Re: [Tutor] Recognising Errors
Thanks for the advice and tips. I wasn't taking anything as an insult; I just have a problem with one of the staffs attitude responses. He needs sleep. Alan Gauld has been very helpful- a special thanks to you. Kind regards Saba On 21 Apr 2014, at 18:40, Danny Yoo d...@hashcollision.org wrote: If for some reason you can't read this code properly as outlook has formatted it to look messy/cluttered; you do not have to respond. You are missing the point of people point this out. Look at what the email archive thinks of your previous messages: https://mail.python.org/pipermail/tutor/2014-April/100904.html https://mail.python.org/pipermail/tutor/2014-April/100940.html https://mail.python.org/pipermail/tutor/2014-April/100985.html https://mail.python.org/pipermail/tutor/2014-April/100997.html When folks are saying that we can't read your programs, we're not trying to insult you. Rather, we're making a very technical observation: your email client is interfering with the indentation of your program. In Python, indentation and formatting _changes_ the meaning of your program, so we really can not tell what your program _means_. Under those conditions, we can't help very effectively. If you really can not fix your email client, then post your programs on a pastebin which should preserve formatting and meaning. For example, http://gist.github.com. But please do not treat the advice you're been getting as personal insults. They are not intended to be such. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
[Tutor] Recognising Errors
Hi,
I have designed some code, but I want it to be able to recognize invalid inputs
- such as a binary number with more than 8 digits or non-binary values. What do
I have to add and where do I add it?
print Welcome to the binary - decimal / decimal - binary converter!loop =
Truewhile loop:choice = raw_input(Enter b to convert from binary to
decimal, d to convert from decimal to binary or e to exit)if choice ==
b:decimal_num = 0binary_num = 0factor = 1;
binary_num = raw_input (Enter Binary Number:)
binary_num=binary_num.lstrip(0)binary_num = int(binary_num)
while(binary_num 0):if((int(binary_num) % 10) == 1):
decimal_num += factorbinary_num /= 10factor = factor
* 2print The Decimal Equivalent is: , decimal_num elif
choice == d:z=0n=int(input('Enter Decimal Number: '))
z=nk=[] # arraywhile (n0):a=int(float(n%2))
k.append(a)n=(n-a)/2k.append(0)string=
for j in k[::-1]:string=string+str(j)print('The
Binary Equivalent is %d is %s'%(z, string)) elif choice == e :
print Thanks For Using This Converter!loop = False
If for some reason you can't read this code properly as outlook has formatted
it to look messy/cluttered; you do not have to respond.
Thanks___
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[Tutor] Creating an Invalid Message for user
Hi,
I am meant to design code for a program that converts from binary number to
decimal and vice versa.
This is what i have so far:
print Welcome to the binary and decimal converterloop = Truewhile loop:
bord = raw_input(Enter b for binary or d decimal or exit to exit)if bord
== b:d = 0b = 0factor = 1;b = raw_input
(Enter Binary Number:)b=b.lstrip(0)b = int(b)
while(b 0):if((int(b) % 10) == 1):d += factor
b /= 10factor = factor * 2print The Decimal Number
is: , d elif bord == d:x=0n=int(input('Enter
Decimal Number: '))x=nk=[] # arraywhile (n0):
a=int(float(n%2))k.append(a)n=(n-a)/2
k.append(0)string=for j in k[::-1]:
string=string+str(j)print('The binary Number for %d is %s'%(x, string))
elif bord == exit :print Goodbyeloop = False
- This code does not recognize invalid inputs e.g in the binary to decimal
conversion, so if I enter e.g 10021, not a binary number, it will not inform
me,the user, that the input is invalid. The same problem occurs with the
decimal to binary conversion - if i enter e.g 123gf I am not told to try
again with a valid input - how do I implement this in the code above
ThanksSaba___
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[Tutor] Creating an Invalid message for user
Hi,
I am meant to design code for a program that converts from binary number to
decimal and vice versa.
