Re: [Tutor] Extremely simple question
Noah Hall wrote: On Wed, Jan 11, 2012 at 7:14 AM, Chris Johnson c.johnso...@gmail.com wrote: Hi there, I am *new* (I cannot put enough emphasis on that!) to Python programming, and to programming in general. I am trying to write out a statement that will protect a file on my computer from being run unless I enter the right specifications; your_weight = int(raw_input(Please enter your weight: )) if your_weight 0: print 'You're not Chris!' elif your_weight == 170: print 'You might be Chris! But...' your_height = int(raw_input(Please enter your height: )) if your_height 180: print 'You're not Chris! elif your_height == 180: print 'You're Chris!' your_name = int(raw_input(What is your name? )) elif your_height 180: print 'You're not Chris! elif x 170: print 'You're not Chris!' When I open it, the program says I have a syntax error. Praytell, where did I go wrong? When you have a problem like this, you should copy and paste the *whole* traceback here. Anyway, just from quickly looking, I think your error lines in the the line elif x 170: I'm sure you can work out why. Well, I can't. Chris reported that he gets a SYNTAX error, and for the life of me I can't work out what SyntaxError you think he'll be getting from that line. Based on Chris' post, he has a whole lot of code starting with , which of course will give a SyntaxError. He also hasn't indented his if/elif blocks. But of course his mail client might be mangling his code. Without being able to see the code, and the actual error message in full, we're all just guessing. And frankly, my crystal ball is out of order. -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Extremely simple question
On Wed, Jan 11, 2012 at 10:24 AM, Steven D'Aprano st...@pearwood.info wrote: Noah Hall wrote: On Wed, Jan 11, 2012 at 7:14 AM, Chris Johnson c.johnso...@gmail.com wrote: Hi there, I am *new* (I cannot put enough emphasis on that!) to Python programming, and to programming in general. I am trying to write out a statement that will protect a file on my computer from being run unless I enter the right specifications; your_weight = int(raw_input(Please enter your weight: )) if your_weight 0: print 'You're not Chris!' elif your_weight == 170: print 'You might be Chris! But...' your_height = int(raw_input(Please enter your height: )) if your_height 180: print 'You're not Chris! elif your_height == 180: print 'You're Chris!' your_name = int(raw_input(What is your name? )) elif your_height 180: print 'You're not Chris! elif x 170: print 'You're not Chris!' When I open it, the program says I have a syntax error. Praytell, where did I go wrong? When you have a problem like this, you should copy and paste the *whole* traceback here. Anyway, just from quickly looking, I think your error lines in the the line elif x 170: I'm sure you can work out why. Well, I can't. Chris reported that he gets a SYNTAX error, and for the life of me I can't work out what SyntaxError you think he'll be getting from that line. Based on Chris' post, he has a whole lot of code starting with , which of course will give a SyntaxError. He also hasn't indented his if/elif blocks. But of course his mail client might be mangling his code. Without being able to see the code, and the actual error message in full, we're all just guessing. And frankly, my crystal ball is out of order. I had assumed that to him, a Syntax Error == any error, so guess it was probably a name error as x isn't defined. (Also, for me his post was indented correctly - probably down to my client, though) ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Extremely simple question
your_weight = int(raw_input(Please enter your weight: )) if your_weight 0: print 'You're not Chris!' elif your_weight == 170: print 'You might be Chris! But...' your_height = int(raw_input(Please enter your height: )) if your_height 180: print 'You're not Chris! elif your_height == 180: print 'You're Chris!' your_name = int(raw_input(What is your name? )) elif your_height 180: print 'You're not Chris! elif x 170: print 'You're not Chris!' When I open it, the program says I have a syntax error. Praytell, where did I go wrong?n I'm a newbie, but I get NameError because 'x' is not defined. Also your_name = int(raw_input(What is your name? )) will give this : ValueError: invalid literal for int() with base 10: 'name'. As you can't change a string to be an int. I can't find a syntax error, but next time, please paste the whole traceback as this helps people with less time than me to sort out problems. Good luck with Python Col ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] Extremely simple question
Hi Chris I'm new to programming and Python myself so I would listen to the previous guys first, and I'll repeat a bit of what has already been mentioned... Make sure you define 'x'. Is name really an 'int', or is it possibly a 'str'? Fix any indentation issues. Is there anything you can do with quotes - single or double: print You're not Chris! or print 'You\'re not Chris!' You should be able to make your code work as is but it would also look nice in a function, passing the user 'raw_input' to a function - def chris(name, height, weight): ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Extremely simple question
I believe that line 3 raises an error. The because you contained the text
in single quotes, and then used the same character in 'you're not chris',
Python believes that you are trying to type you re not chris. You can
change the single quotes surrounding your string to double quotes (you're
not chris), triple-single quotes ('''you're not chris'''), or
triple-double quotes (you're not chris), or you can tell Python that
you want to include the apostrophe in your string by preceding it with a \
('you\'re not chris'). The latter works on the same idea as \n and \t.
