Re: [Tutor] counting number of inputs (EARLIER VERSION SENT ACCIDENTLY)

2006-05-04 Thread MICHELLE EVANS 
This is exactly what I am trying to do.  I am so confused with trying to
write this.  I am not very familiar with any of the functions.  I keep
reading my book and reading my book, and none of it seems to make sense
anymore.  I can write extremely simple functions, but when I need to use
more than one in a code, I'm lost!

Thanks

- Original Message - 
From: Marc Poulin [EMAIL PROTECTED]
To: tutor@python.org
Sent: Thursday, May 04, 2006 12:08 AM
Subject: Re: [Tutor] counting number of inputs (EARLIER VERSION SENT
ACCIDENTLY)



 Michelle:

 Are you familiar with writing functions?
 Here I've created a function named getInputs.

 I've also created a few test cases to verify that (a)
 my understanding of the problem is correct, and (b) my
 solution is correct.

 It's important to think about how your program is
 supposed to behave in different situations. Do you
 think these 3 tests are enough to prove that the code
 is correct?

 #
 ## start of code   ##
 #
 def getInputs():
 
 Description:
Collect numbers entered by the user (up to a
 maximum of 5 values) and
store them in the listOfValues.

Stop collecting numbers if the user enters -1
 or if 5 numbers have been collected.

If the user entered -1, the -1 is NOT returned
 as part of the list.
 
 listOfValues = [] ## this list holds the values
 entered by the user

 for i in range(5):
 newValue = int(raw_input('Enter a number [-1
 to exit]:'))
 if newValue == -1:
 # Return right now with whatever is
 currently in the list.
 return listOfValues
 else:
 # Add this new value to the list and keep
 looping.
 listOfValues.append(newValue)

 ## If we got this far, it means the user did not
 enter a -1 so
 ## the list contains 5 values.
 return listOfValues

 
 Here are a few test cases to verify the logic of my
 code.

 Test Case 1:
INPUTS:
   first entered value: -1
RESULT:
   function returns empty list

 Test Case 2:
INPUTS:
   first entered value: 1
   second entered value: 2
   third entered value: -1
RESULT:
   returned list contains [1,2]

 Test Case 3:
INPUTS:
   first entered value: 1
   second entered value: 2
   third entered value: 3
   fourth entered value: 4
   fifth entered value: 5
RESULT:
   returned list contains [1,2,3,4,5]
 
 if __name__ == __main__:
 print getInputs()

 ###
 ## end of code   ##
 ###


 --- Python [EMAIL PROTECTED] wrote:

  On Wed, 2006-05-03 at 15:33 -0400, MICHELLE EVANS
  wrote:
   OK, I've tried a different approach to this.
   How do I get this to stop by using -1?
   I do not want this to print until either 5 inputs
  have been entered or -1
   has been entered.  See below:
  
 
  use a for block rather than a while block to
  have a normal limit of
  5 repetitions:
 
  for x in range(5):
 
  will repeat 5 times with x running from 0 to 4.
  x is ignored - unless some use for it does turn up.
 
  the break statement allows you to terminate a block,
  so
 
  if number == -1: break
 
  will end the for block.
 
 
  Now, one of the cute features in Python is the else
  clause that goes
  with the for and while blocks.  The else block is
  executed when there is
  no break.  So the skeleton for your program can look
  something like
 
  for x in range(5):
  # get inputs and break on -1
  else:
  # no break so just process the inputs
 
  Good luck.
 
   # Add number of per hour
   numbers = []
   stop = None
   while stop != -1:
   number = int(raw_input(Run number(-1 to end)
  : ))
   numbers.append(number)
   print
   for number in numbers:
   print number
  
  
  
  
   - Original Message - 
   From: Python [EMAIL PROTECTED]
   To: MICHELLE EVANS [EMAIL PROTECTED]
   Cc: Tutor Python tutor@python.org
   Sent: Wednesday, May 03, 2006 12:18 PM
   Subject: Re: [Tutor] counting number of inputs
  (EARLIER VERSION SENT
   ACCIDENTLY)
  
  
(Tip: Best to use reply-to-all when responding
  to an email on the list)
On Tue, 2006-05-02 at 21:34 -0400, MICHELLE
  EVANS wrote:
 number1 = int(raw_input(Run number 1 (-1 to
  end) : ))
 number2 = int(raw_input(Run number 2 (-1 to
  end) : ))
 number3 = int(raw_input(Run number 3 (-1 to
  end) : ))
 number4 = int(raw_input(Run number 4 (-1 to
  end) : ))
 number5 = int(raw_input(Run number 5 (-1 to
  end) : ))
Good.  You collect the string from raw_input and
  convert it to an
integer.
   
