Thanks David, But the loop was suppose to produce the count of even divisors an
integer has.
Like, 6 has 2 "even" divisors, which is 2 and 6, itself.
8 = 3 even divisors, which is 2, 4 ,and 8
10 = 2 even divisors, which is 2, and 10
12 = 4 even divisors, which is 2, 4, 6, and 12
sorry, I just don't know how to write a code to count the number of divisors
From: David Hutto
To: masawudu bature
Cc: tutor@python.org
Sent: Mon, September 27, 2010 11:36:05 PM
Subject: Re: [Tutor] Python Help
On Tue, Sep 28, 2010 at 12:15 AM, masawudu bature wrote:
> I'm having a hard time finding the count of divisors that are even. Help
> anybody?
>
> Here's my code.
>
> The output is suppose to count the number of even divisors the range has.
>
> def evenCount(b) :
> for n in range(x, y+1) :
> count = 0
> if n % 2 == 0 :
> count += n/3
> count % n == 1
> return n
>
>
> ### main
>
> x = input("Enter a starting value: ")
> y = input("Enter a stopping value: ")
>
> count = evenCount(x)
>
> for n in range(x, y+1) :
> count = 0
> if n % 2 == 0 :
> count += n/3
> print "%2d: " %n, "has%2d" %count, "even divisors",
> else :
> print "%2d: " %n, "has 0 even divisors",
> print
>
>
>
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>
#You start with your range variables
x = input("Enter a starting value: ")
y = input("Enter a stopping value: ")
#You set a for loop for range
for num in range(x, y):
#If that number divided by 2 has a remainder of 0, it's of course even.
if num % 2 == 0:
#print the number
print num
And various other ways as well.
David
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