On Wed, Jan 11, 2012 at 6:04 AM, col speed ajarnco...@gmail.com wrote:
your_weight = int(raw_input(Please enter your weight: ))
if your_weight 0:
print 'You're not Chris!'
elif your_weight == 170:
print 'You might be Chris! But...'
your_height = int(raw_input(Please enter your height: ))
if your_height 180:
print 'You're not Chris!
elif your_height == 180:
print 'You're Chris!'
your_name = int(raw_input(What is your name? ))
elif your_height 180:
print 'You're not Chris!
elif x 170:
print 'You're not Chris!'
When I open it, the program says I have a syntax error. Praytell,
where
did
I go wrong?n
I'm a newbie, but I get NameError because 'x' is not defined.
Also your_name = int(raw_input(What is your name? )) will give this :
ValueError: invalid literal for int() with base 10: 'name'.
As you can't change a string to be an int.
I can't find a syntax error, but next time, please paste the whole
traceback as this helps people with less time than me to sort out
problems.
Good luck with Python
Col
___
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
___
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Extremely simple question
On 11 January 2012 20:11, Max S. maxskywalk...@gmail.com wrote:
I believe that line 3 raises an error. The because you contained the text
in single quotes, and then used the same character in 'you're not chris',
Python believes that you are trying to type you re not chris. You can
change the single quotes surrounding your string to double quotes (you're
not chris), triple-single quotes ('''you're not chris'''), or triple-double
quotes (you're not chris), or you can tell Python that you want to
include the apostrophe in your string by preceding it with a \ ('you\'re not
chris'). The latter works on the same idea as \n and \t.
How didn't I see that?
It just goes to show a gooddun from a baddun.
Cheers
Col
___
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Extremely simple question
You should be using double quotes on this line and you are missing the last
quote:
print 'You're not Chris!
Should be:
print You're not Chris!
On Wed, Jan 11, 2012 at 8:17 AM, col speed ajarnco...@gmail.com wrote:
On 11 January 2012 20:11, Max S. maxskywalk...@gmail.com wrote:
I believe that line 3 raises an error. The because you contained the
text
in single quotes, and then used the same character in 'you're not chris',
Python believes that you are trying to type you re not chris. You can
change the single quotes surrounding your string to double quotes
(you're
not chris), triple-single quotes ('''you're not chris'''), or
triple-double
quotes (you're not chris), or you can tell Python that you want to
include the apostrophe in your string by preceding it with a \ ('you\'re
not
chris'). The latter works on the same idea as \n and \t.
How didn't I see that?
It just goes to show a gooddun from a baddun.
Cheers
Col
___
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
___
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
[Tutor] Extremely simple question
Hi there, I am *new* (I cannot put enough emphasis on that!) to Python programming, and to programming in general. I am trying to write out a statement that will protect a file on my computer from being run unless I enter the right specifications; your_weight = int(raw_input(Please enter your weight: )) if your_weight 0: print 'You're not Chris!' elif your_weight == 170: print 'You might be Chris! But...' your_height = int(raw_input(Please enter your height: )) if your_height 180: print 'You're not Chris! elif your_height == 180: print 'You're Chris!' your_name = int(raw_input(What is your name? )) elif your_height 180: print 'You're not Chris! elif x 170: print 'You're not Chris!' When I open it, the program says I have a syntax error. Praytell, where did I go wrong? ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Extremely simple question
On Wed, Jan 11, 2012 at 7:14 AM, Chris Johnson c.johnso...@gmail.com wrote: Hi there, I am *new* (I cannot put enough emphasis on that!) to Python programming, and to programming in general. I am trying to write out a statement that will protect a file on my computer from being run unless I enter the right specifications; your_weight = int(raw_input(Please enter your weight: )) if your_weight 0: print 'You're not Chris!' elif your_weight == 170: print 'You might be Chris! But...' your_height = int(raw_input(Please enter your height: )) if your_height 180: print 'You're not Chris! elif your_height == 180: print 'You're Chris!' your_name = int(raw_input(What is your name? )) elif your_height 180: print 'You're not Chris! elif x 170: print 'You're not Chris!' When I open it, the program says I have a syntax error. Praytell, where did I go wrong? When you have a problem like this, you should copy and paste the *whole* traceback here. Anyway, just from quickly looking, I think your error lines in the the line elif x 170: I'm sure you can work out why. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