This will prompt for 5 inputs, but it is missing
  any logic to actually
break if -1 is entered.  With a language like
  BASIC, you could stick in
tests sort of like:
if number1 == -1 goto done:
BUT Python does not have a goto.  So we actually
  need some flow
control around the block of code where you
  collect

Re: [Tutor] counting number of inputs (EARLIER VERSION SENT ACCIDENTLY)

2006-05-03 Thread Python 
(Tip: Best to use reply-to-all when responding to an email on the list)
On Tue, 2006-05-02 at 21:34 -0400, MICHELLE EVANS wrote:
 number1 = int(raw_input(Run number 1 (-1 to end) : ))
 number2 = int(raw_input(Run number 2 (-1 to end) : ))
 number3 = int(raw_input(Run number 3 (-1 to end) : ))
 number4 = int(raw_input(Run number 4 (-1 to end) : ))
 number5 = int(raw_input(Run number 5 (-1 to end) : ))
Good.  You collect the string from raw_input and convert it to an
integer.

This will prompt for 5 inputs, but it is missing any logic to actually
break if -1 is entered.  With a language like BASIC, you could stick in
tests sort of like:
if number1 == -1 goto done:
BUT Python does not have a goto.  So we actually need some flow
control around the block of code where you collect inputs.

while blocks process an indefinite number of times while a test
condition is True.

for blocks iterate through a sequence until they reach the end.  By
providing a sequence with the correct count, you can repeat the block
the correct number of times.  The range (and xrange for big sequences)
functions provide a sequence of integers that can be used conveniently
with for.

The easiest way to fix your code above would be something like:
ask_for_number = True
while ask_for_number:
number1 = 
if number1 == -1: break
...
number5 = ...
ask_for_number = False

HOWEVER, that is not a good approach in the long run.

A better approach is to have a single container to hold all of the
inputs.  For this, Python provides lists.  Rather than have 5 separate
variables, use a single list variable to hold all of the inputs.  Then
use a for block to ask for the input and put the result into the list.
You already know how to convert the input from a string to a number.

If you have trouble figuring out lists and for blocks, ask for help.

(Sorry about the extra email.  I forgot and used ad editor hot-key combo
in my email program which sent the email.)


 
 
 # The following will sum the numbers and then print the answer
 sum = number1 + number2 + number3 + number4 + number5
 print
 print The total number of parts produced was:, sum,.
 
 I need this to ask the user to enter their number per each run.  That is why
 I have 5 different input numbers.  I need this break if a -1 is entered.
 Would I use if-else to break this if -1 is entered?  I need to be able to
 count the number of lines entered.
 
 Thanks
 Rick
 
 
 - Original Message - 
 From: Python [EMAIL PROTECTED]
 To: MICHELLE EVANS [EMAIL PROTECTED]
 Cc: Tutor Python tutor@python.org
 Sent: Tuesday, May 02, 2006 7:56 PM
 Subject: Re: [Tutor] counting number of inputs
 
 
  On Tue, 2006-05-02 at 19:25 -0400, MICHELLE EVANS wrote:
   I am trying to count the number of times a positive number is entered
   from the user.  But, the program must stop after 5 user inputs or a
   negative number.
  
   Can anyone help.
  Yes, but you need to help yourself also.
 
  Do you know how to get input from the user?
  Do you know how to count things in Python?
  Do you know how to test a number to see if it is positive or negative?
 
  Why don't you post your code for any part of this problem and explain
  how it is supposed to work and where you are having difficulty.  If
  necessary, review some of the tutorials to get some pointers on writing
  Python programs.
 
  We're happy to help you learn, but do not want to simply write your
  program for you.
 
   Rick
   ___
   Tutor maillist  -  Tutor@python.org
   http://mail.python.org/mailman/listinfo/tutor
  -- 
  Lloyd Kvam
  Venix Corp
 
 
 
-- 
Lloyd Kvam
Venix Corp

___
Tutor maillist  -  Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor

Re: [Tutor] counting number of inputs (EARLIER VERSION SENT ACCIDENTLY)

2006-05-03 Thread MICHELLE EVANS 
OK, I've tried a different approach to this.
How do I get this to stop by using -1?
I do not want this to print until either 5 inputs have been entered or -1
has been entered.  See below:

# Add number of per hour
numbers = []
stop = None
while stop != -1:
number = int(raw_input(Run number(-1 to end) : ))
numbers.append(number)
print
for number in numbers:
print number




