[Tutor] Urllib Problem
I am trying to make a simple programm with Python 3,that tries to open
differnet pages from a wordlist and prints which are alive.Here is the code:
from urllib import request
fob=open('c:/passwords/pass.txt','r')
x = fob.readlines()
for i in x:
urllib.request.openurl('www.google.gr/' + i)
But it doesent work.Whats the problem?
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Re: [Tutor] Urllib Problem
On 07/29/2011 11:52 AM, George Anonymous wrote:
I am trying to make a simple programm with Python 3,that tries to open
differnet pages from a wordlist and prints which are alive.Here is the
code:
from urllib import request
fob=open('c:/passwords/pass.txt','r')
x = fob.readlines()
for i in x:
urllib.request.openurl('www.google.gr/ http://www.google.gr/' + i)
But it doesent work.Whats the problem?
Please give the exception error you get?!
And you should have in the html header
the html code error number which gives
you the fail answer from the server.
Cheers
Karim
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Re: [Tutor] Urllib Problem
On Fri, Jul 29, 2011 at 5:58 AM, Karim karim.liat...@free.fr wrote:
**
On 07/29/2011 11:52 AM, George Anonymous wrote:
I am trying to make a simple programm with Python 3,that tries to open
differnet pages from a wordlist and prints which are alive.Here is the code:
from urllib import request
fob=open('c:/passwords/pass.txt','r')
x = fob.readlines()
for i in x:
urllib.request.openurl('www.google.gr/' + i)
But it doesent work.Whats the problem?
Please give the exception error you get?!
And you should have in the html header
the html code error number which gives
you the fail answer from the server.
Cheers
Karim
As Karim noted you'll want to mention any exceptions you are getting. I'm
not sure what it is you are trying to do with your code. If you'd like to
try to open each line and try something if it works else an exception the
code may read something similar to:
fob = open('C:/passwords/pass.txt','r')
fob_rlines = fob.readlines()
for line in fob_rlines:
try:
#whatever it is you would like to do with each line
except Exception: #where code didn't work and an exception occured
#whatever you would like to do when a particular *Exception* occurs
Hope that helps,
Alexander
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Re: [Tutor] Urllib Problem
George Anonymous wrote:
I am trying to make a simple programm with Python 3,that tries to open
differnet pages from a wordlist and prints which are alive.Here is the code:
from urllib import request
fob=open('c:/passwords/pass.txt','r')
x = fob.readlines()
for i in x:
urllib.request.openurl('www.google.gr/' + i)
But it doesent work.Whats the problem?
A guessing game! I LOVE guessing games!!! :)
Let's seen let me guess what you mean by doesn't work:
- the computer locks up and sits there until you hit the restart switch
- the computer gives a Blue Screen Of Death
- Python raises an exception
- Python downloads the Yahoo website instead of Google
- something else
My guess is... you're getting a NameError exception, like this one:
from urllib import request
x = urllib.request.openurl('www.google.com')
Traceback (most recent call last):
File stdin, line 1, in module
NameError: name 'urllib' is not defined
Am I close?
You need to use request.urlopen, not urllib.request.openurl.
That's your *first* problem. There are more. Come back if you need help
with the others, and next time, don't make us play guessing games. Show
us the code you use -- copy and paste it, don't retype it from memory --
what you expect should happen, and what actually happens instead.
--
Steven
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[Tutor] urllib problem
Hoi,
I have this programm :
import urllib
import re
f =
urllib.urlopen(http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=6;)
inhoud = f.read()
f.close()
nummer = re.search('[0-9]', inhoud)
volgende = int(nummer.group())
teller = 1
while teller = 3 :
url = http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=; +
str(volgende)
f = urllib.urlopen(url)
inhoud = f.read()
f.close()
nummer = re.search('[0-9]', inhoud)
print nummer is, nummer.group()
volgende = int(nummer.group())
print volgende
teller = teller + 1
but now the url changes but volgende not.
What do I have done wrong ?
