Re: [Tutor] bruteforce match word in text file
David wrote:
Thanks Bob,
I changed the wordlist.txt to
next
block
is
meat
and the program;
#!/usr/bin/python
password = 'loser'
wordlist = '/home/david/Challenge-You/wordlist.txt'
try:
words = open(wordlist, 'r').readlines()
except IOError, e:
print "Sorry no words"
for word in words:
word = word.replace("\n","")
if password in word:
print "The password is: ", word
else:
pass
Good work!
I could not figure out how to split the file into words.
look up the string method split.
Also take a look at the syntax of the for statement and notice it has an
else clause.
--
Bob Gailer
Chapel Hill NC
919-636-4239
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Re: [Tutor] bruteforce match word in text file
#!/usr/bin/python
import re
password = 'loser'
wordlist = '/home/david/Challenge-You/wordlist.txt'
try:
words = open(wordlist, 'r').readlines()
except IOError, e:
print "Sorry no words"
for word in words:
word = word.replace("\n","")
if password in word:
print "The password is: ", word
else:
pass
I could not figure out how to split the file into words.
I removed the import re as that was left over from my experimenting.
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Re: [Tutor] bruteforce match word in text file
bob gailer wrote:
David wrote:
bob gailer wrote:
David wrote:
I have to ask for a pointer, not sure what I am doing wrong.
The first thing you are doing "wrong" is failing to tell us what is
in the wordlist file and what results you get when you run the program.
Please re-post with that information.
#!/usr/bin/python
password = 'loser'
wordlist = '/home/david/Challenge-You/wordlist.txt'
try:
words = open(wordlist, 'r').readlines()
except IOError, e:
print "Sorry no words"
for word in words:
word = word.replace("\n","")
if password in word:
print word
else:
print 'You are a loser'
Now what can you change to get it to do what (I assume) you want -
examine each "word" in the file, print the word if 'loser' is in it, and
print 'You are a loser' ONLY if no words match.
Thanks Bob,
I changed the wordlist.txt to
next
block
is
meat
and the program;
#!/usr/bin/python
import re
password = 'loser'
wordlist = '/home/david/Challenge-You/wordlist.txt'
try:
words = open(wordlist, 'r').readlines()
except IOError, e:
print "Sorry no words"
for word in words:
word = word.replace("\n","")
if password in word:
print "The password is: ", word
else:
pass
I could not figure out how to split the file into words.
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Re: [Tutor] bruteforce match word in text file
David wrote:
bob gailer wrote:
David wrote:
I have to ask for a pointer, not sure what I am doing wrong.
The first thing you are doing "wrong" is failing to tell us what is
in the wordlist file and what results you get when you run the program.
Please re-post with that information.
#!/usr/bin/python
password = 'loser'
wordlist = '/home/david/Challenge-You/wordlist.txt'
try:
words = open(wordlist, 'r').readlines()
except IOError, e:
print "Sorry no words"
for word in words:
word = word.replace("\n","")
if password in word:
print word
else:
print 'You are a loser'
wordlist.txt
next block is the meat the script will go through the list of words
create our form with information encode that form and then apply that
loser get source added comments above each line to help you understand
results;
./py_bruteforce.py
next block is the meat the script will go through the list of words
create our form with information encode that form and then apply that
loser get source added comments above each line to help you understand
You are a loser
Thank you. Please always post the relevant information, and if you get
an exception, post the full traceback.
It looks like the file contains 1 line. So the for statement will put
that line in word. 'loser' is in word so the print statement prints the
line.
The program is working as written.
Now what can you change to get it to do what (I assume) you want -
examine each "word" in the file, print the word if 'loser' is in it, and
print 'You are a loser' ONLY if no words match.
--
Bob Gailer
Chapel Hill NC
919-636-4239
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Re: [Tutor] bruteforce match word in text file
bob gailer wrote:
David wrote:
I have to ask for a pointer, not sure what I am doing wrong.
The first thing you are doing "wrong" is failing to tell us what is in
the wordlist file and what results you get when you run the program.
Please re-post with that information.
#!/usr/bin/python
password = 'loser'
wordlist = '/home/david/Challenge-You/wordlist.txt'
try:
words = open(wordlist, 'r').readlines()
except IOError, e:
print "Sorry no words"
for word in words:
word = word.replace("\n","")
if password in word:
print word
else:
print 'You are a loser'
wordlist.txt
next block is the meat the script will go through the list of words
create our form with information encode that form and then apply that
loser get source added comments above each line to help you understand
results;
./py_bruteforce.py
next block is the meat the script will go through the list of words
create our form with information encode that form and then apply that
loser get source added comments above each line to help you understand
You are a loser
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Re: [Tutor] bruteforce match word in text file
David wrote:
I have to ask for a pointer, not sure what I am doing wrong.
The first thing you are doing "wrong" is failing to tell us what is in
the wordlist file and what results you get when you run the program.
Please re-post with that information.
#!/usr/bin/python
password = 'loser'
wordlist = '/home/david/Challenge-You/wordlist.txt'
try:
words = open(wordlist, 'r').readlines()
except IOError, e:
print "Sorry no words"
for word in words:
word = word.replace("\n","")
if password in word:
print word
else:
print 'You are a loser'
--
Bob Gailer
Chapel Hill NC
919-636-4239
___
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[Tutor] bruteforce match word in text file
I have to ask for a pointer, not sure what I am doing wrong.
thanks
-david
#!/usr/bin/python
password = 'loser'
wordlist = '/home/david/Challenge-You/wordlist.txt'
try:
words = open(wordlist, 'r').readlines()
except IOError, e:
print "Sorry no words"
for word in words:
word = word.replace("\n","")
if password in word:
print word
else:
print 'You are a loser'
--
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http://www.linuxcrazy.com
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