- Original Message - 
From: Python [EMAIL PROTECTED]
To: MICHELLE EVANS [EMAIL PROTECTED]
Cc: Tutor Python tutor@python.org
Sent: Wednesday, May 03, 2006 12:18 PM
Subject: Re: [Tutor] counting number of inputs (EARLIER VERSION SENT
ACCIDENTLY)


 (Tip: Best to use reply-to-all when responding to an email on the list)
 On Tue, 2006-05-02 at 21:34 -0400, MICHELLE EVANS wrote:
  number1 = int(raw_input(Run number 1 (-1 to end) : ))
  number2 = int(raw_input(Run number 2 (-1 to end) : ))
  number3 = int(raw_input(Run number 3 (-1 to end) : ))
  number4 = int(raw_input(Run number 4 (-1 to end) : ))
  number5 = int(raw_input(Run number 5 (-1 to end) : ))
 Good.  You collect the string from raw_input and convert it to an
 integer.

 This will prompt for 5 inputs, but it is missing any logic to actually
 break if -1 is entered.  With a language like BASIC, you could stick in
 tests sort of like:
 if number1 == -1 goto done:
 BUT Python does not have a goto.  So we actually need some flow
 control around the block of code where you collect inputs.

 while blocks process an indefinite number of times while a test
 condition is True.

 for blocks iterate through a sequence until they reach the end.  By
 providing a sequence with the correct count, you can repeat the block
 the correct number of times.  The range (and xrange for big sequences)
 functions provide a sequence of integers that can be used conveniently
 with for.

 The easiest way to fix your code above would be something like:
 ask_for_number = True
 while ask_for_number:
 number1 = 
 if number1 == -1: break
 ...
 number5 = ...
 ask_for_number = False

 HOWEVER, that is not a good approach in the long run.

 A better approach is to have a single container to hold all of the
 inputs.  For this, Python provides lists.  Rather than have 5 separate
 variables, use a single list variable to hold all of the inputs.  Then
 use a for block to ask for the input and put the result into the list.
 You already know how to convert the input from a string to a number.

 If you have trouble figuring out lists and for blocks, ask for help.

 (Sorry about the extra email.  I forgot and used ad editor hot-key combo
 in my email program which sent the email.)


 
 
  # The following will sum the numbers and then print the answer
  sum = number1 + number2 + number3 + number4 + number5
  print
  print The total number of parts produced was:, sum,.
 
  I need this to ask the user to enter their number per each run.  That is
why
  I have 5 different input numbers.  I need this break if a -1 is entered.
  Would I use if-else to break this if -1 is entered?  I need to be able
to
  count the number of lines entered.
 
  Thanks
  Rick
 
 
  - Original Message - 
  From: Python [EMAIL PROTECTED]
  To: MICHELLE EVANS [EMAIL PROTECTED]
  Cc: Tutor Python tutor@python.org
  Sent: Tuesday, May 02, 2006 7:56 PM
  Subject: Re: [Tutor] counting number of inputs
 
 
   On Tue, 2006-05-02 at 19:25 -0400, MICHELLE EVANS wrote:
I am trying to count the number of times a positive number is
entered
from the user.  But, the program must stop after 5 user inputs or a
negative number.
   
Can anyone help.
   Yes, but you need to help yourself also.
  
   Do you know how to get input from the user?
   Do you know how to count things in Python?
   Do you know how to test a number to see if it is positive or negative?
  
   Why don't you post your code for any part of this problem and explain
   how it is supposed to work and where you are having difficulty.  If
   necessary, review some of the tutorials to get some pointers on
writing
   Python programs.
  
   We're happy to help you learn, but do not want to simply write your
   program for you.
  
Rick
___
Tutor maillist  -  Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
   -- 
   Lloyd Kvam
   Venix Corp
  
  
 
 -- 
 Lloyd Kvam
 Venix Corp



___
Tutor maillist  -  Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor

Re: [Tutor] counting number of inputs (EARLIER VERSION SENT ACCIDENTLY)

2006-05-03 Thread Python 
On Wed, 2006-05-03 at 15:33 -0400, MICHELLE EVANS wrote:
 OK, I've tried a different approach to this.
 How do I get this to stop by using -1?
 I do not want this to print until either 5 inputs have been entered or -1
 has been entered.  See below:
 

use a for block rather than a while block to have a normal limit of
5 repetitions:

for x in range(5):

will repeat 5 times with x running from 0 to 4.
x is ignored - unless some use for it does turn up.

the break statement allows you to terminate a block, so

if number == -1: break

will end the for block.