Roelof
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Re: [Tutor] urllib problem
I have this program :
import urllib
import re
f =
urllib.urlopen(http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=6;)
inhoud = f.read()
f.close()
nummer = re.search('[0-9]', inhoud)
volgende = int(nummer.group())
teller = 1
while teller = 3 :
url = http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=; +
str(volgende)
f = urllib.urlopen(url)
inhoud = f.read()
f.close()
nummer = re.search('[0-9]', inhoud)
print nummer is, nummer.group()
volgende = int(nummer.group())
print volgende
teller = teller + 1
but now the url changes but volgende not.
I think number will change; *unless* you happen to retrieve the same number
every time, even when you access a different url.
What is the result when you run this program, ie, the output of your print
statements (then, also, print url)?
And, how can url change, but volgende not? Since url depends on volgende.
Btw, it may be better to use parentheses in your regular expression to
explicitly group whatever you want to match, though the above will work (since
it groups the whole match). But Python has this Explicit is better than
implicit thing.
Cheers,
Evert
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Re: [Tutor] urllib problem
On Tue, 12 Oct 2010 11:40:17 pm Roelof Wobben wrote:
Hoi,
I have this programm :
import urllib
import re
f =
urllib.urlopen(http://www.pythonchallenge.com/pc/def/linkedlist.php?
nothing=6) inhoud = f.read()
f.close()
nummer = re.search('[0-9]', inhoud)
volgende = int(nummer.group())
teller = 1
while teller = 3 :
url =
http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=; +
str(volgende) f = urllib.urlopen(url)
inhoud = f.read()
f.close()
nummer = re.search('[0-9]', inhoud)
print nummer is, nummer.group()
volgende = int(nummer.group())
print volgende
teller = teller + 1
but now the url changes but volgende not.
What do I have done wrong ?
Each time through the loop, you set volgende to the same result:
nummer = re.search('[0-9]', inhoud)
volgende = int(nummer.group())
Since inhoud never changes, and the search never changes, the search
result never changes, and volgende never changes.
--
Steven D'Aprano
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Re: [Tutor] urllib problem
On Tue, 12 Oct 2010 11:58:03 pm Steven D'Aprano wrote:
On Tue, 12 Oct 2010 11:40:17 pm Roelof Wobben wrote:
Hoi,
I have this programm :
import urllib
import re
f =
urllib.urlopen(http://www.pythonchallenge.com/pc/def/linkedlist.ph
p? nothing=6) inhoud = f.read()
f.close()
nummer = re.search('[0-9]', inhoud)
volgende = int(nummer.group())
teller = 1
while teller = 3 :
url =
http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=; +
str(volgende) f = urllib.urlopen(url)
inhoud = f.read()
f.close()
nummer = re.search('[0-9]', inhoud)
print nummer is, nummer.group()
volgende = int(nummer.group())
print volgende
teller = teller + 1
but now the url changes but volgende not.
What do I have done wrong ?
Each time through the loop, you set volgende to the same result:
nummer = re.search('[0-9]', inhoud)
volgende = int(nummer.group())
Since inhoud never changes, and the search never changes, the search
result never changes, and volgende never changes.
Wait, sorry, inhoud should change... I missed the line inhoud = f.read()
My mistake, sorry about that. However, I can now see what is going
wrong. Your regular expression only looks for a single digit:
re.search('[0-9]', inhoud)
If you want any number of digits, you need '[0-9]+' instead.
Starting from the first URL:
f = urllib.urlopen(
... http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=6;)
inhoud = f.read()
f.close()
print inhoud
and the next nothing is 87599
but:
nummer = re.search('[0-9]', inhoud)
nummer.group()
'8'
See, you only get the first digit. Then looking up the page with
nothing=8 gives a first digit starting with 5, and then you get stuck
on 5 forever:
urllib.urlopen(
... http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=8;).read()
'and the next nothing is 59212'
urllib.urlopen(
... http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=5;).read()
'and the next nothing is 51716'
You need to add a + to the regular expression, which means one or more
digits instead of a single digit.
