Re: [Tutor] Function list that might have a tuple that might have one of its indexs set to 's'
Paul D. Kraus wrote:
I need to scan through a list that contains headers to my table.
If one of the elements is a tuple and one of the elements of the tuple
is s set self.sort to the index of the tuple in the header list and
then replace the element in header with a two field tuple containing
everything that was not 's'.
Actual code in my working example used to call function ...
report.set_header(
['','Ext','Name','',('Calls','r','s'),('Ring','r'),('Talk','r'),('Wait','r'),('Max
Talk','r') ] )
def set_header(self,header):
list = []
for cindex in range(len(header)):
if type(()) == type(header[cindex]):
for index in range(len(header[cindex]) ):
if header[cindex][index] == 's':
self.sort = cindex
for tindex in range(len(header[cindex])):
if tindex != index:
list.append(header[cindex][tindex])
header[cindex] = tuple(list)
self.header = header
You didn't actually ask a question. I assume you are looking for a
version of this that is less stroke-inducing?
You are doing a lot of work that Python would happily do for you.
To iterate over a sequence h, instead of generating the indexes to h, use
for x in h:
which will return the items of h directly. If you also need the indices, use
for i, x in enumerate(h)
You can test for membership in a sequence with
if i in h:
You can filter a sequence with a list comprehension:
[ x for x in h if x != s ]
creates a new list containing all the elements of h that are not s.
Putting this all together gives this rewrite:
def set_header(self, header):
for i, item in enumerate(header):
if type(item) != type(()):
continue
if 's' in item:
self.sort = i
header[i] = tuple([x for x in item if x!='s'])
self.header = header
Note this does change the list passed in, that could be a problem
depending on if you use it for anything else.
Kent
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[Tutor] Function list that might have a tuple that might have one of its indexs set to 's'
I am writing my first python program(at least in a really long time). Its purpose is to take csv or pipe delimintaed files and convert them to html pages. Was going to be excel but its just not worth the headache. Everyone viewing the reports is doing just that viewing simple tables.
I need to scan through a list that contains headers to my table.If one of the elements is a tuple and one of the elements of the tuple is s set self.sort to the index of the tuple in the header list and then replace the element in header with a two field tuple containing everything that was not 's'.
header = ['my first column',('my second num column','s','r'),(' my third num column','r') ]I pass header to a function actually a method but lets pretend its just a plain old function. Be careful reading the below code may cause random strokes. I have woken up twice laying on the floor disoriented :)
Actual code in my working example used to call function ...report.set_header( ['','Ext','Name','',('Calls','r','s'),('Ring','r'),('Talk','r'),('Wait','r'),('Max Talk','r') ] ) def set_header(self,header):
list = [] for cindex in range(len(header)): if type(()) == type(header[cindex]): for index in range(len(header[cindex]) ): if header[cindex][index] == 's':
self.sort = cindex for tindex in range(len(header[cindex])): if tindex != index: list.append(header[cindex][tindex]) header[cindex] = tuple(list)
self.header = header
___
Tutor maillist - Tutor@python.org
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[Tutor] Function list that might have a tuple that might have one of its indexs set to 's'
I am writing my first python program(at least in a really long time).
Its purpose is to take csv or pipe delimited files and convert them
to html pages. Was going to be excel but its just not worth the
headache. Everyone viewing the reports is doing just that viewing
simple tables.
I need to scan through a list that contains headers to my table.If
one of the elements is a tuple and one of the elements of the tuple is
s set self.sort to the index of the tuple in the header list and then
replace the element in header with a two field tuple containing
everything that was not 's'.
header = ['my first column',('my second num column','s','r'),(' my third num column','r') ]I
pass header to a function actually a method but lets pretend its just a
plain old function. Be careful reading the below code may cause random
strokes. I have woken up twice laying on the floor disoriented :)
Actual code in my working example used to call function ...report.set_header( ['','Ext','Name','',('Calls','r','s'),('Ring','r'),('Talk','r'),('Wait','r'),('Max Talk','r') ] ) def set_header(self,header):
list = [] for cindex in range(len(header)): if type(()) == type(header[cindex]): for index in range(len(header[cindex]) ): if header[cindex][index] == 's':
self.sort = cindex for tindex in range(len(header[cindex])): if tindex != index: list.append(header[cindex][tindex]) header[cindex] = tuple(list)
self.header = headerTIA,Paul
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