Now, one of the cute features in Python is the else clause that goes
with the for and while blocks.  The else block is executed when there is
no break.  So the skeleton for your program can look something like

for x in range(5):
# get inputs and break on -1
else:
# no break so just process the inputs

Good luck.

 # Add number of per hour
 numbers = []
 stop = None
 while stop != -1:
 number = int(raw_input(Run number(-1 to end) : ))
 numbers.append(number)
 print
 for number in numbers:
 print number
 
 
 
 
 - Original Message - 
 From: Python [EMAIL PROTECTED]
 To: MICHELLE EVANS [EMAIL PROTECTED]
 Cc: Tutor Python tutor@python.org
 Sent: Wednesday, May 03, 2006 12:18 PM
 Subject: Re: [Tutor] counting number of inputs (EARLIER VERSION SENT
 ACCIDENTLY)
 
 
  (Tip: Best to use reply-to-all when responding to an email on the list)
  On Tue, 2006-05-02 at 21:34 -0400, MICHELLE EVANS wrote:
   number1 = int(raw_input(Run number 1 (-1 to end) : ))
   number2 = int(raw_input(Run number 2 (-1 to end) : ))
   number3 = int(raw_input(Run number 3 (-1 to end) : ))
   number4 = int(raw_input(Run number 4 (-1 to end) : ))
   number5 = int(raw_input(Run number 5 (-1 to end) : ))
  Good.  You collect the string from raw_input and convert it to an
  integer.
 
  This will prompt for 5 inputs, but it is missing any logic to actually
  break if -1 is entered.  With a language like BASIC, you could stick in
  tests sort of like:
  if number1 == -1 goto done:
  BUT Python does not have a goto.  So we actually need some flow
  control around the block of code where you collect inputs.
 
  while blocks process an indefinite number of times while a test
  condition is True.
 
  for blocks iterate through a sequence until they reach the end.  By
  providing a sequence with the correct count, you can repeat the block
  the correct number of times.  The range (and xrange for big sequences)
  functions provide a sequence of integers that can be used conveniently
  with for.
 
  The easiest way to fix your code above would be something like:
  ask_for_number = True
  while ask_for_number:
  number1 = 
  if number1 == -1: break
  ...
  number5 = ...
  ask_for_number = False
 
  HOWEVER, that is not a good approach in the long run.
 
  A better approach is to have a single container to hold all of the
  inputs.  For this, Python provides lists.  Rather than have 5 separate
  variables, use a single list variable to hold all of the inputs.  Then
  use a for block to ask for the input and put the result into the list.
  You already know how to convert the input from a string to a number.
 
  If you have trouble figuring out lists and for blocks, ask for help.
 
  (Sorry about the extra email.  I forgot and used ad editor hot-key combo
  in my email program which sent the email.)
 
 
  
  
   # The following will sum the numbers and then print the answer
   sum = number1 + number2 + number3 + number4 + number5
   print
   print The total number of parts produced was:, sum,.
  
   I need this to ask the user to enter their number per each run.  That is
 why
   I have 5 different input numbers.  I need this break if a -1 is entered.
   Would I use if-else to break this if -1 is entered?  I need to be able
 to
   count the number of lines entered.
  
   Thanks
   Rick
  
  
   - Original Message - 
   From: Python [EMAIL PROTECTED]
   To: MICHELLE EVANS [EMAIL PROTECTED]
   Cc: Tutor Python tutor@python.org
   Sent: Tuesday, May 02, 2006 7:56 PM
   Subject: Re: [Tutor] counting number of inputs
  
  
On Tue, 2006-05-02 at 19:25 -0400, MICHELLE EVANS wrote:
 I am trying to count the number of times a positive number is
 entered
 from the user.  But, the program must stop after 5 user inputs or a
 negative number.

 Can anyone help.
Yes, but you need to help yourself also.
   
Do you know how to get input from the user?
Do you know how to count things in Python?
Do you know how to test a number to see if it is positive or negative?
   
Why don't you post your code for any part of this problem and explain
how it is supposed to work and where you are having difficulty.  If
necessary, review some of the tutorials to get some pointers on
 writing
Python programs.
   
We're happy to help you learn, but do not want to simply write your
program for you

Re: [Tutor] counting number of inputs (EARLIER VERSION SENT ACCIDENTLY)

2006-05-03 Thread Marc Poulin 

Michelle:

Are you familiar with writing functions?
Here I've created a function named getInputs.

I've also created a few test cases to verify that (a)
my understanding of the problem is correct, and (b) my
solution is correct.