--
Steven D'Aprano
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Re: [Tutor] urllib problem
From: st...@pearwood.info
To: tutor@python.org
Date: Tue, 12 Oct 2010 23:58:03 +1100
Subject: Re: [Tutor] urllib problem
On Tue, 12 Oct 2010 11:40:17 pm Roelof Wobben wrote:
Hoi,
I have this programm :
import urllib
import re
f =
urllib.urlopen(http://www.pythonchallenge.com/pc/def/linkedlist.php?
nothing=6) inhoud = f.read()
f.close()
nummer = re.search('[0-9]', inhoud)
volgende = int(nummer.group())
teller = 1
while teller = 3 :
url =
http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=; +
str(volgende) f = urllib.urlopen(url)
inhoud = f.read()
f.close()
nummer = re.search('[0-9]', inhoud)
print nummer is, nummer.group()
volgende = int(nummer.group())
print volgende
teller = teller + 1
but now the url changes but volgende not.
What do I have done wrong ?
Each time through the loop, you set volgende to the same result:
nummer = re.search('[0-9]', inhoud)
volgende = int(nummer.group())
Since inhoud never changes, and the search never changes, the search
result never changes, and volgende never changes.
--
Steven D'Aprano
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Hello,
Here is the output when I print every step in the beginning :
inhoud : and the next nothing is 87599
nummer is 8
volgende is 8
and here is the output in the loop :
url is: http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=8
inhoud is and the next nothing is 59212
nummer is 5
2ste run:
url is: http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=5
inhoud is and the next nothing is 51716
nummer is 5
3ste run:
url is: http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=5
inhoud is and the next nothing is 51716
nummer is 5
4ste run:
I see the problem. It only takes the first number of the nothing.
So I have to look how to solve that.
Roelof
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Re: [Tutor] urllib problem
From: st...@pearwood.info
To: tutor@python.org
Date: Wed, 13 Oct 2010 01:51:16 +1100
Subject: Re: [Tutor] urllib problem
On Tue, 12 Oct 2010 11:58:03 pm Steven D'Aprano wrote:
On Tue, 12 Oct 2010 11:40:17 pm Roelof Wobben wrote:
Hoi,
I have this programm :
import urllib
import re
f =
urllib.urlopen(http://www.pythonchallenge.com/pc/def/linkedlist.ph
p? nothing=6) inhoud = f.read()
f.close()
nummer = re.search('[0-9]', inhoud)
volgende = int(nummer.group())
teller = 1
while teller = 3 :
url =
http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=; +
str(volgende) f = urllib.urlopen(url)
inhoud = f.read()
f.close()
nummer = re.search('[0-9]', inhoud)
print nummer is, nummer.group()
volgende = int(nummer.group())
print volgende
teller = teller + 1
but now the url changes but volgende not.
What do I have done wrong ?
Each time through the loop, you set volgende to the same result:
nummer = re.search('[0-9]', inhoud)
volgende = int(nummer.group())
Since inhoud never changes, and the search never changes, the search
result never changes, and volgende never changes.
Wait, sorry, inhoud should change... I missed the line inhoud = f.read()
My mistake, sorry about that. However, I can now see what is going
wrong. Your regular expression only looks for a single digit:
re.search('[0-9]', inhoud)
If you want any number of digits, you need '[0-9]+' instead.
Starting from the first URL:
f = urllib.urlopen(
... http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=6;)
inhoud = f.read()
f.close()
print inhoud
and the next nothing is 87599
but:
nummer = re.search('[0-9]', inhoud)
nummer.group()
'8'
See, you only get the first digit. Then looking up the page with
nothing=8 gives a first digit starting with 5, and then you get stuck
on 5 forever:
urllib.urlopen(
... http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=8;).read()
'and the next nothing is 59212'
urllib.urlopen(
... http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=5;).read()
'and the next nothing is 51716'
You need to add a + to the regular expression, which means one or more
digits instead of a single digit.
--
Steven D'Aprano
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Hoi Steven,
Finally solved this puzzle.
Now the next one of the 33 puzzles.
Roelof
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Re: [Tutor] urllib problem
Roelof Wobben rwob...@hotmail.com wrote Finally solved this puzzle. Now the next one of the 33 puzzles. Don;t be surprised if you get stuck. Python Challenge is quite tricky and is deliberately designed to make you explore parts of the standard library you might not otherwise find. Expect to do a lot of reading in the documebntation. Its really targeted at intermediate rather than novice programmers IMHO. -- Alan Gauld Author of the Learn to Program web site http://www.alan-g.me.uk/ ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
