Re: [Tutor] guess my number game (reversed)

[chiara pascucci]

Hi,

sorry for "resurrecting" this thread. I have tried doing as suggested but
with no luck.
I now managed to make the programme work "partially". It works as desired
for "too high" and "right" answer input, but when the users input "too low"
the programme closes.
here is what the code looks like right now.

print ("Think of a number from 1 to 100, and I will try to guess it")
input ("press enter when ready...")

import random

number = random.randint(1,100)
print (number)

answer = input ("right, too low, too high?")

while answer != "right":
if answer == "too high":
number2 = random.randint (1,number)
print (number2)

elif answer == "too low":
number3 = random.randit (number,100)
print (number3)

answer = input ("is this right, too high, or too low?")

print ("I finally guessed your number")

input ("\n\n press the enter key to exit")

any help is really appreciated :)

Chiara

Il giorno ven 1 giu 2018 alle ore 18:15 Alan Gauld via Tutor <
tutor@python.org> ha scritto:

> On 01/06/18 14:00, chiara pascucci wrote:
>
> > the user's input. The programme works fine if the it guesses the number
> > right on its first try, but when the users inputs "too low" or "too high"
> > an infinite loop is returned. I thinkI have done something wrong in my
> > while loop and that my sentry variable is somehow wrong
>
> Nope, it's simpler than that.
>
> You only ask the user for input once, outside the loop.
> Move the input() statement inside the loop before the if
> statements and all should be well. (You will also need to
> initialise answer to some value - an empty string
> say - before entering the while loop.)
>
> > print("think of a number from 1 to 100")
> > print("I will try and guess it!")
> >
> > import random
> >
> > number = random.randint(1,100)
> > print(number)
> >
> > answer = input("is this right, too high, or too low?")
> >
> > while answer != "right":
> > if answer == "too high":
> > number2 = random.randint(1,number)
> > print(number2)
> > elif answer == "too low":
> > number3 = random.randint(number,100)
> > print(number3)
> >
> > print("I finally guessed your number. Thank you for playing")
>
> HTH
> --
> Alan G
> Author of the Learn to Program web site
> http://www.alan-g.me.uk/
> http://www.amazon.com/author/alan_gauld
> Follow my photo-blog on Flickr at:
> http://www.flickr.com/photos/alangauldphotos
>
>
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[Tutor] guess my number game (reversed)

[chiara pascucci]

Hello.

I am very new to learning Python, and I would need some help with a little
game I am trying to write. I am trying to write a game where the user is
asked to think of a number from 1 to a 100, and the computer tries to guess
it. Now, after every guess I would want the programme to ask whether its
guess is right, too low, or too high, and then take another guess based on
the user's input. The programme works fine if the it guesses the number
right on its first try, but when the users inputs "too low" or "too high"
an infinite loop is returned. I thinkI have done something wrong in my
while loop and that my sentry variable is somehow wrong -but I can't seem
to be able to fix it!
Any help or commments would be very appreciated.
Below is the code written so far

Many thanks

Chiara

print("think of a number from 1 to 100")
print("I will try and guess it!")

import random

number = random.randint(1,100)
print(number)

answer = input("is this right, too high, or too low?")

while answer != "right":
if answer == "too high":
number2 = random.randint(1,number)
print(number2)
elif answer == "too low":
number3 = random.randint(number,100)
print(number3)

print("I finally guessed your number. Thank you for playing")


input("\n\nPress enter key to exit")
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