It's important to think about how your program is
supposed to behave in different situations. Do you
think these 3 tests are enough to prove that the code
is correct?

#
## start of code   ##
#
def getInputs():

Description:
   Collect numbers entered by the user (up to a
maximum of 5 values) and
   store them in the listOfValues.

   Stop collecting numbers if the user enters -1
or if 5 numbers have been collected.

   If the user entered -1, the -1 is NOT returned
as part of the list.   

listOfValues = [] ## this list holds the values
entered by the user

for i in range(5):
newValue = int(raw_input('Enter a number [-1
to exit]:'))
if newValue == -1:
# Return right now with whatever is
currently in the list.
return listOfValues
else:
# Add this new value to the list and keep
looping.
listOfValues.append(newValue)

## If we got this far, it means the user did not
enter a -1 so
## the list contains 5 values.
return listOfValues


Here are a few test cases to verify the logic of my
code.

Test Case 1:
   INPUTS:
  first entered value: -1
   RESULT:
  function returns empty list

Test Case 2:
   INPUTS:
  first entered value: 1
  second entered value: 2
  third entered value: -1
   RESULT:
  returned list contains [1,2]

Test Case 3:
   INPUTS:
  first entered value: 1
  second entered value: 2
  third entered value: 3
  fourth entered value: 4
  fifth entered value: 5
   RESULT:
  returned list contains [1,2,3,4,5]

if __name__ == __main__:
print getInputs()

###
## end of code   ##
###


--- Python [EMAIL PROTECTED] wrote:

 On Wed, 2006-05-03 at 15:33 -0400, MICHELLE EVANS
 wrote:
  OK, I've tried a different approach to this.
  How do I get this to stop by using -1?
  I do not want this to print until either 5 inputs
 have been entered or -1
  has been entered.  See below:
  
 
 use a for block rather than a while block to
 have a normal limit of
 5 repetitions:
 
 for x in range(5):
 
 will repeat 5 times with x running from 0 to 4.
 x is ignored - unless some use for it does turn up.
 
 the break statement allows you to terminate a block,
 so
 
   if number == -1: break
 
 will end the for block.
 
 
 Now, one of the cute features in Python is the else
 clause that goes
 with the for and while blocks.  The else block is
 executed when there is
 no break.  So the skeleton for your program can look
 something like
 
 for x in range(5):
   # get inputs and break on -1
 else:
   # no break so just process the inputs
 
 Good luck.
 
  # Add number of per hour
  numbers = []
  stop = None
  while stop != -1:
  number = int(raw_input(Run number(-1 to end)
 : ))
  numbers.append(number)
  print
  for number in numbers:
  print number
  
  
  
  
  - Original Message - 
  From: Python [EMAIL PROTECTED]
  To: MICHELLE EVANS [EMAIL PROTECTED]
  Cc: Tutor Python tutor@python.org
  Sent: Wednesday, May 03, 2006 12:18 PM
  Subject: Re: [Tutor] counting number of inputs
 (EARLIER VERSION SENT
  ACCIDENTLY)
  
  
   (Tip: Best to use reply-to-all when responding
 to an email on the list)
   On Tue, 2006-05-02 at 21:34 -0400, MICHELLE
 EVANS wrote:
number1 = int(raw_input(Run number 1 (-1 to
 end) : ))
number2 = int(raw_input(Run number 2 (-1 to
 end) : ))
number3 = int(raw_input(Run number 3 (-1 to
 end) : ))
number4 = int(raw_input(Run number 4 (-1 to
 end) : ))
number5 = int(raw_input(Run number 5 (-1 to
 end) : ))
   Good.  You collect the string from raw_input and
 convert it to an
   integer.
  
   This will prompt for 5 inputs, but it is missing
 any logic to actually
   break if -1 is entered.  With a language like
 BASIC, you could stick in
   tests sort of like:
   if number1 == -1 goto done:
   BUT Python does not have a goto.  So we actually
 need some flow
   control around the block of code where you
 collect inputs.
  
   while blocks process an indefinite number of
 times while a test
   condition is True.
  
   for blocks iterate through a sequence until they
 reach the end.  By
   providing a sequence with the correct count, you
 can repeat the block
   the correct number of times.  The range (and
 xrange for big sequences)
   functions provide a sequence of integers that
 can be used conveniently
   with for.
  
   The easiest way to fix your code above would be
 something like:
   ask_for_number = True
   while ask_for_number:
   number1 = 
   if number1 == -1: break
   ...
   number5 = ...
   ask_for_number = False
  
   HOWEVER