This is what i have so far:
print Welcome to the binary and decimal converterloop = Truewhile loop:
bord = raw_input(Enter b for binary or d decimal or exit to exit)if bord
== b:d = 0b = 0factor = 1;b = raw_input
(Enter Binary Number:)b=b.lstrip(0)b = int(b)
while(b 0):if((int(b) % 10) == 1):d += factor
b /= 10factor = factor * 2print The Decimal Number
is: , d elif bord == d:x=0n=int(input('Enter
Decimal Number: '))x=nk=[] # arraywhile (n0):
a=int(float(n%2))k.append(a)n=(n-a)/2
k.append(0)string=for j in k[::-1]:
string=string+str(j)print('The binary Number for %d is %s'%(x, string))
elif bord == exit :print Goodbyeloop = False
- This code does not recognize invalid inputs e.g in the binary to decimal
conversion, if I enter 10021 it will not inform me,the user, that the input is
invalid. The same problem occurs with the decimal to binary conversion - if i
enter 123gf I am not told to try again with a valid input - how do I
implement this in the code above
ThanksSaba___
Tutor maillist - Tutor@python.org
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[Tutor] Refining Code
My task is :A food vending machine accepts 10p, 20p, 50p and £1 coins. One or more coins are inserted and the current credit is calculated and displayed. A product is selected from those available. The system checks to see if there is enough credit to purchase the product chosen. If there is not enough credit the system displays an error message. If there is enough credit it dispenses the product, updates the credit available and displays the remaining credit. Further selections can be made if there is enough credit. The vending machine simulation should have five products and prices. Design, code, test and evaluate a program for this simulation. I have designed the following code, but would like to know how to make it more efficient without making it too complex as I am a beginner or is this fine? Also, how do I add a loop to this so that once one product has been dispensed the program asks the user if they would like to continue and purchase another product? Code: print Welcome to Snack Attack snack1 = 0.40snack2 = 0.75snack3 = 1.20snack4 = 0.99snack5 = 0.50insert = 0 change = 0currentCredit = 0.00A = 0.10B = 0.20C = 0.50D = 1.00a = 0.10b = 0.20c = 0.50d = 1.00 print Menuprint Snack 1: Snickers - £0.40print Snack 2: Doritos - £0.75 print Snack 3: J20 - £1.20print Snack 4: Oreos - £0.99print Snack 5: MM's - £0.50 print Exit?- how do I make this a Boolean expression, so the user can respond with either yes or no? choice = input(Select your snack: ) if choice==1: printprint You have selected Snickers, which cost £0.40 print Please insert £0.40 while currentCredit snack1: print Please select which of these coins to insert; A:10p,B:20p,C:50p and D:£1 insert_coins = input(Insert coins: ) currentCredit = insert_coins + currentCredit print Your current credit is £,currentCredit else: change_given=currentCredit-snack1 printprint Your change is £,change_given print Your Snickers have been dispensed...Enjoy! elif choice==2: print You have selected Doritos, which cost £0.75 print Please insert £0.75 while currentCreditsnack2: print Please select which of these coins to insert; A:10p,B:20p,C:50p and D:£1 insert_coins = input(Enter coins: ) currentCredit = insert_coins + currentCredit print Your current credit is £,currentCredit else: change_given=currentCredit-snack2 printprint Your change is £,change_given print Your Doritos have been dispensed...Enjoy! elif choice==3: print You have selected J20, which costs £1.20 print Please insert £1.20 while currentCreditsnack3: print Please select which of these coins to insert; A:10p,B:20p,C:50p and D:£1 insert_coins = input(Enter coins: ) currentCredit = insert_coins + currentCredit print Your current credit is £,currentCredit else: change_given=currentCredit-snack3 printprint Your change is £,change_given print Your J2O has been dispensed...Enjoy! elif choice==4: print You have selcetd Oreos, which cost £0.99 print Please insert £0.99 while currentCreditsnack4: print Please select which of these coins to insert; A:10p,B:20p,C:50p and D:£1 insert_coins = input(Enter coins: ) currentCredit = insert_coins + currentCredit print Your current credit is £,currentCredit else: change_given=currentCredit-snack4 printprint Your change is £,change_given print Your Oreos have been dispensed...Enjoy! elif choice==5: print You have selected MM's, which cost £0.50 print Please insert £0.50 while currentCreditsnack5: print Please select which of these coins to insert; A:10p,B:20p,C:50p and D:£1 insert_coins = input(Enter coins: ) currentCredit = insert_coins + currentCredit print Your current credit is £,currentCredit else: change_given=currentCredit-snack5 printprint Your change is £,change_given print Your MM's have been dispensed...Enjoy! elif choice==Exit:print Thank You and Have a Nice Day else:print print Invalid choice Thanks,Saba ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
