking for ideas here.
>
> A working solution for my sudoku solver is a 9 x 9 grid of entry boxes but
> it looks a bit basic. So I created a 9 x 9 grid on a canvas which looks
> much better. I can display digits in the centre of the squares but entering
> the digits from the keyboard seems to be beyond me. I experimented with
> entering a digit at the mouse location but it all seems to be too
> complicated. Perhaps someone can offer a repetitively simple solution?
>
> A second experiment involved the earlier grid of entry boxes but with a
> space between every third row and column. This seems to be more achievable,
> eventually.
>
> Something along these lines:
>
> for i in range(9):
> if i % 4 == 0:
> place a blank text label
> else:
> place an entry box
>
> So, how might I enter digits into a grid on a canvas or how could I create
> a space between a grid entry boxes?
>
> --
> Regards,
> Phil
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Re: [Tutor] bracket issue

[Palm Tree]

-- Forwarded message --
From: "Palm Tree" <timeofsa...@gmail.com>
Date: 16 Apr 2017 10:07
Subject: Re: [Tutor] bracket issue
To: "Peter Otten" <__pete...@web.de>
Cc:

Ok thanks for the answers. Perfect.

Just to clarify why i wanted recursion was that well coming to compiler
theory, i created a python-based language called newB

it allows you to define your own keywords but don't abuse

like you can configure if to cheese

cheese x == 4:

coming to recursion well i currently use eval() so everything ok i don't
have to worry about brackets but i want to write my own parser. a top down
parser for expressions.

you can also view the lang here:
http://wp.me/p7UB6x-oV

thanks for the answers once more

On 15 Apr 2017 18:46, "Peter Otten" <__pete...@web.de> wrote:

> Palm Tree wrote:
>
> > hi all. i'm trying to write a simple program. i'm using python 3.4
> >
> > let us say i have
> >
> > s="2*3+3(8-4(5+6+9))+2+3+3(4/4)"
> >
> > i want to find expression enclosed in brackets.
> >
> > i want outputs to be like:
> > (8-4(5+6+9))
> > (5+6+9)
> > (4/4)
> > note : i'd like an answer involving recursion if possible
>
> No recursion, but a stack managed manually:
>
> >>> s = "2*3+3(8-4(5+6+9))+2+3+3(4/4)"
> >>> stack = []
> >>> for i, c in enumerate(s):
> ... if c == "(":
> ... stack.append(i)
> ... elif c == ")":
> ... print(s[stack.pop():i+1])
> ...
> (5+6+9)
> (8-4(5+6+9))
> (4/4)
>
> The order is determined by the closing parenthesis, you could sort if you
> don't want that.
>
> I did not find a convincing translation using recursion, but I'll give one
> anyway:
>
> def find_closing(s):
> i = c = None
> pairs = enumerate(s)
> def step(start=None):
> nonlocal i, c
> for i, c in pairs:
> if c == "(":
> step(i)
> elif c == ")":
> if start is not None:
> print(s[start:i+1])
> return
> step()
>
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Re: [Tutor] How do we create a GUI to run a simple calculation program in Python?

[Palm Tree]

On 16 Apr 2017 10:01, "Palm Tree" <timeofsa...@gmail.com> wrote:

Sorry for late reply.

We usually organise python challenges.

Once we organise a gui calculator challenge.

You can view the submissions on my blog here:
https://abdurrahmaanjanhangeer.wordpress.com/gui-py-
calculator-challenge-19-1-17/

On 16 Apr 2017 09:50, "Alex Kleider" <aklei...@sonic.net> wrote:

> On 2017-04-15 01:04, Alan Gauld via Tutor wrote:
>
>
>
>> Finally, if you can find a copy of my recent book "Python Projects"
>> there is a rolling project within that which demonstrates how
>> the same logic code can be used to build a CLI, a GUI and a
>> Web app. [ In fact it goes even further by demonstrating how
>> to break an app into 3 tiers - data, logic and UI - which
>> is industry best practice, but usually overkill for small
>> projects.]
>>
>
> Thanks, Alan, for the guidance.  As it happens, I have a copy of your
> Python Projects" book- time to get it off the shelf and have a closer look!
> Alex
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[Tutor] bracket issue

[Palm Tree]

hi all. i'm trying to write a simple program. i'm using python 3.4

let us say i have

s="2*3+3(8-4(5+6+9))+2+3+3(4/4)"

i want to find expression enclosed in brackets.

i want outputs to be like:
(8-4(5+6+9))
(5+6+9)
(4/4)

i've tried where  denotes an indentation level :

#first part
sbracket=[ ]
ebracket=[ ]
for i in range(len(s)):
global sbracket
global ebracket
if f[i] == "(":
sbracket.append(i)
elif f[i] == ")":
ebracket.append(i)

#second part
for i in range(len(sbracket)):
print(f[sbracket[i]:ebracket[i]])

however, the above code works well as long as there are no nested brackets
like

s="(1+2)(2+3)"

but fails as soon as

s="((3+2))2"

prior to that i wrote it like:
for i in range(len(f)):
if f[i] == "(":
sbracket.append(i)
for x in range(len(f)):
if f[i+x]==")":
ebracket.append(x)
break

but that too failed to output correctly

note : i'd like an answer involving recursion if possible
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